Convert List of string to Integer












-2















I have a list whose elements are only single string.



my_list = ['9', '4', '4', '5', '4', '3', '5']


How can I convert this into a single integer like: 9445435



Note: ' '.join() only works for lists of strings, not integers.






python python-3.x







share|improve this question




















  • 3





    Use join and then cast it to int! like => int(''.join(my_list))

    – DarkSuniuM
    Nov 20 '18 at 8:43






  • 1





    Is your list made of integers or of strings? If integers, then int(''.join(str(v) for v in my_list)), otherwise what DarkSuniuM said

    – FernAndr
    Nov 20 '18 at 8:45








  • 1





    You say it's a list of integers, but the list you have in your question contains strings, not integers.

    – khelwood
    Nov 20 '18 at 8:53


















-2















I have a list whose elements are only single string.



my_list = ['9', '4', '4', '5', '4', '3', '5']


How can I convert this into a single integer like: 9445435



Note: ' '.join() only works for lists of strings, not integers.






python python-3.x







share|improve this question




















  • 3





    Use join and then cast it to int! like => int(''.join(my_list))

    – DarkSuniuM
    Nov 20 '18 at 8:43






  • 1





    Is your list made of integers or of strings? If integers, then int(''.join(str(v) for v in my_list)), otherwise what DarkSuniuM said

    – FernAndr
    Nov 20 '18 at 8:45








  • 1





    You say it's a list of integers, but the list you have in your question contains strings, not integers.

    – khelwood
    Nov 20 '18 at 8:53
















-2












-2








-2








I have a list whose elements are only single string.



my_list = ['9', '4', '4', '5', '4', '3', '5']


How can I convert this into a single integer like: 9445435



Note: ' '.join() only works for lists of strings, not integers.






python python-3.x







share|improve this question
















I have a list whose elements are only single string.



my_list = ['9', '4', '4', '5', '4', '3', '5']


How can I convert this into a single integer like: 9445435



Note: ' '.join() only works for lists of strings, not integers.






python python-3.x




python python-3.x






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 20 '18 at 9:02









eyllanesc

79.4k103258




79.4k103258










asked Nov 20 '18 at 8:42









Oliver MurfettOliver Murfett

175




175








  • 3





    Use join and then cast it to int! like => int(''.join(my_list))

    – DarkSuniuM
    Nov 20 '18 at 8:43






  • 1





    Is your list made of integers or of strings? If integers, then int(''.join(str(v) for v in my_list)), otherwise what DarkSuniuM said

    – FernAndr
    Nov 20 '18 at 8:45








  • 1





    You say it's a list of integers, but the list you have in your question contains strings, not integers.

    – khelwood
    Nov 20 '18 at 8:53
















  • 3





    Use join and then cast it to int! like => int(''.join(my_list))

    – DarkSuniuM
    Nov 20 '18 at 8:43






  • 1





    Is your list made of integers or of strings? If integers, then int(''.join(str(v) for v in my_list)), otherwise what DarkSuniuM said

    – FernAndr
    Nov 20 '18 at 8:45








  • 1





    You say it's a list of integers, but the list you have in your question contains strings, not integers.

    – khelwood
    Nov 20 '18 at 8:53










3




3





Use join and then cast it to int! like => int(''.join(my_list))

– DarkSuniuM
Nov 20 '18 at 8:43





Use join and then cast it to int! like => int(''.join(my_list))

– DarkSuniuM
Nov 20 '18 at 8:43




1




1





Is your list made of integers or of strings? If integers, then int(''.join(str(v) for v in my_list)), otherwise what DarkSuniuM said

– FernAndr
Nov 20 '18 at 8:45







Is your list made of integers or of strings? If integers, then int(''.join(str(v) for v in my_list)), otherwise what DarkSuniuM said

– FernAndr
Nov 20 '18 at 8:45






1




1





You say it's a list of integers, but the list you have in your question contains strings, not integers.

– khelwood
Nov 20 '18 at 8:53







You say it's a list of integers, but the list you have in your question contains strings, not integers.

