MySQL select fields from row where criteria met, and field from row above











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0
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I have a data table of results where I would like to select information which is mostly held against the record relating to the second-place finisher.



So, for example, the location of the race, the date of the race, and the time deficit to the winner.



But what I would like to show in my query is the winner followed by their winning margin, which is actually stored against the record relating to the second-place finisher.



For example:



id | race_id | result | Entrant       | Time
---|---------|--------|---------------|------
0 | 001 | 1 | Huw Edwards | 54:78.491
1 | 001 | 2 | Fiona Bruce | 0.250
2 | 001 | 3 | Sophie Raworth| 3.114
3 | 001 | 4 | George Alagiah| 6.756
4 | 001 | 5 | Mishal Husain | 42.452
5 | 001 | 6 | Peter Sissons | 58.004
6 | 002 | 1 | Fiona Bruce | 43:08.549
7 | 002 | 2 | Sophie Raworth| 5.439
8 | 002 | 3 | Mishal Husain | 5.444
9 | 002 | 4 | Huw Edwards | 6.007
10 | 002 | 5 | Peter Sissons | 13.000
11 | 002 | 6 | George Alagiah| 2:12.782


I have tried a query such as this (not working as desired):



SELECT r.id, r.entrant, r.time 
FROM races as r
LEFT JOIN races as r1
ON r1.id > r.id
WHERE r.result = "2"


I'd like to end up with a result like the following, because it shows the winning margin that Huw Edwards enjoyed.



id | race_id | entrant     | time
---|---------|-------------|-------
1 | 001 | Huw Edwards | 0.250
7 | 002 | Fiona Bruce | 5.439


Here is my table schema:



CREATE TABLE `races` (
`series` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`year` int(11) NOT NULL,
`round` int(11) NOT NULL,
`date` date NOT NULL,
`race_id` text COLLATE utf8_unicode_ci NOT NULL,
`track` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`result` int(11) NOT NULL,
`number` int(11) NOT NULL,
`class` varchar(11) COLLATE utf8_unicode_ci NOT NULL,
`class_pos` int(11) NOT NULL,
`runner` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`runner_id` int(11) NOT NULL,
`runner2` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`runner_id2` int(11) NOT NULL,
`entrant` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`laps` int(11) NOT NULL,
`time` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`best` text COLLATE utf8_unicode_ci NOT NULL,
`qual` int(11) NOT NULL,
`marque` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`id` int(11) NOT NULL AUTO_INCREMENT,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=43021 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci









share|improve this question
























  • This isn't really enough information to help you. Where is the race ID stored? That's a necessary part of your query.
    – Ed Cottrell
    Nov 8 at 14:26










  • What's your logic in your question? it is not clear.
    – D-Shih
    Nov 8 at 14:28










  • The race ID is stored in the table 'races' if you hadn't worked it out...
    – Andrew Abbott
    Nov 8 at 14:42










  • How would your table structure support multiple races?
    – Adder
    Nov 8 at 15:01










  • There is a race ID field as well which isn't included in this example for simplicity.
    – Andrew Abbott
    Nov 8 at 15:08















up vote
0
down vote

favorite












I have a data table of results where I would like to select information which is mostly held against the record relating to the second-place finisher.



So, for example, the location of the race, the date of the race, and the time deficit to the winner.



But what I would like to show in my query is the winner followed by their winning margin, which is actually stored against the record relating to the second-place finisher.



For example:



id | race_id | result | Entrant       | Time
---|---------|--------|---------------|------
0 | 001 | 1 | Huw Edwards | 54:78.491
1 | 001 | 2 | Fiona Bruce | 0.250
2 | 001 | 3 | Sophie Raworth| 3.114
3 | 001 | 4 | George Alagiah| 6.756
4 | 001 | 5 | Mishal Husain | 42.452
5 | 001 | 6 | Peter Sissons | 58.004
6 | 002 | 1 | Fiona Bruce | 43:08.549
7 | 002 | 2 | Sophie Raworth| 5.439
8 | 002 | 3 | Mishal Husain | 5.444
9 | 002 | 4 | Huw Edwards | 6.007
10 | 002 | 5 | Peter Sissons | 13.000
11 | 002 | 6 | George Alagiah| 2:12.782


