PHP MySQL select all matching rows ans echo another table rows
I have 2 table message and answer. where message id = answer id. I want select using message. when message = hi then expected answer hello, hey.
Message Table:
| id | message |
| 1 | hi |
| 2 | hi |
| 3 | Hi |
and answer table:
| id | answer |
| 1 | hello |
| 2 | hey |
| 3 | Hello |
I already tried:
$inp = "hi";
SELECT * FROM message JOIN answer ON message.message = answer.answer WHERE message='$inp'"
any suggestions?
php mysql mysqli
|
show 1 more comment
I have 2 table message and answer. where message id = answer id. I want select using message. when message = hi then expected answer hello, hey.
Message Table:
| id | message |
| 1 | hi |
| 2 | hi |
| 3 | Hi |
and answer table:
| id | answer |
| 1 | hello |
| 2 | hey |
| 3 | Hello |
I already tried:
$inp = "hi";
SELECT * FROM message JOIN answer ON message.message = answer.answer WHERE message='$inp'"
any suggestions?
php mysql mysqli
1
Please share your latest code attempt; this would help us in pointing you to right direction.
– Madhur Bhaiya
Nov 23 '18 at 5:18
now may you can understand!
– Rabib
Nov 23 '18 at 5:25
2
SELECT * FROM answer JOIN message ON message.id= answer.id WHERE message='$inp'"
Any luck with this.
– Prashant Deshmukh.....
Nov 23 '18 at 5:25
1
Always join using the appropriate relationships. As specified in previous comment, you should usingid
notmessage/answer
– Madhur Bhaiya
Nov 23 '18 at 5:28
1
Also, Your code is open to SQL injection related attacks. Please learn to use Prepared Statements
– Madhur Bhaiya
Nov 23 '18 at 5:28
|
show 1 more comment
I have 2 table message and answer. where message id = answer id. I want select using message. when message = hi then expected answer hello, hey.
Message Table:
| id | message |
| 1 | hi |
| 2 | hi |
| 3 | Hi |
and answer table:
| id | answer |
| 1 | hello |
| 2 | hey |
| 3 | Hello |
I already tried:
$inp = "hi";
SELECT * FROM message JOIN answer ON message.message = answer.answer WHERE message='$inp'"
any suggestions?
php mysql mysqli
I have 2 table message and answer. where message id = answer id. I want select using message. when message = hi then expected answer hello, hey.
Message Table:
| id | message |
| 1 | hi |
| 2 | hi |
| 3 | Hi |
and answer table:
| id | answer |
| 1 | hello |
| 2 | hey |
| 3 | Hello |
I already tried:
$inp = "hi";
SELECT * FROM message JOIN answer ON message.message = answer.answer WHERE message='$inp'"
any suggestions?
php mysql mysqli
php mysql mysqli
edited Nov 23 '18 at 5:24
Rabib
asked Nov 23 '18 at 5:16
RabibRabib
188
188
1
Please share your latest code attempt; this would help us in pointing you to right direction.
– Madhur Bhaiya
Nov 23 '18 at 5:18
now may you can understand!
– Rabib
Nov 23 '18 at 5:25
2
SELECT * FROM answer JOIN message ON message.id= answer.id WHERE message='$inp'"
Any luck with this.
– Prashant Deshmukh.....
Nov 23 '18 at 5:25
1
Always join using the appropriate relationships. As specified in previous comment, you should usingid
notmessage/answer
– Madhur Bhaiya
Nov 23 '18 at 5:28
1
Also, Your code is open to SQL injection related attacks. Please learn to use Prepared Statements
– Madhur Bhaiya
Nov 23 '18 at 5:28
|
show 1 more comment
1
Please share your latest code attempt; this would help us in pointing you to right direction.
– Madhur Bhaiya
Nov 23 '18 at 5:18
now may you can understand!
– Rabib
Nov 23 '18 at 5:25
2
SELECT * FROM answer JOIN message ON message.id= answer.id WHERE message='$inp'"
Any luck with this.
– Prashant Deshmukh.....
Nov 23 '18 at 5:25
1
Always join using the appropriate relationships. As specified in previous comment, you should usingid
notmessage/answer
– Madhur Bhaiya
Nov 23 '18 at 5:28
1
Also, Your code is open to SQL injection related attacks. Please learn to use Prepared Statements
– Madhur Bhaiya
Nov 23 '18 at 5:28
1
1
Please share your latest code attempt; this would help us in pointing you to right direction.
– Madhur Bhaiya
Nov 23 '18 at 5:18
Please share your latest code attempt; this would help us in pointing you to right direction.
