jquery version compatibilty issue unrecognized expression












0















I am using jquery-1.7.1 and I need to upgrade upon my client's request to jquery-1.12.0.



I get the following error when I do so :




Syntax error, unrecognized expression: #dragAndDropFiles input[name=Sans titre][type=text]




So that means that the downgraded jquery version doesn't understand this :



$("#dragAndDropFiles input[name=No Title][type=text]").val()


Can someone help me to understand why is this expression an issue?










share|improve this question





























    0















    I am using jquery-1.7.1 and I need to upgrade upon my client's request to jquery-1.12.0.



    I get the following error when I do so :




    Syntax error, unrecognized expression: #dragAndDropFiles input[name=Sans titre][type=text]




    So that means that the downgraded jquery version doesn't understand this :



    $("#dragAndDropFiles input[name=No Title][type=text]").val()


    Can someone help me to understand why is this expression an issue?










    share|improve this question



























      0












      0








      0








      I am using jquery-1.7.1 and I need to upgrade upon my client's request to jquery-1.12.0.



      I get the following error when I do so :




      Syntax error, unrecognized expression: #dragAndDropFiles input[name=Sans titre][type=text]




      So that means that the downgraded jquery version doesn't understand this :



      $("#dragAndDropFiles input[name=No Title][type=text]").val()


      Can someone help me to understand why is this expression an issue?










      share|improve this question
















      I am using jquery-1.7.1 and I need to upgrade upon my client's request to jquery-1.12.0.



      I get the following error when I do so :




      Syntax error, unrecognized expression: #dragAndDropFiles input[name=Sans titre][type=text]




      So that means that the downgraded jquery version doesn't understand this :



      $("#dragAndDropFiles input[name=No Title][type=text]").val()


      Can someone help me to understand why is this expression an issue?







      jquery






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 20 '18 at 13:30

























      asked Nov 20 '18 at 13:18







      user10641275































          2 Answers
          2






          active

          oldest

          votes


















          0














          If you have a whitespace in the attribute value you need to use it like name='No Title':






          $(function() {
          console.log($("#dragAndDropFiles input[name='No Title'][type=text]").val());
          });

          <script src="https://code.jquery.com/jquery-1.12.0.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="myval" />
          </div>








          share|improve this answer
























          • Oops stupid me, thanks!

            – user10641275
            Nov 20 '18 at 13:42



















          0

















          $(function() {
          console.log($('#dragAndDropFiles input[name="No Title"][type=text]').val());
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="check value" />
          </div>





          Use ' or " alternatively.






          share|improve this answer
























          • Yes that's what the other answer said, thanks! :)

            – user10641275
            Nov 20 '18 at 13:46











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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          If you have a whitespace in the attribute value you need to use it like name='No Title':






          $(function() {
          console.log($("#dragAndDropFiles input[name='No Title'][type=text]").val());
          });

          <script src="https://code.jquery.com/jquery-1.12.0.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="myval" />
          </div>








          share|improve this answer
























          • Oops stupid me, thanks!

            – user10641275
            Nov 20 '18 at 13:42
















          0














          If you have a whitespace in the attribute value you need to use it like name='No Title':






          $(function() {
          console.log($("#dragAndDropFiles input[name='No Title'][type=text]").val());
          });

          <script src="https://code.jquery.com/jquery-1.12.0.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="myval" />
          </div>








          share|improve this answer
























          • Oops stupid me, thanks!

            – user10641275
            Nov 20 '18 at 13:42














          0












          0








          0







          If you have a whitespace in the attribute value you need to use it like name='No Title':






          $(function() {
          console.log($("#dragAndDropFiles input[name='No Title'][type=text]").val());
          });

          <script src="https://code.jquery.com/jquery-1.12.0.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="myval" />
          </div>








          share|improve this answer













          If you have a whitespace in the attribute value you need to use it like name='No Title':






          $(function() {
          console.log($("#dragAndDropFiles input[name='No Title'][type=text]").val());
          });

          <script src="https://code.jquery.com/jquery-1.12.0.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="myval" />
          </div>








          $(function() {
          console.log($("#dragAndDropFiles input[name='No Title'][type=text]").val());
          });

          <script src="https://code.jquery.com/jquery-1.12.0.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="myval" />
          </div>





          $(function() {
          console.log($("#dragAndDropFiles input[name='No Title'][type=text]").val());
          });

          <script src="https://code.jquery.com/jquery-1.12.0.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="myval" />
          </div>






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 20 '18 at 13:37









          EskoEsko

          3,19121330




          3,19121330













          • Oops stupid me, thanks!

            – user10641275
            Nov 20 '18 at 13:42



















          • Oops stupid me, thanks!

            – user10641275
            Nov 20 '18 at 13:42

















          Oops stupid me, thanks!

          – user10641275
          Nov 20 '18 at 13:42





          Oops stupid me, thanks!

          – user10641275
          Nov 20 '18 at 13:42













          0

















          $(function() {
          console.log($('#dragAndDropFiles input[name="No Title"][type=text]').val());
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="check value" />
          </div>





          Use ' or " alternatively.






          share|improve this answer
























          • Yes that's what the other answer said, thanks! :)

            – user10641275
            Nov 20 '18 at 13:46
















          0

















          $(function() {
          console.log($('#dragAndDropFiles input[name="No Title"][type=text]').val());
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="check value" />
          </div>





          Use ' or " alternatively.






          share|improve this answer
























          • Yes that's what the other answer said, thanks! :)

            – user10641275
            Nov 20 '18 at 13:46














          0












          0








          0










          $(function() {
          console.log($('#dragAndDropFiles input[name="No Title"][type=text]').val());
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="check value" />
          </div>





          Use ' or " alternatively.






          share|improve this answer
















          $(function() {
          console.log($('#dragAndDropFiles input[name="No Title"][type=text]').val());
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="check value" />
          </div>





          Use ' or " alternatively.






          $(function() {
          console.log($('#dragAndDropFiles input[name="No Title"][type=text]').val());
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="check value" />
          </div>





          $(function() {
          console.log($('#dragAndDropFiles input[name="No Title"][type=text]').val());
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
          <div id="dragAndDropFiles">
          <input name="No Title" type="text" value="check value" />
          </div>






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 20 '18 at 13:44









          Sumesh TGSumesh TG

          2,1201723




          2,1201723













          • Yes that's what the other answer said, thanks! :)

            – user10641275
            Nov 20 '18 at 13:46



















          • Yes that's what the other answer said, thanks! :)

            – user10641275
            Nov 20 '18 at 13:46

















          Yes that's what the other answer said, thanks! :)

          – user10641275
          Nov 20 '18 at 13:46





          Yes that's what the other answer said, thanks! :)

          – user10641275
          Nov 20 '18 at 13:46


















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