Java dynamic array sizes?
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I have a class - xClass, that I want to load into an array of xClass so I the declaration:
xClass mysclass = new xClass[10];
myclass[0] = new xClass();
myclass[9] = new xClass();
However, I don't know if I will need 10. I may need 8 or 12 or any other number for that matter. I won't know until runtime.
Can I change the number of elements in an array on the fly?
If so, how?
java
add a comment |
I have a class - xClass, that I want to load into an array of xClass so I the declaration:
xClass mysclass = new xClass[10];
myclass[0] = new xClass();
myclass[9] = new xClass();
However, I don't know if I will need 10. I may need 8 or 12 or any other number for that matter. I won't know until runtime.
Can I change the number of elements in an array on the fly?
If so, how?
java
I fixed up the formatting of the question, you can just the title if you want, just be descriptive. and welcome to stackoverflow! :D
– Gordon Gustafson
Oct 30 '09 at 0:05
add a comment |
I have a class - xClass, that I want to load into an array of xClass so I the declaration:
xClass mysclass = new xClass[10];
myclass[0] = new xClass();
myclass[9] = new xClass();
However, I don't know if I will need 10. I may need 8 or 12 or any other number for that matter. I won't know until runtime.
Can I change the number of elements in an array on the fly?
If so, how?
java
I have a class - xClass, that I want to load into an array of xClass so I the declaration:
xClass mysclass = new xClass[10];
myclass[0] = new xClass();
myclass[9] = new xClass();
However, I don't know if I will need 10. I may need 8 or 12 or any other number for that matter. I won't know until runtime.
Can I change the number of elements in an array on the fly?
If so, how?
java
java
edited Mar 3 '17 at 21:46
Donnied
58542446
58542446
asked Oct 30 '09 at 0:00
PaulPaul
465265
465265
I fixed up the formatting of the question, you can just the title if you want, just be descriptive. and welcome to stackoverflow! :D
– Gordon Gustafson
Oct 30 '09 at 0:05
add a comment |
I fixed up the formatting of the question, you can just the title if you want, just be descriptive. and welcome to stackoverflow! :D
– Gordon Gustafson
Oct 30 '09 at 0:05
I fixed up the formatting of the question, you can just the title if you want, just be descriptive. and welcome to stackoverflow! :D
– Gordon Gustafson
Oct 30 '09 at 0:05
I fixed up the formatting of the question, you can just the title if you want, just be descriptive. and welcome to stackoverflow! :D
– Gordon Gustafson
Oct 30 '09 at 0:05
add a comment |
18 Answers
18
active
oldest
votes
No you can't change the size of an array once created. You either have to allocate it bigger than you think you'll need or accept the overhead of having to reallocate it needs to grow in size. When it does you'll have to allocate a new one and copy the data from the old to the new:
int oldItems = new int[10];
for (int i=0; i<10; i++) {
oldItems[i] = i+10;
}
int newItems = new int[20];
System.arraycopy(oldItems, 0, newItems, 0, 10);
oldItems = newItems;
If you find yourself in this situation, I'd highly recommend using the Java Collections instead. In particular ArrayList essentially wraps an array and takes care of the logic for growing the array as required:
List<xClass> mysclass = new ArrayList<xClass>();
myclass.add(new xClass());
myclass.add(new xClass());
Generally an ArrayList is a preferable solution to an array anyway for several reasons. For one thing, arrays are mutable. If you have a class that does this:
class Myclass {
private int items;
public int getItems() { return items; }
}
you've created a problem as a caller can change your private data member, which leads to all sorts of defensive copying. Compare this to the List version:
class Myclass {
private List<Integer> items;
public List<Integer> getItems() { return Collections.unmodifiableList(items); }
}
2
I use ArrayList instead of List and everything works fine.
– ConductedClever
Aug 17 '14 at 18:11
List is the interface and ArrayList is the implementation. Creating it as an ArrayList but referring to it as a List (so it can change later) is correct.
– CBGraham
Sep 24 '18 at 16:25
add a comment |
In java array length is fixed.
You can use a List to hold the values and invoke the toArray method if needed
See the following sample:
import java.util.List;
import java.util.ArrayList;
import java.util.Random;
public class A {
public static void main( String args ) {
// dynamically hold the instances
List<xClass> list = new ArrayList<xClass>();
// fill it with a random number between 0 and 100
int elements = new Random().nextInt(100);
for( int i = 0 ; i < elements ; i++ ) {
list.add( new xClass() );
}
// convert it to array
xClass array = list.toArray( new xClass[ list.size() ] );
System.out.println( "size of array = " + array.length );
}
}
class xClass {}
add a comment |
As others have said, you cannot change the size of an existing Java array.
ArrayList is the closest that standard Java has to a dynamic sized array. However, there are some things about ArrayList (actually the List interface) that are not "array like". For example:
- You cannot use
[ ... ]to index a list. You have to use theget(int)andset(int, E)methods. - An ArrayList is created with zero elements. You cannot simple create an ArrayList with 20 elements and then call
set(15, foo). - You cannot directly change the size of an ArrayList. You do it indirectly using the various
add,insertandremovemethods.
If you want something more array-like, you will need to design your own API. (Maybe someone could chime in with an existing third party library ... I couldn't find one with 2 minutes "research" using Google :-) )
If you only really need an array that grows as you are initializing it, then the solution is something like this.
ArrayList<T> tmp = new ArrayList<T>();
while (...) {
tmp.add(new T(...));
}
// This creates a new array and copies the element of 'tmp' to it.
T array = tmp.toArray(new T[tmp.size()]);
add a comment |
You set the number of elements to anything you want at the time you create it:
xClass mysclass = new xClass[n];
Then you can initialize the elements in a loop. I am guessing that this is what you need.
If you need to add or remove elements to the array after you create it, then you would have to use an ArrayList.
add a comment |
You can use ArrayList:
import java.util.ArrayList;
import java.util.Iterator;
...
ArrayList<String> arr = new ArrayList<String>();
arr.add("neo");
arr.add("morpheus");
arr.add("trinity");
Iterator<String> foreach = arr.iterator();
while (foreach.hasNext()) System.out.println(foreach.next());
add a comment |
Arrays.copyOf() method has many options to fix the problem with Array length increasing dynamically.
Java API
To be specific: if (i >= mysclass.length) mysclass = Arrays.copyOf(mysclass, i+1); mysclass[i] = new MyClass();
– Micha Berger
Aug 30 '17 at 20:39
add a comment |
Yes, wrap it and use the Collections framework.
List l = new ArrayList();
l.add(new xClass());
// do stuff
l.add(new xClass());
Then use List.toArray() when necessary, or just iterate over said List.
add a comment |
As other users say, you probably need an implementation of java.util.List.
If, for some reason, you finally need an array, you can do two things:
Use a List and then convert it to an array with myList.toArray()
Use an array of certain size. If you need more or less size, you can modify it with java.util.Arrays methods.
Best solution will depend on your problem ;)
add a comment |
I recommend using vectors instead. Very easy to use and has many predefined methods for implementation.
import java.util.*;
Vector<Integer> v=new Vector<Integer>(5,2);
to add an element simply use:
v.addElement(int);
In the (5,2) the first 5 is the initial size of the vector. If you exceed the initial size,the vector will grow by 2 places. If it exceeds again, then it will again increase by 2 places and so on.
4
Unless you specifically need a thread-safe (-ish) type, you should use ArrayList rather than Vector.
– Stephen C
Nov 27 '12 at 13:07
add a comment |
Where you declare the myclass array as :
xClass myclass = new xClass[10]
, simply pass in as an argument the number of XClass elements you'll need. At that point do you know how many you will need? By declaring the array as having 10 elements, you are not declaring 10 XClass objects, you're simply creating an array with 10 elements of type xClass.
add a comment |
It is a good practice get the amount you need to store first then initialize the array.
for example, you would ask the user how many data he need to store and then initialize it, or query the component or argument of how many you need to store.
if you want a dynamic array you could use ArrayList() and use al.add(); function to keep adding, then you can transfer it to a fixed array.