– Madhur Bhaiya
Nov 23 '18 at 5:18
now may you can understand!
– Rabib
Nov 23 '18 at 5:25
now may you can understand!
– Rabib
Nov 23 '18 at 5:25
2
2
SELECT * FROM answer JOIN message ON message.id= answer.id WHERE message='$inp'"
Any luck with this.– Prashant Deshmukh.....
Nov 23 '18 at 5:25
SELECT * FROM answer JOIN message ON message.id= answer.id WHERE message='$inp'"
Any luck with this.– Prashant Deshmukh.....
Nov 23 '18 at 5:25
1
1
Always join using the appropriate relationships. As specified in previous comment, you should using
id
not message/answer
– Madhur Bhaiya
Nov 23 '18 at 5:28
Always join using the appropriate relationships. As specified in previous comment, you should using
id
not message/answer
– Madhur Bhaiya
Nov 23 '18 at 5:28
1
1
Also, Your code is open to SQL injection related attacks. Please learn to use Prepared Statements
– Madhur Bhaiya
Nov 23 '18 at 5:28
Also, Your code is open to SQL injection related attacks. Please learn to use Prepared Statements
– Madhur Bhaiya
Nov 23 '18 at 5:28
|
show 1 more comment
2 Answers
2
active
oldest
votes
Try this code :
"SELECT * FROM message JOIN answer ON message.id= answer.id WHERE message.message='".$inp."'";
same output just 1 row. I want 2 row . thank you
– Rabib
Nov 23 '18 at 8:52
add a comment |
use common b/w each table in your case id so query should be..
SELECT * FROM message JOIN answer ON answer.id = message.id WHERE message = 'hi';
rest in php you should use different ways to run query like prepared statements in order to avoid sql injection or concatenate the variables
like
'SELECT * FROM message JOIN answer ON answer.id = message.id WHERE message = "'.$input.'"';
or mysqli_prepare() bind_params()
or learn using PDO which is good to avoid sql injections as well as supports multiple db drivers which make your work more dynamic and flexible.
thank you for your answer. but my expected output single time 2 results hello and hey. how can do this? any suggestions?
– Rabib
Nov 23 '18 at 8:58
1
it is giving you two answers for the message 'hi' isn't it ?? so all you need to do is loop through it using php.
– Akhilesh
Nov 23 '18 at 9:06
haha my code is working. but I forgotten to add while loop. thank you again
– Rabib
Nov 23 '18 at 10:08
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try this code :
"SELECT * FROM message JOIN answer ON message.id= answer.id WHERE message.message='".$inp."'";
same output just 1 row. I want 2 row . thank you
– Rabib
Nov 23 '18 at 8:52
add a comment |
Try this code :
"SELECT * FROM message JOIN answer ON message.id= answer.id WHERE message.message='".$inp."'";
same output just 1 row. I want 2 row . thank you
– Rabib
Nov 23 '18 at 8:52
add a comment |
Try this code :
"SELECT * FROM message JOIN answer ON message.id= answer.id WHERE message.message='".$inp."'";
Try this code :
"SELECT * FROM message JOIN answer ON message.id= answer.id WHERE message.message='".$inp."'";
answered Nov 23 '18 at 6:48
Bhoomi patelBhoomi patel
515220
515220
same output just 1 row. I want 2 row . thank you
– Rabib
Nov 23 '18 at 8:52
add a comment |
same output just 1 row. I want 2 row . thank you
– Rabib
Nov 23 '18 at 8:52
same output just 1 row. I want 2 row . thank you
– Rabib
Nov 23 '18 at 8:52
same output just 1 row. I want 2 row . thank you
– Rabib
Nov 23 '18 at 8:52
add a comment |
use common b/w each table in your case id so query should be..
SELECT * FROM message JOIN answer ON answer.id = message.id WHERE message = 'hi';
rest in php you should use different ways to run query like prepared statements in order to avoid sql injection or concatenate the variables
like
'SELECT * FROM message JOIN answer ON answer.id = message.id WHERE message = "'.$input.'"';
or mysqli_prepare() bind_params()
or learn using PDO which is good to avoid sql injections as well as supports multiple db drivers which make your work more dynamic and flexible.
thank you for your answer. but my expected output single time 2 results hello and hey. how can do this? any suggestions?
– Rabib
Nov 23 '18 at 8:58
1
it is giving you two answers for the message 'hi' isn't it ?? so all you need to do is loop through it using php.