I have tried a query such as this (not working as desired):



SELECT r.id, r.entrant, r.time 
FROM races as r
LEFT JOIN races as r1
ON r1.id > r.id
WHERE r.result = "2"


I'd like to end up with a result like the following, because it shows the winning margin that Huw Edwards enjoyed.



id | race_id | entrant     | time
---|---------|-------------|-------
1 | 001 | Huw Edwards | 0.250
7 | 002 | Fiona Bruce | 5.439


Here is my table schema:



CREATE TABLE `races` (
`series` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`year` int(11) NOT NULL,
`round` int(11) NOT NULL,
`date` date NOT NULL,
`race_id` text COLLATE utf8_unicode_ci NOT NULL,
`track` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`result` int(11) NOT NULL,
`number` int(11) NOT NULL,
`class` varchar(11) COLLATE utf8_unicode_ci NOT NULL,
`class_pos` int(11) NOT NULL,
`runner` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`runner_id` int(11) NOT NULL,
`runner2` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`runner_id2` int(11) NOT NULL,
`entrant` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`laps` int(11) NOT NULL,
`time` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`best` text COLLATE utf8_unicode_ci NOT NULL,
`qual` int(11) NOT NULL,
`marque` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`id` int(11) NOT NULL AUTO_INCREMENT,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=43021 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci









share|improve this question
























  • This isn't really enough information to help you. Where is the race ID stored? That's a necessary part of your query.
    – Ed Cottrell
    Nov 8 at 14:26










  • What's your logic in your question? it is not clear.
    – D-Shih
    Nov 8 at 14:28










  • The race ID is stored in the table 'races' if you hadn't worked it out...
    – Andrew Abbott
    Nov 8 at 14:42










  • How would your table structure support multiple races?
    – Adder
    Nov 8 at 15:01










  • There is a race ID field as well which isn't included in this example for simplicity.
    – Andrew Abbott
    Nov 8 at 15:08













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have a data table of results where I would like to select information which is mostly held against the record relating to the second-place finisher.



So, for example, the location of the race, the date of the race, and the time deficit to the winner.



But what I would like to show in my query is the winner followed by their winning margin, which is actually stored against the record relating to the second-place finisher.



For example:



id | race_id | result | Entrant       | Time
---|---------|--------|---------------|------
0 | 001 | 1 | Huw Edwards | 54:78.491
1 | 001 | 2 | Fiona Bruce | 0.250
2 | 001 | 3 | Sophie Raworth| 3.114
3 | 001 | 4 | George Alagiah| 6.756
4 | 001 | 5 | Mishal Husain | 42.452
5 | 001 | 6 | Peter Sissons | 58.004
6 | 002 | 1 | Fiona Bruce | 43:08.549
7 | 002 | 2 | Sophie Raworth| 5.439
8 | 002 | 3 | Mishal Husain | 5.444
9 | 002 | 4 | Huw Edwards | 6.007
10 | 002 | 5 | Peter Sissons | 13.000
11 | 002 | 6 | George Alagiah| 2:12.782


I have tried a query such as this (not working as desired):



SELECT r.id, r.entrant, r.time 
FROM races as r
LEFT JOIN races as r1
ON r1.id > r.id
WHERE r.result = "2"


I'd like to end up with a result like the following, because it shows the winning margin that Huw Edwards enjoyed.



id | race_id | entrant     | time
---|---------|-------------|-------
1 | 001 | Huw Edwards | 0.250
7 | 002 | Fiona Bruce | 5.439


Here is my table schema:



CREATE TABLE `races` (
`series` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`year` int(11) NOT NULL,
`round` int(11) NOT NULL,
`date` date NOT NULL,
`race_id` text COLLATE utf8_unicode_ci NOT NULL,
`track` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`result` int(11) NOT NULL,
`number` int(11) NOT NULL,
`class` varchar(11) COLLATE utf8_unicode_ci NOT NULL,
`class_pos` int(11) NOT NULL,
`runner` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`runner_id` int(11) NOT NULL,
`runner2` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`runner_id2` int(11) NOT NULL,
`entrant` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`laps` int(11) NOT NULL,
`time` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`best` text COLLATE utf8_unicode_ci NOT NULL,
`qual` int(11) NOT NULL,
`marque` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`id` int(11) NOT NULL AUTO_INCREMENT,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=43021 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci









share|improve this question















I have a data table of results where I would like to select information which is mostly held against the record relating to the second-place finisher.