//Initialize ArrayList and cast string so ArrayList accepts strings (or anything
ArrayList<string> al = new ArrayList();
//add a certain amount of data
for(int i=0;i<x;i++)
{
al.add("data "+i);
}
//get size of data inside
int size = al.size();
//initialize String array with the size you have
String strArray = new String[size];
//insert data from ArrayList to String array
for(int i=0;i<size;i++)
{
strArray[i] = al.get(i);
}
doing so is redundant but just to show you the idea, ArrayList can hold objects unlike other primitive data types and are very easy to manipulate, removing anything from the middle is easy as well, completely dynamic.same with List and Stack
add a comment |
Java Array sizes are fixed , You cannot make dynamic Arrays as that of in C++.
add a comment |
I don't know if you can change the size at runtime but you can allocate the size at runtime. Try using this code:
class MyClass {
void myFunction () {
Scanner s = new Scanner (System.in);
int myArray ;
int x;
System.out.print ("Enter the size of the array: ");
x = s.nextInt();
myArray = new int[x];
}
}
this assigns your array size to be the one entered at run time into x.
add a comment |
Here's a method that doesn't use ArrayList. The user specifies the size and you can add a do-while loop for recursion.
import java.util.Scanner;
public class Dynamic {
public static Scanner value;
public static void main(Stringargs){
value=new Scanner(System.in);
System.out.println("Enter the number of tests to calculate averagen");
int limit=value.nextInt();
int index=0;
int marks=new int[limit];
float sum,ave;
sum=0;
while(index<limit)
{
int test=index+1;
System.out.println("Enter the marks on test " +test);
marks[index]=value.nextInt();
sum+=marks[index];
index++;
}
ave=sum/limit;
System.out.println("The average is: " + ave);
}
}
add a comment |
In Java Array Sizes are always of Fixed Length But there is way in which you can Dynamically increase the Size of the Array at Runtime Itself
This is the most "used" as well as preferred way to do it-
int temp=new int[stck.length+1];
for(int i=0;i<stck.length;i++)temp[i]=stck[i];
stck=temp;
In the above code we are initializing a new temp array, and further using a for loop to initialize the contents of the temp with the contents of the original array ie. stck. And then again copying it back to the original one, giving us a new array of new SIZE.
No doubt it generates a CPU Overhead due to reinitializing an array using for loop repeatedly. But you can still use and implement it in your code.
For the best practice use "Linked List" instead of Array, if you want the data to be stored dynamically in the memory, of variable length.
Here's a Real-Time Example based on Dynamic Stacks to INCREASE ARRAY SIZE at Run-Time
File-name: DStack.java
public class DStack {
private int stck;
int tos;
void Init_Stck(int size) {
stck=new int[size];
tos=-1;
}
int Change_Stck(int size){
return stck[size];
}
public void push(int item){
if(tos==stck.length-1){
int temp=new int[stck.length+1];
for(int i=0;i<stck.length;i++)temp[i]=stck[i];
stck=temp;
stck[++tos]=item;
}
else
stck[++tos]=item;
}
public int pop(){
if(tos<0){
System.out.println("Stack Underflow");
return 0;
}
else return stck[tos--];
}
public void display(){
for(int x=0;x<stck.length;x++){
System.out.print(stck[x]+" ");
}
System.out.println();
}
}
File-name: Exec.java
(with the main class)
import java.util.*;
public class Exec {
private static Scanner in;
public static void main(String args) {
in = new Scanner(System.in);
int option,item,i=1;
DStack obj=new DStack();
obj.Init_Stck(1);
do{
System.out.println();
System.out.println("--MENU--");
System.out.println("1. Push a Value in The Stack");
System.out.println("2. Pop a Value from the Stack");
System.out.println("3. Display Stack");
System.out.println("4. Exit");
option=in.nextInt();
switch(option){
case 1:
System.out.println("Enter the Value to be Pushed");
item=in.nextInt();
obj.push(item);
break;
case 2:
System.out.println("Popped Item: "+obj.pop());
obj.Change_Stck(obj.tos);
break;
case 3:
System.out.println("Displaying...");
obj.display();
break;
case 4:
System.out.println("Exiting...");
i=0;
break;
default:
System.out.println("Enter a Valid Value");
}
}while(i==1);
}
}
Hope this solves your query.
add a comment |
Yes, we can do this way.
import java.util.Scanner;
public class Collection_Basic {
private static Scanner sc;
public static void main(String args) {
Object obj=new Object[4];
sc = new Scanner(System.in);
//Storing element
System.out.println("enter your element");
for(int i=0;i<4;i++){
obj[i]=sc.nextInt();
}
/*
* here, size reaches with its maximum capacity so u can not store more element,
*
* for storing more element we have to create new array Object with required size
*/
Object tempObj=new Object[10];
//copying old array to new Array
int oldArraySize=obj.length;
int i=0;
for(;i<oldArraySize;i++){
tempObj[i]=obj[i];
}
/*
* storing new element to the end of new Array objebt
*/
tempObj[i]=90;
//assigning new array Object refeence to the old one
obj=tempObj;
for(int j=0;j<obj.length;j++){
System.out.println("obj["+j+"] -"+obj[j]);
}
}
}
add a comment |
Since ArrayList takes to much memory when I need array of primitive types, I prefer using IntStream.builder() for creating int array (You can also use LongStream and DoubleStream builders).
Example:
Builder builder = IntStream.builder();
int arraySize = new Random().nextInt();
for(int i = 0; i<arraySize; i++ ) {
builder.add(i);
}
int array = builder.build().toArray();
Note: available since Java 8.
add a comment |
You can do some thing
private static Person addPersons(Person persons, Person personToAdd) {
int currentLenght = persons.length;
Person personsArrayNew = Arrays.copyOf(persons, currentLenght +1);
personsArrayNew[currentLenght] = personToAdd;
return personsArrayNew;
}
add a comment |
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18 Answers
18
active
oldest
votes
18 Answers
18
active
oldest
votes
active
oldest
votes
active
oldest
votes
No you can't change the size of an array once created. You either have to allocate it bigger than you think you'll need or accept the overhead of having to reallocate it needs to grow in size. When it does you'll have to allocate a new one and copy the data from the old to the new:
int oldItems = new int[10];
for (int i=0; i<10; i++) {
oldItems[i] = i+10;
}
int newItems = new int[20];
System.arraycopy(oldItems, 0, newItems, 0, 10);
oldItems = newItems;
If you find yourself in this situation, I'd highly recommend using the Java Collections instead. In particular ArrayList essentially wraps an array and takes care of the logic for growing the array as required:
List<xClass> mysclass = new ArrayList<xClass>();
myclass.add(new xClass());
myclass.add(new xClass());
Generally an ArrayList is a preferable solution to an array anyway for several reasons. For one thing, arrays are mutable. If you have a class that does this:
class Myclass {
private int items;
public int getItems() { return items; }
}
you've created a problem as a caller can change your private data member, which leads to all sorts of defensive copying. Compare this to the List version:
class Myclass {
private List<Integer> items;
public List<Integer> getItems() { return Collections.unmodifiableList(items); }
}
2
I use ArrayList instead of List and everything works fine.
– ConductedClever
Aug 17 '14 at 18:11
List is the interface and ArrayList is the implementation. Creating it as an ArrayList but referring to it as a List (so it can change later) is correct.
