Excel VBA Pivot Table Filter
I am trying to do a VBA code for Microsoft Excel to filter our a few items out of many (e.g. 3 items out of 100) from a pivot table. So far the method I've been using is by declaring items I do not want to be false such as:
.PivotItems("Item A").Visible = True
.PivotItems("Item B").Visible = True
.PivotItems("Item C").Visible = False
.PivotItems("Item D").Visible = False
.PivotItems("Item E").Visible = False
However this gets tedious in the future as there maybe more items added to the table and which means I would need to edit the codes every time there is a new item added.
Is there a way to filter out two or more items without using
.Visible=false
such as
pf.CurrentPage = "Item A" + "Item B"
excel vba excel-vba
asked Nov 15 '18 at 2:56
KeithKeith
32
add a comment |
I am trying to do a VBA code for Microsoft Excel to filter our a few items out of many (e.g. 3 items out of 100) from a pivot table. So far the method I've been using is by declaring items I do not want to be false such as:
.PivotItems("Item A").Visible = True
.PivotItems("Item B").Visible = True
.PivotItems("Item C").Visible = False
.PivotItems("Item D").Visible = False
.PivotItems("Item E").Visible = False
However this gets tedious in the future as there maybe more items added to the table and which means I would need to edit the codes every time there is a new item added.
Is there a way to filter out two or more items without using
.Visible=false
such as
pf.CurrentPage = "Item A" + "Item B"
excel vba excel-vba
asked Nov 15 '18 at 2:56
KeithKeith
32
add a comment |
I am trying to do a VBA code for Microsoft Excel to filter our a few items out of many (e.g. 3 items out of 100) from a pivot table. So far the method I've been using is by declaring items I do not want to be false such as:
.PivotItems("Item A").Visible = True
.PivotItems("Item B").Visible = True
.PivotItems("Item C").Visible = False
.PivotItems("Item D").Visible = False
.PivotItems("Item E").Visible = False
However this gets tedious in the future as there maybe more items added to the table and which means I would need to edit the codes every time there is a new item added.
Is there a way to filter out two or more items without using
.Visible=false
such as
pf.CurrentPage = "Item A" + "Item B"
excel vba excel-vba
asked Nov 15 '18 at 2:56
KeithKeith
32
I am trying to do a VBA code for Microsoft Excel to filter our a few items out of many (e.g. 3 items out of 100) from a pivot table. So far the method I've been using is by declaring items I do not want to be false such as:
.PivotItems("Item A").Visible = True
.PivotItems("Item B").Visible = True
.PivotItems("Item C").Visible = False
.PivotItems("Item D").Visible = False
.PivotItems("Item E").Visible = False
However this gets tedious in the future as there maybe more items added to the table and which means I would need to edit the codes every time there is a new item added.
Is there a way to filter out two or more items without using
.Visible=false
such as
pf.CurrentPage = "Item A" + "Item B"
excel vba excel-vba
excel vba excel-vba
asked Nov 15 '18 at 2:56
KeithKeith
32
asked Nov 15 '18 at 2:56
KeithKeith
32
asked Nov 15 '18 at 2:56
KeithKeith
32
asked Nov 15 '18 at 2:56
KeithKeith
32
asked Nov 15 '18 at 2:56
KeithKeith
32
32
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You can use an array of items:
Dim arr() As Variant
' Array of items to be kept visible (or hidden depending on your code)
arr = Array("Item 1", "Item 2", "Item 2")
For Each itm In pt.PivotFields("Value").PivotItems
If Not IsError(Application.Match(itm.Caption, arr, 0)) Then
itm.Visible = True
Else
itm.Visible = False
End If
Next
answered Nov 15 '18 at 3:40
Michal RosaMichal Rosa
1,3191814
This is exactly what I was looking for! Thanks a bunch!
– Keith
Nov 15 '18 at 9:53
Welcome and please mark the question as answered.
– Michal Rosa
Nov 15 '18 at 10:13
add a comment |
You'll have to adapt pivot table and field names but this works on my test:
Sub filter_pivot()
Dim i As Integer
ActiveSheet.PivotTables("PivotTable1").ClearAllFilters
With ActiveSheet.PivotTables("PivotTable1").PivotFields("CLCL")
For i = 1 To .PivotItems.Count
Debug.Print .PivotItems(i)
Select Case .PivotItems(i).Name
Case Is = "Item C"
.PivotItems(i).Visible = False
Case Is = "Item D"
.PivotItems(i).Visible = False
Case Is = "Item E"
.PivotItems(i).Visible = False
End Select
Next i
End With
End Sub
We're still using .Visible but it does not matter how many new items you add.
answered Nov 15 '18 at 3:27
Display nameDisplay name
54416
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use an array of items:
Dim arr() As Variant
' Array of items to be kept visible (or hidden depending on your code)
arr = Array("Item 1", "Item 2", "Item 2")
For Each itm In pt.PivotFields("Value").PivotItems
If Not IsError(Application.Match(itm.Caption, arr, 0)) Then
itm.Visible = True
Else
itm.Visible = False
End If
Next
answered Nov 15 '18 at 3:40
Michal RosaMichal Rosa
1,3191814
This is exactly what I was looking for! Thanks a bunch!
– Keith
Nov 15 '18 at 9:53
Welcome and please mark the question as answered.
– Michal Rosa
Nov 15 '18 at 10:13
add a comment |
You can use an array of items:
Dim arr() As Variant
' Array of items to be kept visible (or hidden depending on your code)
arr = Array("Item 1", "Item 2", "Item 2")
For Each itm In pt.PivotFields("Value").PivotItems
If Not IsError(Application.Match(itm.Caption, arr, 0)) Then
itm.Visible = True
Else
itm.Visible = False
End If
Next
answered Nov 15 '18 at 3:40
Michal RosaMichal Rosa
1,3191814
This is exactly what I was looking for! Thanks a bunch!
