How to fix this histogram so that the bars are equidistant and the labels are in the center of the bars.?
-2
The title explains it all. I don't know what I am doing wrong.
matplotlib plot
asked Nov 13 '18 at 6:35
TigerBuddhaTigerBuddha
37114
add a comment |
-2
The title explains it all. I don't know what I am doing wrong.
matplotlib plot
asked Nov 13 '18 at 6:35
TigerBuddhaTigerBuddha
37114
1
Would you mind providing a snippet of code which reproduces the graph ?
– Patol75
Nov 13 '18 at 6:54
def syndPlt(columnName, pltTitle,xLabel, yLabel): # Distribution based on continent columnList = df[columnName] columnList = columnList.tolist() #Plot n, bins, patches = plt.hist(x=columnList, bins='auto', align='mid') plt.grid(axis='y', alpha=0.75) plt.xlabel(xLabel) plt.ylabel(yLabel) plt.title(pltTitle) plt.xticks(rotation='vertical') maxfreq = n.max()
– TigerBuddha
Nov 13 '18 at 18:11
add a comment |
-2
-2
-2
The title explains it all. I don't know what I am doing wrong.
matplotlib plot
asked Nov 13 '18 at 6:35
TigerBuddhaTigerBuddha
37114
The title explains it all. I don't know what I am doing wrong.
matplotlib plot
matplotlib plot
asked Nov 13 '18 at 6:35
TigerBuddhaTigerBuddha
37114
asked Nov 13 '18 at 6:35
TigerBuddhaTigerBuddha
37114
asked Nov 13 '18 at 6:35
TigerBuddhaTigerBuddha
37114
asked Nov 13 '18 at 6:35
TigerBuddhaTigerBuddha
37114
asked Nov 13 '18 at 6:35
TigerBuddhaTigerBuddha
37114
37114
1
Would you mind providing a snippet of code which reproduces the graph ?
– Patol75
Nov 13 '18 at 6:54
def syndPlt(columnName, pltTitle,xLabel, yLabel): # Distribution based on continent columnList = df[columnName] columnList = columnList.tolist() #Plot n, bins, patches = plt.hist(x=columnList, bins='auto', align='mid') plt.grid(axis='y', alpha=0.75) plt.xlabel(xLabel) plt.ylabel(yLabel) plt.title(pltTitle) plt.xticks(rotation='vertical') maxfreq = n.max()
– TigerBuddha
Nov 13 '18 at 18:11
add a comment |
1
Would you mind providing a snippet of code which reproduces the graph ?
– Patol75
Nov 13 '18 at 6:54
def syndPlt(columnName, pltTitle,xLabel, yLabel): # Distribution based on continent columnList = df[columnName] columnList = columnList.tolist() #Plot n, bins, patches = plt.hist(x=columnList, bins='auto', align='mid') plt.grid(axis='y', alpha=0.75) plt.xlabel(xLabel) plt.ylabel(yLabel) plt.title(pltTitle) plt.xticks(rotation='vertical') maxfreq = n.max()
– TigerBuddha
Nov 13 '18 at 18:11
1
1
Would you mind providing a snippet of code which reproduces the graph ?
– Patol75
Nov 13 '18 at 6:54
Would you mind providing a snippet of code which reproduces the graph ?
– Patol75
Nov 13 '18 at 6:54
def syndPlt(columnName, pltTitle,xLabel, yLabel): # Distribution based on continent columnList = df[columnName] columnList = columnList.tolist() #Plot n, bins, patches = plt.hist(x=columnList, bins='auto', align='mid') plt.grid(axis='y', alpha=0.75) plt.xlabel(xLabel) plt.ylabel(yLabel) plt.title(pltTitle) plt.xticks(rotation='vertical') maxfreq = n.max()
– TigerBuddha
Nov 13 '18 at 18:11
def syndPlt(columnName, pltTitle,xLabel, yLabel): # Distribution based on continent columnList = df[columnName] columnList = columnList.tolist() #Plot n, bins, patches = plt.hist(x=columnList, bins='auto', align='mid') plt.grid(axis='y', alpha=0.75) plt.xlabel(xLabel) plt.ylabel(yLabel) plt.title(pltTitle) plt.xticks(rotation='vertical') maxfreq = n.max()
– TigerBuddha
Nov 13 '18 at 18:11
add a comment |
1 Answer
1
active
oldest
votes
1
Based on the piece of code you provided, this snippet below should achieve what you want. The idea is to provide manually the bins location, set the width of each bar and align everything left. More information here.
import matplotlib.pyplot as plt
import numpy
columnList =
for i in range(32):
columnList.append('Asia')
for i in range(58):
columnList.append('Europe')
for i in range(18):
columnList.append('North America')
for i in range(12):
columnList.append('Central ornSouth America')
for i in range(7):
columnList.append('Australia ornOceania')
n, bins, patches = plt.hist(x=columnList, bins=numpy.arange(6), rwidth=0.5,
align='left')
plt.grid(axis='y', alpha=0.75)
plt.xlabel('Continents')
plt.ylabel('Frequency')
plt.title('Continental Distribution of respondents')
plt.show()
answered Nov 14 '18 at 1:34
Patol75Patol75
6236
Thank you that works.
– TigerBuddha
Nov 14 '18 at 20:08
No worries, feel free to accept the answer.
