Non-structured table to narrow format table transformation?












-6















I need to make the data go from Example 1 to Example 2.



# Example 1
data.frame(Player = c("Brad Abbey", "Wins", "Losses", "Neither", "Caleb Aekins", "Wins", "Losses", "Neither"),
No = c(1, NA, NA, NA))

# Player No
# 1 Brad Abbey 1
# 2 Wins NA
# 3 Losses NA
# 4 Neither NA
# 5 Caleb Aekins 1
# 6 Wins NA
# 7 Losses NA
# 8 Neither NA


# Example 2
structure(list(Player = structure(c(1L, 1L, 1L, 1L, 2L, 2L, 2L,
2L), .Label = c("Brad Abbey", "Caleb Aekins"), class = "factor"),
Result = structure(c(3L, 4L, 1L, 2L, 3L, 4L, 1L, 2L), class = "factor",
.Label = c("Losses",
"Neither", "Overall", "Wins"))), class = "data.frame", row.names = c(NA,
-8L))

# Player Result
# 1 Brad Abbey Overall
# 2 Brad Abbey Wins
# 3 Brad Abbey Losses
# 4 Brad Abbey Neither
# 5 Caleb Aekins Overall
# 6 Caleb Aekins Wins
# 7 Caleb Aekins Losses
# 8 Caleb Aekins Neither


How can I move 'wins', 'losses' and 'neither' to the column next to it, while copying the person's name down to the rows below it?










share|improve this question

























  • 1. Copy the Player column to a new column, Result. 2. Where Player == Result, Result = "Overall.

    – Marius
    Nov 15 '18 at 3:09






  • 1





    Please provide example data as plain text (using e.g. dput), not images, so as users can easily copy/paste it.

    – neilfws
    Nov 15 '18 at 3:12











  • Welcome to SO Adrian! Please have a read and update your question accordingly: stackoverflow.com/questions/5963269/…

    – snoram
    Nov 15 '18 at 9:28
















-6















I need to make the data go from Example 1 to Example 2.



# Example 1
data.frame(Player = c("Brad Abbey", "Wins", "Losses", "Neither", "Caleb Aekins", "Wins", "Losses", "Neither"),
No = c(1, NA, NA, NA))

# Player No
# 1 Brad Abbey 1
# 2 Wins NA
# 3 Losses NA
# 4 Neither NA
# 5 Caleb Aekins 1
# 6 Wins NA
# 7 Losses NA
# 8 Neither NA


# Example 2
structure(list(Player = structure(c(1L, 1L, 1L, 1L, 2L, 2L, 2L,
2L), .Label = c("Brad Abbey", "Caleb Aekins"), class = "factor"),
Result = structure(c(3L, 4L, 1L, 2L, 3L, 4L, 1L, 2L), class = "factor",
.Label = c("Losses",
"Neither", "Overall", "Wins"))), class = "data.frame", row.names = c(NA,
-8L))

# Player Result
# 1 Brad Abbey Overall
# 2 Brad Abbey Wins
# 3 Brad Abbey Losses
# 4 Brad Abbey Neither
# 5 Caleb Aekins Overall
# 6 Caleb Aekins Wins
# 7 Caleb Aekins Losses
# 8 Caleb Aekins Neither


How can I move 'wins', 'losses' and 'neither' to the column next to it, while copying the person's name down to the rows below it?










share|improve this question

























  • 1. Copy the Player column to a new column, Result. 2. Where Player == Result, Result = "Overall.

    – Marius
    Nov 15 '18 at 3:09






  • 1





    Please provide example data as plain text (using e.g. dput), not images, so as users can easily copy/paste it.

    – neilfws
    Nov 15 '18 at 3:12











  • Welcome to SO Adrian! Please have a read and update your question accordingly: stackoverflow.com/questions/5963269/…

    – snoram
    Nov 15 '18 at 9:28














-6












-6








-6








I need to make the data go from Example 1 to Example 2.



