How can I group multiple columns into an object when making a database call in Laravel?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
0
Let's say I am fetching users
Each user has 10 columns associated with it
How can I group 5 columns together into an object on each user so I can more easily map over them with javascript?
I could do
foreach ($users as $user)
{
$user['new_object']['col_1'] = $user->col_1;
unset($user->col_1);
$user['new_object']['col_2'] = $user->col_2;
// etc
}
But surely there is a way to group columns into an object on Laravel?
For example, something like
$users = User::where('verified', 1)
->group('new_object', ['col_1', 'col_2', 'col_3']),
->get();
Or is there a way for me to update my User model to do this?
php mysql laravel eloquent
asked Nov 24 '18 at 21:32
DazzleDazzle
6792728
add a comment |
0
Let's say I am fetching users
Each user has 10 columns associated with it
How can I group 5 columns together into an object on each user so I can more easily map over them with javascript?
I could do
foreach ($users as $user)
{
$user['new_object']['col_1'] = $user->col_1;
unset($user->col_1);
$user['new_object']['col_2'] = $user->col_2;
// etc
}
But surely there is a way to group columns into an object on Laravel?
For example, something like
$users = User::where('verified', 1)
->group('new_object', ['col_1', 'col_2', 'col_3']),
->get();
Or is there a way for me to update my User model to do this?
php mysql laravel eloquent
asked Nov 24 '18 at 21:32
DazzleDazzle
6792728
Use collections to manipulate data within the PHP. Good Luck!
– Kyslik
Nov 24 '18 at 21:43
add a comment |
0
0
0
Let's say I am fetching users
Each user has 10 columns associated with it
How can I group 5 columns together into an object on each user so I can more easily map over them with javascript?
I could do
foreach ($users as $user)
{
$user['new_object']['col_1'] = $user->col_1;
unset($user->col_1);
$user['new_object']['col_2'] = $user->col_2;
// etc
}
But surely there is a way to group columns into an object on Laravel?
For example, something like
$users = User::where('verified', 1)
->group('new_object', ['col_1', 'col_2', 'col_3']),
->get();
Or is there a way for me to update my User model to do this?
php mysql laravel eloquent
asked Nov 24 '18 at 21:32
DazzleDazzle
6792728
Let's say I am fetching users
Each user has 10 columns associated with it
How can I group 5 columns together into an object on each user so I can more easily map over them with javascript?
I could do
foreach ($users as $user)
{
$user['new_object']['col_1'] = $user->col_1;
unset($user->col_1);
$user['new_object']['col_2'] = $user->col_2;
// etc
}
But surely there is a way to group columns into an object on Laravel?
For example, something like
$users = User::where('verified', 1)
->group('new_object', ['col_1', 'col_2', 'col_3']),
->get();
Or is there a way for me to update my User model to do this?
php mysql laravel eloquent
php mysql laravel eloquent
asked Nov 24 '18 at 21:32
DazzleDazzle
6792728
asked Nov 24 '18 at 21:32
DazzleDazzle
6792728
edited Nov 24 '18 at 23:14
Dazzle
asked Nov 24 '18 at 21:32
DazzleDazzle
6792728
asked Nov 24 '18 at 21:32
DazzleDazzle
6792728
asked Nov 24 '18 at 21:32
DazzleDazzle
6792728
6792728
Use collections to manipulate data within the PHP. Good Luck!
– Kyslik
Nov 24 '18 at 21:43
add a comment |
Use collections to manipulate data within the PHP. Good Luck!
– Kyslik
Nov 24 '18 at 21:43
Use collections to manipulate data within the PHP. Good Luck!
– Kyslik
Nov 24 '18 at 21:43
Use collections to manipulate data within the PHP. Good Luck!
– Kyslik
Nov 24 '18 at 21:43
add a comment |
2 Answers
2
active
oldest
votes
1
You can use mutators in your model:
public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}
And in $appends attribute inside that model:
protected $appends = [
'new_obj',
];
answered Nov 25 '18 at 8:42
Ali FarhoudiAli Farhoudi
1,08411334
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
1
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
add a comment |
2
you can do something like this:
$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});
answered Nov 24 '18 at 21:49
Eriks KlotinsEriks Klotins
1,4381618
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53462550%2fhow-can-i-group-multiple-columns-into-an-object-when-making-a-database-call-in-l%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You can use mutators in your model:
public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}
And in $appends attribute inside that model:
protected $appends = [
'new_obj',
];
answered Nov 25 '18 at 8:42
Ali FarhoudiAli Farhoudi
1,08411334
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
1
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
add a comment |
1
You can use mutators in your model:
public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}
And in $appends attribute inside that model:
protected $appends = [
'new_obj',
];
answered Nov 25 '18 at 8:42
Ali FarhoudiAli Farhoudi
1,08411334
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
1
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
add a comment |
1
1
1
You can use mutators in your model:
public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}
And in $appends attribute inside that model:
protected $appends = [
'new_obj',
];
answered Nov 25 '18 at 8:42
Ali FarhoudiAli Farhoudi
1,08411334
You can use mutators in your model:
public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}
And in $appends attribute inside that model:
protected $appends = [
'new_obj',
];
answered Nov 25 '18 at 8:42
Ali FarhoudiAli Farhoudi
1,08411334
answered Nov 25 '18 at 8:42
Ali FarhoudiAli Farhoudi
1,08411334
answered Nov 25 '18 at 8:42
Ali FarhoudiAli Farhoudi
1,08411334
answered Nov 25 '18 at 8:42
Ali FarhoudiAli Farhoudi
1,08411334
1,08411334
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
1
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
add a comment |
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
1
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
1
1
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
add a comment |
2
you can do something like this:
$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});
answered Nov 24 '18 at 21:49
Eriks KlotinsEriks Klotins
1,4381618
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
add a comment |
2
you can do something like this:
$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});
answered Nov 24 '18 at 21:49
Eriks KlotinsEriks Klotins
1,4381618
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
add a comment |
2
2
2
you can do something like this:
$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});
answered Nov 24 '18 at 21:49
Eriks KlotinsEriks Klotins
1,4381618
you can do something like this:
$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});
answered Nov 24 '18 at 21:49
Eriks KlotinsEriks Klotins
1,4381618
edited Nov 24 '18 at 22:00
answered Nov 24 '18 at 21:49
Eriks KlotinsEriks Klotins
1,4381618
answered Nov 24 '18 at 21:49
Eriks KlotinsEriks Klotins
1,4381618
answered Nov 24 '18 at 21:49
Eriks KlotinsEriks Klotins
1,4381618
1,4381618
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
add a comment |
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53462550%2fhow-can-i-group-multiple-columns-into-an-object-when-making-a-database-call-in-l%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Use collections to manipulate data within the PHP. Good Luck!
– Kyslik
Nov 24 '18 at 21:43