– Patol75
Nov 19 '18 at 8:48
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Based on the piece of code you provided, this snippet below should achieve what you want. The idea is to provide manually the bins location, set the width of each bar and align everything left. More information here.
import matplotlib.pyplot as plt
import numpy
columnList =
for i in range(32):
columnList.append('Asia')
for i in range(58):
columnList.append('Europe')
for i in range(18):
columnList.append('North America')
for i in range(12):
columnList.append('Central ornSouth America')
for i in range(7):
columnList.append('Australia ornOceania')
n, bins, patches = plt.hist(x=columnList, bins=numpy.arange(6), rwidth=0.5,
align='left')
plt.grid(axis='y', alpha=0.75)
plt.xlabel('Continents')
plt.ylabel('Frequency')
plt.title('Continental Distribution of respondents')
plt.show()
answered Nov 14 '18 at 1:34
Patol75Patol75
6236
Thank you that works.
– TigerBuddha
Nov 14 '18 at 20:08
No worries, feel free to accept the answer.
– Patol75
Nov 19 '18 at 8:48
add a comment |
1
Based on the piece of code you provided, this snippet below should achieve what you want. The idea is to provide manually the bins location, set the width of each bar and align everything left. More information here.
import matplotlib.pyplot as plt
import numpy
columnList =
for i in range(32):
columnList.append('Asia')
for i in range(58):
columnList.append('Europe')
for i in range(18):
columnList.append('North America')
for i in range(12):
columnList.append('Central ornSouth America')
for i in range(7):
columnList.append('Australia ornOceania')
n, bins, patches = plt.hist(x=columnList, bins=numpy.arange(6), rwidth=0.5,
align='left')
plt.grid(axis='y', alpha=0.75)
plt.xlabel('Continents')
plt.ylabel('Frequency')
plt.title('Continental Distribution of respondents')
plt.show()
answered Nov 14 '18 at 1:34
Patol75Patol75
6236
Thank you that works.
– TigerBuddha
Nov 14 '18 at 20:08
No worries, feel free to accept the answer.
– Patol75
Nov 19 '18 at 8:48
add a comment |
1
1
1
Based on the piece of code you provided, this snippet below should achieve what you want. The idea is to provide manually the bins location, set the width of each bar and align everything left. More information here.
import matplotlib.pyplot as plt
import numpy
columnList =
for i in range(32):
columnList.append('Asia')
for i in range(58):
columnList.append('Europe')
for i in range(18):
columnList.append('North America')
for i in range(12):
columnList.append('Central ornSouth America')
for i in range(7):
columnList.append('Australia ornOceania')
n, bins, patches = plt.hist(x=columnList, bins=numpy.arange(6), rwidth=0.5,
align='left')
plt.grid(axis='y', alpha=0.75)
plt.xlabel('Continents')
plt.ylabel('Frequency')
plt.title('Continental Distribution of respondents')
plt.show()
answered Nov 14 '18 at 1:34
Patol75Patol75
6236
Based on the piece of code you provided, this snippet below should achieve what you want. The idea is to provide manually the bins location, set the width of each bar and align everything left. More information here.
import matplotlib.pyplot as plt
import numpy
columnList =
for i in range(32):
columnList.append('Asia')
for i in range(58):
columnList.append('Europe')
for i in range(18):
columnList.append('North America')
for i in range(12):
columnList.append('Central ornSouth America')
for i in range(7):
columnList.append('Australia ornOceania')
n, bins, patches = plt.hist(x=columnList, bins=numpy.arange(6), rwidth=0.5,
align='left')
plt.grid(axis='y', alpha=0.75)
plt.xlabel('Continents')
plt.ylabel('Frequency')
plt.title('Continental Distribution of respondents')
plt.show()
answered Nov 14 '18 at 1:34
Patol75Patol75
6236
answered Nov 14 '18 at 1:34
Patol75Patol75
6236
answered Nov 14 '18 at 1:34
Patol75Patol75
6236
answered Nov 14 '18 at 1:34
Patol75Patol75
6236
6236
Thank you that works.
– TigerBuddha
Nov 14 '18 at 20:08
No worries, feel free to accept the answer.
– Patol75
Nov 19 '18 at 8:48
add a comment |
Thank you that works.
– TigerBuddha
Nov 14 '18 at 20:08
No worries, feel free to accept the answer.
– Patol75
Nov 19 '18 at 8:48
Thank you that works.
– TigerBuddha
Nov 14 '18 at 20:08
Thank you that works.
– TigerBuddha
Nov 14 '18 at 20:08
No worries, feel free to accept the answer.
– Patol75
Nov 19 '18 at 8:48
No worries, feel free to accept the answer.
– Patol75
Nov 19 '18 at 8:48
add a comment |
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1
Would you mind providing a snippet of code which reproduces the graph ?
– Patol75
Nov 13 '18 at 6:54
def syndPlt(columnName, pltTitle,xLabel, yLabel): # Distribution based on continent columnList = df[columnName] columnList = columnList.tolist() #Plot n, bins, patches = plt.hist(x=columnList, bins='auto', align='mid') plt.grid(axis='y', alpha=0.75) plt.xlabel(xLabel) plt.ylabel(yLabel) plt.title(pltTitle) plt.xticks(rotation='vertical') maxfreq = n.max()
– TigerBuddha
Nov 13 '18 at 18:11