How to remove punctuation inside brackets in R












0














I have tried to split documents into sentences, but there are some strange outcomes due to punctuation inside brackets. So I'd like to remove any punctuation.



example input:



A <- c('How to remove all punctuations(like this?) in side it?')


wanted output:



"How to remove all punctuations(like this) in side it?"





r brackets punctuation







share|improve this question
























  • Note it's generally considered that there is no need to add the language title into questions. Also, there's no need to comment to thank people for a solution--but you should use the check mark to accept the answer (gives them points, and resolves the question).
    – HostileFork
    Nov 13 '18 at 7:34
















0














I have tried to split documents into sentences, but there are some strange outcomes due to punctuation inside brackets. So I'd like to remove any punctuation.



example input:



A <- c('How to remove all punctuations(like this?) in side it?')


wanted output:



"How to remove all punctuations(like this) in side it?"





r brackets punctuation







share|improve this question
























  • Note it's generally considered that there is no need to add the language title into questions. Also, there's no need to comment to thank people for a solution--but you should use the check mark to accept the answer (gives them points, and resolves the question).
    – HostileFork
    Nov 13 '18 at 7:34














0












0








0


1





I have tried to split documents into sentences, but there are some strange outcomes due to punctuation inside brackets. So I'd like to remove any punctuation.



example input:



A <- c('How to remove all punctuations(like this?) in side it?')


wanted output:



"How to remove all punctuations(like this) in side it?"





r brackets punctuation







share|improve this question















I have tried to split documents into sentences, but there are some strange outcomes due to punctuation inside brackets. So I'd like to remove any punctuation.



example input:



A <- c('How to remove all punctuations(like this?) in side it?')


wanted output:



"How to remove all punctuations(like this) in side it?"





r brackets punctuation




r brackets punctuation






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 7:37









HostileFork

25.5k777133




25.5k777133










asked Nov 13 '18 at 6:18









서한솔서한솔

82




82












  • Note it's generally considered that there is no need to add the language title into questions. Also, there's no need to comment to thank people for a solution--but you should use the check mark to accept the answer (gives them points, and resolves the question).
    – HostileFork
    Nov 13 '18 at 7:34


















  • Note it's generally considered that there is no need to add the language title into questions. Also, there's no need to comment to thank people for a solution--but you should use the check mark to accept the answer (gives them points, and resolves the question).
    – HostileFork
    Nov 13 '18 at 7:34
















Note it's generally considered that there is no need to add the language title into questions. Also, there's no need to comment to thank people for a solution--but you should use the check mark to accept the answer (gives them points, and resolves the question).
– HostileFork
Nov 13 '18 at 7:34




Note it's generally considered that there is no need to add the language title into questions. Also, there's no need to comment to thank people for a solution--but you should use the check mark to accept the answer (gives them points, and resolves the question).
– HostileFork
Nov 13 '18 at 7:34












1 Answer
1






active

oldest

votes


















0














Perhaps something like this using a positive lookahead?



gsub("[?!;,.](?=\))", "", A, perl = T)

#[1] "How to remove all punctuations(like this) in side it?"


Or using POSIX character classes



gsub("[[:punct:]](?=\))", "", A, perl = T)


Or if you need to match other types of closing brackets (e.g. curly, square)



gsub("[[:punct:]](?=[)\]}])", "", A, perl = T)





share|improve this answer























  • You're very welcome @서한솔
    – Maurits Evers
    Nov 13 '18 at 6:44











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1 Answer
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1 Answer
1






active

oldest

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oldest

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active

oldest

votes









0














Perhaps something like this using a positive lookahead?



gsub("[?!;,.](?=\))", "", A, perl = T)

#[1] "How to remove all punctuations(like this) in side it?"


Or using POSIX character classes



gsub("[[:punct:]](?=\))", "", A, perl = T)


Or if you need to match other types of closing brackets (e.g. curly, square)



gsub("[[:punct:]](?=[)\]}])", "", A, perl = T)





share|improve this answer























  • You're very welcome @서한솔
    – Maurits Evers
    Nov 13 '18 at 6:44
















0














Perhaps something like this using a positive lookahead?



gsub("[?!;,.](?=\))", "", A, perl = T)

#[1] "How to remove all punctuations(like this) in side it?"


Or using POSIX character classes



gsub("[[:punct:]](?=\))", "", A, perl = T)


Or if you need to match other types of closing brackets (e.g. curly, square)



gsub("[[:punct:]](?=[)\]}])", "", A, perl = T)





share|improve this answer























  • You're very welcome @서한솔
    – Maurits Evers
    Nov 13 '18 at 6:44














0












0








0






Perhaps something like this using a positive lookahead?



gsub("[?!;,.](?=\))", "", A, perl = T)

#[1] "How to remove all punctuations(like this) in side it?"


Or using POSIX character classes



gsub("[[:punct:]](?=\))", "", A, perl = T)


Or if you need to match other types of closing brackets (e.g. curly, square)



gsub("[[:punct:]](?=[)\]}])", "", A, perl = T)





share|improve this answer














Perhaps something like this using a positive lookahead?



gsub("[?!;,.](?=\))", "", A, perl = T)

#[1] "How to remove all punctuations(like this) in side it?"


Or using POSIX character classes



gsub("[[:punct:]](?=\))", "", A, perl = T)


Or if you need to match other types of closing brackets (e.g. curly, square)



gsub("[[:punct:]](?=[)\]}])", "", A, perl = T)






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 13 '18 at 6:30

























answered Nov 13 '18 at 6:24









Maurits EversMaurits Evers

26.2k41532




26.2k41532












  • You're very welcome @서한솔
    – Maurits Evers
    Nov 13 '18 at 6:44


















  • You're very welcome @서한솔
    – Maurits Evers
    Nov 13 '18 at 6:44
















You're very welcome @서한솔
– Maurits Evers
Nov 13 '18 at 6:44




You're very welcome @서한솔
– Maurits Evers
Nov 13 '18 at 6:44


















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