how to make dry contact with serial reading one time in every state in Arduino
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-1
I did this code and when button is released open message is in loop but when I press the button the "close" message keep no loop
how can I show "open" message one time not in loop...I mean when button release then the "open" message shows one time?
So when button is release will write "open" in serial , then when push the buton the write "close" in serial.
int Switch = 2;
int buttonState; // current state of the button
int lastButtonState = 1; // previous state of the button
void setup()
{
Serial.begin(9600);
pinMode(Switch, INPUT);
Serial.begin(9600);
}
void loop()
{
buttonState = digitalRead(Switch);
if (digitalRead(Switch) == LOW && buttonState == lastButtonState) {
Serial.println("Open");
delay(100);
}
if (digitalRead(Switch) == HIGH && buttonState != lastButtonState){
Serial.println("Close");
}
lastButtonState = buttonState;
}
arduino-uno
asked Nov 23 '18 at 16:18
Mohammad KhaledMohammad Khaled
58
add a comment |
-1
I did this code and when button is released open message is in loop but when I press the button the "close" message keep no loop
how can I show "open" message one time not in loop...I mean when button release then the "open" message shows one time?
So when button is release will write "open" in serial , then when push the buton the write "close" in serial.
int Switch = 2;
int buttonState; // current state of the button
int lastButtonState = 1; // previous state of the button
void setup()
{
Serial.begin(9600);
pinMode(Switch, INPUT);
Serial.begin(9600);
}
void loop()
{
buttonState = digitalRead(Switch);
if (digitalRead(Switch) == LOW && buttonState == lastButtonState) {
Serial.println("Open");
delay(100);
}
if (digitalRead(Switch) == HIGH && buttonState != lastButtonState){
Serial.println("Close");
}
lastButtonState = buttonState;
}
arduino-uno
asked Nov 23 '18 at 16:18
Mohammad KhaledMohammad Khaled
58
add a comment |
-1
-1
-1
I did this code and when button is released open message is in loop but when I press the button the "close" message keep no loop
how can I show "open" message one time not in loop...I mean when button release then the "open" message shows one time?
So when button is release will write "open" in serial , then when push the buton the write "close" in serial.
int Switch = 2;
int buttonState; // current state of the button
int lastButtonState = 1; // previous state of the button
void setup()
{
Serial.begin(9600);
pinMode(Switch, INPUT);
Serial.begin(9600);
}
void loop()
{
buttonState = digitalRead(Switch);
if (digitalRead(Switch) == LOW && buttonState == lastButtonState) {
Serial.println("Open");
delay(100);
}
if (digitalRead(Switch) == HIGH && buttonState != lastButtonState){
Serial.println("Close");
}
lastButtonState = buttonState;
}
arduino-uno
asked Nov 23 '18 at 16:18
Mohammad KhaledMohammad Khaled
58
I did this code and when button is released open message is in loop but when I press the button the "close" message keep no loop
how can I show "open" message one time not in loop...I mean when button release then the "open" message shows one time?
So when button is release will write "open" in serial , then when push the buton the write "close" in serial.
int Switch = 2;
int buttonState; // current state of the button
int lastButtonState = 1; // previous state of the button
void setup()
{
Serial.begin(9600);
pinMode(Switch, INPUT);
Serial.begin(9600);
}
void loop()
{
buttonState = digitalRead(Switch);
if (digitalRead(Switch) == LOW && buttonState == lastButtonState) {
Serial.println("Open");
delay(100);
}
if (digitalRead(Switch) == HIGH && buttonState != lastButtonState){
Serial.println("Close");
}
lastButtonState = buttonState;
}
arduino-uno
arduino-uno
asked Nov 23 '18 at 16:18
Mohammad KhaledMohammad Khaled
58
asked Nov 23 '18 at 16:18
Mohammad KhaledMohammad Khaled
58
asked Nov 23 '18 at 16:18
Mohammad KhaledMohammad Khaled
58
asked Nov 23 '18 at 16:18
Mohammad KhaledMohammad Khaled
58
asked Nov 23 '18 at 16:18
Mohammad KhaledMohammad Khaled
58
58
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
0
use a flag instead of lastButtonState!
for example:
int flag=0; //global
void loop(){
if(digitalRead(Switch) == LOW && flag==0){
flag=1;
}
else if(digitalRead(Switch)==HIGH && flag ==0){
flag=2;
}
if(flag==1){
//print whatever you want
flag=0;
}
else if(flag==2){
//print the second case
flag=0;
}}
Also, it is not a good practice to read the button state like that. Because buttons will be pressed Async to the system and you should denounce them.
if(digitalRead(SWITCH)==LOW){
delay(40);
if(digitalRead(SWITCH)==LOW)
changeButtonState();
}
answered Nov 23 '18 at 22:46
TheEngineerTheEngineer
373111
I tried Flag, and gave me boncing loop between "open" and "close" and when press the button gave me "close" in loop!