– CBGraham
Sep 24 '18 at 16:25
add a comment |
No you can't change the size of an array once created. You either have to allocate it bigger than you think you'll need or accept the overhead of having to reallocate it needs to grow in size. When it does you'll have to allocate a new one and copy the data from the old to the new:
int oldItems = new int[10];
for (int i=0; i<10; i++) {
oldItems[i] = i+10;
}
int newItems = new int[20];
System.arraycopy(oldItems, 0, newItems, 0, 10);
oldItems = newItems;
If you find yourself in this situation, I'd highly recommend using the Java Collections instead. In particular ArrayList essentially wraps an array and takes care of the logic for growing the array as required:
List<xClass> mysclass = new ArrayList<xClass>();
myclass.add(new xClass());
myclass.add(new xClass());
Generally an ArrayList is a preferable solution to an array anyway for several reasons. For one thing, arrays are mutable. If you have a class that does this:
class Myclass {
private int items;
public int getItems() { return items; }
}
you've created a problem as a caller can change your private data member, which leads to all sorts of defensive copying. Compare this to the List version:
class Myclass {
private List<Integer> items;
public List<Integer> getItems() { return Collections.unmodifiableList(items); }
}
2
I use ArrayList instead of List and everything works fine.
– ConductedClever
Aug 17 '14 at 18:11
List is the interface and ArrayList is the implementation. Creating it as an ArrayList but referring to it as a List (so it can change later) is correct.
– CBGraham
Sep 24 '18 at 16:25
add a comment |
No you can't change the size of an array once created. You either have to allocate it bigger than you think you'll need or accept the overhead of having to reallocate it needs to grow in size. When it does you'll have to allocate a new one and copy the data from the old to the new:
int oldItems = new int[10];
for (int i=0; i<10; i++) {
oldItems[i] = i+10;
}
int newItems = new int[20];
System.arraycopy(oldItems, 0, newItems, 0, 10);
oldItems = newItems;
If you find yourself in this situation, I'd highly recommend using the Java Collections instead. In particular ArrayList essentially wraps an array and takes care of the logic for growing the array as required:
List<xClass> mysclass = new ArrayList<xClass>();
myclass.add(new xClass());
myclass.add(new xClass());
Generally an ArrayList is a preferable solution to an array anyway for several reasons. For one thing, arrays are mutable. If you have a class that does this:
class Myclass {
private int items;
public int getItems() { return items; }
}
you've created a problem as a caller can change your private data member, which leads to all sorts of defensive copying. Compare this to the List version:
class Myclass {
private List<Integer> items;
public List<Integer> getItems() { return Collections.unmodifiableList(items); }
}
No you can't change the size of an array once created. You either have to allocate it bigger than you think you'll need or accept the overhead of having to reallocate it needs to grow in size. When it does you'll have to allocate a new one and copy the data from the old to the new:
int oldItems = new int[10];
for (int i=0; i<10; i++) {
oldItems[i] = i+10;
}
int newItems = new int[20];
System.arraycopy(oldItems, 0, newItems, 0, 10);
oldItems = newItems;
If you find yourself in this situation, I'd highly recommend using the Java Collections instead. In particular ArrayList essentially wraps an array and takes care of the logic for growing the array as required:
List<xClass> mysclass = new ArrayList<xClass>();
myclass.add(new xClass());
myclass.add(new xClass());
Generally an ArrayList is a preferable solution to an array anyway for several reasons. For one thing, arrays are mutable. If you have a class that does this:
class Myclass {
private int items;
public int getItems() { return items; }
}
you've created a problem as a caller can change your private data member, which leads to all sorts of defensive copying. Compare this to the List version:
class Myclass {
private List<Integer> items;
public List<Integer> getItems() { return Collections.unmodifiableList(items); }
}
edited Jan 18 '15 at 17:58
JasonMArcher
9,442104849
9,442104849
answered Oct 30 '09 at 0:05
cletuscletus
512k141843914
512k141843914
2
I use ArrayList instead of List and everything works fine.
– ConductedClever
Aug 17 '14 at 18:11
List is the interface and ArrayList is the implementation. Creating it as an ArrayList but referring to it as a List (so it can change later) is correct.
– CBGraham
Sep 24 '18 at 16:25
add a comment |
2
I use ArrayList instead of List and everything works fine.
– ConductedClever
Aug 17 '14 at 18:11
List is the interface and ArrayList is the implementation. Creating it as an ArrayList but referring to it as a List (so it can change later) is correct.
– CBGraham
Sep 24 '18 at 16:25
2
2
I use ArrayList instead of List and everything works fine.
– ConductedClever
Aug 17 '14 at 18:11
I use ArrayList instead of List and everything works fine.
– ConductedClever
Aug 17 '14 at 18:11
List is the interface and ArrayList is the implementation. Creating it as an ArrayList but referring to it as a List (so it can change later) is correct.
– CBGraham
Sep 24 '18 at 16:25
List is the interface and ArrayList is the implementation. Creating it as an ArrayList but referring to it as a List (so it can change later) is correct.
– CBGraham
Sep 24 '18 at 16:25
add a comment |
In java array length is fixed.
You can use a List to hold the values and invoke the toArray method if needed
See the following sample:
import java.util.List;
import java.util.ArrayList;
import java.util.Random;
public class A {
public static void main( String args ) {
// dynamically hold the instances
List<xClass> list = new ArrayList<xClass>();
// fill it with a random number between 0 and 100
int elements = new Random().nextInt(100);
for( int i = 0 ; i < elements ; i++ ) {
list.add( new xClass() );
}
// convert it to array
xClass array = list.toArray( new xClass[ list.size() ] );
System.out.println( "size of array = " + array.length );
}
}
class xClass {}
add a comment |
In java array length is fixed.
You can use a List to hold the values and invoke the toArray method if needed
See the following sample:
import java.util.List;
import java.util.ArrayList;
import java.util.Random;
public class A {
public static void main( String args ) {
// dynamically hold the instances
List<xClass> list = new ArrayList<xClass>();
// fill it with a random number between 0 and 100
int elements = new Random().nextInt(100);
for( int i = 0 ; i < elements ; i++ ) {
list.add( new xClass() );
}
// convert it to array
xClass array = list.toArray( new xClass[ list.size() ] );
System.out.println( "size of array = " + array.length );
}
}
class xClass {}
add a comment |
In java array length is fixed.
You can use a List to hold the values and invoke the toArray method if needed
See the following sample:
import java.util.List;
import java.util.ArrayList;
import java.util.Random;
public class A {
public static void main( String args ) {
// dynamically hold the instances
List<xClass> list = new ArrayList<xClass>();
// fill it with a random number between 0 and 100
int elements = new Random().nextInt(100);
for( int i = 0 ; i < elements ; i++ ) {
list.add( new xClass() );
}
// convert it to array
xClass array = list.toArray( new xClass[ list.size() ] );
System.out.println( "size of array = " + array.length );
}
}
class xClass {}
In java array length is fixed.
You can use a List to hold the values and invoke the toArray method if needed
See the following sample:
import java.util.List;
import java.util.ArrayList;
import java.util.Random;
public class A {
public static void main( String args ) {
// dynamically hold the instances
List<xClass> list = new ArrayList<xClass>();
// fill it with a random number between 0 and 100
int elements = new Random().nextInt(100);
for( int i = 0 ; i < elements ; i++ ) {
list.add( new xClass() );
}
// convert it to array
xClass array = list.toArray( new xClass[ list.size() ] );
System.out.println( "size of array = " + array.length );
}
}
class xClass {}
answered Oct 30 '09 at 0:45
OscarRyzOscarRyz
144k99340518
144k99340518
add a comment |
add a comment |
As others have said, you cannot change the size of an existing Java array.
ArrayList is the closest that standard Java has to a dynamic sized array. However, there are some things about ArrayList (actually the List interface) that are not "array like". For example:
- You cannot use
[ ... ]to index a list. You have to use theget(int)andset(int, E)methods. - An ArrayList is created with zero elements. You cannot simple create an ArrayList with 20 elements and then call
set(15, foo). - You cannot directly change the size of an ArrayList. You do it indirectly using the various
add,insertandremovemethods.
