Defining parameters in SQLDatasource in devexpress
0
I have a SQLDataSource that has an insert statement and parameters defined, please see photo below:
As I run my program, it will always states that it cannot find the txtlName control. What is wrong with my implementation? Can someone tell how to fix this?
This is my mark up code for my sqldatasource.
<asp:SqlDataSource ID="SqlDataSource4" runat="server" ConnectionString="<%$ ConnectionStrings:MDRFConnectionString %>" InsertCommand="INSERT INTO MDRF_Main(MDRF_LName, MDRF_FName, MDRF_MName, MDRF_Department, MDRF_RequestType, MDRF_Status, MDRF_WorkflowId, MDRF_Company, MDRF_Remarks, MDRF_RequestModule, MDRF_DateRequired, MDRF_Priority, MDRF_ResponseTime, MDRF_Module, MDRF_DocNum) VALUES (@lname, @fname, @mname, @dept, @rt, @status, @work, @comp, @remarks, @rm, CONVERT(datetime, @date) , @prio, @response, @module, @dn)" OnSelecting="SqlDataSource4_Selecting" ProviderName="System.Data.SqlClient" SelectCommand="SELECT * FROM [MDRF_Main]">
<InsertParameters>
<asp:ControlParameter ControlID="txtLname" Name="lname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtFname" Name="fname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtMname" Name="mname" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbDepartment" Name="dept" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbRequestType" Name="rt" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbStatus" Name="status" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbWorkflow" Name="work" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbCompany" Name="comp" PropertyName="Value" />
<asp:ControlParameter ControlID="txtRemarks" Name="remarks" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbMasterData" Name="rm" PropertyName="Value" />
<asp:ControlParameter ControlID="txtDate" Name="date" PropertyName="Date" DbType="DateTime" />
<asp:ControlParameter ControlID="cmbPriority" Name="prio" PropertyName="Value" />
<asp:ControlParameter ControlID="txtResponse" Name="response" PropertyName="Text" />
<asp:Parameter DefaultValue="''" Name="module" />
<asp:ControlParameter ControlID="txtDocNum" DefaultValue="" Name="dn" PropertyName="Text" />
</InsertParameters>
</asp:SqlDataSource>
Thanks
devexpress sqldatasource
asked Nov 20 '18 at 13:10
user3312649user3312649
921113
add a comment |
0
I have a SQLDataSource that has an insert statement and parameters defined, please see photo below:
As I run my program, it will always states that it cannot find the txtlName control. What is wrong with my implementation? Can someone tell how to fix this?
This is my mark up code for my sqldatasource.
<asp:SqlDataSource ID="SqlDataSource4" runat="server" ConnectionString="<%$ ConnectionStrings:MDRFConnectionString %>" InsertCommand="INSERT INTO MDRF_Main(MDRF_LName, MDRF_FName, MDRF_MName, MDRF_Department, MDRF_RequestType, MDRF_Status, MDRF_WorkflowId, MDRF_Company, MDRF_Remarks, MDRF_RequestModule, MDRF_DateRequired, MDRF_Priority, MDRF_ResponseTime, MDRF_Module, MDRF_DocNum) VALUES (@lname, @fname, @mname, @dept, @rt, @status, @work, @comp, @remarks, @rm, CONVERT(datetime, @date) , @prio, @response, @module, @dn)" OnSelecting="SqlDataSource4_Selecting" ProviderName="System.Data.SqlClient" SelectCommand="SELECT * FROM [MDRF_Main]">
<InsertParameters>
<asp:ControlParameter ControlID="txtLname" Name="lname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtFname" Name="fname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtMname" Name="mname" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbDepartment" Name="dept" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbRequestType" Name="rt" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbStatus" Name="status" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbWorkflow" Name="work" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbCompany" Name="comp" PropertyName="Value" />
<asp:ControlParameter ControlID="txtRemarks" Name="remarks" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbMasterData" Name="rm" PropertyName="Value" />
<asp:ControlParameter ControlID="txtDate" Name="date" PropertyName="Date" DbType="DateTime" />
<asp:ControlParameter ControlID="cmbPriority" Name="prio" PropertyName="Value" />
<asp:ControlParameter ControlID="txtResponse" Name="response" PropertyName="Text" />
<asp:Parameter DefaultValue="''" Name="module" />
<asp:ControlParameter ControlID="txtDocNum" DefaultValue="" Name="dn" PropertyName="Text" />
</InsertParameters>
</asp:SqlDataSource>
Thanks
devexpress sqldatasource
asked Nov 20 '18 at 13:10
user3312649user3312649
921113
Please show theSqlDataSourceandASPxTextBoxmarkup to let us find out possible cause of this issue. Try usingtxtLName_Init()event handler to see the unique ID, e.g.var textbox = sender as ASPxTextBox; Debug.WriteLine(textbox.UniqueID);.
