Defining parameters in SQLDatasource in devexpress












0















I have a SQLDataSource that has an insert statement and parameters defined, please see photo below:



enter image description here



As I run my program, it will always states that it cannot find the txtlName control. What is wrong with my implementation? Can someone tell how to fix this?



This is my mark up code for my sqldatasource.



<asp:SqlDataSource ID="SqlDataSource4" runat="server" ConnectionString="<%$ ConnectionStrings:MDRFConnectionString %>" InsertCommand="INSERT INTO MDRF_Main(MDRF_LName, MDRF_FName, MDRF_MName, MDRF_Department, MDRF_RequestType, MDRF_Status, MDRF_WorkflowId, MDRF_Company, MDRF_Remarks, MDRF_RequestModule, MDRF_DateRequired, MDRF_Priority, MDRF_ResponseTime, MDRF_Module, MDRF_DocNum) VALUES (@lname, @fname, @mname, @dept, @rt, @status, @work, @comp, @remarks, @rm, CONVERT(datetime, @date) , @prio, @response, @module, @dn)" OnSelecting="SqlDataSource4_Selecting" ProviderName="System.Data.SqlClient" SelectCommand="SELECT * FROM [MDRF_Main]">
<InsertParameters>
<asp:ControlParameter ControlID="txtLname" Name="lname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtFname" Name="fname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtMname" Name="mname" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbDepartment" Name="dept" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbRequestType" Name="rt" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbStatus" Name="status" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbWorkflow" Name="work" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbCompany" Name="comp" PropertyName="Value" />
<asp:ControlParameter ControlID="txtRemarks" Name="remarks" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbMasterData" Name="rm" PropertyName="Value" />
<asp:ControlParameter ControlID="txtDate" Name="date" PropertyName="Date" DbType="DateTime" />
<asp:ControlParameter ControlID="cmbPriority" Name="prio" PropertyName="Value" />
<asp:ControlParameter ControlID="txtResponse" Name="response" PropertyName="Text" />
<asp:Parameter DefaultValue="''" Name="module" />
<asp:ControlParameter ControlID="txtDocNum" DefaultValue="" Name="dn" PropertyName="Text" />
</InsertParameters>
</asp:SqlDataSource>


Thanks










share|improve this question

























  • Please show the SqlDataSource and ASPxTextBox markup to let us find out possible cause of this issue. Try using txtLName_Init() event handler to see the unique ID, e.g. var textbox = sender as ASPxTextBox; Debug.WriteLine(textbox.UniqueID);.

    – Tetsuya Yamamoto
    Nov 21 '18 at 8:21











  • I have already the problem but whenever I enter the value for date it would always display error.

    – user3312649
    Nov 22 '18 at 1:56











  • Is that txtLname contained inside GridView's ItemTemplate or other container? If the textbox doesn't contained inside any container you can use the control name directly, but if using any container then you should use container name too, e.g. GridView1$txtLname.

    – Tetsuya Yamamoto
    Nov 22 '18 at 2:05











  • I recently just solved this, I have just put it inside the formlayout fields. sigh.

    – user3312649
    Nov 22 '18 at 3:45
















0















I have a SQLDataSource that has an insert statement and parameters defined, please see photo below:



enter image description here



As I run my program, it will always states that it cannot find the txtlName control. What is wrong with my implementation? Can someone tell how to fix this?



This is my mark up code for my sqldatasource.



<asp:SqlDataSource ID="SqlDataSource4" runat="server" ConnectionString="<%$ ConnectionStrings:MDRFConnectionString %>" InsertCommand="INSERT INTO MDRF_Main(MDRF_LName, MDRF_FName, MDRF_MName, MDRF_Department, MDRF_RequestType, MDRF_Status, MDRF_WorkflowId, MDRF_Company, MDRF_Remarks, MDRF_RequestModule, MDRF_DateRequired, MDRF_Priority, MDRF_ResponseTime, MDRF_Module, MDRF_DocNum) VALUES (@lname, @fname, @mname, @dept, @rt, @status, @work, @comp, @remarks, @rm, CONVERT(datetime, @date) , @prio, @response, @module, @dn)" OnSelecting="SqlDataSource4_Selecting" ProviderName="System.Data.SqlClient" SelectCommand="SELECT * FROM [MDRF_Main]">
<InsertParameters>
<asp:ControlParameter ControlID="txtLname" Name="lname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtFname" Name="fname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtMname" Name="mname" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbDepartment" Name="dept" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbRequestType" Name="rt" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbStatus" Name="status" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbWorkflow" Name="work" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbCompany" Name="comp" PropertyName="Value" />
<asp:ControlParameter ControlID="txtRemarks" Name="remarks" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbMasterData" Name="rm" PropertyName="Value" />
<asp:ControlParameter ControlID="txtDate" Name="date" PropertyName="Date" DbType="DateTime" />
<asp:ControlParameter ControlID="cmbPriority" Name="prio" PropertyName="Value" />
<asp:ControlParameter ControlID="txtResponse" Name="response" PropertyName="Text" />
<asp:Parameter DefaultValue="''" Name="module" />
<asp:ControlParameter ControlID="txtDocNum" DefaultValue="" Name="dn" PropertyName="Text" />
</InsertParameters>
</asp:SqlDataSource>