If you want something more array-like, you will need to design your own API. (Maybe someone could chime in with an existing third party library ... I couldn't find one with 2 minutes "research" using Google :-) )
If you only really need an array that grows as you are initializing it, then the solution is something like this.
ArrayList<T> tmp = new ArrayList<T>();
while (...) {
tmp.add(new T(...));
}
// This creates a new array and copies the element of 'tmp' to it.
T array = tmp.toArray(new T[tmp.size()]);
add a comment |
As others have said, you cannot change the size of an existing Java array.
ArrayList is the closest that standard Java has to a dynamic sized array. However, there are some things about ArrayList (actually the List interface) that are not "array like". For example:
- You cannot use
[ ... ]to index a list. You have to use theget(int)andset(int, E)methods. - An ArrayList is created with zero elements. You cannot simple create an ArrayList with 20 elements and then call
set(15, foo). - You cannot directly change the size of an ArrayList. You do it indirectly using the various
add,insertandremovemethods.
If you want something more array-like, you will need to design your own API. (Maybe someone could chime in with an existing third party library ... I couldn't find one with 2 minutes "research" using Google :-) )
If you only really need an array that grows as you are initializing it, then the solution is something like this.
ArrayList<T> tmp = new ArrayList<T>();
while (...) {
tmp.add(new T(...));
}
// This creates a new array and copies the element of 'tmp' to it.
T array = tmp.toArray(new T[tmp.size()]);
add a comment |
As others have said, you cannot change the size of an existing Java array.
ArrayList is the closest that standard Java has to a dynamic sized array. However, there are some things about ArrayList (actually the List interface) that are not "array like". For example:
- You cannot use
[ ... ]to index a list. You have to use theget(int)andset(int, E)methods. - An ArrayList is created with zero elements. You cannot simple create an ArrayList with 20 elements and then call
set(15, foo). - You cannot directly change the size of an ArrayList. You do it indirectly using the various
add,insertandremovemethods.
If you want something more array-like, you will need to design your own API. (Maybe someone could chime in with an existing third party library ... I couldn't find one with 2 minutes "research" using Google :-) )
If you only really need an array that grows as you are initializing it, then the solution is something like this.
ArrayList<T> tmp = new ArrayList<T>();
while (...) {
tmp.add(new T(...));
}
// This creates a new array and copies the element of 'tmp' to it.
T array = tmp.toArray(new T[tmp.size()]);
As others have said, you cannot change the size of an existing Java array.
ArrayList is the closest that standard Java has to a dynamic sized array. However, there are some things about ArrayList (actually the List interface) that are not "array like". For example:
- You cannot use
[ ... ]to index a list. You have to use theget(int)andset(int, E)methods. - An ArrayList is created with zero elements. You cannot simple create an ArrayList with 20 elements and then call
set(15, foo). - You cannot directly change the size of an ArrayList. You do it indirectly using the various
add,insertandremovemethods.
If you want something more array-like, you will need to design your own API. (Maybe someone could chime in with an existing third party library ... I couldn't find one with 2 minutes "research" using Google :-) )
If you only really need an array that grows as you are initializing it, then the solution is something like this.
ArrayList<T> tmp = new ArrayList<T>();
while (...) {
tmp.add(new T(...));
}
// This creates a new array and copies the element of 'tmp' to it.
T array = tmp.toArray(new T[tmp.size()]);
edited Oct 30 '09 at 0:44
answered Oct 30 '09 at 0:30
Stephen CStephen C
526k72586944
526k72586944
add a comment |
add a comment |
You set the number of elements to anything you want at the time you create it:
xClass mysclass = new xClass[n];
Then you can initialize the elements in a loop. I am guessing that this is what you need.
If you need to add or remove elements to the array after you create it, then you would have to use an ArrayList.
add a comment |
You set the number of elements to anything you want at the time you create it:
xClass mysclass = new xClass[n];
Then you can initialize the elements in a loop. I am guessing that this is what you need.
If you need to add or remove elements to the array after you create it, then you would have to use an ArrayList.
add a comment |
You set the number of elements to anything you want at the time you create it:
xClass mysclass = new xClass[n];
Then you can initialize the elements in a loop. I am guessing that this is what you need.
If you need to add or remove elements to the array after you create it, then you would have to use an ArrayList.
You set the number of elements to anything you want at the time you create it:
xClass mysclass = new xClass[n];
Then you can initialize the elements in a loop. I am guessing that this is what you need.
If you need to add or remove elements to the array after you create it, then you would have to use an ArrayList.
answered Oct 30 '09 at 0:04
newacctnewacct
96k23135197
96k23135197
add a comment |
add a comment |
You can use ArrayList:
import java.util.ArrayList;
import java.util.Iterator;
...
ArrayList<String> arr = new ArrayList<String>();
arr.add("neo");
arr.add("morpheus");
arr.add("trinity");
Iterator<String> foreach = arr.iterator();
while (foreach.hasNext()) System.out.println(foreach.next());
add a comment |
You can use ArrayList:
import java.util.ArrayList;
import java.util.Iterator;
...
ArrayList<String> arr = new ArrayList<String>();
arr.add("neo");
arr.add("morpheus");
arr.add("trinity");
Iterator<String> foreach = arr.iterator();
while (foreach.hasNext()) System.out.println(foreach.next());
add a comment |
You can use ArrayList:
import java.util.ArrayList;
import java.util.Iterator;
...
ArrayList<String> arr = new ArrayList<String>();
arr.add("neo");
arr.add("morpheus");
arr.add("trinity");
Iterator<String> foreach = arr.iterator();
while (foreach.hasNext()) System.out.println(foreach.next());
You can use ArrayList:
import java.util.ArrayList;
import java.util.Iterator;
...
ArrayList<String> arr = new ArrayList<String>();
arr.add("neo");
arr.add("morpheus");
arr.add("trinity");
Iterator<String> foreach = arr.iterator();
while (foreach.hasNext()) System.out.println(foreach.next());
answered Dec 18 '13 at 4:28
Pascal9xPascal9x
17123
17123
add a comment |
add a comment |
Arrays.copyOf() method has many options to fix the problem with Array length increasing dynamically.
Java API
To be specific: if (i >= mysclass.length) mysclass = Arrays.copyOf(mysclass, i+1); mysclass[i] = new MyClass();
– Micha Berger
Aug 30 '17 at 20:39
add a comment |
Arrays.copyOf() method has many options to fix the problem with Array length increasing dynamically.
Java API
To be specific: if (i >= mysclass.length) mysclass = Arrays.copyOf(mysclass, i+1); mysclass[i] = new MyClass();
– Micha Berger
Aug 30 '17 at 20:39
add a comment |
Arrays.copyOf() method has many options to fix the problem with Array length increasing dynamically.
Java API
Arrays.copyOf() method has many options to fix the problem with Array length increasing dynamically.
Java API
edited Feb 10 '17 at 1:31
chancyWu
8,44794767
8,44794767
answered Apr 15 '13 at 2:54
man.2067067man.2067067
10011
10011
To be specific: if (i >= mysclass.length) mysclass = Arrays.copyOf(mysclass, i+1); mysclass[i] = new MyClass();
– Micha Berger
Aug 30 '17 at 20:39
add a comment |
To be specific: if (i >= mysclass.length) mysclass = Arrays.copyOf(mysclass, i+1); mysclass[i] = new MyClass();
– Micha Berger
Aug 30 '17 at 20:39
To be specific: if (i >= mysclass.length) mysclass = Arrays.copyOf(mysclass, i+1); mysclass[i] = new MyClass();
– Micha Berger
Aug 30 '17 at 20:39
To be specific: if (i >= mysclass.length) mysclass = Arrays.copyOf(mysclass, i+1); mysclass[i] = new MyClass();
– Micha Berger
Aug 30 '17 at 20:39
add a comment |
Yes, wrap it and use the Collections framework.
