HCF Python Program Not Debugging
0
def computeHCF(x,y):
if x>y:
small=int(y)
else:
small=int(x)
for i in range(1,small+1):
if ((x%i)==0) and ((y%i)==0)):
hcf=i
return hcf
a=input('Enter first number: ')
b=input('Enter second number: ')
print('The HCF of ',a,' and ',b,' is ',computeHCF(a,b))
I tried this code on Python to compute HCF and it showed:
Exception has occurred: TypeError
not all arguments converted during string formatting
File "C:UsersDellDesktopPythonfindhcf.py", line 7, in computeHCF
if ((x%i)==0 and (y%i)==0):
File "C:UsersDellDesktopPythonfindhcf.py", line 13, in <module>
print('The HCF of ',a,' and ',b,' is ',computeHCF(a,b))
Please help my to figure the mistake that I have done in this program, I tried many things but it didn't work at all. Thank you.
python visual-studio
asked Nov 17 '18 at 3:55
Binish JoshiBinish Joshi
33
add a comment |
0
def computeHCF(x,y):
if x>y:
small=int(y)
else:
small=int(x)
for i in range(1,small+1):
if ((x%i)==0) and ((y%i)==0)):
hcf=i
return hcf
a=input('Enter first number: ')
b=input('Enter second number: ')
print('The HCF of ',a,' and ',b,' is ',computeHCF(a,b))
I tried this code on Python to compute HCF and it showed:
Exception has occurred: TypeError
not all arguments converted during string formatting
File "C:UsersDellDesktopPythonfindhcf.py", line 7, in computeHCF
if ((x%i)==0 and (y%i)==0):
File "C:UsersDellDesktopPythonfindhcf.py", line 13, in <module>
print('The HCF of ',a,' and ',b,' is ',computeHCF(a,b))
Please help my to figure the mistake that I have done in this program, I tried many things but it didn't work at all. Thank you.
python visual-studio
asked Nov 17 '18 at 3:55
Binish JoshiBinish Joshi
33
1
input(..)returns a string. Make sure you convert it to int usingint().
– Austin
Nov 17 '18 at 4:18
Thank you so much @Austin ! That solved it!!
– Binish Joshi
Nov 17 '18 at 4:59
add a comment |
0
0
0
def computeHCF(x,y):
if x>y:
small=int(y)
else:
small=int(x)
for i in range(1,small+1):
if ((x%i)==0) and ((y%i)==0)):
hcf=i
return hcf
a=input('Enter first number: ')
b=input('Enter second number: ')
print('The HCF of ',a,' and ',b,' is ',computeHCF(a,b))
I tried this code on Python to compute HCF and it showed:
Exception has occurred: TypeError
not all arguments converted during string formatting
File "C:UsersDellDesktopPythonfindhcf.py", line 7, in computeHCF
if ((x%i)==0 and (y%i)==0):
File "C:UsersDellDesktopPythonfindhcf.py", line 13, in <module>
print('The HCF of ',a,' and ',b,' is ',computeHCF(a,b))
Please help my to figure the mistake that I have done in this program, I tried many things but it didn't work at all. Thank you.
python visual-studio
asked Nov 17 '18 at 3:55
Binish JoshiBinish Joshi
33
def computeHCF(x,y):
if x>y:
small=int(y)
else:
small=int(x)
for i in range(1,small+1):
if ((x%i)==0) and ((y%i)==0)):
hcf=i
return hcf
a=input('Enter first number: ')
b=input('Enter second number: ')
print('The HCF of ',a,' and ',b,' is ',computeHCF(a,b))
I tried this code on Python to compute HCF and it showed:
Exception has occurred: TypeError
not all arguments converted during string formatting
File "C:UsersDellDesktopPythonfindhcf.py", line 7, in computeHCF
if ((x%i)==0 and (y%i)==0):
File "C:UsersDellDesktopPythonfindhcf.py", line 13, in <module>
print('The HCF of ',a,' and ',b,' is ',computeHCF(a,b))
Please help my to figure the mistake that I have done in this program, I tried many things but it didn't work at all. Thank you.
python visual-studio
python visual-studio
asked Nov 17 '18 at 3:55
Binish JoshiBinish Joshi
33
asked Nov 17 '18 at 3:55
Binish JoshiBinish Joshi
33
asked Nov 17 '18 at 3:55
Binish JoshiBinish Joshi
33
asked Nov 17 '18 at 3:55
Binish JoshiBinish Joshi
33
asked Nov 17 '18 at 3:55
Binish JoshiBinish Joshi
33
33
1
input(..)returns a string. Make sure you convert it to int usingint().
