Web Scraping with Puppeteer. If can't get a selector multiple times go to another element











up vote
1
down vote

favorite












I'm saving URLs from a playlist of a video player.



The sequence of actions:




  1. Click on a video

  2. Find video element and get it's src

  3. Add src to an array


Everything is going just fine, but sometimes there is an element I can't get it src from. So what I want to do is to try to get element's src for 5 times and if it fails on the 5th time, then I should push the counter's (i) value in the array instead of the URL and click on the next video and get src of the next element. Please let me know how I can do it.



Here is my current code which clicks one by one and gets element's src and just freezes if it can't get element's src:



const links = await page.evaluate((SELECTORS) => {
return new Promise((resolve, reject) => {
const items = document.querySelector(SELECTORS.list).childNodes;
let i = 0;
const urls = ;
const video = document.querySelector(SELECTORS.video);

let counter = 0;
const limit = 10;
var timer = setInterval(() => {
const url = video.getAttribute('src');
if (!urls.includes(url)) {
urls.push(url);
i++;
if (items[i]) {
setTimeout(items[i].click(), 2000);
} else {
clearInterval(timer);
resolve(urls);
}
}
}, 10);
items[0].click();
});
}, SELECTORS);









share|improve this question


























    up vote
    1
    down vote

    favorite












    I'm saving URLs from a playlist of a video player.



    The sequence of actions:




    1. Click on a video

    2. Find video element and get it's src

    3. Add src to an array


    Everything is going just fine, but sometimes there is an element I can't get it src from. So what I want to do is to try to get element's src for 5 times and if it fails on the 5th time, then I should push the counter's (i) value in the array instead of the URL and click on the next video and get src of the next element. Please let me know how I can do it.



    Here is my current code which clicks one by one and gets element's src and just freezes if it can't get element's src:



    const links = await page.evaluate((SELECTORS) => {
    return new Promise((resolve, reject) => {
    const items = document.querySelector(SELECTORS.list).childNodes;
    let i = 0;
    const urls = ;
    const video = document.querySelector(SELECTORS.video);

    let counter = 0;
    const limit = 10;
    var timer = setInterval(() => {
    const url = video.getAttribute('src');
    if (!urls.includes(url)) {
    urls.push(url);
    i++;
    if (items[i]) {
    setTimeout(items[i].click(), 2000);
    } else {
    clearInterval(timer);
    resolve(urls);
    }
    }
    }, 10);
    items[0].click();
    });
    }, SELECTORS);









    share|improve this question
























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      I'm saving URLs from a playlist of a video player.



      The sequence of actions:




      1. Click on a video

      2. Find video element and get it's src

      3. Add src to an array


      Everything is going just fine, but sometimes there is an element I can't get it src from. So what I want to do is to try to get element's src for 5 times and if it fails on the 5th time, then I should push the counter's (i) value in the array instead of the URL and click on the next video and get src of the next element. Please let me know how I can do it.



      Here is my current code which clicks one by one and gets element's src and just freezes if it can't get element's src:



      const links = await page.evaluate((SELECTORS) => {
      return new Promise((resolve, reject) => {
      const items = document.querySelector(SELECTORS.list).childNodes;
      let i = 0;
      const urls = ;
      const video = document.querySelector(SELECTORS.video);

      let counter = 0;
      const limit = 10;
      var timer = setInterval(() => {
      const url = video.getAttribute('src');
      if (!urls.includes(url)) {
      urls.push(url);
      i++;
      if (items[i]) {
      setTimeout(items[i].click(), 2000);
      } else {
      clearInterval(timer);
      resolve(urls);
      }
      }
      }, 10);
      items[0].click();
      });
      }, SELECTORS);









      share|improve this question













      I'm saving URLs from a playlist of a video player.



      The sequence of actions:




      1. Click on a video

      2. Find video element and get it's src

      3. Add src to an array


      Everything is going just fine, but sometimes there is an element I can't get it src from. So what I want to do is to try to get element's src for 5 times and if it fails on the 5th time, then I should push the counter's (i) value in the array instead of the URL and click on the next video and get src of the next element. Please let me know how I can do it.



      Here is my current code which clicks one by one and gets element's src and just freezes if it can't get element's src:



      const links = await page.evaluate((SELECTORS) => {
      return new Promise((resolve, reject) => {
      const items = document.querySelector(SELECTORS.list).childNodes;
      let i = 0;
      const urls = ;
      const video = document.querySelector(SELECTORS.video);

      let counter = 0;
      const limit = 10;
      var timer = setInterval(() => {
      const url = video.getAttribute('src');
      if (!urls.includes(url)) {
      urls.push(url);
      i++;
      if (items[i]) {
      setTimeout(items[i].click(), 2000);
      } else {
      clearInterval(timer);
      resolve(urls);
      }
      }
      }, 10);
      items[0].click();
      });
      }, SELECTORS);






      javascript web-scraping puppeteer






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 8 at 13:53









      Bong2000

      385




      385





























          active

          oldest

          votes











          Your Answer






          StackExchange.ifUsing("editor", function () {
          StackExchange.using("externalEditor", function () {
          StackExchange.using("snippets", function () {
          StackExchange.snippets.init();
          });
          });
          }, "code-snippets");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "1"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53209146%2fweb-scraping-with-puppeteer-if-cant-get-a-selector-multiple-times-go-to-anothe%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown






























          active

          oldest

          votes













          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes
















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Stack Overflow!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          To learn more, see our tips on writing great answers.





          Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


          Please pay close attention to the following guidance:


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53209146%2fweb-scraping-with-puppeteer-if-cant-get-a-selector-multiple-times-go-to-anothe%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          這個網誌中的熱門文章

          Xamarin.form Move up view when keyboard appear

          Post-Redirect-Get with Spring WebFlux and Thymeleaf

          Anylogic : not able to use stopDelay()