How extract values from this list (from rgbif) and convert it in data frame in R?












0















I have this list l



l

$`5216014`
$`5216014`[[1]]
name key rank
1 Animalia 1 kingdom
2 Chordata 44 phylum
3 Elasmobranchii 121 class
4 Rajiformes 884 order
5 Rajidae 5877 family
6 Raja 2342057 genus
7 Raja montagui 5216014 species


$`5216208`
$`5216208`[[1]]
name key rank
1 Animalia 1 kingdom
2 Chordata 44 phylum
3 Elasmobranchii 121 class
4 Rajiformes 884 order
5 Rajidae 5877 family
6 Amblyraja 2420436 genus
7 Amblyraja radiata 2420446 species


I would like to extract only row number 7 for column name and key and to create a database like this:



df

name key
Raja montagui 5216014
Amblyraja radiata 2420446


I tried with lapply function:



lapply(l,function(x) x[7])


but the result is this:



$`5216014`
$`5216014`[[1]]
NULL


$`5216208`
$`5216208`[[1]]
NULL


I tried to transform l in a data frame:



data.frame(matrix(unlist(l)))


but I obtained one big column with all data as:



kingdom
phylum
class
order
family
genus
species
Animalia
Chordata
Elasmobranchii
4943
Rajiformes
Rajidae
Raja
Raja montagui
1
44
121
884
5877
2342057
5216014
4954
kingdom
phylum
class
order
family
genus
species
Animalia
Chordata
Elasmobranchii
Rajiformes
4965
Rajidae
Amblyraja
Amblyraja radiata
1
44
121
884
5877
2420436
2420446
kingdom
phylum
class
order
family
genus
species


Where am I wrong?



P.S: this kind of list l is an output of packages rgbif, with code:



    keySpecies <- c(5216014,2420446)
l.1 <- occ_search(taxonKey=keySpecies,
limit=1, return='hier',
curlopts=list(verbose=F))
l <- l.1[c(1:length(unique(keySpecies)))] #cut all element of list that are not useful









share|improve this question



























    0















    I have this list l



    l

    $`5216014`
    $`5216014`[[1]]
    name key rank
    1 Animalia 1 kingdom
    2 Chordata 44 phylum
    3 Elasmobranchii 121 class
    4 Rajiformes 884 order
    5 Rajidae 5877 family
    6 Raja 2342057 genus
    7 Raja montagui 5216014 species


    $`5216208`
    $`5216208`[[1]]
    name key rank
    1 Animalia 1 kingdom
    2 Chordata 44 phylum
    3 Elasmobranchii 121 class
    4 Rajiformes 884 order
    5 Rajidae 5877 family
    6 Amblyraja 2420436 genus
    7 Amblyraja radiata 2420446 species


    I would like to extract only row number 7 for column name and key and to create a database like this:



    df

    name key
    Raja montagui 5216014
    Amblyraja radiata 2420446


    I tried with lapply function:



    lapply(l,function(x) x[7])


    but the result is this:



    $`5216014`
    $`5216014`[[1]]
    NULL


    $`5216208`
    $`5216208`[[1]]
    NULL


    I tried to transform l in a data frame:



    data.frame(matrix(unlist(l)))


    but I obtained one big column with all data as:



    kingdom
    phylum
    class
    order
    family
    genus
    species
    Animalia
    Chordata
    Elasmobranchii
    4943
    Rajiformes
    Rajidae
    Raja
    Raja montagui
    1
    44
    121
    884
    5877
    2342057
    5216014
    4954
    kingdom
    phylum
    class
    order
    family
    genus
    species
    Animalia
    Chordata
    Elasmobranchii
    Rajiformes
    4965
    Rajidae
    Amblyraja
    Amblyraja radiata
    1
    44
    121
    884
    5877
    2420436
    2420446
    kingdom
    phylum
    class
    order
    family
    genus
    species


    Where am I wrong?



    P.S: this kind of list l is an output of packages rgbif, with code:



        keySpecies <- c(5216014,2420446)
    l.1 <- occ_search(taxonKey=keySpecies,
    limit=1, return='hier',
    curlopts=list(verbose=F))
    l <- l.1[c(1:length(unique(keySpecies)))] #cut all element of list that are not useful









    share|improve this question

























      0












      0








      0








      I have this list l



      l

      $`5216014`
      $`5216014`[[1]]
      name key rank
      1 Animalia 1 kingdom
      2 Chordata 44 phylum
      3 Elasmobranchii 121 class
      4 Rajiformes 884 order
      5 Rajidae 5877 family
      6 Raja 2342057 genus
      7 Raja montagui 5216014 species