So, for example, the location of the race, the date of the race, and the time deficit to the winner.



But what I would like to show in my query is the winner followed by their winning margin, which is actually stored against the record relating to the second-place finisher.



For example:



id | race_id | result | Entrant       | Time
---|---------|--------|---------------|------
0 | 001 | 1 | Huw Edwards | 54:78.491
1 | 001 | 2 | Fiona Bruce | 0.250
2 | 001 | 3 | Sophie Raworth| 3.114
3 | 001 | 4 | George Alagiah| 6.756
4 | 001 | 5 | Mishal Husain | 42.452
5 | 001 | 6 | Peter Sissons | 58.004
6 | 002 | 1 | Fiona Bruce | 43:08.549
7 | 002 | 2 | Sophie Raworth| 5.439
8 | 002 | 3 | Mishal Husain | 5.444
9 | 002 | 4 | Huw Edwards | 6.007
10 | 002 | 5 | Peter Sissons | 13.000
11 | 002 | 6 | George Alagiah| 2:12.782


I have tried a query such as this (not working as desired):



SELECT r.id, r.entrant, r.time 
FROM races as r
LEFT JOIN races as r1
ON r1.id > r.id
WHERE r.result = "2"


I'd like to end up with a result like the following, because it shows the winning margin that Huw Edwards enjoyed.



id | race_id | entrant     | time
---|---------|-------------|-------
1 | 001 | Huw Edwards | 0.250
7 | 002 | Fiona Bruce | 5.439


Here is my table schema:



CREATE TABLE `races` (
`series` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`year` int(11) NOT NULL,
`round` int(11) NOT NULL,
`date` date NOT NULL,
`race_id` text COLLATE utf8_unicode_ci NOT NULL,
`track` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`result` int(11) NOT NULL,
`number` int(11) NOT NULL,
`class` varchar(11) COLLATE utf8_unicode_ci NOT NULL,
`class_pos` int(11) NOT NULL,
`runner` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`runner_id` int(11) NOT NULL,
`runner2` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`runner_id2` int(11) NOT NULL,
`entrant` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`laps` int(11) NOT NULL,
`time` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`best` text COLLATE utf8_unicode_ci NOT NULL,
`qual` int(11) NOT NULL,
`marque` varchar(256) COLLATE utf8_unicode_ci NOT NULL,
`id` int(11) NOT NULL AUTO_INCREMENT,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=43021 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci






mysql database






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 9 at 16:09









Alex

14.1k11736




14.1k11736










asked Nov 8 at 14:24









Andrew Abbott

871219




871219












  • This isn't really enough information to help you. Where is the race ID stored? That's a necessary part of your query.
    – Ed Cottrell
    Nov 8 at 14:26










  • What's your logic in your question? it is not clear.
    – D-Shih
    Nov 8 at 14:28










  • The race ID is stored in the table 'races' if you hadn't worked it out...
    – Andrew Abbott
    Nov 8 at 14:42










  • How would your table structure support multiple races?
    – Adder
    Nov 8 at 15:01










  • There is a race ID field as well which isn't included in this example for simplicity.
    – Andrew Abbott
    Nov 8 at 15:08


















  • This isn't really enough information to help you. Where is the race ID stored? That's a necessary part of your query.
    – Ed Cottrell
    Nov 8 at 14:26










  • What's your logic in your question? it is not clear.
    – D-Shih
    Nov 8 at 14:28










  • The race ID is stored in the table 'races' if you hadn't worked it out...
    – Andrew Abbott
    Nov 8 at 14:42










  • How would your table structure support multiple races?
    – Adder
    Nov 8 at 15:01