Thanks










share|improve this question

























  • Please show the SqlDataSource and ASPxTextBox markup to let us find out possible cause of this issue. Try using txtLName_Init() event handler to see the unique ID, e.g. var textbox = sender as ASPxTextBox; Debug.WriteLine(textbox.UniqueID);.

    – Tetsuya Yamamoto
    Nov 21 '18 at 8:21











  • I have already the problem but whenever I enter the value for date it would always display error.

    – user3312649
    Nov 22 '18 at 1:56











  • Is that txtLname contained inside GridView's ItemTemplate or other container? If the textbox doesn't contained inside any container you can use the control name directly, but if using any container then you should use container name too, e.g. GridView1$txtLname.

    – Tetsuya Yamamoto
    Nov 22 '18 at 2:05











  • I recently just solved this, I have just put it inside the formlayout fields. sigh.

    – user3312649
    Nov 22 '18 at 3:45














0












0








0


1






I have a SQLDataSource that has an insert statement and parameters defined, please see photo below:



enter image description here



As I run my program, it will always states that it cannot find the txtlName control. What is wrong with my implementation? Can someone tell how to fix this?



This is my mark up code for my sqldatasource.



<asp:SqlDataSource ID="SqlDataSource4" runat="server" ConnectionString="<%$ ConnectionStrings:MDRFConnectionString %>" InsertCommand="INSERT INTO MDRF_Main(MDRF_LName, MDRF_FName, MDRF_MName, MDRF_Department, MDRF_RequestType, MDRF_Status, MDRF_WorkflowId, MDRF_Company, MDRF_Remarks, MDRF_RequestModule, MDRF_DateRequired, MDRF_Priority, MDRF_ResponseTime, MDRF_Module, MDRF_DocNum) VALUES (@lname, @fname, @mname, @dept, @rt, @status, @work, @comp, @remarks, @rm, CONVERT(datetime, @date) , @prio, @response, @module, @dn)" OnSelecting="SqlDataSource4_Selecting" ProviderName="System.Data.SqlClient" SelectCommand="SELECT * FROM [MDRF_Main]">
<InsertParameters>
<asp:ControlParameter ControlID="txtLname" Name="lname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtFname" Name="fname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtMname" Name="mname" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbDepartment" Name="dept" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbRequestType" Name="rt" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbStatus" Name="status" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbWorkflow" Name="work" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbCompany" Name="comp" PropertyName="Value" />
<asp:ControlParameter ControlID="txtRemarks" Name="remarks" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbMasterData" Name="rm" PropertyName="Value" />
<asp:ControlParameter ControlID="txtDate" Name="date" PropertyName="Date" DbType="DateTime" />
<asp:ControlParameter ControlID="cmbPriority" Name="prio" PropertyName="Value" />
<asp:ControlParameter ControlID="txtResponse" Name="response" PropertyName="Text" />
<asp:Parameter DefaultValue="''" Name="module" />
<asp:ControlParameter ControlID="txtDocNum" DefaultValue="" Name="dn" PropertyName="Text" />
</InsertParameters>
</asp:SqlDataSource>


Thanks










share|improve this question
















I have a SQLDataSource that has an insert statement and parameters defined, please see photo below:



enter image description here



As I run my program, it will always states that it cannot find the txtlName control. What is wrong with my implementation? Can someone tell how to fix this?



This is my mark up code for my sqldatasource.



