What would be the right way to present business objects in the front end?












-1















There is a backend that returns list of persons.
It gets automatically mapped into collection of TypeScript busness object class (Person) objects using Angular/rxjs.



export class Person {
Id: string;
Name: string;
Age: number;
}


There is a need to display these entities in a list with an additional column, stating whether records are selected or not - required for further processing.



The question is - what would be the right way to do this?



Should I create a PersonModel class that inherits from Person and add additional field in there?



export class PersonModel extends Person {
Selected: boolean;
}


Or, should I ignore the fact that back-end has nothing to do with the Selected property and simply add the property to the Person class?



export class Person {
Id: string;
Name: string;
Age: number;
Selected: boolean;
}


Are there other, more proper ways of dealing with such situation?










share|improve this question


















  • 1





    Composition, perhaps, an object like { person: Person, selected: boolean }.

    – jonrsharpe
    Nov 22 '18 at 17:26






  • 1





    Create a PersonRow class/interface with a field person of type Person and a field selected of type boolean?

    – JB Nizet
    Nov 22 '18 at 17:26


















-1















There is a backend that returns list of persons.
It gets automatically mapped into collection of TypeScript busness object class (Person) objects using Angular/rxjs.



export class Person {
Id: string;
Name: string;
Age: number;
}


There is a need to display these entities in a list with an additional column, stating whether records are selected or not - required for further processing.



The question is - what would be the right way to do this?



Should I create a PersonModel class that inherits from Person and add additional field in there?



export class PersonModel extends Person {
Selected: boolean;
}


Or, should I ignore the fact that back-end has nothing to do with the Selected property and simply add the property to the Person class?



export class Person {
Id: string;
Name: string;
Age: number;
Selected: boolean;
}


Are there other, more proper ways of dealing with such situation?










share|improve this question


















  • 1





    Composition, perhaps, an object like { person: Person, selected: boolean }.

    – jonrsharpe
    Nov 22 '18 at 17:26






  • 1





    Create a PersonRow class/interface with a field person of type Person and a field selected of type boolean?

    – JB Nizet
    Nov 22 '18 at 17:26
















-1












-1








-1








There is a backend that returns list of persons.
It gets automatically mapped into collection of TypeScript busness object class (Person) objects using Angular/rxjs.



export class Person {
Id: string;
Name: string;
Age: number;
}


There is a need to display these entities in a list with an additional column, stating whether records are selected or not - required for further processing.



The question is - what would be the right way to do this?



Should I create a PersonModel class that inherits from Person and add additional field in there?



export class PersonModel extends Person {
Selected: boolean;
}


Or, should I ignore the fact that back-end has nothing to do with the Selected property and simply add the property to the Person class?



export class Person {
Id: string;
Name: string;
Age: number;
Selected: boolean;
}


Are there other, more proper ways of dealing with such situation?










share|improve this question














There is a backend that returns list of persons.
It gets automatically mapped into collection of TypeScript busness object class (Person) objects using Angular/rxjs.



export class Person {
Id: string;
Name: string;
Age: number;
}


There is a need to display these entities in a list with an additional column, stating whether records are selected or not - required for further processing.



The question is - what would be the right way to do this?



Should I create a PersonModel class that inherits from Person and add additional field in there?



export class PersonModel extends Person {
Selected: boolean;
}


Or, should I ignore the fact that back-end has nothing to do with the Selected property and simply add the property to the Person class?



export class Person {
Id: string;
Name: string;
Age: number;
Selected: boolean;
}


Are there other, more proper ways of dealing with such situation?







angular typescript architecture rxjs angular6






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asked Nov 22 '18 at 17:21









PatrykPatryk

1,12382967




1,12382967








  • 1





    Composition, perhaps, an object like { person: Person, selected: boolean }.

    – jonrsharpe
    Nov 22 '18 at 17:26






  • 1





    Create a PersonRow class/interface with a field person of type Person and a field selected of type boolean?

    – JB Nizet
    Nov 22 '18 at 17:26
















  • 1





    Composition, perhaps, an object like { person: Person, selected: boolean }.

    – jonrsharpe
    Nov 22 '18 at 17:26






  • 1





    Create a PersonRow class/interface with a field person of type Person and a field selected of type boolean?

    – JB Nizet
    Nov 22 '18 at 17:26










1




1





Composition, perhaps, an object like { person: Person, selected: boolean }.

– jonrsharpe
Nov 22 '18 at 17:26





Composition, perhaps, an object like { person: Person, selected: boolean }.

– jonrsharpe
Nov 22 '18 at 17:26




1




1





Create a PersonRow class/interface with a field person of type Person and a field selected of type boolean?

– JB Nizet
Nov 22 '18 at 17:26







Create a PersonRow class/interface with a field person of type Person and a field selected of type boolean?

– JB Nizet
Nov 22 '18 at 17:26














1 Answer
1






active

oldest

votes


















0














Instead of Class, You can create an interface which extends another interface.



export interface Person {
Id: string;
Name: string;
Age: number;
}

export interface PersonAttrib extends Person {
Selected: boolean;
}





share|improve this answer























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    0














    Instead of Class, You can create an interface which extends another interface.



    export interface Person {
    Id: string;
    Name: string;
    Age: number;
    }

    export interface PersonAttrib extends Person {
    Selected: boolean;
    }





    share|improve this answer




























      0














      Instead of Class, You can create an interface which extends another interface.



      export interface Person {
      Id: string;
      Name: string;
      Age: number;
      }

      export interface PersonAttrib extends Person {
      Selected: boolean;
      }





      share|improve this answer


























        0












        0








        0







        Instead of Class, You can create an interface which extends another interface.



        export interface Person {
        Id: string;
        Name: string;
        Age: number;
        }

        export interface PersonAttrib extends Person {
        Selected: boolean;
        }





        share|improve this answer













        Instead of Class, You can create an interface which extends another interface.



        export interface Person {
        Id: string;
        Name: string;
        Age: number;
        }

        export interface PersonAttrib extends Person {
        Selected: boolean;
        }






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 22 '18 at 17:37









        Suresh Kumar AriyaSuresh Kumar Ariya

        4,8591217




        4,8591217
































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