– Mohammad Khaled
Nov 24 '18 at 6:23
add a comment |
0
I got what I want from the code like this:
int Switch = 2; //Pin for sensor switch
int buttonState; // current state of the button
int lastButtonState = 0; // previous state of the button
void setup()
{
Serial.begin(9600);
pinMode(Switch, INPUT);
Serial.begin(9600);
}
void loop()
{
buttonState = digitalRead(Switch);
if (digitalRead(Switch) == HIGH && buttonState != lastButtonState) {
Serial.println("open");
delay(180);
}
lastButtonState = buttonState;
if (digitalRead(Switch) == LOW && buttonState == 1){
Serial.println("Close");
delay(200);
}
}
answered Nov 24 '18 at 9:43
Mohammad KhaledMohammad Khaled
58
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
use a flag instead of lastButtonState!
for example:
int flag=0; //global
void loop(){
if(digitalRead(Switch) == LOW && flag==0){
flag=1;
}
else if(digitalRead(Switch)==HIGH && flag ==0){
flag=2;
}
if(flag==1){
//print whatever you want
flag=0;
}
else if(flag==2){
//print the second case
flag=0;
}}
Also, it is not a good practice to read the button state like that. Because buttons will be pressed Async to the system and you should denounce them.
if(digitalRead(SWITCH)==LOW){
delay(40);
if(digitalRead(SWITCH)==LOW)
changeButtonState();
}
answered Nov 23 '18 at 22:46
TheEngineerTheEngineer
373111
I tried Flag, and gave me boncing loop between "open" and "close" and when press the button gave me "close" in loop!
– Mohammad Khaled
Nov 24 '18 at 6:23
add a comment |
0
use a flag instead of lastButtonState!
for example:
int flag=0; //global
void loop(){
if(digitalRead(Switch) == LOW && flag==0){
flag=1;
}
else if(digitalRead(Switch)==HIGH && flag ==0){
flag=2;
}
if(flag==1){
//print whatever you want
flag=0;
}
else if(flag==2){
//print the second case
flag=0;
}}
Also, it is not a good practice to read the button state like that. Because buttons will be pressed Async to the system and you should denounce them.
if(digitalRead(SWITCH)==LOW){
delay(40);
if(digitalRead(SWITCH)==LOW)
changeButtonState();
}
answered Nov 23 '18 at 22:46
TheEngineerTheEngineer
373111
I tried Flag, and gave me boncing loop between "open" and "close" and when press the button gave me "close" in loop!
– Mohammad Khaled
Nov 24 '18 at 6:23
add a comment |
0
0
0
use a flag instead of lastButtonState!
for example:
int flag=0; //global
void loop(){
if(digitalRead(Switch) == LOW && flag==0){
flag=1;
}
else if(digitalRead(Switch)==HIGH && flag ==0){
flag=2;
}
if(flag==1){
//print whatever you want
flag=0;
}
else if(flag==2){
//print the second case
flag=0;
}}
Also, it is not a good practice to read the button state like that. Because buttons will be pressed Async to the system and you should denounce them.
if(digitalRead(SWITCH)==LOW){
delay(40);
if(digitalRead(SWITCH)==LOW)
changeButtonState();
}
answered Nov 23 '18 at 22:46
TheEngineerTheEngineer
373111
use a flag instead of lastButtonState!
for example:
int flag=0; //global
void loop(){
if(digitalRead(Switch) == LOW && flag==0){
flag=1;
}
else if(digitalRead(Switch)==HIGH && flag ==0){
flag=2;
}
if(flag==1){
//print whatever you want
flag=0;
}
else if(flag==2){
//print the second case
flag=0;
}}
Also, it is not a good practice to read the button state like that. Because buttons will be pressed Async to the system and you should denounce them.
if(digitalRead(SWITCH)==LOW){
delay(40);
if(digitalRead(SWITCH)==LOW)
changeButtonState();
}
answered Nov 23 '18 at 22:46
TheEngineerTheEngineer
373111
answered Nov 23 '18 at 22:46
TheEngineerTheEngineer
373111
answered Nov 23 '18 at 22:46
TheEngineerTheEngineer
373111
answered Nov 23 '18 at 22:46
TheEngineerTheEngineer
373111
373111
I tried Flag, and gave me boncing loop between "open" and "close" and when press the button gave me "close" in loop!
