XQuery 3 merging two node sequences and de-duplicating





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In XQuery 3.1 (under eXistDB 4.4) I have two functions which return two sets of nodes that describe family relations of a person. The results of the two functions can overlap.



A first function person:person-relationship-as-object("#Guilhem_Faure_SML-AU") returns:



<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Martin_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>

<person relation="Raimund_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>


A second function person:person-relationship-as-subject("#Guilhem_Faure_SML-AU") returns



<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Bernarda_Guilhem_Faure_SML-AU">
<span class="en">Spouse(s)</span>
<span class="fr">Époux/épouse(s)</span>
</person>


Now I want to merge the two sets of nodes into one, and return each distinct node only once.



I attempted a rough SQL-like structure, but failed:



let $x := person:person-relationship-as-object("#Guilhem_Faure_SML-AU") 
| person:person-relationship-as-subject("#Guilhem_Faure_SML-AU")

for $y in $x

order by $y/@relation ascending

group by $y/@relation, $y/span[@class="en"], $y/span[@class="fr"]

return $y


I don't think I really understand why the group by doesn't work here. Moreover, if group by doesn't do the job, how else can I approach what (I think?) should be a simple exercise in grouping/distinct results?










share|improve this question

























  • return functx:distinct-deep($x) does the job, without grouping...

    – jbrehr
    Nov 23 '18 at 16:40


















1















In XQuery 3.1 (under eXistDB 4.4) I have two functions which return two sets of nodes that describe family relations of a person. The results of the two functions can overlap.



A first function person:person-relationship-as-object("#Guilhem_Faure_SML-AU") returns:



<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Martin_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>

<person relation="Raimund_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>


A second function person:person-relationship-as-subject("#Guilhem_Faure_SML-AU") returns



<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Bernarda_Guilhem_Faure_SML-AU">
<span class="en">Spouse(s)</span>
<span class="fr">Époux/épouse(s)</span>
</person>


Now I want to merge the two sets of nodes into one, and return each distinct node only once.



I attempted a rough SQL-like structure, but failed:



let $x := person:person-relationship-as-object("#Guilhem_Faure_SML-AU") 
| person:person-relationship-as-subject("#Guilhem_Faure_SML-AU")

for $y in $x

order by $y/@relation ascending

group by $y/@relation, $y/span[@class="en"], $y/span[@class="fr"]

return $y


I don't think I really understand why the group by doesn't work here. Moreover, if group by doesn't do the job, how else can I approach what (I think?) should be a simple exercise in grouping/distinct results?










share|improve this question

























  • return functx:distinct-deep($x) does the job, without grouping...

    – jbrehr
    Nov 23 '18 at 16:40














1












1








1








In XQuery 3.1 (under eXistDB 4.4) I have two functions which return two sets of nodes that describe family relations of a person. The results of the two functions can overlap.



A first function person:person-relationship-as-object("#Guilhem_Faure_SML-AU") returns:



<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Martin_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>

<person relation="Raimund_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>


A second function person:person-relationship-as-subject("#Guilhem_Faure_SML-AU") returns



<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Bernarda_Guilhem_Faure_SML-AU">
<span class="en">Spouse(s)</span>
<span class="fr">Époux/épouse(s)</span>
</person>


Now I want to merge the two sets of nodes into one, and return each distinct node only once.



I attempted a rough SQL-like structure, but failed:



let $x := person:person-relationship-as-object("#Guilhem_Faure_SML-AU") 
| person:person-relationship-as-subject("#Guilhem_Faure_SML-AU")

for $y in $x

order by $y/@relation ascending

group by $y/@relation, $y/span[@class="en"], $y/span[@class="fr"]

return $y


I don't think I really understand why the group by doesn't work here. Moreover, if group by doesn't do the job, how else can I approach what (I think?) should be a simple exercise in grouping/distinct results?










share|improve this question
















In XQuery 3.1 (under eXistDB 4.4) I have two functions which return two sets of nodes that describe family relations of a person. The results of the two functions can overlap.



A first function person:person-relationship-as-object("#Guilhem_Faure_SML-AU") returns:



<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Martin_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>

<person relation="Raimund_de_Verazilh_SML-AU">
<span class="en">Aunt(s)/Uncle(s)</span>
<span class="fr">Tante(s)/Oncle(s)</span>
</person>


A second function person:person-relationship-as-subject("#Guilhem_Faure_SML-AU") returns



<person relation="Arnald_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Peire_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Esteve_Faure_SML-AU">
<span class="en">Sibling(s)</span>
<span class="fr">Frère(s)/sœur(s)</span>
</person>

<person relation="Bernarda_Guilhem_Faure_SML-AU">
<span class="en">Spouse(s)</span>
<span class="fr">Époux/épouse(s)</span>
</person>


Now I want to merge the two sets of nodes into one, and return each distinct node only once.