      $`5216208`
      $`5216208`[[1]]
      name key rank
      1 Animalia 1 kingdom
      2 Chordata 44 phylum
      3 Elasmobranchii 121 class
      4 Rajiformes 884 order
      5 Rajidae 5877 family
      6 Amblyraja 2420436 genus
      7 Amblyraja radiata 2420446 species


      I would like to extract only row number 7 for column name and key and to create a database like this:



      df

      name key
      Raja montagui 5216014
      Amblyraja radiata 2420446


      I tried with lapply function:



      lapply(l,function(x) x[7])


      but the result is this:



      $`5216014`
      $`5216014`[[1]]
      NULL


      $`5216208`
      $`5216208`[[1]]
      NULL


      I tried to transform l in a data frame:



      data.frame(matrix(unlist(l)))


      but I obtained one big column with all data as:



      kingdom
      phylum
      class
      order
      family
      genus
      species
      Animalia
      Chordata
      Elasmobranchii
      4943
      Rajiformes
      Rajidae
      Raja
      Raja montagui
      1
      44
      121
      884
      5877
      2342057
      5216014
      4954
      kingdom
      phylum
      class
      order
      family
      genus
      species
      Animalia
      Chordata
      Elasmobranchii
      Rajiformes
      4965
      Rajidae
      Amblyraja
      Amblyraja radiata
      1
      44
      121
      884
      5877
      2420436
      2420446
      kingdom
      phylum
      class
      order
      family
      genus
      species


      Where am I wrong?



      P.S: this kind of list l is an output of packages rgbif, with code:



          keySpecies <- c(5216014,2420446)
      l.1 <- occ_search(taxonKey=keySpecies,
      limit=1, return='hier',
      curlopts=list(verbose=F))
      l <- l.1[c(1:length(unique(keySpecies)))] #cut all element of list that are not useful









      share|improve this question














      I have this list l



      l

      $`5216014`
      $`5216014`[[1]]
      name key rank
      1 Animalia 1 kingdom
      2 Chordata 44 phylum
      3 Elasmobranchii 121 class
      4 Rajiformes 884 order
      5 Rajidae 5877 family
      6 Raja 2342057 genus
      7 Raja montagui 5216014 species


      $`5216208`
      $`5216208`[[1]]
      name key rank
      1 Animalia 1 kingdom
      2 Chordata 44 phylum
      3 Elasmobranchii 121 class
      4 Rajiformes 884 order
      5 Rajidae 5877 family
      6 Amblyraja 2420436 genus
      7 Amblyraja radiata 2420446 species


      I would like to extract only row number 7 for column name and key and to create a database like this:



      df

      name key
      Raja montagui 5216014
      Amblyraja radiata 2420446


      I tried with lapply function:



      lapply(l,function(x) x[7])


      but the result is this:



      $`5216014`
      $`5216014`[[1]]
      NULL


      $`5216208`
      $`5216208`[[1]]
      NULL


      I tried to transform l in a data frame:



      data.frame(matrix(unlist(l)))


      but I obtained one big column with all data as:



      kingdom
      phylum
      class
      order
      family
      genus
      species
      Animalia
      Chordata
      Elasmobranchii
      4943
      Rajiformes
      Rajidae
      Raja
      Raja montagui
      1
      44
      121
      884
      5877
      2342057
      5216014
      4954
      kingdom
      phylum
      class
      order
      family
      genus
      species
      Animalia
      Chordata
      Elasmobranchii
      Rajiformes
      4965
      Rajidae
      Amblyraja
      Amblyraja radiata
      1
      44
      121
      884
      5877
      2420436
      2420446
      kingdom
      phylum
      class
      order
      family
      genus
      species


      Where am I wrong?



      P.S: this kind of list l is an output of packages rgbif, with code:



          keySpecies <- c(5216014,2420446)
      l.1 <- occ_search(taxonKey=keySpecies,
      limit=1, return='hier',
      curlopts=list(verbose=F))
      l <- l.1[c(1:length(unique(keySpecies)))] #cut all element of list that are not useful






      r list dataframe lapply






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 13 '18 at 14:23









      skyloboskylobo

      766




      766
























          1 Answer
          1






          active

          oldest

          votes


















          1














          lapply(l,function(x) x[7]) is close, but you need to index [row, column], not just [row]. Instead do this:



          res = lapply(l,function(x) x[7, c("name", "key")])
          # or more simply
          res = lapply(l, "[", 7, c("name", "key"))


          This will still give you a list, which you'll need to combine together into a single data frame:



          do.call(rbind, res)




          Edit: I installed your package and ran your code, and apparently l is a list of lists of data frames, not a list of data frames. So we need to extract that as well:



          res = lapply(lapply(l, "[[", 1), "[", 7, c("name", "key"))
          res = do.call(rbind, res)
          res
          # name key
          # 5216014 Raja montagui 5216014
          # 2420446 Amblyraja radiata 2420446





          share|improve this answer


























          • R tell me: Error in x[7, c("name", "key")] : incorrect number of dimensions

            – skylobo
            Nov 13 '18 at 14:36











          • Thank you very much!