– khelwood
Nov 20 '18 at 8:53














3 Answers
3






active

oldest

votes


















0














Try this,



In [5]: int(''.join(my_list))

Out[5]: 9445435





share|improve this answer































    0














    Why don't you try this approach? 



    my_list = ['9', '4', '4', '5', '4', '3', '5']
    
output = int(''.join(str(num) for num in my_list))
    
print(output) ## 9445435





    share|improve this answer



















    • 1





      or output = int(''.join(my_list))

      – eyllanesc
      Nov 20 '18 at 8:51











    • @eyllanesc nah, the for is there so if the list items was int, it casts them to str

      – DarkSuniuM
      Nov 20 '18 at 8:53






    • 1





      @DarkSuniuM join accepts an iterable and converts them internally with str() to each iterable element, the for is unnecessary

      – eyllanesc
      Nov 20 '18 at 8:55













    • @eyllanesc TypeError: sequence item 0: expected str instance, int found

      – DarkSuniuM
      Nov 20 '18 at 8:56











    • @DarkSuniuM my_list = ['9', '4', '4', '5', '4', '3', '5'] output = int(''.join(my_list)) print(output) ---> 9445435 in Python 2.7.15 and python 3.7.1

      – eyllanesc
      Nov 20 '18 at 8:58



















    0














    result = ' '.join(my_list)
    

    
result = int(result)





    share|improve this answer

























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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      Try this,



      In [5]: int(''.join(my_list))
      
Out[5]: 9445435





      share|improve this answer




























        0














        Try this,



        In [5]: int(''.join(my_list))
        
Out[5]: 9445435





        share|improve this answer


























          0












          0








          0







          Try this,



          In [5]: int(''.join(my_list))
          
Out[5]: 9445435





          share|improve this answer













          Try this,



          In [5]: int(''.join(my_list))
          
Out[5]: 9445435






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 20 '18 at 8:49









          Rahul K PRahul K P

          7,37122234




          7,37122234

























              0














              Why don't you try this approach? 



              my_list = ['9', '4', '4', '5', '4', '3', '5']
              
output = int(''.join(str(num) for num in my_list))
              
print(output) ## 9445435





              share|improve this answer



















              • 1





                or output = int(''.join(my_list))

                – eyllanesc
                Nov 20 '18 at 8:51











              • @eyllanesc nah, the for is there so if the list items was int, it casts them to str

                – DarkSuniuM
                Nov 20 '18 at 8:53






              • 1





                @DarkSuniuM join accepts an iterable and converts them internally with str() to each iterable element, the for is unnecessary

                – eyllanesc
                Nov 20 '18 at 8:55













              • @eyllanesc TypeError: sequence item 0: expected str instance, int found

                – DarkSuniuM
                Nov 20 '18 at 8:56











              • @DarkSuniuM my_list = ['9', '4', '4', '5', '4', '3', '5'] output = int(''.join(my_list)) print(output) ---> 9445435 in Python 2.7.15 and python 3.7.1

                – eyllanesc
                Nov 20 '18 at 8:58
















              0














              Why don't you try this approach? 



              my_list = ['9', '4', '4', '5', '4', '3', '5']
              
output = int(''.join(str(num) for num in my_list))
              
print(output) ## 9445435





              share|improve this answer



















              • 1





                or output = int(''.join(my_list))

                – eyllanesc
                Nov 20 '18 at 8:51











              • @eyllanesc nah, the for is there so if the list items was int, it casts them to str

                – DarkSuniuM
                Nov 20 '18 at 8:53






              • 1





                @DarkSuniuM join accepts an iterable and converts them internally with str() to each iterable element, the for is unnecessary

                – eyllanesc
                Nov 20 '18 at 8:55













              • @eyllanesc TypeError: sequence item 0: expected str instance, int found

                – DarkSuniuM
                Nov 20 '18 at 8:56











              • @DarkSuniuM my_list = ['9', '4', '4', '5', '4', '3', '5'] output = int(''.join(my_list)) print(output) ---> 9445435 in Python 2.7.15 and python 3.7.1

                – eyllanesc
                Nov 20 '18 at 8:58














              0












              0








              0







              Why don't you try this approach? 



              my_list = ['9', '4', '4', '5', '4', '3', '5']
              
output = int(''.join(str(num) for num in my_list))
              
print(output) ## 9445435





              share|improve this answer













              Why don't you try this approach? 



