order column from union select by another column












0















I have a table:



Message



id, user_from_id, user_to_id, send_date, message, is_readed


and I would like to select all the users that I chat with, so my query looks like this:



SELECT user_from_id as user_id
FROM message
WHERE user_to_id=xxx
UNION
SELECT user_to_id
FROM message
WHERE user_from_id=xxx


..and I have a list of user_id's, the problem is that I can't find a way to order those id's by send_data, so that at the beginning of that list i would have a user that i lately chat with



Can someone help me?










share|improve this question



























    0















    I have a table:



    Message



    id, user_from_id, user_to_id, send_date, message, is_readed


    and I would like to select all the users that I chat with, so my query looks like this:



    SELECT user_from_id as user_id
    FROM message
    WHERE user_to_id=xxx
    UNION
    SELECT user_to_id
    FROM message
    WHERE user_from_id=xxx


    ..and I have a list of user_id's, the problem is that I can't find a way to order those id's by send_data, so that at the beginning of that list i would have a user that i lately chat with



    Can someone help me?










    share|improve this question

























      0












      0








      0








      I have a table:



      Message



      id, user_from_id, user_to_id, send_date, message, is_readed


      and I would like to select all the users that I chat with, so my query looks like this:



      SELECT user_from_id as user_id
      FROM message
      WHERE user_to_id=xxx
      UNION
      SELECT user_to_id
      FROM message
      WHERE user_from_id=xxx


      ..and I have a list of user_id's, the problem is that I can't find a way to order those id's by send_data, so that at the beginning of that list i would have a user that i lately chat with



      Can someone help me?










      share|improve this question














      I have a table:



      Message



      id, user_from_id, user_to_id, send_date, message, is_readed


      and I would like to select all the users that I chat with, so my query looks like this:



      SELECT user_from_id as user_id
      FROM message
      WHERE user_to_id=xxx
      UNION
      SELECT user_to_id
      FROM message
      WHERE user_from_id=xxx


      ..and I have a list of user_id's, the problem is that I can't find a way to order those id's by send_data, so that at the beginning of that list i would have a user that i lately chat with



      Can someone help me?







      mysql sql sql-order-by union






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 23 '18 at 13:21









      Andrzej MAndrzej M

      11




      11
























          2 Answers
          2






          active

          oldest

          votes


















          0














          How about dispensing with the union?



          SELECT (CASE WHEN m.user_to_id = xxx THEN m.user_from_id
          ELSE m.user_to_id
          END) as user_id
          FROM message m
          WHERE xxx IN (m.user_to_id, m.user_from_id)
          ORDER BY m.send_date DESC;


          This is probably not what you really want, because users will appear multiple times in the list. What you really want is:



          SELECT (CASE WHEN m.user_to_id = xxx THEN m.user_from_id
          ELSE m.user_to_id
          END) as user_id
          FROM message m
          WHERE xxx IN (m.user_to_id, m.user_from_id)
          GROUP BY m.user_id
          ORDER BY MAX(m.send_date) DESC;





          share|improve this answer































            0














            with x as(
            SELECT user_from_id as user_id, send_date
            FROM message
            WHERE user_to_id=xxx
            UNION
            SELECT user_to_id, send_date
            FROM message
            WHERE user_from_id=xxx
            ) select user_id
            from x
            order by send_date


            This wraps the UNION query up with the send_date column into a single variable, from which you can then SELECT and ORDER BY send_date.






            share|improve this answer


























              Your Answer






              StackExchange.ifUsing("editor", function () {
              StackExchange.using("externalEditor", function () {
              StackExchange.using("snippets", function () {
              StackExchange.snippets.init();
              });
              });
              }, "code-snippets");

              StackExchange.ready(function() {
              var channelOptions = {
              tags: "".split(" "),
              id: "1"
              };
              initTagRenderer("".split(" "), "".split(" "), channelOptions);

              StackExchange.using("externalEditor", function() {
              // Have to fire editor after snippets, if snippets enabled
              if (StackExchange.settings.snippets.snippetsEnabled) {
              StackExchange.using("snippets", function() {
              createEditor();
              });
              }
              else {
              createEditor();
              }
              });

              function createEditor() {
              StackExchange.prepareEditor({
              heartbeatType: 'answer',
              autoActivateHeartbeat: false,
              convertImagesToLinks: true,
              noModals: true,
              showLowRepImageUploadWarning: true,
              reputationToPostImages: 10,
              bindNavPrevention: true,
              postfix: "",
              imageUploader: {
              brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
              contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
              allowUrls: true
              },
              onDemand: true,
              discardSelector: ".discard-answer"
              ,immediatelyShowMarkdownHelp:true
              });


              }
              });














              draft saved

              draft discarded


















              StackExchange.ready(
              function () {
              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53447504%2forder-column-from-union-select-by-another-column%23new-answer', 'question_page');
              }
              );

              Post as a guest















              Required, but never shown

























              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              0














              How about dispensing with the union?



              SELECT (CASE WHEN m.user_to_id = xxx THEN m.user_from_id
              ELSE m.user_to_id
              END) as user_id
              FROM message m
              WHERE xxx IN (m.user_to_id, m.user_from_id)
              ORDER BY m.send_date DESC;


              This is probably not what you really want, because users will appear multiple times in the list. What you really want is:



              SELECT (CASE WHEN m.user_to_id = xxx THEN m.user_from_id
              ELSE m.user_to_id
              END) as user_id
              FROM message m
              WHERE xxx IN (m.user_to_id, m.user_from_id)
              GROUP BY m.user_id
              ORDER BY MAX(m.send_date) DESC;





              share|improve this answer




























                0














                How about dispensing with the union?