  • There is a race ID field as well which isn't included in this example for simplicity.
    – Andrew Abbott
    Nov 8 at 15:08
















This isn't really enough information to help you. Where is the race ID stored? That's a necessary part of your query.
– Ed Cottrell
Nov 8 at 14:26




This isn't really enough information to help you. Where is the race ID stored? That's a necessary part of your query.
– Ed Cottrell
Nov 8 at 14:26












What's your logic in your question? it is not clear.
– D-Shih
Nov 8 at 14:28




What's your logic in your question? it is not clear.
– D-Shih
Nov 8 at 14:28












The race ID is stored in the table 'races' if you hadn't worked it out...
– Andrew Abbott
Nov 8 at 14:42




The race ID is stored in the table 'races' if you hadn't worked it out...
– Andrew Abbott
Nov 8 at 14:42












How would your table structure support multiple races?
– Adder
Nov 8 at 15:01




How would your table structure support multiple races?
– Adder
Nov 8 at 15:01












There is a race ID field as well which isn't included in this example for simplicity.
– Andrew Abbott
Nov 8 at 15:08




There is a race ID field as well which isn't included in this example for simplicity.
– Andrew Abbott
Nov 8 at 15:08












3 Answers
3






active

oldest

votes

















up vote
1
down vote



accepted










It is not 100% clear what do you want to get.



Please provide more examples with some other expected results.
So far, to give you some ideas of how you can get data you need:



http://sqlfiddle.com/#!9/7eb44f/2



SELECT r.id,
r.race_id,
r.entrant,
r1.entrant as Winner,
r1.time WinnerTime,
r.time
FROM races as r
LEFT JOIN races as r1
ON r1.result = 1
AND r1.race_id = r.race_id
WHERE r.result = 2


UPDATE Your table schema is terrible. to make my query faster for your table you should at least change race_id column type integer (or varchar) but not text! And you need then to create an index over result and race_id columns:



ALTER TABLE races MODIFY race_id INTEGER; 

CREATE INDEX result_race_id ON races (result, race_id);





share|improve this answer























  • I've edited my question now and realise I should have included the unique identifier for each race. Hopefully the addition of the second intended result row from the select statement helps. I've tried some of the responses in this thread, but it seems like they take longer than expected to process.
    – Andrew Abbott
    Nov 8 at 22:09










  • Thanks for the edit. I've now run this on a data table of ~42,000 rows in phpmyadmin, but the query takes around 55 seconds. Is it expected to run slow on a dataset of 42k?
    – Andrew Abbott
    Nov 9 at 15:30










  • Provide your table schema: SHOW CREATE TABLE races;?
    – Alex
    Nov 9 at 15:32










  • OMG! 'time' varchar(256) WHY?
    – Alex
    Nov 9 at 16:07










  • It sometimes contains comments.
    – Andrew Abbott
    Nov 9 at 16:24


















up vote
1
down vote













Your query looks pretty close, you just want to use the correct aliases - so you want r1.time and r1.result instead or r.time and r.result



SELECT r.id, r.entrant, r1.time 
FROM races as r
LEFT JOIN races as r1
ON r1.id > r.id
WHERE r1.result = "2"





share|improve this answer




























    up vote
    1
    down vote













    You can use a correlated query:



    select id, entrant, (
    select time
    from races x
    where race_id = races.race_id AND result = 2
    ) as win_margin
    from races
    where result = 1





    share|improve this answer























    • What is the purpose of the x after races? Is it just an alias? It seems to work fine without it.
      – Andrew Abbott
      Nov 8 at 21:45










    • Yes it is an alias. It'll be useful if you want to reference the outer table (e.g. x.raceid = races.raceid)
      – Salman A
      Nov 8 at 22:36











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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    1
    down vote



    accepted










    It is not 100% clear what do you want to get.