List l = new ArrayList();
l.add(new xClass());
// do stuff
l.add(new xClass());
Then use List.toArray() when necessary, or just iterate over said List.
add a comment |
Yes, wrap it and use the Collections framework.
List l = new ArrayList();
l.add(new xClass());
// do stuff
l.add(new xClass());
Then use List.toArray() when necessary, or just iterate over said List.
add a comment |
Yes, wrap it and use the Collections framework.
List l = new ArrayList();
l.add(new xClass());
// do stuff
l.add(new xClass());
Then use List.toArray() when necessary, or just iterate over said List.
Yes, wrap it and use the Collections framework.
List l = new ArrayList();
l.add(new xClass());
// do stuff
l.add(new xClass());
Then use List.toArray() when necessary, or just iterate over said List.
answered Oct 30 '09 at 0:11
Jé QueueJé Queue
6,496104356
6,496104356
add a comment |
add a comment |
As other users say, you probably need an implementation of java.util.List.
If, for some reason, you finally need an array, you can do two things:
Use a List and then convert it to an array with myList.toArray()
Use an array of certain size. If you need more or less size, you can modify it with java.util.Arrays methods.
Best solution will depend on your problem ;)
add a comment |
As other users say, you probably need an implementation of java.util.List.
If, for some reason, you finally need an array, you can do two things:
Use a List and then convert it to an array with myList.toArray()
Use an array of certain size. If you need more or less size, you can modify it with java.util.Arrays methods.
Best solution will depend on your problem ;)
add a comment |
As other users say, you probably need an implementation of java.util.List.
If, for some reason, you finally need an array, you can do two things:
Use a List and then convert it to an array with myList.toArray()
Use an array of certain size. If you need more or less size, you can modify it with java.util.Arrays methods.
Best solution will depend on your problem ;)
As other users say, you probably need an implementation of java.util.List.
If, for some reason, you finally need an array, you can do two things:
Use a List and then convert it to an array with myList.toArray()
Use an array of certain size. If you need more or less size, you can modify it with java.util.Arrays methods.
Best solution will depend on your problem ;)
answered Oct 30 '09 at 0:59
sinuhepopsinuhepop
13.4k135793
13.4k135793
add a comment |
add a comment |
I recommend using vectors instead. Very easy to use and has many predefined methods for implementation.
import java.util.*;
Vector<Integer> v=new Vector<Integer>(5,2);
to add an element simply use:
v.addElement(int);
In the (5,2) the first 5 is the initial size of the vector. If you exceed the initial size,the vector will grow by 2 places. If it exceeds again, then it will again increase by 2 places and so on.
4
Unless you specifically need a thread-safe (-ish) type, you should use ArrayList rather than Vector.
– Stephen C
Nov 27 '12 at 13:07
add a comment |
I recommend using vectors instead. Very easy to use and has many predefined methods for implementation.
import java.util.*;
Vector<Integer> v=new Vector<Integer>(5,2);
to add an element simply use:
v.addElement(int);
In the (5,2) the first 5 is the initial size of the vector. If you exceed the initial size,the vector will grow by 2 places. If it exceeds again, then it will again increase by 2 places and so on.
4
Unless you specifically need a thread-safe (-ish) type, you should use ArrayList rather than Vector.
– Stephen C
Nov 27 '12 at 13:07
add a comment |
I recommend using vectors instead. Very easy to use and has many predefined methods for implementation.
import java.util.*;
Vector<Integer> v=new Vector<Integer>(5,2);
to add an element simply use:
v.addElement(int);
In the (5,2) the first 5 is the initial size of the vector. If you exceed the initial size,the vector will grow by 2 places. If it exceeds again, then it will again increase by 2 places and so on.
I recommend using vectors instead. Very easy to use and has many predefined methods for implementation.
import java.util.*;
Vector<Integer> v=new Vector<Integer>(5,2);
to add an element simply use:
v.addElement(int);
In the (5,2) the first 5 is the initial size of the vector. If you exceed the initial size,the vector will grow by 2 places. If it exceeds again, then it will again increase by 2 places and so on.
edited Oct 4 '12 at 7:23
Jav_Rock
17.3k18104160
17.3k18104160
answered Sep 4 '12 at 18:55
Shashank RaghunathShashank Raghunath
11413
11413
4
Unless you specifically need a thread-safe (-ish) type, you should use ArrayList rather than Vector.
– Stephen C
Nov 27 '12 at 13:07
add a comment |
4
Unless you specifically need a thread-safe (-ish) type, you should use ArrayList rather than Vector.
– Stephen C
Nov 27 '12 at 13:07
4
4
Unless you specifically need a thread-safe (-ish) type, you should use ArrayList rather than Vector.
– Stephen C
Nov 27 '12 at 13:07
Unless you specifically need a thread-safe (-ish) type, you should use ArrayList rather than Vector.
– Stephen C
Nov 27 '12 at 13:07
add a comment |
Where you declare the myclass array as :
xClass myclass = new xClass[10]
, simply pass in as an argument the number of XClass elements you'll need. At that point do you know how many you will need? By declaring the array as having 10 elements, you are not declaring 10 XClass objects, you're simply creating an array with 10 elements of type xClass.
add a comment |
Where you declare the myclass array as :
xClass myclass = new xClass[10]
, simply pass in as an argument the number of XClass elements you'll need. At that point do you know how many you will need? By declaring the array as having 10 elements, you are not declaring 10 XClass objects, you're simply creating an array with 10 elements of type xClass.
add a comment |
Where you declare the myclass array as :
xClass myclass = new xClass[10]
, simply pass in as an argument the number of XClass elements you'll need. At that point do you know how many you will need? By declaring the array as having 10 elements, you are not declaring 10 XClass objects, you're simply creating an array with 10 elements of type xClass.
Where you declare the myclass array as :
xClass myclass = new xClass[10]
, simply pass in as an argument the number of XClass elements you'll need. At that point do you know how many you will need? By declaring the array as having 10 elements, you are not declaring 10 XClass objects, you're simply creating an array with 10 elements of type xClass.
answered Oct 30 '09 at 0:05
Amir AfghaniAmir Afghani
29.2k1571114
29.2k1571114
add a comment |
add a comment |
It is a good practice get the amount you need to store first then initialize the array.
for example, you would ask the user how many data he need to store and then initialize it, or query the component or argument of how many you need to store.
if you want a dynamic array you could use ArrayList() and use al.add(); function to keep adding, then you can transfer it to a fixed array.
//Initialize ArrayList and cast string so ArrayList accepts strings (or anything
ArrayList<string> al = new ArrayList();
//add a certain amount of data
for(int i=0;i<x;i++)
{
al.add("data "+i);
}
//get size of data inside
int size = al.size();
//initialize String array with the size you have
String strArray = new String[size];
//insert data from ArrayList to String array
for(int i=0;i<size;i++)
{
strArray[i] = al.get(i);
}
doing so is redundant but just to show you the idea, ArrayList can hold objects unlike other primitive data types and are very easy to manipulate, removing anything from the middle is easy as well, completely dynamic.same with List and Stack
add a comment |
It is a good practice get the amount you need to store first then initialize the array.
for example, you would ask the user how many data he need to store and then initialize it, or query the component or argument of how many you need to store.
if you want a dynamic array you could use ArrayList() and use al.add(); function to keep adding, then you can transfer it to a fixed array.
//Initialize ArrayList and cast string so ArrayList accepts strings (or anything
ArrayList<string> al = new ArrayList();
//add a certain amount of data
for(int i=0;i<x;i++)
{
al.add("data "+i);
}
//get size of data inside
int size = al.size();
//initialize String array with the size you have
String strArray = new String[size];
//insert data from ArrayList to String array
for(int i=0;i<size;i++)
{
strArray[i] = al.get(i);
}
doing so is redundant but just to show you the idea, ArrayList can hold objects unlike other primitive data types and are very easy to manipulate, removing anything from the middle is easy as well, completely dynamic.same with List and Stack
add a comment |
It is a good practice get the amount you need to store first then initialize the array.
for example, you would ask the user how many data he need to store and then initialize it, or query the component or argument of how many you need to store.
if you want a dynamic array you could use ArrayList() and use al.add(); function to keep adding, then you can transfer it to a fixed array.