I attempted a rough SQL-like structure, but failed:



let $x := person:person-relationship-as-object("#Guilhem_Faure_SML-AU") 
| person:person-relationship-as-subject("#Guilhem_Faure_SML-AU")

for $y in $x

order by $y/@relation ascending

group by $y/@relation, $y/span[@class="en"], $y/span[@class="fr"]

return $y


I don't think I really understand why the group by doesn't work here. Moreover, if group by doesn't do the job, how else can I approach what (I think?) should be a simple exercise in grouping/distinct results?







xquery exist-db






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edited Nov 23 '18 at 16:00







jbrehr

















asked Nov 23 '18 at 15:02









jbrehrjbrehr

134212




134212













  • return functx:distinct-deep($x) does the job, without grouping...

    – jbrehr
    Nov 23 '18 at 16:40



















  • return functx:distinct-deep($x) does the job, without grouping...

    – jbrehr
    Nov 23 '18 at 16:40

















return functx:distinct-deep($x) does the job, without grouping...

– jbrehr
Nov 23 '18 at 16:40





return functx:distinct-deep($x) does the job, without grouping...

– jbrehr
Nov 23 '18 at 16:40












1 Answer
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active

oldest

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2














With XQuery and group by, the variable $y in your return clause is bound to the whole group you have created so to eliminate duplicates you need to use return $y[1]. See https://www.w3.org/TR/xquery-31/#id-group-by which says




In the post-grouping tuple generated for a given group, each
non-grouping variable is bound to a sequence containing the
concatenated values of that variable in all the pre-grouping tuples
that were assigned to that group.




and then




This behavior may be surprising to SQL programmers, since SQL reduces
the equivalent of a non-grouping variable to one representative value.







share|improve this answer


























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    With XQuery and group by, the variable $y in your return clause is bound to the whole group you have created so to eliminate duplicates you need to use return $y[1]. See https://www.w3.org/TR/xquery-31/#id-group-by which says




    In the post-grouping tuple generated for a given group, each
    non-grouping variable is bound to a sequence containing the
    concatenated values of that variable in all the pre-grouping tuples
    that were assigned to that group.




    and then




    This behavior may be surprising to SQL programmers, since SQL reduces
    the equivalent of a non-grouping variable to one representative value.







    share|improve this answer






























      2














      With XQuery and group by, the variable $y in your return clause is bound to the whole group you have created so to eliminate duplicates you need to use return $y[1]. See https://www.w3.org/TR/xquery-31/#id-group-by which says




      In the post-grouping tuple generated for a given group, each
      non-grouping variable is bound to a sequence containing the
      concatenated values of that variable in all the pre-grouping tuples
      that were assigned to that group.




      and then




      This behavior may be surprising to SQL programmers, since SQL reduces
      the equivalent of a non-grouping variable to one representative value.







      share|improve this answer




























        2












        2








        2







        With XQuery and group by, the variable $y in your return clause is bound to the whole group you have created so to eliminate duplicates you need to use return $y[1]. See https://www.w3.org/TR/xquery-31/#id-group-by which says




        In the post-grouping tuple generated for a given group, each
        non-grouping variable is bound to a sequence containing the
        concatenated values of that variable in all the pre-grouping tuples
        that were assigned to that group.




        and then




        This behavior may be surprising to SQL programmers, since SQL reduces
        the equivalent of a non-grouping variable to one representative value.







        share|improve this answer















        With XQuery and group by, the variable $y in your return clause is bound to the whole group you have created so to eliminate duplicates you need to use return $y[1]. See https://www.w3.org/TR/xquery-31/#id-group-by which says




        In the post-grouping tuple generated for a given group, each
        non-grouping variable is bound to a sequence containing the
        concatenated values of that variable in all the pre-grouping tuples
        that were assigned to that group.




        and then




        This behavior may be surprising to SQL programmers, since SQL reduces
        the equivalent of a non-grouping variable to one representative value.








        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 23 '18 at 20:41

























        answered Nov 23 '18 at 19:55









        Martin HonnenMartin Honnen

        113k66279




        113k66279
































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