– Mohammad Khaled
Nov 24 '18 at 6:23
add a comment |
I tried Flag, and gave me boncing loop between "open" and "close" and when press the button gave me "close" in loop!
– Mohammad Khaled
Nov 24 '18 at 6:23
I tried Flag, and gave me boncing loop between "open" and "close" and when press the button gave me "close" in loop!
– Mohammad Khaled
Nov 24 '18 at 6:23
I tried Flag, and gave me boncing loop between "open" and "close" and when press the button gave me "close" in loop!
– Mohammad Khaled
Nov 24 '18 at 6:23
add a comment |
0
I got what I want from the code like this:
int Switch = 2; //Pin for sensor switch
int buttonState; // current state of the button
int lastButtonState = 0; // previous state of the button
void setup()
{
Serial.begin(9600);
pinMode(Switch, INPUT);
Serial.begin(9600);
}
void loop()
{
buttonState = digitalRead(Switch);
if (digitalRead(Switch) == HIGH && buttonState != lastButtonState) {
Serial.println("open");
delay(180);
}
lastButtonState = buttonState;
if (digitalRead(Switch) == LOW && buttonState == 1){
Serial.println("Close");
delay(200);
}
}
answered Nov 24 '18 at 9:43
Mohammad KhaledMohammad Khaled
58
add a comment |
0
I got what I want from the code like this:
int Switch = 2; //Pin for sensor switch
int buttonState; // current state of the button
int lastButtonState = 0; // previous state of the button
void setup()
{
Serial.begin(9600);
pinMode(Switch, INPUT);
Serial.begin(9600);
}
void loop()
{
buttonState = digitalRead(Switch);
if (digitalRead(Switch) == HIGH && buttonState != lastButtonState) {
Serial.println("open");
delay(180);
}
lastButtonState = buttonState;
if (digitalRead(Switch) == LOW && buttonState == 1){
Serial.println("Close");
delay(200);
}
}
answered Nov 24 '18 at 9:43
Mohammad KhaledMohammad Khaled
58
add a comment |
0
0
0
I got what I want from the code like this:
int Switch = 2; //Pin for sensor switch
int buttonState; // current state of the button
int lastButtonState = 0; // previous state of the button
void setup()
{
Serial.begin(9600);
pinMode(Switch, INPUT);
Serial.begin(9600);
}
void loop()
{
buttonState = digitalRead(Switch);
if (digitalRead(Switch) == HIGH && buttonState != lastButtonState) {
Serial.println("open");
delay(180);
}
lastButtonState = buttonState;
if (digitalRead(Switch) == LOW && buttonState == 1){
Serial.println("Close");
delay(200);
}
}
answered Nov 24 '18 at 9:43
Mohammad KhaledMohammad Khaled
58
I got what I want from the code like this:
int Switch = 2; //Pin for sensor switch
int buttonState; // current state of the button
int lastButtonState = 0; // previous state of the button
void setup()
{
Serial.begin(9600);
pinMode(Switch, INPUT);
Serial.begin(9600);
}
void loop()
{
buttonState = digitalRead(Switch);
if (digitalRead(Switch) == HIGH && buttonState != lastButtonState) {
Serial.println("open");
delay(180);
}
lastButtonState = buttonState;
if (digitalRead(Switch) == LOW && buttonState == 1){
Serial.println("Close");
delay(200);
}
}
answered Nov 24 '18 at 9:43
Mohammad KhaledMohammad Khaled
58
answered Nov 24 '18 at 9:43
Mohammad KhaledMohammad Khaled
58
answered Nov 24 '18 at 9:43
Mohammad KhaledMohammad Khaled
58
answered Nov 24 '18 at 9:43
Mohammad KhaledMohammad Khaled
58
58
add a comment |
add a comment |
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