//Initialize ArrayList and cast string so ArrayList accepts strings (or anything
ArrayList<string> al = new ArrayList();
//add a certain amount of data
for(int i=0;i<x;i++)
{
al.add("data "+i);
}
//get size of data inside
int size = al.size();
//initialize String array with the size you have
String strArray = new String[size];
//insert data from ArrayList to String array
for(int i=0;i<size;i++)
{
strArray[i] = al.get(i);
}
doing so is redundant but just to show you the idea, ArrayList can hold objects unlike other primitive data types and are very easy to manipulate, removing anything from the middle is easy as well, completely dynamic.same with List and Stack
It is a good practice get the amount you need to store first then initialize the array.
for example, you would ask the user how many data he need to store and then initialize it, or query the component or argument of how many you need to store.
if you want a dynamic array you could use ArrayList() and use al.add(); function to keep adding, then you can transfer it to a fixed array.
//Initialize ArrayList and cast string so ArrayList accepts strings (or anything
ArrayList<string> al = new ArrayList();
//add a certain amount of data
for(int i=0;i<x;i++)
{
al.add("data "+i);
}
//get size of data inside
int size = al.size();
//initialize String array with the size you have
String strArray = new String[size];
//insert data from ArrayList to String array
for(int i=0;i<size;i++)
{
strArray[i] = al.get(i);
}
doing so is redundant but just to show you the idea, ArrayList can hold objects unlike other primitive data types and are very easy to manipulate, removing anything from the middle is easy as well, completely dynamic.same with List and Stack
edited Dec 6 '15 at 20:19
Mi-Creativity
8,215102943
8,215102943
answered Dec 6 '15 at 20:02
bakzbakz
688
688
add a comment |
add a comment |
Java Array sizes are fixed , You cannot make dynamic Arrays as that of in C++.
add a comment |
Java Array sizes are fixed , You cannot make dynamic Arrays as that of in C++.
add a comment |
Java Array sizes are fixed , You cannot make dynamic Arrays as that of in C++.
Java Array sizes are fixed , You cannot make dynamic Arrays as that of in C++.
answered Dec 12 '15 at 3:25
user5096772
add a comment |
add a comment |
I don't know if you can change the size at runtime but you can allocate the size at runtime. Try using this code:
class MyClass {
void myFunction () {
Scanner s = new Scanner (System.in);
int myArray ;
int x;
System.out.print ("Enter the size of the array: ");
x = s.nextInt();
myArray = new int[x];
}
}
this assigns your array size to be the one entered at run time into x.
add a comment |
I don't know if you can change the size at runtime but you can allocate the size at runtime. Try using this code:
class MyClass {
void myFunction () {
Scanner s = new Scanner (System.in);
int myArray ;
int x;
System.out.print ("Enter the size of the array: ");
x = s.nextInt();
myArray = new int[x];
}
}
this assigns your array size to be the one entered at run time into x.
add a comment |
I don't know if you can change the size at runtime but you can allocate the size at runtime. Try using this code:
class MyClass {
void myFunction () {
Scanner s = new Scanner (System.in);
int myArray ;
int x;
System.out.print ("Enter the size of the array: ");
x = s.nextInt();
myArray = new int[x];
}
}
this assigns your array size to be the one entered at run time into x.
I don't know if you can change the size at runtime but you can allocate the size at runtime. Try using this code:
class MyClass {
void myFunction () {
Scanner s = new Scanner (System.in);
int myArray ;
int x;
System.out.print ("Enter the size of the array: ");
x = s.nextInt();
myArray = new int[x];
}
}
this assigns your array size to be the one entered at run time into x.
edited Jul 3 '16 at 7:22
The F
2,93211225
2,93211225
answered Jul 3 '16 at 5:15
MaranathaMaranatha
1
1
add a comment |
add a comment |
Here's a method that doesn't use ArrayList. The user specifies the size and you can add a do-while loop for recursion.
import java.util.Scanner;
public class Dynamic {
public static Scanner value;
public static void main(Stringargs){
value=new Scanner(System.in);
System.out.println("Enter the number of tests to calculate averagen");
int limit=value.nextInt();
int index=0;
int marks=new int[limit];
float sum,ave;
sum=0;
while(index<limit)
{
int test=index+1;
System.out.println("Enter the marks on test " +test);
marks[index]=value.nextInt();
sum+=marks[index];
index++;
}
ave=sum/limit;
System.out.println("The average is: " + ave);
}
}
add a comment |
Here's a method that doesn't use ArrayList. The user specifies the size and you can add a do-while loop for recursion.
import java.util.Scanner;
public class Dynamic {
public static Scanner value;
public static void main(Stringargs){
value=new Scanner(System.in);
System.out.println("Enter the number of tests to calculate averagen");
int limit=value.nextInt();
int index=0;
int marks=new int[limit];
float sum,ave;
sum=0;
while(index<limit)
{
int test=index+1;
System.out.println("Enter the marks on test " +test);
marks[index]=value.nextInt();
sum+=marks[index];
index++;
}
ave=sum/limit;
System.out.println("The average is: " + ave);
}
}
add a comment |
Here's a method that doesn't use ArrayList. The user specifies the size and you can add a do-while loop for recursion.
import java.util.Scanner;
public class Dynamic {
public static Scanner value;
public static void main(Stringargs){
value=new Scanner(System.in);
System.out.println("Enter the number of tests to calculate averagen");
int limit=value.nextInt();
int index=0;
int marks=new int[limit];
float sum,ave;
sum=0;
while(index<limit)
{
int test=index+1;
System.out.println("Enter the marks on test " +test);
marks[index]=value.nextInt();
sum+=marks[index];
index++;
}
ave=sum/limit;
System.out.println("The average is: " + ave);
}
}
Here's a method that doesn't use ArrayList. The user specifies the size and you can add a do-while loop for recursion.
import java.util.Scanner;
public class Dynamic {
public static Scanner value;
public static void main(Stringargs){
value=new Scanner(System.in);
System.out.println("Enter the number of tests to calculate averagen");
int limit=value.nextInt();
int index=0;
int marks=new int[limit];
float sum,ave;
sum=0;
while(index<limit)
{
int test=index+1;
System.out.println("Enter the marks on test " +test);
marks[index]=value.nextInt();
sum+=marks[index];
index++;
}
ave=sum/limit;
System.out.println("The average is: " + ave);
}
}
answered Nov 26 '16 at 7:07
wallace_stevwallace_stev
1
1
add a comment |
add a comment |
In Java Array Sizes are always of Fixed Length But there is way in which you can Dynamically increase the Size of the Array at Runtime Itself
This is the most "used" as well as preferred way to do it-
int temp=new int[stck.length+1];
for(int i=0;i<stck.length;i++)temp[i]=stck[i];
stck=temp;
In the above code we are initializing a new temp array, and further using a for loop to initialize the contents of the temp with the contents of the original array ie. stck. And then again copying it back to the original one, giving us a new array of new SIZE.
No doubt it generates a CPU Overhead due to reinitializing an array using for loop repeatedly. But you can still use and implement it in your code.
For the best practice use "Linked List" instead of Array, if you want the data to be stored dynamically in the memory, of variable length.
