Pagination in Janusgraph - how do I implement traversal.next(pagesize) in Java





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Environment: Janusgraph 0.3.3 cql-es, tinkergraph 3.3.3, gremlin driver 3.3.3 with remote websocket connection and following advice from stephen mallette:
How to perform pagination in Gremlin



Following works in gremlin console:



t = g.V().hasLabel('V_USER').has('v_UserName',textContains('Frank')); 

t.next(1)


However in Java the graph traversal next operation does not return vertices



GraphTraversal<Vertex,Vertex> t = 

     g.V().hasLabel("V_USER").has("v_UserName","textContains('Frank')");

List<Vertex> vl = t.next(10) // returns null


The GraphTraversal variable t in debug appears as follows:



[GraphStep(vertex,), HasStep([~label.eq(V_USER), 

     v_UserName.eq(textContains('Frank')))])]


So I assume I need to do something other than append the .next() function but I cannot figure out what. Any assistance much appreciated.






pagination gremlin janusgraph







share|improve this question























  • Seems to work for me in this example. A bit surprised t.next(10) would return null instead of an empty list. Do you have a stack trace?

    – Jason Plurad
    Nov 26 '18 at 21:01











  • Thanks Jason appreciate the response and link to the example. My code was returning an empty list, the problem was with the text contains predicate which in Java needs to be Text.textContains.

    – ptc
    Nov 28 '18 at 19:17


















1















Environment: Janusgraph 0.3.3 cql-es, tinkergraph 3.3.3, gremlin driver 3.3.3 with remote websocket connection and following advice from stephen mallette:
How to perform pagination in Gremlin



Following works in gremlin console:



t = g.V().hasLabel('V_USER').has('v_UserName',textContains('Frank')); 

t.next(1)


However in Java the graph traversal next operation does not return vertices



GraphTraversal<Vertex,Vertex> t = 

     g.V().hasLabel("V_USER").has("v_UserName","textContains('Frank')");

List<Vertex> vl = t.next(10) // returns null


The GraphTraversal variable t in debug appears as follows:



[GraphStep(vertex,), HasStep([~label.eq(V_USER), 

     v_UserName.eq(textContains('Frank')))])]


So I assume I need to do something other than append the .next() function but I cannot figure out what. Any assistance much appreciated.






pagination gremlin janusgraph







share|improve this question























  • Seems to work for me in this example. A bit surprised t.next(10) would return null instead of an empty list. Do you have a stack trace?

    – Jason Plurad
    Nov 26 '18 at 21:01











  • Thanks Jason appreciate the response and link to the example. My code was returning an empty list, the problem was with the text contains predicate which in Java needs to be Text.textContains.

    – ptc
    Nov 28 '18 at 19:17














1












1








1








Environment: Janusgraph 0.3.3 cql-es, tinkergraph 3.3.3, gremlin driver 3.3.3 with remote websocket connection and following advice from stephen mallette:
How to perform pagination in Gremlin



Following works in gremlin console:



t = g.V().hasLabel('V_USER').has('v_UserName',textContains('Frank')); 

t.next(1)


However in Java the graph traversal next operation does not return vertices



GraphTraversal<Vertex,Vertex> t = 

     g.V().hasLabel("V_USER").has("v_UserName","textContains('Frank')");

List<Vertex> vl = t.next(10) // returns null


The GraphTraversal variable t in debug appears as follows:



[GraphStep(vertex,), HasStep([~label.eq(V_USER), 

     v_UserName.eq(textContains('Frank')))])]


So I assume I need to do something other than append the .next() function but I cannot figure out what. Any assistance much appreciated.






pagination gremlin janusgraph







share|improve this question














Environment: Janusgraph 0.3.3 cql-es, tinkergraph 3.3.3, gremlin driver 3.3.3 with remote websocket connection and following advice from stephen mallette:
How to perform pagination in Gremlin



Following works in gremlin console:



t = g.V().hasLabel('V_USER').has('v_UserName',textContains('Frank')); 

t.next(1)


However in Java the graph traversal next operation does not return vertices



GraphTraversal<Vertex,Vertex> t = 

     g.V().hasLabel("V_USER").has("v_UserName","textContains('Frank')");

List<Vertex> vl = t.next(10) // returns null


The GraphTraversal variable t in debug appears as follows:



[GraphStep(vertex,), HasStep([~label.eq(V_USER), 

     v_UserName.eq(textContains('Frank')))])]


So I assume I need to do something other than append the .next() function but I cannot figure out what. Any assistance much appreciated.






pagination gremlin janusgraph




pagination gremlin janusgraph






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 25 '18 at 3:28









ptcptc

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  • Seems to work for me in this example. A bit surprised t.next(10) would return null instead of an empty list. Do you have a stack trace?

    – Jason Plurad
    Nov 26 '18 at 21:01











  • Thanks Jason appreciate the response and link to the example. My code was returning an empty list, the problem was with the text contains predicate which in Java needs to be Text.textContains.

    – ptc
    Nov 28 '18 at 19:17



















  • Seems to work for me in this example. A bit surprised t.next(10) would return null instead of an empty list. Do you have a stack trace?

    – Jason Plurad
    Nov 26 '18 at 21:01











  • Thanks Jason appreciate the response and link to the example. My code was returning an empty list, the problem was with the text contains predicate which in Java needs to be Text.textContains.

    – ptc
    Nov 28 '18 at 19:17

















Seems to work for me in this example. A bit surprised t.next(10) would return null instead of an empty list. Do you have a stack trace?

– Jason Plurad
Nov 26 '18 at 21:01





Seems to work for me in this example. A bit surprised t.next(10) would return null instead of an empty list. Do you have a stack trace?

– Jason Plurad
Nov 26 '18 at 21:01













Thanks Jason appreciate the response and link to the example. My code was returning an empty list, the problem was with the text contains predicate which in Java needs to be Text.textContains.

– ptc
Nov 28 '18 at 19:17





Thanks Jason appreciate the response and link to the example. My code was returning an empty list, the problem was with the text contains predicate which in Java needs to be Text.textContains.

– ptc
Nov 28 '18 at 19:17












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Problem was with text contains predicate which need to user Text.textContains function in Java, thanks to Jason Plurad for his response and example.






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    Problem was with text contains predicate which need to user Text.textContains function in Java, thanks to Jason Plurad for his response and example.






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      Problem was with text contains predicate which need to user Text.textContains function in Java, thanks to Jason Plurad for his response and example.






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        Problem was with text contains predicate which need to user Text.textContains function in Java, thanks to Jason Plurad for his response and example.






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        Problem was with text contains predicate which need to user Text.textContains function in Java, thanks to Jason Plurad for his response and example.







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        answered Nov 28 '18 at 19:19









        ptcptc

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