              my_list = ['9', '4', '4', '5', '4', '3', '5']
              
output = int(''.join(str(num) for num in my_list))
              
print(output) ## 9445435






              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Nov 20 '18 at 8:50









              toom501toom501

              3021313




              3021313








              • 1





                or output = int(''.join(my_list))

                – eyllanesc
                Nov 20 '18 at 8:51











              • @eyllanesc nah, the for is there so if the list items was int, it casts them to str

                – DarkSuniuM
                Nov 20 '18 at 8:53






              • 1





                @DarkSuniuM join accepts an iterable and converts them internally with str() to each iterable element, the for is unnecessary

                – eyllanesc
                Nov 20 '18 at 8:55













              • @eyllanesc TypeError: sequence item 0: expected str instance, int found

                – DarkSuniuM
                Nov 20 '18 at 8:56











              • @DarkSuniuM my_list = ['9', '4', '4', '5', '4', '3', '5'] output = int(''.join(my_list)) print(output) ---> 9445435 in Python 2.7.15 and python 3.7.1

                – eyllanesc
                Nov 20 '18 at 8:58














              • 1





                or output = int(''.join(my_list))

                – eyllanesc
                Nov 20 '18 at 8:51











              • @eyllanesc nah, the for is there so if the list items was int, it casts them to str

                – DarkSuniuM
                Nov 20 '18 at 8:53






              • 1





                @DarkSuniuM join accepts an iterable and converts them internally with str() to each iterable element, the for is unnecessary

                – eyllanesc
                Nov 20 '18 at 8:55













              • @eyllanesc TypeError: sequence item 0: expected str instance, int found

                – DarkSuniuM
                Nov 20 '18 at 8:56











              • @DarkSuniuM my_list = ['9', '4', '4', '5', '4', '3', '5'] output = int(''.join(my_list)) print(output) ---> 9445435 in Python 2.7.15 and python 3.7.1

                – eyllanesc
                Nov 20 '18 at 8:58








              1




              1





              or output = int(''.join(my_list))

              – eyllanesc
              Nov 20 '18 at 8:51





              or output = int(''.join(my_list))

              – eyllanesc
              Nov 20 '18 at 8:51













              @eyllanesc nah, the for is there so if the list items was int, it casts them to str

              – DarkSuniuM
              Nov 20 '18 at 8:53





              @eyllanesc nah, the for is there so if the list items was int, it casts them to str

              – DarkSuniuM
              Nov 20 '18 at 8:53




              1




              1





              @DarkSuniuM join accepts an iterable and converts them internally with str() to each iterable element, the for is unnecessary

              – eyllanesc
              Nov 20 '18 at 8:55







              @DarkSuniuM join accepts an iterable and converts them internally with str() to each iterable element, the for is unnecessary

              – eyllanesc
              Nov 20 '18 at 8:55















              @eyllanesc TypeError: sequence item 0: expected str instance, int found

              – DarkSuniuM
              Nov 20 '18 at 8:56





              @eyllanesc TypeError: sequence item 0: expected str instance, int found

              – DarkSuniuM
              Nov 20 '18 at 8:56













              @DarkSuniuM my_list = ['9', '4', '4', '5', '4', '3', '5'] output = int(''.join(my_list)) print(output) ---> 9445435 in Python 2.7.15 and python 3.7.1

              – eyllanesc
              Nov 20 '18 at 8:58





              @DarkSuniuM my_list = ['9', '4', '4', '5', '4', '3', '5'] output = int(''.join(my_list)) print(output) ---> 9445435 in Python 2.7.15 and python 3.7.1

              – eyllanesc
              Nov 20 '18 at 8:58











              0














              result = ' '.join(my_list)
              

              
result = int(result)





              share|improve this answer






























                0














                result = ' '.join(my_list)
                

                
result = int(result)





                share|improve this answer




























                  0












                  0








                  0







                  result = ' '.join(my_list)
                  

                  
result = int(result)





                  share|improve this answer















                  result = ' '.join(my_list)
                  

                  
result = int(result)






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 20 '18 at 8:52









                  AkshayNevrekar

                  4,83791837




                  4,83791837










                  answered Nov 20 '18 at 8:48









                  crazy_codercrazy_coder

                  14116




                  14116






























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