Here's a Real-Time Example based on Dynamic Stacks to INCREASE ARRAY SIZE at Run-Time
File-name: DStack.java
public class DStack {
private int stck;
int tos;
void Init_Stck(int size) {
stck=new int[size];
tos=-1;
}
int Change_Stck(int size){
return stck[size];
}
public void push(int item){
if(tos==stck.length-1){
int temp=new int[stck.length+1];
for(int i=0;i<stck.length;i++)temp[i]=stck[i];
stck=temp;
stck[++tos]=item;
}
else
stck[++tos]=item;
}
public int pop(){
if(tos<0){
System.out.println("Stack Underflow");
return 0;
}
else return stck[tos--];
}
public void display(){
for(int x=0;x<stck.length;x++){
System.out.print(stck[x]+" ");
}
System.out.println();
}
}
File-name: Exec.java
(with the main class)
import java.util.*;
public class Exec {
private static Scanner in;
public static void main(String args) {
in = new Scanner(System.in);
int option,item,i=1;
DStack obj=new DStack();
obj.Init_Stck(1);
do{
System.out.println();
System.out.println("--MENU--");
System.out.println("1. Push a Value in The Stack");
System.out.println("2. Pop a Value from the Stack");
System.out.println("3. Display Stack");
System.out.println("4. Exit");
option=in.nextInt();
switch(option){
case 1:
System.out.println("Enter the Value to be Pushed");
item=in.nextInt();
obj.push(item);
break;
case 2:
System.out.println("Popped Item: "+obj.pop());
obj.Change_Stck(obj.tos);
break;
case 3:
System.out.println("Displaying...");
obj.display();
break;
case 4:
System.out.println("Exiting...");
i=0;
break;
default:
System.out.println("Enter a Valid Value");
}
}while(i==1);
}
}
Hope this solves your query.
add a comment |
In Java Array Sizes are always of Fixed Length But there is way in which you can Dynamically increase the Size of the Array at Runtime Itself
This is the most "used" as well as preferred way to do it-
int temp=new int[stck.length+1];
for(int i=0;i<stck.length;i++)temp[i]=stck[i];
stck=temp;
In the above code we are initializing a new temp array, and further using a for loop to initialize the contents of the temp with the contents of the original array ie. stck. And then again copying it back to the original one, giving us a new array of new SIZE.
No doubt it generates a CPU Overhead due to reinitializing an array using for loop repeatedly. But you can still use and implement it in your code.
For the best practice use "Linked List" instead of Array, if you want the data to be stored dynamically in the memory, of variable length.
Here's a Real-Time Example based on Dynamic Stacks to INCREASE ARRAY SIZE at Run-Time
File-name: DStack.java
public class DStack {
private int stck;
int tos;
void Init_Stck(int size) {
stck=new int[size];
tos=-1;
}
int Change_Stck(int size){
return stck[size];
}
public void push(int item){
if(tos==stck.length-1){
int temp=new int[stck.length+1];
for(int i=0;i<stck.length;i++)temp[i]=stck[i];
stck=temp;
stck[++tos]=item;
}
else
stck[++tos]=item;
}
public int pop(){
if(tos<0){
System.out.println("Stack Underflow");
return 0;
}
else return stck[tos--];
}
public void display(){
for(int x=0;x<stck.length;x++){
System.out.print(stck[x]+" ");
}
System.out.println();
}
}
File-name: Exec.java
(with the main class)
import java.util.*;
public class Exec {
private static Scanner in;
public static void main(String args) {
in = new Scanner(System.in);
int option,item,i=1;
DStack obj=new DStack();
obj.Init_Stck(1);
do{
System.out.println();
System.out.println("--MENU--");
System.out.println("1. Push a Value in The Stack");
System.out.println("2. Pop a Value from the Stack");
System.out.println("3. Display Stack");
System.out.println("4. Exit");
option=in.nextInt();
switch(option){
case 1:
System.out.println("Enter the Value to be Pushed");
item=in.nextInt();
obj.push(item);
break;
case 2:
System.out.println("Popped Item: "+obj.pop());
obj.Change_Stck(obj.tos);
break;
case 3:
System.out.println("Displaying...");
obj.display();
break;
case 4:
System.out.println("Exiting...");
i=0;
break;
default:
System.out.println("Enter a Valid Value");
}
}while(i==1);
}
}
Hope this solves your query.
add a comment |
In Java Array Sizes are always of Fixed Length But there is way in which you can Dynamically increase the Size of the Array at Runtime Itself
This is the most "used" as well as preferred way to do it-
int temp=new int[stck.length+1];
for(int i=0;i<stck.length;i++)temp[i]=stck[i];
stck=temp;
In the above code we are initializing a new temp array, and further using a for loop to initialize the contents of the temp with the contents of the original array ie. stck. And then again copying it back to the original one, giving us a new array of new SIZE.
No doubt it generates a CPU Overhead due to reinitializing an array using for loop repeatedly. But you can still use and implement it in your code.
For the best practice use "Linked List" instead of Array, if you want the data to be stored dynamically in the memory, of variable length.
Here's a Real-Time Example based on Dynamic Stacks to INCREASE ARRAY SIZE at Run-Time
File-name: DStack.java
public class DStack {
private int stck;
int tos;
void Init_Stck(int size) {
stck=new int[size];
tos=-1;
}
int Change_Stck(int size){
return stck[size];
}
public void push(int item){
if(tos==stck.length-1){
int temp=new int[stck.length+1];
for(int i=0;i<stck.length;i++)temp[i]=stck[i];
stck=temp;
stck[++tos]=item;
}
else
stck[++tos]=item;
}
public int pop(){
if(tos<0){
System.out.println("Stack Underflow");
return 0;
}
else return stck[tos--];
}
public void display(){
for(int x=0;x<stck.length;x++){
System.out.print(stck[x]+" ");
}
System.out.println();
}
}
File-name: Exec.java
(with the main class)
import java.util.*;
public class Exec {
private static Scanner in;
public static void main(String args) {
in = new Scanner(System.in);
int option,item,i=1;
DStack obj=new DStack();
obj.Init_Stck(1);
do{
System.out.println();
System.out.println("--MENU--");
System.out.println("1. Push a Value in The Stack");
System.out.println("2. Pop a Value from the Stack");
System.out.println("3. Display Stack");
System.out.println("4. Exit");
option=in.nextInt();
switch(option){
case 1:
System.out.println("Enter the Value to be Pushed");
item=in.nextInt();
obj.push(item);
break;
case 2:
System.out.println("Popped Item: "+obj.pop());
obj.Change_Stck(obj.tos);
break;
case 3:
System.out.println("Displaying...");
obj.display();
break;
case 4:
System.out.println("Exiting...");
i=0;
break;
default:
System.out.println("Enter a Valid Value");
}
}while(i==1);
}
}
Hope this solves your query.
In Java Array Sizes are always of Fixed Length But there is way in which you can Dynamically increase the Size of the Array at Runtime Itself
This is the most "used" as well as preferred way to do it-
int temp=new int[stck.length+1];
for(int i=0;i<stck.length;i++)temp[i]=stck[i];
stck=temp;
In the above code we are initializing a new temp array, and further using a for loop to initialize the contents of the temp with the contents of the original array ie. stck. And then again copying it back to the original one, giving us a new array of new SIZE.
No doubt it generates a CPU Overhead due to reinitializing an array using for loop repeatedly. But you can still use and implement it in your code.
For the best practice use "Linked List" instead of Array, if you want the data to be stored dynamically in the memory, of variable length.
