SQL - How do I make an auto computing column?
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I've created a table named House, which has the column 'area'.
I have another table named HouseFire, with the columns '%_Burnt' and 'area_burnt'.
I have values for both 'area' and '%_Burnt'. I want to make 'area_burnt' to automatically give me the value as soon as I input the % value in '%_burnt'.
I'm using heidisql
mysql sql mariadb auto-update heidisql
asked Nov 23 '18 at 15:44
João NunesJoão Nunes
11
add a comment |
I've created a table named House, which has the column 'area'.
I have another table named HouseFire, with the columns '%_Burnt' and 'area_burnt'.
I have values for both 'area' and '%_Burnt'. I want to make 'area_burnt' to automatically give me the value as soon as I input the % value in '%_burnt'.
I'm using heidisql
mysql sql mariadb auto-update heidisql
asked Nov 23 '18 at 15:44
João NunesJoão Nunes
11
2
You probably need a VIEW: w3schools.com/sql/sql_view.asp
– UjinT34
Nov 23 '18 at 15:51
1
Tag your question with the database you are using.
– Gordon Linoff
Nov 23 '18 at 16:09
I doubt that it's even possible to create an auto computed column based on a field from another table.
– LukStorms
Nov 23 '18 at 16:12
This seems to be a UI problem, not a database problem. Adjust the tags accordingly.
– Rick James
Nov 24 '18 at 23:04
add a comment |
I've created a table named House, which has the column 'area'.
I have another table named HouseFire, with the columns '%_Burnt' and 'area_burnt'.
I have values for both 'area' and '%_Burnt'. I want to make 'area_burnt' to automatically give me the value as soon as I input the % value in '%_burnt'.
I'm using heidisql
mysql sql mariadb auto-update heidisql
asked Nov 23 '18 at 15:44
João NunesJoão Nunes
11
I've created a table named House, which has the column 'area'.
I have another table named HouseFire, with the columns '%_Burnt' and 'area_burnt'.
I have values for both 'area' and '%_Burnt'. I want to make 'area_burnt' to automatically give me the value as soon as I input the % value in '%_burnt'.
I'm using heidisql
mysql sql mariadb auto-update heidisql
mysql sql mariadb auto-update heidisql
asked Nov 23 '18 at 15:44
João NunesJoão Nunes
11
asked Nov 23 '18 at 15:44
João NunesJoão Nunes
11
edited Nov 24 '18 at 0:01
João Nunes
asked Nov 23 '18 at 15:44
João NunesJoão Nunes
11
asked Nov 23 '18 at 15:44
João NunesJoão Nunes
11
asked Nov 23 '18 at 15:44
João NunesJoão Nunes
11
11
2
You probably need a VIEW: w3schools.com/sql/sql_view.asp
– UjinT34
Nov 23 '18 at 15:51
1
Tag your question with the database you are using.
– Gordon Linoff
Nov 23 '18 at 16:09
I doubt that it's even possible to create an auto computed column based on a field from another table.
– LukStorms
Nov 23 '18 at 16:12
This seems to be a UI problem, not a database problem. Adjust the tags accordingly.
– Rick James
Nov 24 '18 at 23:04
add a comment |
2
You probably need a VIEW: w3schools.com/sql/sql_view.asp
– UjinT34
Nov 23 '18 at 15:51
1
Tag your question with the database you are using.
– Gordon Linoff
Nov 23 '18 at 16:09
I doubt that it's even possible to create an auto computed column based on a field from another table.
– LukStorms
Nov 23 '18 at 16:12
This seems to be a UI problem, not a database problem. Adjust the tags accordingly.
– Rick James
Nov 24 '18 at 23:04
2
2
You probably need a VIEW: w3schools.com/sql/sql_view.asp
– UjinT34
Nov 23 '18 at 15:51
You probably need a VIEW: w3schools.com/sql/sql_view.asp
– UjinT34
Nov 23 '18 at 15:51
1
1
Tag your question with the database you are using.
– Gordon Linoff
Nov 23 '18 at 16:09
Tag your question with the database you are using.
– Gordon Linoff
Nov 23 '18 at 16:09
I doubt that it's even possible to create an auto computed column based on a field from another table.
– LukStorms
Nov 23 '18 at 16:12
I doubt that it's even possible to create an auto computed column based on a field from another table.
– LukStorms
Nov 23 '18 at 16:12
This seems to be a UI problem, not a database problem. Adjust the tags accordingly.
– Rick James
Nov 24 '18 at 23:04
This seems to be a UI problem, not a database problem. Adjust the tags accordingly.
– Rick James
Nov 24 '18 at 23:04
add a comment |
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2
You probably need a VIEW: w3schools.com/sql/sql_view.asp
– UjinT34
Nov 23 '18 at 15:51
1
Tag your question with the database you are using.
– Gordon Linoff
Nov 23 '18 at 16:09
I doubt that it's even possible to create an auto computed column based on a field from another table.
– LukStorms
Nov 23 '18 at 16:12
This seems to be a UI problem, not a database problem. Adjust the tags accordingly.
– Rick James
Nov 24 '18 at 23:04