    Please provide more examples with some other expected results.
    So far, to give you some ideas of how you can get data you need:



    http://sqlfiddle.com/#!9/7eb44f/2



    SELECT r.id,
    r.race_id,
    r.entrant,
    r1.entrant as Winner,
    r1.time WinnerTime,
    r.time
    FROM races as r
    LEFT JOIN races as r1
    ON r1.result = 1
    AND r1.race_id = r.race_id
    WHERE r.result = 2


    UPDATE Your table schema is terrible. to make my query faster for your table you should at least change race_id column type integer (or varchar) but not text! And you need then to create an index over result and race_id columns:



    ALTER TABLE races MODIFY race_id INTEGER; 

    CREATE INDEX result_race_id ON races (result, race_id);





    share|improve this answer























    • I've edited my question now and realise I should have included the unique identifier for each race. Hopefully the addition of the second intended result row from the select statement helps. I've tried some of the responses in this thread, but it seems like they take longer than expected to process.
      – Andrew Abbott
      Nov 8 at 22:09










    • Thanks for the edit. I've now run this on a data table of ~42,000 rows in phpmyadmin, but the query takes around 55 seconds. Is it expected to run slow on a dataset of 42k?
      – Andrew Abbott
      Nov 9 at 15:30










    • Provide your table schema: SHOW CREATE TABLE races;?
      – Alex
      Nov 9 at 15:32










    • OMG! 'time' varchar(256) WHY?
      – Alex
      Nov 9 at 16:07










    • It sometimes contains comments.
      – Andrew Abbott
      Nov 9 at 16:24















    up vote
    1
    down vote



    accepted










    It is not 100% clear what do you want to get.



    Please provide more examples with some other expected results.
    So far, to give you some ideas of how you can get data you need:



    http://sqlfiddle.com/#!9/7eb44f/2



    SELECT r.id,
    r.race_id,
    r.entrant,
    r1.entrant as Winner,
    r1.time WinnerTime,
    r.time
    FROM races as r
    LEFT JOIN races as r1
    ON r1.result = 1
    AND r1.race_id = r.race_id
    WHERE r.result = 2


    UPDATE Your table schema is terrible. to make my query faster for your table you should at least change race_id column type integer (or varchar) but not text! And you need then to create an index over result and race_id columns:



    ALTER TABLE races MODIFY race_id INTEGER; 

    CREATE INDEX result_race_id ON races (result, race_id);





    share|improve this answer























    • I've edited my question now and realise I should have included the unique identifier for each race. Hopefully the addition of the second intended result row from the select statement helps. I've tried some of the responses in this thread, but it seems like they take longer than expected to process.
      – Andrew Abbott
      Nov 8 at 22:09










    • Thanks for the edit. I've now run this on a data table of ~42,000 rows in phpmyadmin, but the query takes around 55 seconds. Is it expected to run slow on a dataset of 42k?
      – Andrew Abbott
      Nov 9 at 15:30










    • Provide your table schema: SHOW CREATE TABLE races;?
      – Alex
      Nov 9 at 15:32










    • OMG! 'time' varchar(256) WHY?
      – Alex
      Nov 9 at 16:07










    • It sometimes contains comments.
      – Andrew Abbott
      Nov 9 at 16:24













    up vote
    1
    down vote



    accepted







    up vote
    1
    down vote



    accepted






    It is not 100% clear what do you want to get.



    Please provide more examples with some other expected results.
    So far, to give you some ideas of how you can get data you need:



    http://sqlfiddle.com/#!9/7eb44f/2



    SELECT r.id,
    r.race_id,
    r.entrant,
    r1.entrant as Winner,
    r1.time WinnerTime,
    r.time
    FROM races as r
    LEFT JOIN races as r1
    ON r1.result = 1
    AND r1.race_id = r.race_id
    WHERE r.result = 2


    UPDATE Your table schema is terrible. to make my query faster for your table you should at least change race_id column type integer (or varchar) but not text! And you need then to create an index over result and race_id columns:



    ALTER TABLE races MODIFY race_id INTEGER; 

    CREATE INDEX result_race_id ON races (result, race_id);





    share|improve this answer














    It is not 100% clear what do you want to get.