– Tetsuya Yamamoto
Nov 21 '18 at 8:21
I have already the problem but whenever I enter the value for date it would always display error.
– user3312649
Nov 22 '18 at 1:56
Is thattxtLnamecontained insideGridView'sItemTemplateor other container? If the textbox doesn't contained inside any container you can use the control name directly, but if using any container then you should use container name too, e.g.GridView1$txtLname.
– Tetsuya Yamamoto
Nov 22 '18 at 2:05
I recently just solved this, I have just put it inside the formlayout fields. sigh.
– user3312649
Nov 22 '18 at 3:45
add a comment |
0
0
0
1
I have a SQLDataSource that has an insert statement and parameters defined, please see photo below:
As I run my program, it will always states that it cannot find the txtlName control. What is wrong with my implementation? Can someone tell how to fix this?
This is my mark up code for my sqldatasource.
<asp:SqlDataSource ID="SqlDataSource4" runat="server" ConnectionString="<%$ ConnectionStrings:MDRFConnectionString %>" InsertCommand="INSERT INTO MDRF_Main(MDRF_LName, MDRF_FName, MDRF_MName, MDRF_Department, MDRF_RequestType, MDRF_Status, MDRF_WorkflowId, MDRF_Company, MDRF_Remarks, MDRF_RequestModule, MDRF_DateRequired, MDRF_Priority, MDRF_ResponseTime, MDRF_Module, MDRF_DocNum) VALUES (@lname, @fname, @mname, @dept, @rt, @status, @work, @comp, @remarks, @rm, CONVERT(datetime, @date) , @prio, @response, @module, @dn)" OnSelecting="SqlDataSource4_Selecting" ProviderName="System.Data.SqlClient" SelectCommand="SELECT * FROM [MDRF_Main]">
<InsertParameters>
<asp:ControlParameter ControlID="txtLname" Name="lname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtFname" Name="fname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtMname" Name="mname" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbDepartment" Name="dept" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbRequestType" Name="rt" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbStatus" Name="status" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbWorkflow" Name="work" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbCompany" Name="comp" PropertyName="Value" />
<asp:ControlParameter ControlID="txtRemarks" Name="remarks" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbMasterData" Name="rm" PropertyName="Value" />
<asp:ControlParameter ControlID="txtDate" Name="date" PropertyName="Date" DbType="DateTime" />
<asp:ControlParameter ControlID="cmbPriority" Name="prio" PropertyName="Value" />
<asp:ControlParameter ControlID="txtResponse" Name="response" PropertyName="Text" />
<asp:Parameter DefaultValue="''" Name="module" />
<asp:ControlParameter ControlID="txtDocNum" DefaultValue="" Name="dn" PropertyName="Text" />
</InsertParameters>
</asp:SqlDataSource>
Thanks
devexpress sqldatasource
asked Nov 20 '18 at 13:10
user3312649user3312649
921113
I have a SQLDataSource that has an insert statement and parameters defined, please see photo below:
As I run my program, it will always states that it cannot find the txtlName control. What is wrong with my implementation? Can someone tell how to fix this?
This is my mark up code for my sqldatasource.
<asp:SqlDataSource ID="SqlDataSource4" runat="server" ConnectionString="<%$ ConnectionStrings:MDRFConnectionString %>" InsertCommand="INSERT INTO MDRF_Main(MDRF_LName, MDRF_FName, MDRF_MName, MDRF_Department, MDRF_RequestType, MDRF_Status, MDRF_WorkflowId, MDRF_Company, MDRF_Remarks, MDRF_RequestModule, MDRF_DateRequired, MDRF_Priority, MDRF_ResponseTime, MDRF_Module, MDRF_DocNum) VALUES (@lname, @fname, @mname, @dept, @rt, @status, @work, @comp, @remarks, @rm, CONVERT(datetime, @date) , @prio, @response, @module, @dn)" OnSelecting="SqlDataSource4_Selecting" ProviderName="System.Data.SqlClient" SelectCommand="SELECT * FROM [MDRF_Main]">
<InsertParameters>
<asp:ControlParameter ControlID="txtLname" Name="lname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtFname" Name="fname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtMname" Name="mname" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbDepartment" Name="dept" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbRequestType" Name="rt" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbStatus" Name="status" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbWorkflow" Name="work" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbCompany" Name="comp" PropertyName="Value" />
<asp:ControlParameter ControlID="txtRemarks" Name="remarks" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbMasterData" Name="rm" PropertyName="Value" />
<asp:ControlParameter ControlID="txtDate" Name="date" PropertyName="Date" DbType="DateTime" />
<asp:ControlParameter ControlID="cmbPriority" Name="prio" PropertyName="Value" />
<asp:ControlParameter ControlID="txtResponse" Name="response" PropertyName="Text" />
<asp:Parameter DefaultValue="''" Name="module" />
<asp:ControlParameter ControlID="txtDocNum" DefaultValue="" Name="dn" PropertyName="Text" />
</InsertParameters>
</asp:SqlDataSource>
Thanks
devexpress sqldatasource
devexpress sqldatasource
asked Nov 20 '18 at 13:10
user3312649user3312649
921113
asked Nov 20 '18 at 13:10
user3312649user3312649
921113
edited Nov 22 '18 at 1:57
user3312649
asked Nov 20 '18 at 13:10
user3312649user3312649
921113
asked Nov 20 '18 at 13:10
user3312649user3312649
921113
asked Nov 20 '18 at 13:10
user3312649user3312649
921113
921113
Please show theSqlDataSourceandASPxTextBoxmarkup to let us find out possible cause of this issue. Try usingtxtLName_Init()event handler to see the unique ID, e.g.var textbox = sender as ASPxTextBox; Debug.WriteLine(textbox.UniqueID);.