                SELECT (CASE WHEN m.user_to_id = xxx THEN m.user_from_id
                ELSE m.user_to_id
                END) as user_id
                FROM message m
                WHERE xxx IN (m.user_to_id, m.user_from_id)
                ORDER BY m.send_date DESC;


                This is probably not what you really want, because users will appear multiple times in the list. What you really want is:



                SELECT (CASE WHEN m.user_to_id = xxx THEN m.user_from_id
                ELSE m.user_to_id
                END) as user_id
                FROM message m
                WHERE xxx IN (m.user_to_id, m.user_from_id)
                GROUP BY m.user_id
                ORDER BY MAX(m.send_date) DESC;





                share|improve this answer


























                  0












                  0








                  0







                  How about dispensing with the union?



                  SELECT (CASE WHEN m.user_to_id = xxx THEN m.user_from_id
                  ELSE m.user_to_id
                  END) as user_id
                  FROM message m
                  WHERE xxx IN (m.user_to_id, m.user_from_id)
                  ORDER BY m.send_date DESC;


                  This is probably not what you really want, because users will appear multiple times in the list. What you really want is:



                  SELECT (CASE WHEN m.user_to_id = xxx THEN m.user_from_id
                  ELSE m.user_to_id
                  END) as user_id
                  FROM message m
                  WHERE xxx IN (m.user_to_id, m.user_from_id)
                  GROUP BY m.user_id
                  ORDER BY MAX(m.send_date) DESC;





                  share|improve this answer













                  How about dispensing with the union?



                  SELECT (CASE WHEN m.user_to_id = xxx THEN m.user_from_id
                  ELSE m.user_to_id
                  END) as user_id
                  FROM message m
                  WHERE xxx IN (m.user_to_id, m.user_from_id)
                  ORDER BY m.send_date DESC;


                  This is probably not what you really want, because users will appear multiple times in the list. What you really want is:



                  SELECT (CASE WHEN m.user_to_id = xxx THEN m.user_from_id
                  ELSE m.user_to_id
                  END) as user_id
                  FROM message m
                  WHERE xxx IN (m.user_to_id, m.user_from_id)
                  GROUP BY m.user_id
                  ORDER BY MAX(m.send_date) DESC;






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 23 '18 at 13:22









                  Gordon LinoffGordon Linoff

                  793k36318421




                  793k36318421

























                      0














                      with x as(
                      SELECT user_from_id as user_id, send_date
                      FROM message
                      WHERE user_to_id=xxx
                      UNION
                      SELECT user_to_id, send_date
                      FROM message
                      WHERE user_from_id=xxx
                      ) select user_id
                      from x
                      order by send_date


                      This wraps the UNION query up with the send_date column into a single variable, from which you can then SELECT and ORDER BY send_date.






                      share|improve this answer






























                        0














                        with x as(
                        SELECT user_from_id as user_id, send_date
                        FROM message
                        WHERE user_to_id=xxx
                        UNION
                        SELECT user_to_id, send_date
                        FROM message
                        WHERE user_from_id=xxx
                        ) select user_id
                        from x
                        order by send_date


                        This wraps the UNION query up with the send_date column into a single variable, from which you can then SELECT and ORDER BY send_date.






                        share|improve this answer




























                          0












                          0








                          0







                          with x as(
                          SELECT user_from_id as user_id, send_date
                          FROM message
                          WHERE user_to_id=xxx
                          UNION
                          SELECT user_to_id, send_date
                          FROM message
                          WHERE user_from_id=xxx
                          ) select user_id
                          from x
                          order by send_date


                          This wraps the UNION query up with the send_date column into a single variable, from which you can then SELECT and ORDER BY send_date.






                          share|improve this answer















                          with x as(
                          SELECT user_from_id as user_id, send_date
                          FROM message
                          WHERE user_to_id=xxx
                          UNION
                          SELECT user_to_id, send_date
                          FROM message
                          WHERE user_from_id=xxx
                          ) select user_id
                          from x
                          order by send_date


                          This wraps the UNION query up with the send_date column into a single variable, from which you can then SELECT and ORDER BY send_date.







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Nov 23 '18 at 15:11









                          Benjamin Howarth

                          2,75131423




                          2,75131423










                          answered Nov 23 '18 at 13:26









                          picklerickpicklerick

                          32918




                          32918






























                              draft saved

                              draft discarded




















































                              Thanks for contributing an answer to Stack Overflow!


                              • Please be sure to answer the question. Provide details and share your research!

                              But avoid



                              • Asking for help, clarification, or responding to other answers.

                              • Making statements based on opinion; back them up with references or personal experience.


                              To learn more, see our tips on writing great answers.




                              draft saved


                              draft discarded














                              StackExchange.ready(
                              function () {
                              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53447504%2forder-column-from-union-select-by-another-column%23new-answer', 'question_page');
                              }
                              );

                              Post as a guest















                              Required, but never shown





















































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown

































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown







                              這個網誌中的熱門文章

                              Tangent Lines Diagram Along Smooth Curve

                              Yusuf al-Mu'taman ibn Hud

                              Zucchini