    Please provide more examples with some other expected results.
    So far, to give you some ideas of how you can get data you need:



    http://sqlfiddle.com/#!9/7eb44f/2



    SELECT r.id,
    r.race_id,
    r.entrant,
    r1.entrant as Winner,
    r1.time WinnerTime,
    r.time
    FROM races as r
    LEFT JOIN races as r1
    ON r1.result = 1
    AND r1.race_id = r.race_id
    WHERE r.result = 2


    UPDATE Your table schema is terrible. to make my query faster for your table you should at least change race_id column type integer (or varchar) but not text! And you need then to create an index over result and race_id columns:



    ALTER TABLE races MODIFY race_id INTEGER; 

    CREATE INDEX result_race_id ON races (result, race_id);






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 9 at 16:13

























    answered Nov 8 at 14:40









    Alex

    14.1k11736




    14.1k11736












    • I've edited my question now and realise I should have included the unique identifier for each race. Hopefully the addition of the second intended result row from the select statement helps. I've tried some of the responses in this thread, but it seems like they take longer than expected to process.
      – Andrew Abbott
      Nov 8 at 22:09










    • Thanks for the edit. I've now run this on a data table of ~42,000 rows in phpmyadmin, but the query takes around 55 seconds. Is it expected to run slow on a dataset of 42k?
      – Andrew Abbott
      Nov 9 at 15:30










    • Provide your table schema: SHOW CREATE TABLE races;?
      – Alex
      Nov 9 at 15:32










    • OMG! 'time' varchar(256) WHY?
      – Alex
      Nov 9 at 16:07










    • It sometimes contains comments.
      – Andrew Abbott
      Nov 9 at 16:24


















    • I've edited my question now and realise I should have included the unique identifier for each race. Hopefully the addition of the second intended result row from the select statement helps. I've tried some of the responses in this thread, but it seems like they take longer than expected to process.
      – Andrew Abbott
      Nov 8 at 22:09










    • Thanks for the edit. I've now run this on a data table of ~42,000 rows in phpmyadmin, but the query takes around 55 seconds. Is it expected to run slow on a dataset of 42k?
      – Andrew Abbott
      Nov 9 at 15:30










    • Provide your table schema: SHOW CREATE TABLE races;?
      – Alex
      Nov 9 at 15:32










    • OMG! 'time' varchar(256) WHY?
      – Alex
      Nov 9 at 16:07










    • It sometimes contains comments.
      – Andrew Abbott
      Nov 9 at 16:24
















    I've edited my question now and realise I should have included the unique identifier for each race. Hopefully the addition of the second intended result row from the select statement helps. I've tried some of the responses in this thread, but it seems like they take longer than expected to process.
    – Andrew Abbott
    Nov 8 at 22:09




    I've edited my question now and realise I should have included the unique identifier for each race. Hopefully the addition of the second intended result row from the select statement helps. I've tried some of the responses in this thread, but it seems like they take longer than expected to process.
    – Andrew Abbott
    Nov 8 at 22:09












    Thanks for the edit. I've now run this on a data table of ~42,000 rows in phpmyadmin, but the query takes around 55 seconds. Is it expected to run slow on a dataset of 42k?
    – Andrew Abbott
    Nov 9 at 15:30




    Thanks for the edit. I've now run this on a data table of ~42,000 rows in phpmyadmin, but the query takes around 55 seconds. Is it expected to run slow on a dataset of 42k?
    – Andrew Abbott
    Nov 9 at 15:30












    Provide your table schema: SHOW CREATE TABLE races;?
    – Alex
    Nov 9 at 15:32




    Provide your table schema: SHOW CREATE TABLE races;?
    – Alex
    Nov 9 at 15:32












    OMG! 'time' varchar(256) WHY?
    – Alex
    Nov 9 at 16:07




    OMG! 'time' varchar(256) WHY?
    – Alex
    Nov 9 at 16:07












    It sometimes contains comments.
    – Andrew Abbott
    Nov 9 at 16:24




    It sometimes contains comments.
    – Andrew Abbott
    Nov 9 at 16:24












    up vote
    1
    down vote













    Your query looks pretty close, you just want to use the correct aliases - so you want r1.time and r1.result instead or r.time and r.result