Here's a Real-Time Example based on Dynamic Stacks to INCREASE ARRAY SIZE at Run-Time
File-name: DStack.java
public class DStack {
private int stck;
int tos;
void Init_Stck(int size) {
stck=new int[size];
tos=-1;
}
int Change_Stck(int size){
return stck[size];
}
public void push(int item){
if(tos==stck.length-1){
int temp=new int[stck.length+1];
for(int i=0;i<stck.length;i++)temp[i]=stck[i];
stck=temp;
stck[++tos]=item;
}
else
stck[++tos]=item;
}
public int pop(){
if(tos<0){
System.out.println("Stack Underflow");
return 0;
}
else return stck[tos--];
}
public void display(){
for(int x=0;x<stck.length;x++){
System.out.print(stck[x]+" ");
}
System.out.println();
}
}
File-name: Exec.java
(with the main class)
import java.util.*;
public class Exec {
private static Scanner in;
public static void main(String args) {
in = new Scanner(System.in);
int option,item,i=1;
DStack obj=new DStack();
obj.Init_Stck(1);
do{
System.out.println();
System.out.println("--MENU--");
System.out.println("1. Push a Value in The Stack");
System.out.println("2. Pop a Value from the Stack");
System.out.println("3. Display Stack");
System.out.println("4. Exit");
option=in.nextInt();
switch(option){
case 1:
System.out.println("Enter the Value to be Pushed");
item=in.nextInt();
obj.push(item);
break;
case 2:
System.out.println("Popped Item: "+obj.pop());
obj.Change_Stck(obj.tos);
break;
case 3:
System.out.println("Displaying...");
obj.display();
break;
case 4:
System.out.println("Exiting...");
i=0;
break;
default:
System.out.println("Enter a Valid Value");
}
}while(i==1);
}
}
Hope this solves your query.
answered Feb 1 '17 at 0:57
Jatin ChauhanJatin Chauhan
113
113
add a comment |
add a comment |
Yes, we can do this way.
import java.util.Scanner;
public class Collection_Basic {
private static Scanner sc;
public static void main(String args) {
Object obj=new Object[4];
sc = new Scanner(System.in);
//Storing element
System.out.println("enter your element");
for(int i=0;i<4;i++){
obj[i]=sc.nextInt();
}
/*
* here, size reaches with its maximum capacity so u can not store more element,
*
* for storing more element we have to create new array Object with required size
*/
Object tempObj=new Object[10];
//copying old array to new Array
int oldArraySize=obj.length;
int i=0;
for(;i<oldArraySize;i++){
tempObj[i]=obj[i];
}
/*
* storing new element to the end of new Array objebt
*/
tempObj[i]=90;
//assigning new array Object refeence to the old one
obj=tempObj;
for(int j=0;j<obj.length;j++){
System.out.println("obj["+j+"] -"+obj[j]);
}
}
}
add a comment |
Yes, we can do this way.
import java.util.Scanner;
public class Collection_Basic {
private static Scanner sc;
public static void main(String args) {
Object obj=new Object[4];
sc = new Scanner(System.in);
//Storing element
System.out.println("enter your element");
for(int i=0;i<4;i++){
obj[i]=sc.nextInt();
}
/*
* here, size reaches with its maximum capacity so u can not store more element,
*
* for storing more element we have to create new array Object with required size
*/
Object tempObj=new Object[10];
//copying old array to new Array
int oldArraySize=obj.length;
int i=0;
for(;i<oldArraySize;i++){
tempObj[i]=obj[i];
}
/*
* storing new element to the end of new Array objebt
*/
tempObj[i]=90;
//assigning new array Object refeence to the old one
obj=tempObj;
for(int j=0;j<obj.length;j++){
System.out.println("obj["+j+"] -"+obj[j]);
}
}
}
add a comment |
Yes, we can do this way.
import java.util.Scanner;
public class Collection_Basic {
private static Scanner sc;
public static void main(String args) {
Object obj=new Object[4];
sc = new Scanner(System.in);
//Storing element
System.out.println("enter your element");
for(int i=0;i<4;i++){
obj[i]=sc.nextInt();
}
/*
* here, size reaches with its maximum capacity so u can not store more element,
*
* for storing more element we have to create new array Object with required size
*/
Object tempObj=new Object[10];
//copying old array to new Array
int oldArraySize=obj.length;
int i=0;
for(;i<oldArraySize;i++){
tempObj[i]=obj[i];
}
/*
* storing new element to the end of new Array objebt
*/
tempObj[i]=90;
//assigning new array Object refeence to the old one
obj=tempObj;
for(int j=0;j<obj.length;j++){
System.out.println("obj["+j+"] -"+obj[j]);
}
}
}
Yes, we can do this way.
import java.util.Scanner;
public class Collection_Basic {
private static Scanner sc;
public static void main(String args) {
Object obj=new Object[4];
sc = new Scanner(System.in);
//Storing element
System.out.println("enter your element");
for(int i=0;i<4;i++){
obj[i]=sc.nextInt();
}
/*
* here, size reaches with its maximum capacity so u can not store more element,
*
* for storing more element we have to create new array Object with required size
*/
Object tempObj=new Object[10];
//copying old array to new Array
int oldArraySize=obj.length;
int i=0;
for(;i<oldArraySize;i++){
tempObj[i]=obj[i];
}
/*
* storing new element to the end of new Array objebt
*/
tempObj[i]=90;
//assigning new array Object refeence to the old one
obj=tempObj;
for(int j=0;j<obj.length;j++){
System.out.println("obj["+j+"] -"+obj[j]);
}
}
}
edited Jun 1 '17 at 6:20
Satan Pandeya
2,51531635
2,51531635
answered Jun 1 '17 at 3:51
jyoti bhushanjyoti bhushan
1
1
add a comment |
add a comment |
Since ArrayList takes to much memory when I need array of primitive types, I prefer using IntStream.builder() for creating int array (You can also use LongStream and DoubleStream builders).
Example:
Builder builder = IntStream.builder();
int arraySize = new Random().nextInt();
for(int i = 0; i<arraySize; i++ ) {
builder.add(i);
}
int array = builder.build().toArray();
Note: available since Java 8.
add a comment |
Since ArrayList takes to much memory when I need array of primitive types, I prefer using IntStream.builder() for creating int array (You can also use LongStream and DoubleStream builders).
Example:
Builder builder = IntStream.builder();
int arraySize = new Random().nextInt();
for(int i = 0; i<arraySize; i++ ) {
builder.add(i);
}
int array = builder.build().toArray();
Note: available since Java 8.
add a comment |
Since ArrayList takes to much memory when I need array of primitive types, I prefer using IntStream.builder() for creating int array (You can also use LongStream and DoubleStream builders).
Example:
Builder builder = IntStream.builder();
int arraySize = new Random().nextInt();
for(int i = 0; i<arraySize; i++ ) {
builder.add(i);
}
int array = builder.build().toArray();
Note: available since Java 8.
Since ArrayList takes to much memory when I need array of primitive types, I prefer using IntStream.builder() for creating int array (You can also use LongStream and DoubleStream builders).
Example:
Builder builder = IntStream.builder();
int arraySize = new Random().nextInt();
for(int i = 0; i<arraySize; i++ ) {
builder.add(i);
}
int array = builder.build().toArray();
Note: available since Java 8.
answered Nov 28 '17 at 22:27
Bosko PopovicBosko Popovic
10125
10125
add a comment |
add a comment |
You can do some thing
private static Person addPersons(Person persons, Person personToAdd) {
int currentLenght = persons.length;
Person personsArrayNew = Arrays.copyOf(persons, currentLenght +1);
personsArrayNew[currentLenght] = personToAdd;
return personsArrayNew;
}
add a comment |
You can do some thing
private static Person addPersons(Person persons, Person personToAdd) {
int currentLenght = persons.length;
Person personsArrayNew = Arrays.copyOf(persons, currentLenght +1);
personsArrayNew[currentLenght] = personToAdd;
return personsArrayNew;
}
add a comment |
You can do some thing
private static Person addPersons(Person persons, Person personToAdd) {
int currentLenght = persons.length;
Person personsArrayNew = Arrays.copyOf(persons, currentLenght +1);
personsArrayNew[currentLenght] = personToAdd;
return personsArrayNew;
}
You can do some thing
private static Person addPersons(Person persons, Person personToAdd) {
int currentLenght = persons.length;
Person personsArrayNew = Arrays.copyOf(persons, currentLenght +1);
personsArrayNew[currentLenght] = personToAdd;
return personsArrayNew;
}
answered Jul 23 '18 at 3:39
Chinthaka DevindaChinthaka Devinda
2612521
2612521
add a comment |
add a comment |
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