– Austin
Nov 17 '18 at 4:18
Thank you so much @Austin ! That solved it!!
– Binish Joshi
Nov 17 '18 at 4:59
add a comment |
1
input(..)returns a string. Make sure you convert it to int usingint().
– Austin
Nov 17 '18 at 4:18
Thank you so much @Austin ! That solved it!!
– Binish Joshi
Nov 17 '18 at 4:59
1
1
input(..) returns a string. Make sure you convert it to int using int().– Austin
Nov 17 '18 at 4:18
input(..) returns a string. Make sure you convert it to int using int().– Austin
Nov 17 '18 at 4:18
Thank you so much @Austin ! That solved it!!
– Binish Joshi
Nov 17 '18 at 4:59
Thank you so much @Austin ! That solved it!!
– Binish Joshi
Nov 17 '18 at 4:59
add a comment |
1 Answer
1
active
oldest
votes
1
Probably you are using Python 3.x, which is causing this error. In Python 3.x input() reads the value as a 'string' and not 'int'. You can read integer like this.
a=int(input('Enter first number: '))
answered Nov 17 '18 at 4:19
Shiv RajawatShiv Rajawat
24617
If some answer works, you should always 'accept' it.
– Shiv Rajawat
Nov 17 '18 at 7:43
Whoops, my bad, @ShivRajawat I didn't know that! (:
– Binish Joshi
Nov 18 '18 at 9:32
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
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oldest
votes
1
Probably you are using Python 3.x, which is causing this error. In Python 3.x input() reads the value as a 'string' and not 'int'. You can read integer like this.
a=int(input('Enter first number: '))
answered Nov 17 '18 at 4:19
Shiv RajawatShiv Rajawat
24617
If some answer works, you should always 'accept' it.
– Shiv Rajawat
Nov 17 '18 at 7:43
Whoops, my bad, @ShivRajawat I didn't know that! (:
– Binish Joshi
Nov 18 '18 at 9:32
add a comment |
1
Probably you are using Python 3.x, which is causing this error. In Python 3.x input() reads the value as a 'string' and not 'int'. You can read integer like this.
a=int(input('Enter first number: '))
answered Nov 17 '18 at 4:19
Shiv RajawatShiv Rajawat
24617
If some answer works, you should always 'accept' it.
– Shiv Rajawat
Nov 17 '18 at 7:43
Whoops, my bad, @ShivRajawat I didn't know that! (:
– Binish Joshi
Nov 18 '18 at 9:32
add a comment |
1
1
1
Probably you are using Python 3.x, which is causing this error. In Python 3.x input() reads the value as a 'string' and not 'int'. You can read integer like this.
a=int(input('Enter first number: '))
answered Nov 17 '18 at 4:19
Shiv RajawatShiv Rajawat
24617
Probably you are using Python 3.x, which is causing this error. In Python 3.x input() reads the value as a 'string' and not 'int'. You can read integer like this.
a=int(input('Enter first number: '))
answered Nov 17 '18 at 4:19
Shiv RajawatShiv Rajawat
24617
answered Nov 17 '18 at 4:19
Shiv RajawatShiv Rajawat
24617
answered Nov 17 '18 at 4:19
Shiv RajawatShiv Rajawat
24617
answered Nov 17 '18 at 4:19
Shiv RajawatShiv Rajawat
24617
24617
If some answer works, you should always 'accept' it.
– Shiv Rajawat
Nov 17 '18 at 7:43
Whoops, my bad, @ShivRajawat I didn't know that! (:
– Binish Joshi
Nov 18 '18 at 9:32
add a comment |
If some answer works, you should always 'accept' it.
– Shiv Rajawat
Nov 17 '18 at 7:43
Whoops, my bad, @ShivRajawat I didn't know that! (:
– Binish Joshi
Nov 18 '18 at 9:32
If some answer works, you should always 'accept' it.
– Shiv Rajawat
Nov 17 '18 at 7:43
If some answer works, you should always 'accept' it.
– Shiv Rajawat
Nov 17 '18 at 7:43
Whoops, my bad, @ShivRajawat I didn't know that! (:
– Binish Joshi
Nov 18 '18 at 9:32
Whoops, my bad, @ShivRajawat I didn't know that! (:
– Binish Joshi
Nov 18 '18 at 9:32
add a comment |
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1
input(..)returns a string. Make sure you convert it to int usingint().– Austin
Nov 17 '18 at 4:18
Thank you so much @Austin ! That solved it!!
– Binish Joshi
Nov 17 '18 at 4:59