            – skylobo
            Nov 13 '18 at 14:58











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          1 Answer
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          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          lapply(l,function(x) x[7]) is close, but you need to index [row, column], not just [row]. Instead do this:



          res = lapply(l,function(x) x[7, c("name", "key")])
          # or more simply
          res = lapply(l, "[", 7, c("name", "key"))


          This will still give you a list, which you'll need to combine together into a single data frame:



          do.call(rbind, res)




          Edit: I installed your package and ran your code, and apparently l is a list of lists of data frames, not a list of data frames. So we need to extract that as well:



          res = lapply(lapply(l, "[[", 1), "[", 7, c("name", "key"))
          res = do.call(rbind, res)
          res
          # name key
          # 5216014 Raja montagui 5216014
          # 2420446 Amblyraja radiata 2420446





          share|improve this answer


























          • R tell me: Error in x[7, c("name", "key")] : incorrect number of dimensions

            – skylobo
            Nov 13 '18 at 14:36











          • Thank you very much!

            – skylobo
            Nov 13 '18 at 14:58
















          1














          lapply(l,function(x) x[7]) is close, but you need to index [row, column], not just [row]. Instead do this:



          res = lapply(l,function(x) x[7, c("name", "key")])
          # or more simply
          res = lapply(l, "[", 7, c("name", "key"))


          This will still give you a list, which you'll need to combine together into a single data frame:



          do.call(rbind, res)




          Edit: I installed your package and ran your code, and apparently l is a list of lists of data frames, not a list of data frames. So we need to extract that as well:



          res = lapply(lapply(l, "[[", 1), "[", 7, c("name", "key"))
          res = do.call(rbind, res)
          res
          # name key
          # 5216014 Raja montagui 5216014
          # 2420446 Amblyraja radiata 2420446





          share|improve this answer


























          • R tell me: Error in x[7, c("name", "key")] : incorrect number of dimensions

            – skylobo
            Nov 13 '18 at 14:36











          • Thank you very much!

            – skylobo
            Nov 13 '18 at 14:58














          1












          1








          1







          lapply(l,function(x) x[7]) is close, but you need to index [row, column], not just [row]. Instead do this:



          res = lapply(l,function(x) x[7, c("name", "key")])
          # or more simply
          res = lapply(l, "[", 7, c("name", "key"))


          This will still give you a list, which you'll need to combine together into a single data frame:



          do.call(rbind, res)




          Edit: I installed your package and ran your code, and apparently l is a list of lists of data frames, not a list of data frames. So we need to extract that as well:



          res = lapply(lapply(l, "[[", 1), "[", 7, c("name", "key"))
          res = do.call(rbind, res)
          res
          # name key
          # 5216014 Raja montagui 5216014
          # 2420446 Amblyraja radiata 2420446





          share|improve this answer















          lapply(l,function(x) x[7]) is close, but you need to index [row, column], not just [row]. Instead do this:



          res = lapply(l,function(x) x[7, c("name", "key")])
          # or more simply
          res = lapply(l, "[", 7, c("name", "key"))


          This will still give you a list, which you'll need to combine together into a single data frame:



          do.call(rbind, res)




          Edit: I installed your package and ran your code, and apparently l is a list of lists of data frames, not a list of data frames. So we need to extract that as well:



          res = lapply(lapply(l, "[[", 1), "[", 7, c("name", "key"))
          res = do.call(rbind, res)
          res
          # name key
          # 5216014 Raja montagui 5216014
          # 2420446 Amblyraja radiata 2420446






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 13 '18 at 14:59

























          answered Nov 13 '18 at 14:30









          GregorGregor

          63.1k989168




          63.1k989168













          • R tell me: Error in x[7, c("name", "key")] : incorrect number of dimensions

            – skylobo
            Nov 13 '18 at 14:36











          • Thank you very much!

            – skylobo
            Nov 13 '18 at 14:58



















          • R tell me: Error in x[7, c("name", "key")] : incorrect number of dimensions

            – skylobo
            Nov 13 '18 at 14:36











          • Thank you very much!

            – skylobo
            Nov 13 '18 at 14:58

















          R tell me: Error in x[7, c("name", "key")] : incorrect number of dimensions

          – skylobo
          Nov 13 '18 at 14:36





          R tell me: Error in x[7, c("name", "key")] : incorrect number of dimensions

          – skylobo
          Nov 13 '18 at 14:36













          Thank you very much!

          – skylobo
          Nov 13 '18 at 14:58





          Thank you very much!

          – skylobo
          Nov 13 '18 at 14:58


















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