# Example 1
data.frame(Player = c("Brad Abbey", "Wins", "Losses", "Neither", "Caleb Aekins", "Wins", "Losses", "Neither"),
No = c(1, NA, NA, NA))

# Player No
# 1 Brad Abbey 1
# 2 Wins NA
# 3 Losses NA
# 4 Neither NA
# 5 Caleb Aekins 1
# 6 Wins NA
# 7 Losses NA
# 8 Neither NA


# Example 2
structure(list(Player = structure(c(1L, 1L, 1L, 1L, 2L, 2L, 2L,
2L), .Label = c("Brad Abbey", "Caleb Aekins"), class = "factor"),
Result = structure(c(3L, 4L, 1L, 2L, 3L, 4L, 1L, 2L), class = "factor",
.Label = c("Losses",
"Neither", "Overall", "Wins"))), class = "data.frame", row.names = c(NA,
-8L))

# Player Result
# 1 Brad Abbey Overall
# 2 Brad Abbey Wins
# 3 Brad Abbey Losses
# 4 Brad Abbey Neither
# 5 Caleb Aekins Overall
# 6 Caleb Aekins Wins
# 7 Caleb Aekins Losses
# 8 Caleb Aekins Neither


How can I move 'wins', 'losses' and 'neither' to the column next to it, while copying the person's name down to the rows below it?










share|improve this question
















I need to make the data go from Example 1 to Example 2.



# Example 1
data.frame(Player = c("Brad Abbey", "Wins", "Losses", "Neither", "Caleb Aekins", "Wins", "Losses", "Neither"),
No = c(1, NA, NA, NA))

# Player No
# 1 Brad Abbey 1
# 2 Wins NA
# 3 Losses NA
# 4 Neither NA
# 5 Caleb Aekins 1
# 6 Wins NA
# 7 Losses NA
# 8 Neither NA


# Example 2
structure(list(Player = structure(c(1L, 1L, 1L, 1L, 2L, 2L, 2L,
2L), .Label = c("Brad Abbey", "Caleb Aekins"), class = "factor"),
Result = structure(c(3L, 4L, 1L, 2L, 3L, 4L, 1L, 2L), class = "factor",
.Label = c("Losses",
"Neither", "Overall", "Wins"))), class = "data.frame", row.names = c(NA,
-8L))

# Player Result
# 1 Brad Abbey Overall
# 2 Brad Abbey Wins
# 3 Brad Abbey Losses
# 4 Brad Abbey Neither
# 5 Caleb Aekins Overall
# 6 Caleb Aekins Wins
# 7 Caleb Aekins Losses
# 8 Caleb Aekins Neither


How can I move 'wins', 'losses' and 'neither' to the column next to it, while copying the person's name down to the rows below it?







r dataframe






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edited Dec 19 '18 at 9:38









Artem

1,7392727




1,7392727










asked Nov 15 '18 at 3:06









Adrian SAdrian S

1




1













  • 1. Copy the Player column to a new column, Result. 2. Where Player == Result, Result = "Overall.

    – Marius
    Nov 15 '18 at 3:09






  • 1





    Please provide example data as plain text (using e.g. dput), not images, so as users can easily copy/paste it.

    – neilfws
    Nov 15 '18 at 3:12











  • Welcome to SO Adrian! Please have a read and update your question accordingly: stackoverflow.com/questions/5963269/…

    – snoram
    Nov 15 '18 at 9:28



















  • 1. Copy the Player column to a new column, Result. 2. Where Player == Result, Result = "Overall.

    – Marius
    Nov 15 '18 at 3:09






  • 1





    Please provide example data as plain text (using e.g. dput), not images, so as users can easily copy/paste it.

    – neilfws
    Nov 15 '18 at 3:12











  • Welcome to SO Adrian! Please have a read and update your question accordingly: stackoverflow.com/questions/5963269/…

    – snoram
    Nov 15 '18 at 9:28

















1. Copy the Player column to a new column, Result. 2. Where Player == Result, Result = "Overall.

– Marius
Nov 15 '18 at 3:09





1. Copy the Player column to a new column, Result. 2. Where Player == Result, Result = "Overall.

– Marius
Nov 15 '18 at 3:09




1




1





Please provide example data as plain text (using e.g. dput), not images, so as users can easily copy/paste it.

– neilfws
Nov 15 '18 at 3:12





Please provide example data as plain text (using e.g. dput), not images, so as users can easily copy/paste it.

– neilfws
Nov 15 '18 at 3:12













Welcome to SO Adrian! Please have a read and update your question accordingly: stackoverflow.com/questions/5963269/…

– snoram
Nov 15 '18 at 9:28





Welcome to SO Adrian! Please have a read and update your question accordingly: stackoverflow.com/questions/5963269/…

– snoram
Nov 15 '18 at 9:28












1 Answer
1






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oldest

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0














You could extract players' names from the colum Players using setdiff function. Then create an output table with each player name repeated 4 times as well as cycle known Result outcomes c("Overall","Wins", "Losses", "Neither").