– Keith
Nov 15 '18 at 9:53
Welcome and please mark the question as answered.
– Michal Rosa
Nov 15 '18 at 10:13
add a comment |
You can use an array of items:
Dim arr() As Variant
' Array of items to be kept visible (or hidden depending on your code)
arr = Array("Item 1", "Item 2", "Item 2")
For Each itm In pt.PivotFields("Value").PivotItems
If Not IsError(Application.Match(itm.Caption, arr, 0)) Then
itm.Visible = True
Else
itm.Visible = False
End If
Next
answered Nov 15 '18 at 3:40
Michal RosaMichal Rosa
1,3191814
You can use an array of items:
Dim arr() As Variant
' Array of items to be kept visible (or hidden depending on your code)
arr = Array("Item 1", "Item 2", "Item 2")
For Each itm In pt.PivotFields("Value").PivotItems
If Not IsError(Application.Match(itm.Caption, arr, 0)) Then
itm.Visible = True
Else
itm.Visible = False
End If
Next
answered Nov 15 '18 at 3:40
Michal RosaMichal Rosa
1,3191814
answered Nov 15 '18 at 3:40
Michal RosaMichal Rosa
1,3191814
answered Nov 15 '18 at 3:40
Michal RosaMichal Rosa
1,3191814
answered Nov 15 '18 at 3:40
Michal RosaMichal Rosa
1,3191814
1,3191814
This is exactly what I was looking for! Thanks a bunch!
– Keith
Nov 15 '18 at 9:53
Welcome and please mark the question as answered.
– Michal Rosa
Nov 15 '18 at 10:13
add a comment |
This is exactly what I was looking for! Thanks a bunch!
– Keith
Nov 15 '18 at 9:53
Welcome and please mark the question as answered.
– Michal Rosa
Nov 15 '18 at 10:13
This is exactly what I was looking for! Thanks a bunch!
– Keith
Nov 15 '18 at 9:53
This is exactly what I was looking for! Thanks a bunch!
– Keith
Nov 15 '18 at 9:53
Welcome and please mark the question as answered.
– Michal Rosa
Nov 15 '18 at 10:13
Welcome and please mark the question as answered.
– Michal Rosa
Nov 15 '18 at 10:13
add a comment |
You'll have to adapt pivot table and field names but this works on my test:
Sub filter_pivot()
Dim i As Integer
ActiveSheet.PivotTables("PivotTable1").ClearAllFilters
With ActiveSheet.PivotTables("PivotTable1").PivotFields("CLCL")
For i = 1 To .PivotItems.Count
Debug.Print .PivotItems(i)
Select Case .PivotItems(i).Name
Case Is = "Item C"
.PivotItems(i).Visible = False
Case Is = "Item D"
.PivotItems(i).Visible = False
Case Is = "Item E"
.PivotItems(i).Visible = False
End Select
Next i
End With
End Sub
We're still using .Visible but it does not matter how many new items you add.
answered Nov 15 '18 at 3:27
Display nameDisplay name
54416
add a comment |
You'll have to adapt pivot table and field names but this works on my test:
Sub filter_pivot()
Dim i As Integer
ActiveSheet.PivotTables("PivotTable1").ClearAllFilters
With ActiveSheet.PivotTables("PivotTable1").PivotFields("CLCL")
For i = 1 To .PivotItems.Count
Debug.Print .PivotItems(i)
Select Case .PivotItems(i).Name
Case Is = "Item C"
.PivotItems(i).Visible = False
Case Is = "Item D"
.PivotItems(i).Visible = False
Case Is = "Item E"
.PivotItems(i).Visible = False
End Select
Next i
End With
End Sub
We're still using .Visible but it does not matter how many new items you add.
answered Nov 15 '18 at 3:27
Display nameDisplay name
54416
add a comment |
You'll have to adapt pivot table and field names but this works on my test:
Sub filter_pivot()
Dim i As Integer
ActiveSheet.PivotTables("PivotTable1").ClearAllFilters
With ActiveSheet.PivotTables("PivotTable1").PivotFields("CLCL")
For i = 1 To .PivotItems.Count
Debug.Print .PivotItems(i)
Select Case .PivotItems(i).Name
Case Is = "Item C"
.PivotItems(i).Visible = False
Case Is = "Item D"
.PivotItems(i).Visible = False
Case Is = "Item E"
.PivotItems(i).Visible = False
End Select
Next i
End With
End Sub
We're still using .Visible but it does not matter how many new items you add.
answered Nov 15 '18 at 3:27
Display nameDisplay name
54416
You'll have to adapt pivot table and field names but this works on my test:
Sub filter_pivot()
Dim i As Integer
ActiveSheet.PivotTables("PivotTable1").ClearAllFilters
With ActiveSheet.PivotTables("PivotTable1").PivotFields("CLCL")
For i = 1 To .PivotItems.Count
Debug.Print .PivotItems(i)
Select Case .PivotItems(i).Name
Case Is = "Item C"
.PivotItems(i).Visible = False
Case Is = "Item D"
.PivotItems(i).Visible = False
Case Is = "Item E"
.PivotItems(i).Visible = False
End Select
Next i
End With
End Sub
We're still using .Visible but it does not matter how many new items you add.
answered Nov 15 '18 at 3:27
Display nameDisplay name
54416
edited Nov 15 '18 at 3:36
answered Nov 15 '18 at 3:27
Display nameDisplay name
54416
answered Nov 15 '18 at 3:27
Display nameDisplay name
54416
answered Nov 15 '18 at 3:27
Display nameDisplay name
54416
54416
add a comment |
add a comment |
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