Wsrtjtyk

If I have a string like this :

TAX ID NO. 01.000.589.0.055.000 

My goal is, I want to get the integer digit after tax phrase, which is 010005890055000

So far I write like this

/(tax id no)s*[^A-Za-z0-9]?s*Kd+/i

but It still not true because sometimes user wrote like this:

TAX ID. 01.000.589.0.055.000 or

TAX ID : 01.000.589.0.055.000 or

TAX ID 01.000.589.0.055.000 or

TAX: 01.000.589.0.055.000

even user wrote directly into a prefect integer digit

TAX ID NO. 010005890055000

Please advise

This is all my possibilities:

1. 
   

   Non Formatted

   
   
   

   JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA TAX ID NO. 010005890055000

   
   


2. 
   

   Formatted

   
   
   

   JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA TAX ID NO. 01.000.589.0.055.000

   
   


3. 
   

   With different tax phrase

   
   
   

   JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA TAX 010005890055000

   
   
   

   JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA TAX ID 01.000.589.0.055.000

   
   
   

   JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA TAX ID. 010005890055000

   
   


4. 
   

   In beginning a sentence

   
   
   

   TAX ID. 010005890055000 , JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA

   
   
   

   TAX ID. 01.000.589.0.055.000 , JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA

   
   

So much thank you...

It looks like your only consistent keyword is TAX, so you can grab digits (with dots and dashes) after it with the regex ~TAX.*?.? *?([d.-]+)~i, then strip non-digits (if desired). Here's an example test:

$data = "JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA TAX ID NO. 010005890055000

JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA TAX ID NO. 01.000.589.0.055.000

JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA TAX 010005890055000

JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA TAX ID 01.000.589.0.055.000

JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA TAX ID. 010005890055000

TAX ID. 010005890055000 , JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA

tax ID. 01.000.589.0.055.000 , JL

TAX ID. 01.000.589.0.055.000 , JL. CACING RT 007/008 CAKUNG, JAKARTA TIMUR 13910 INDONESIA

JL. CAKUNG CILINCING KP BARU RT 007/008 CAKUNG BARAT, CAKUNG, JAKARTA TIMUR 13910 INDONESIA TAX ID NO. 01.109.421.6-902.000";



foreach (explode("n", $data) as $line) {

    preg_match("~TAX.*?.? *?([d.-]+)~i", $line, $m);

    echo preg_replace("~D~", "", $m[1]) . "n";

}

Output:

010005890055000

010005890055000

010005890055000

010005890055000

010005890055000

010005890055000

010005890055000

010005890055000

011094216902000

Try it!

You can make use of this:

/(?:taxs*(?:ids*)?).*?(d[d.]+)/i

The first group checks for tax with id being optional. It then grabs the first digit and all digit and . and groups it under $1

Regexr

You can use preg_replace to remove all but numbers.

preg_replace('/[^d]/', '', $str);

see output: https://3v4l.org/Ne3fo

To answer the new requirement:
Use substr and strpos to remove the part up to "tax".

$arr = ["TAX ID. 01.000.589.0.055.000 or",

"TAX ID : 01.000.589.0.055.000 or",

"TAX ID 01.000.589.0.055.000 or",

"TAX: 01.000.589.0.055.000",

"ARU RT 007/008 CAKUNG BARAT, CAKUNG, JAKARTA TIMUR 13910 INDONESIA TAX ID NO. 010005890055000"];



foreach($arr as $str){

    echo preg_replace('/[^d]/', '', substr($str, stripos($str, "tax"))) . "n";

}

https://3v4l.org/btDAq

You can use this regex, where except TAX part, I have made everything that comes in middle between tax and numbers as optional. Use this regex and capture group1

/tax(?:.*?)s+([d.]+)/i

Demo

Once you get digit and dot part, remove all dot characters from it.

Here is a sample php code,

$arr = ["TAX ID NO. 01.000.589.0.055.000","TAX ID. 01.000.589.0.055.000","TAX ID : 01.000.589.0.055.000","TAX ID 01.000.589.0.055.000","TAX: 01.000.589.0.055.000", "TAX ID NO. 010005890055000"];



foreach ($arr as &$value) {

    preg_match('/tax(?:.*?)s+([d.]+)/i', $value, $matches);

    echo $value . " --> " . preg_replace('/./','',$matches[1]) . "n";

}

This prints following output,

TAX ID NO. 01.000.589.0.055.000 --> 010005890055000

TAX ID. 01.000.589.0.055.000 --> 010005890055000

TAX ID : 01.000.589.0.055.000 --> 010005890055000

TAX ID 01.000.589.0.055.000 --> 010005890055000

TAX: 01.000.589.0.055.000 --> 010005890055000

TAX ID NO. 010005890055000 --> 010005890055000