Please see the code below



df <- data.frame(Player = c("Brad Abbey", "Wins", "Losses", "Neither", "Caleb Aekins", "Wins", "Losses", "Neither"),
No = c(1, NA, NA, NA))

outcome <- c("Overall","Wins", "Losses", "Neither")
name <- setdiff(unique(df$Player), outcome)
res <- data.frame(Player = unlist(lapply(name, rep, 4)), Result = outcome)
res


Output:



        Player  Result
1 Brad Abbey Overall
2 Brad Abbey Wins
3 Brad Abbey Losses
4 Brad Abbey Neither
5 Caleb Aekins Overall
6 Caleb Aekins Wins
7 Caleb Aekins Losses
8 Caleb Aekins Neither





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    1 Answer
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    0














    You could extract players' names from the colum Players using setdiff function. Then create an output table with each player name repeated 4 times as well as cycle known Result outcomes c("Overall","Wins", "Losses", "Neither").



    Please see the code below



    df <- data.frame(Player = c("Brad Abbey", "Wins", "Losses", "Neither", "Caleb Aekins", "Wins", "Losses", "Neither"),
    No = c(1, NA, NA, NA))

    outcome <- c("Overall","Wins", "Losses", "Neither")
    name <- setdiff(unique(df$Player), outcome)
    res <- data.frame(Player = unlist(lapply(name, rep, 4)), Result = outcome)
    res


    Output:



            Player  Result
    1 Brad Abbey Overall
    2 Brad Abbey Wins
    3 Brad Abbey Losses
    4 Brad Abbey Neither
    5 Caleb Aekins Overall
    6 Caleb Aekins Wins
    7 Caleb Aekins Losses
    8 Caleb Aekins Neither





    share|improve this answer






























      0














      You could extract players' names from the colum Players using setdiff function. Then create an output table with each player name repeated 4 times as well as cycle known Result outcomes c("Overall","Wins", "Losses", "Neither").



      Please see the code below



      df <- data.frame(Player = c("Brad Abbey", "Wins", "Losses", "Neither", "Caleb Aekins", "Wins", "Losses", "Neither"),
      No = c(1, NA, NA, NA))

      outcome <- c("Overall","Wins", "Losses", "Neither")
      name <- setdiff(unique(df$Player), outcome)
      res <- data.frame(Player = unlist(lapply(name, rep, 4)), Result = outcome)
      res


      Output:



              Player  Result
      1 Brad Abbey Overall
      2 Brad Abbey Wins
      3 Brad Abbey Losses
      4 Brad Abbey Neither
      5 Caleb Aekins Overall
      6 Caleb Aekins Wins
      7 Caleb Aekins Losses
      8 Caleb Aekins Neither





      share|improve this answer




























        0












        0








        0







        You could extract players' names from the colum Players using setdiff function. Then create an output table with each player name repeated 4 times as well as cycle known Result outcomes c("Overall","Wins", "Losses", "Neither").



        Please see the code below



        df <- data.frame(Player = c("Brad Abbey", "Wins", "Losses", "Neither", "Caleb Aekins", "Wins", "Losses", "Neither"),
        No = c(1, NA, NA, NA))

        outcome <- c("Overall","Wins", "Losses", "Neither")
        name <- setdiff(unique(df$Player), outcome)
        res <- data.frame(Player = unlist(lapply(name, rep, 4)), Result = outcome)
        res


        Output:



                Player  Result
        1 Brad Abbey Overall
        2 Brad Abbey Wins
        3 Brad Abbey Losses
        4 Brad Abbey Neither
        5 Caleb Aekins Overall
        6 Caleb Aekins Wins
        7 Caleb Aekins Losses
        8 Caleb Aekins Neither





        share|improve this answer















        You could extract players' names from the colum Players using setdiff function. Then create an output table with each player name repeated 4 times as well as cycle known Result outcomes c("Overall","Wins", "Losses", "Neither").



        Please see the code below



        df <- data.frame(Player = c("Brad Abbey", "Wins", "Losses", "Neither", "Caleb Aekins", "Wins", "Losses", "Neither"),
        No = c(1, NA, NA, NA))

        outcome <- c("Overall","Wins", "Losses", "Neither")
        name <- setdiff(unique(df$Player), outcome)
        res <- data.frame(Player = unlist(lapply(name, rep, 4)), Result = outcome)
        res


        Output:



                Player  Result
        1 Brad Abbey Overall
        2 Brad Abbey Wins
        3 Brad Abbey Losses
        4 Brad Abbey Neither
        5 Caleb Aekins Overall
        6 Caleb Aekins Wins
        7 Caleb Aekins Losses
        8 Caleb Aekins Neither






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Dec 19 '18 at 6:44

























        answered Dec 19 '18 at 6:22









        ArtemArtem

        1,7392727




        1,7392727






























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