<asp:SqlDataSource ID="SqlDataSource4" runat="server" ConnectionString="<%$ ConnectionStrings:MDRFConnectionString %>" InsertCommand="INSERT INTO MDRF_Main(MDRF_LName, MDRF_FName, MDRF_MName, MDRF_Department, MDRF_RequestType, MDRF_Status, MDRF_WorkflowId, MDRF_Company, MDRF_Remarks, MDRF_RequestModule, MDRF_DateRequired, MDRF_Priority, MDRF_ResponseTime, MDRF_Module, MDRF_DocNum) VALUES (@lname, @fname, @mname, @dept, @rt, @status, @work, @comp, @remarks, @rm, CONVERT(datetime, @date) , @prio, @response, @module, @dn)" OnSelecting="SqlDataSource4_Selecting" ProviderName="System.Data.SqlClient" SelectCommand="SELECT * FROM [MDRF_Main]">
<InsertParameters>
<asp:ControlParameter ControlID="txtLname" Name="lname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtFname" Name="fname" PropertyName="Text" />
<asp:ControlParameter ControlID="txtMname" Name="mname" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbDepartment" Name="dept" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbRequestType" Name="rt" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbStatus" Name="status" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbWorkflow" Name="work" PropertyName="Value" />
<asp:ControlParameter ControlID="cmbCompany" Name="comp" PropertyName="Value" />
<asp:ControlParameter ControlID="txtRemarks" Name="remarks" PropertyName="Text" />
<asp:ControlParameter ControlID="cmbMasterData" Name="rm" PropertyName="Value" />
<asp:ControlParameter ControlID="txtDate" Name="date" PropertyName="Date" DbType="DateTime" />
<asp:ControlParameter ControlID="cmbPriority" Name="prio" PropertyName="Value" />
<asp:ControlParameter ControlID="txtResponse" Name="response" PropertyName="Text" />
<asp:Parameter DefaultValue="''" Name="module" />
<asp:ControlParameter ControlID="txtDocNum" DefaultValue="" Name="dn" PropertyName="Text" />
</InsertParameters>
</asp:SqlDataSource>


Thanks







devexpress sqldatasource






share|improve this question















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share|improve this question




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edited Nov 22 '18 at 1:57







user3312649

















asked Nov 20 '18 at 13:10









user3312649user3312649

921113




921113













  • Please show the SqlDataSource and ASPxTextBox markup to let us find out possible cause of this issue. Try using txtLName_Init() event handler to see the unique ID, e.g. var textbox = sender as ASPxTextBox; Debug.WriteLine(textbox.UniqueID);.

    – Tetsuya Yamamoto
    Nov 21 '18 at 8:21











  • I have already the problem but whenever I enter the value for date it would always display error.

    – user3312649
    Nov 22 '18 at 1:56











  • Is that txtLname contained inside GridView's ItemTemplate or other container? If the textbox doesn't contained inside any container you can use the control name directly, but if using any container then you should use container name too, e.g. GridView1$txtLname.

    – Tetsuya Yamamoto
    Nov 22 '18 at 2:05











  • I recently just solved this, I have just put it inside the formlayout fields. sigh.

    – user3312649
    Nov 22 '18 at 3:45



















  • Please show the SqlDataSource and ASPxTextBox markup to let us find out possible cause of this issue. Try using txtLName_Init() event handler to see the unique ID, e.g. var textbox = sender as ASPxTextBox; Debug.WriteLine(textbox.UniqueID);.

    – Tetsuya Yamamoto
    Nov 21 '18 at 8:21











  • I have already the problem but whenever I enter the value for date it would always display error.

    – user3312649
    Nov 22 '18 at 1:56











  • Is that txtLname contained inside GridView's ItemTemplate or other container? If the textbox doesn't contained inside any container you can use the control name directly, but if using any container then you should use container name too, e.g. GridView1$txtLname.

    – Tetsuya Yamamoto
    Nov 22 '18 at 2:05











  • I recently just solved this, I have just put it inside the formlayout fields. sigh.

    – user3312649
    Nov 22 '18 at 3:45

















Please show the SqlDataSource and ASPxTextBox markup to let us find out possible cause of this issue. Try using txtLName_Init() event handler to see the unique ID, e.g. var textbox = sender as ASPxTextBox; Debug.WriteLine(textbox.UniqueID);.

– Tetsuya Yamamoto
Nov 21 '18 at 8:21





Please show the SqlDataSource and ASPxTextBox markup to let us find out possible cause of this issue. Try using txtLName_Init() event handler to see the unique ID, e.g. var textbox = sender as ASPxTextBox; Debug.WriteLine(textbox.UniqueID);.

– Tetsuya Yamamoto
Nov 21 '18 at 8:21













I have already the problem but whenever I enter the value for date it would always display error.

– user3312649
Nov 22 '18 at 1:56





I have already the problem but whenever I enter the value for date it would always display error.

– user3312649
Nov 22 '18 at 1:56













Is that txtLname contained inside GridView's ItemTemplate or other container? If the textbox doesn't contained inside any container you can use the control name directly, but if using any container then you should use container name too, e.g. GridView1$txtLname.

– Tetsuya Yamamoto
Nov 22 '18 at 2:05





Is that txtLname contained inside GridView's ItemTemplate or other container? If the textbox doesn't contained inside any container you can use the control name directly, but if using any container then you should use container name too, e.g. GridView1$txtLname.

– Tetsuya Yamamoto
Nov 22 '18 at 2:05













I recently just solved this, I have just put it inside the formlayout fields. sigh.

– user3312649
Nov 22 '18 at 3:45





I recently just solved this, I have just put it inside the formlayout fields. sigh.

– user3312649
Nov 22 '18 at 3:45












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