    SELECT r.id, r.entrant, r1.time 
    FROM races as r
    LEFT JOIN races as r1
    ON r1.id > r.id
    WHERE r1.result = "2"





    share|improve this answer

























      up vote
      1
      down vote













      Your query looks pretty close, you just want to use the correct aliases - so you want r1.time and r1.result instead or r.time and r.result



      SELECT r.id, r.entrant, r1.time 
      FROM races as r
      LEFT JOIN races as r1
      ON r1.id > r.id
      WHERE r1.result = "2"





      share|improve this answer























        up vote
        1
        down vote










        up vote
        1
        down vote









        Your query looks pretty close, you just want to use the correct aliases - so you want r1.time and r1.result instead or r.time and r.result



        SELECT r.id, r.entrant, r1.time 
        FROM races as r
        LEFT JOIN races as r1
        ON r1.id > r.id
        WHERE r1.result = "2"





        share|improve this answer












        Your query looks pretty close, you just want to use the correct aliases - so you want r1.time and r1.result instead or r.time and r.result



        SELECT r.id, r.entrant, r1.time 
        FROM races as r
        LEFT JOIN races as r1
        ON r1.id > r.id
        WHERE r1.result = "2"






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 8 at 14:35









        Ian Kenney

        5,35111636




        5,35111636






















            up vote
            1
            down vote













            You can use a correlated query:



            select id, entrant, (
            select time
            from races x
            where race_id = races.race_id AND result = 2
            ) as win_margin
            from races
            where result = 1





            share|improve this answer























            • What is the purpose of the x after races? Is it just an alias? It seems to work fine without it.
              – Andrew Abbott
              Nov 8 at 21:45










            • Yes it is an alias. It'll be useful if you want to reference the outer table (e.g. x.raceid = races.raceid)
              – Salman A
              Nov 8 at 22:36















            up vote
            1
            down vote













            You can use a correlated query:



            select id, entrant, (
            select time
            from races x
            where race_id = races.race_id AND result = 2
            ) as win_margin
            from races
            where result = 1





            share|improve this answer























            • What is the purpose of the x after races? Is it just an alias? It seems to work fine without it.
              – Andrew Abbott
              Nov 8 at 21:45










            • Yes it is an alias. It'll be useful if you want to reference the outer table (e.g. x.raceid = races.raceid)
              – Salman A
              Nov 8 at 22:36













            up vote
            1
            down vote










            up vote
            1
            down vote









            You can use a correlated query:



            select id, entrant, (
            select time
            from races x
            where race_id = races.race_id AND result = 2
            ) as win_margin
            from races
            where result = 1





            share|improve this answer














            You can use a correlated query:



            select id, entrant, (
            select time
            from races x
            where race_id = races.race_id AND result = 2
            ) as win_margin
            from races
            where result = 1






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 10 at 15:09

























            answered Nov 8 at 14:30









            Salman A

            173k66331419




            173k66331419












            • What is the purpose of the x after races? Is it just an alias? It seems to work fine without it.
              – Andrew Abbott
              Nov 8 at 21:45










            • Yes it is an alias. It'll be useful if you want to reference the outer table (e.g. x.raceid = races.raceid)
              – Salman A
              Nov 8 at 22:36


















            • What is the purpose of the x after races? Is it just an alias? It seems to work fine without it.
              – Andrew Abbott
              Nov 8 at 21:45










            • Yes it is an alias. It'll be useful if you want to reference the outer table (e.g. x.raceid = races.raceid)
              – Salman A
              Nov 8 at 22:36
















            What is the purpose of the x after races? Is it just an alias? It seems to work fine without it.
            – Andrew Abbott
            Nov 8 at 21:45




            What is the purpose of the x after races? Is it just an alias? It seems to work fine without it.
            – Andrew Abbott
            Nov 8 at 21:45












            Yes it is an alias. It'll be useful if you want to reference the outer table (e.g. x.raceid = races.raceid)
            – Salman A
            Nov 8 at 22:36




            Yes it is an alias. It'll be useful if you want to reference the outer table (e.g. x.raceid = races.raceid)
            – Salman A
            Nov 8 at 22:36


















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