– Tetsuya Yamamoto
Nov 21 '18 at 8:21
I have already the problem but whenever I enter the value for date it would always display error.
– user3312649
Nov 22 '18 at 1:56
Is thattxtLnamecontained insideGridView'sItemTemplateor other container? If the textbox doesn't contained inside any container you can use the control name directly, but if using any container then you should use container name too, e.g.GridView1$txtLname.
– Tetsuya Yamamoto
Nov 22 '18 at 2:05
I recently just solved this, I have just put it inside the formlayout fields. sigh.
– user3312649
Nov 22 '18 at 3:45
add a comment |
Please show theSqlDataSourceandASPxTextBoxmarkup to let us find out possible cause of this issue. Try usingtxtLName_Init()event handler to see the unique ID, e.g.var textbox = sender as ASPxTextBox; Debug.WriteLine(textbox.UniqueID);.
– Tetsuya Yamamoto
Nov 21 '18 at 8:21
I have already the problem but whenever I enter the value for date it would always display error.
– user3312649
Nov 22 '18 at 1:56
Is thattxtLnamecontained insideGridView'sItemTemplateor other container? If the textbox doesn't contained inside any container you can use the control name directly, but if using any container then you should use container name too, e.g.GridView1$txtLname.
– Tetsuya Yamamoto
Nov 22 '18 at 2:05
I recently just solved this, I have just put it inside the formlayout fields. sigh.
– user3312649
Nov 22 '18 at 3:45
Please show the
SqlDataSource and ASPxTextBox markup to let us find out possible cause of this issue. Try using txtLName_Init() event handler to see the unique ID, e.g. var textbox = sender as ASPxTextBox; Debug.WriteLine(textbox.UniqueID);.– Tetsuya Yamamoto
Nov 21 '18 at 8:21
Please show the
SqlDataSource and ASPxTextBox markup to let us find out possible cause of this issue. Try using txtLName_Init() event handler to see the unique ID, e.g. var textbox = sender as ASPxTextBox; Debug.WriteLine(textbox.UniqueID);.– Tetsuya Yamamoto
Nov 21 '18 at 8:21
I have already the problem but whenever I enter the value for date it would always display error.
– user3312649
Nov 22 '18 at 1:56
I have already the problem but whenever I enter the value for date it would always display error.
– user3312649
Nov 22 '18 at 1:56
Is that
txtLname contained inside GridView's ItemTemplate or other container? If the textbox doesn't contained inside any container you can use the control name directly, but if using any container then you should use container name too, e.g. GridView1$txtLname.– Tetsuya Yamamoto
Nov 22 '18 at 2:05
Is that
txtLname contained inside GridView's ItemTemplate or other container? If the textbox doesn't contained inside any container you can use the control name directly, but if using any container then you should use container name too, e.g. GridView1$txtLname.– Tetsuya Yamamoto
Nov 22 '18 at 2:05
I recently just solved this, I have just put it inside the formlayout fields. sigh.
– user3312649
Nov 22 '18 at 3:45
I recently just solved this, I have just put it inside the formlayout fields. sigh.
– user3312649
Nov 22 '18 at 3:45
add a comment |
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Please show the
SqlDataSourceandASPxTextBoxmarkup to let us find out possible cause of this issue. Try usingtxtLName_Init()event handler to see the unique ID, e.g.var textbox = sender as ASPxTextBox; Debug.WriteLine(textbox.UniqueID);.– Tetsuya Yamamoto
Nov 21 '18 at 8:21
I have already the problem but whenever I enter the value for date it would always display error.
– user3312649
Nov 22 '18 at 1:56
Is that
txtLnamecontained insideGridView'sItemTemplateor other container? If the textbox doesn't contained inside any container you can use the control name directly, but if using any container then you should use container name too, e.g.GridView1$txtLname.– Tetsuya Yamamoto
Nov 22 '18 at 2:05
I recently just solved this, I have just put it inside the formlayout fields. sigh.
– user3312649
Nov 22 '18 at 3:45