– Akhilesh
Nov 23 '18 at 9:06
haha my code is working. but I forgotten to add while loop. thank you again
– Rabib
Nov 23 '18 at 10:08
add a comment |
use common b/w each table in your case id so query should be..
SELECT * FROM message JOIN answer ON answer.id = message.id WHERE message = 'hi';
rest in php you should use different ways to run query like prepared statements in order to avoid sql injection or concatenate the variables
like
'SELECT * FROM message JOIN answer ON answer.id = message.id WHERE message = "'.$input.'"';
or mysqli_prepare() bind_params()
or learn using PDO which is good to avoid sql injections as well as supports multiple db drivers which make your work more dynamic and flexible.
thank you for your answer. but my expected output single time 2 results hello and hey. how can do this? any suggestions?
– Rabib
Nov 23 '18 at 8:58
1
it is giving you two answers for the message 'hi' isn't it ?? so all you need to do is loop through it using php.
– Akhilesh
Nov 23 '18 at 9:06
haha my code is working. but I forgotten to add while loop. thank you again
– Rabib
Nov 23 '18 at 10:08
add a comment |
use common b/w each table in your case id so query should be..
SELECT * FROM message JOIN answer ON answer.id = message.id WHERE message = 'hi';
rest in php you should use different ways to run query like prepared statements in order to avoid sql injection or concatenate the variables
like
'SELECT * FROM message JOIN answer ON answer.id = message.id WHERE message = "'.$input.'"';
or mysqli_prepare() bind_params()
or learn using PDO which is good to avoid sql injections as well as supports multiple db drivers which make your work more dynamic and flexible.
use common b/w each table in your case id so query should be..
SELECT * FROM message JOIN answer ON answer.id = message.id WHERE message = 'hi';
rest in php you should use different ways to run query like prepared statements in order to avoid sql injection or concatenate the variables
like
'SELECT * FROM message JOIN answer ON answer.id = message.id WHERE message = "'.$input.'"';
or mysqli_prepare() bind_params()
or learn using PDO which is good to avoid sql injections as well as supports multiple db drivers which make your work more dynamic and flexible.
edited Nov 23 '18 at 6:47
answered Nov 23 '18 at 6:42
AkhileshAkhilesh
626
626
thank you for your answer. but my expected output single time 2 results hello and hey. how can do this? any suggestions?
– Rabib
Nov 23 '18 at 8:58
1
it is giving you two answers for the message 'hi' isn't it ?? so all you need to do is loop through it using php.
– Akhilesh
Nov 23 '18 at 9:06
haha my code is working. but I forgotten to add while loop. thank you again
– Rabib
Nov 23 '18 at 10:08
add a comment |
thank you for your answer. but my expected output single time 2 results hello and hey. how can do this? any suggestions?
– Rabib
Nov 23 '18 at 8:58
1
it is giving you two answers for the message 'hi' isn't it ?? so all you need to do is loop through it using php.
– Akhilesh
Nov 23 '18 at 9:06
haha my code is working. but I forgotten to add while loop. thank you again
– Rabib
Nov 23 '18 at 10:08
thank you for your answer. but my expected output single time 2 results hello and hey. how can do this? any suggestions?
– Rabib
Nov 23 '18 at 8:58
thank you for your answer. but my expected output single time 2 results hello and hey. how can do this? any suggestions?
– Rabib
Nov 23 '18 at 8:58
1
1
it is giving you two answers for the message 'hi' isn't it ?? so all you need to do is loop through it using php.
– Akhilesh
Nov 23 '18 at 9:06
it is giving you two answers for the message 'hi' isn't it ?? so all you need to do is loop through it using php.
– Akhilesh
Nov 23 '18 at 9:06
haha my code is working. but I forgotten to add while loop. thank you again
– Rabib
Nov 23 '18 at 10:08
haha my code is working. but I forgotten to add while loop. thank you again
– Rabib
Nov 23 '18 at 10:08
add a comment |
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1
Please share your latest code attempt; this would help us in pointing you to right direction.
– Madhur Bhaiya
Nov 23 '18 at 5:18
now may you can understand!
– Rabib
Nov 23 '18 at 5:25
2
SELECT * FROM answer JOIN message ON message.id= answer.id WHERE message='$inp'"
Any luck with this.– Prashant Deshmukh.....
Nov 23 '18 at 5:25
1
Always join using the appropriate relationships. As specified in previous comment, you should using
id
notmessage/answer
– Madhur Bhaiya
Nov 23 '18 at 5:28
1
Also, Your code is open to SQL injection related attacks. Please learn to use Prepared Statements
– Madhur Bhaiya
Nov 23 '18 at 5:28