Renaming columns according to vector inside pipe












1















I have a data.frame df with columns A and B:



df <- data.frame(A = 1:5, B = 11:15)


There's another data.frame, df2, which I'm building by various calculations that ends up having generic column names X1 and X2, which I cannot control directly (because it passes through being a matrix at one point). So it ends up being something like:



mtrx <- matrix(1:10, ncol = 2)
mtrx %>% data.frame()


I would like to rename the columns in df2 to be the same as df. I could, of course, do it after I finish building df2 with a simple assigning:



names(df2)<-names(df)


My question is - is there a way to do this directly within the pipe? I can't seem to use dplyr::rename, because these have to be in the form of newname=oldname, and I can't seem to vectorize it. Same goes to the data.frame call itself - I can't just give it a vector of column names, as far as I can tell. Is there another option I'm missing? What I'm hoping for is something like



mtrx %>% data.frame() %>% rename(names(df))


but this doesn't work - gives error Error: All arguments must be named.



Cheers!










share|improve this question





























    1















    I have a data.frame df with columns A and B:



    df <- data.frame(A = 1:5, B = 11:15)


    There's another data.frame, df2, which I'm building by various calculations that ends up having generic column names X1 and X2, which I cannot control directly (because it passes through being a matrix at one point). So it ends up being something like:



    mtrx <- matrix(1:10, ncol = 2)
    mtrx %>% data.frame()


    I would like to rename the columns in df2 to be the same as df. I could, of course, do it after I finish building df2 with a simple assigning:



    names(df2)<-names(df)


    My question is - is there a way to do this directly within the pipe? I can't seem to use dplyr::rename, because these have to be in the form of newname=oldname, and I can't seem to vectorize it. Same goes to the data.frame call itself - I can't just give it a vector of column names, as far as I can tell. Is there another option I'm missing? What I'm hoping for is something like



    mtrx %>% data.frame() %>% rename(names(df))


    but this doesn't work - gives error Error: All arguments must be named.



    Cheers!










    share|improve this question



























      1












      1








      1








      I have a data.frame df with columns A and B:



      df <- data.frame(A = 1:5, B = 11:15)


      There's another data.frame, df2, which I'm building by various calculations that ends up having generic column names X1 and X2, which I cannot control directly (because it passes through being a matrix at one point). So it ends up being something like:



      mtrx <- matrix(1:10, ncol = 2)
      mtrx %>% data.frame()


      I would like to rename the columns in df2 to be the same as df. I could, of course, do it after I finish building df2 with a simple assigning:



      names(df2)<-names(df)


      My question is - is there a way to do this directly within the pipe? I can't seem to use dplyr::rename, because these have to be in the form of newname=oldname, and I can't seem to vectorize it. Same goes to the data.frame call itself - I can't just give it a vector of column names, as far as I can tell. Is there another option I'm missing? What I'm hoping for is something like



      mtrx %>% data.frame() %>% rename(names(df))


      but this doesn't work - gives error Error: All arguments must be named.



      Cheers!










      share|improve this question
















      I have a data.frame df with columns A and B:



      df <- data.frame(A = 1:5, B = 11:15)


      There's another data.frame, df2, which I'm building by various calculations that ends up having generic column names X1 and X2, which I cannot control directly (because it passes through being a matrix at one point). So it ends up being something like:



      mtrx <- matrix(1:10, ncol = 2)
      mtrx %>% data.frame()


      I would like to rename the columns in df2 to be the same as df. I could, of course, do it after I finish building df2 with a simple assigning:



      names(df2)<-names(df)


      My question is - is there a way to do this directly within the pipe? I can't seem to use dplyr::rename, because these have to be in the form of newname=oldname, and I can't seem to vectorize it. Same goes to the data.frame call itself - I can't just give it a vector of column names, as far as I can tell. Is there another option I'm missing? What I'm hoping for is something like



      mtrx %>% data.frame() %>% rename(names(df))


      but this doesn't work - gives error Error: All arguments must be named.



      Cheers!







      r pipe






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 18 '18 at 7:38









      markus

      11.9k1234




      11.9k1234










      asked Nov 18 '18 at 6:42









      iodiod

      3,8332722




      3,8332722
























          2 Answers
          2






          active

          oldest

          votes


















          1














          We can use rename_all from tidyverse



          library(tidyverse)
          mtrx %>%
          as.data.frame %>%
          rename_all(~ names(df))
          # A B
          # 1 1 6
          # 2 2 7
          # 3 3 8
          # 4 4 9
          # 5 5 10





          share|improve this answer



















          • 1





            That's what I was looking for! Thanks

            – iod
            Nov 18 '18 at 21:15



















          2














          You can use setNames



          mtrx %>% 
          data.frame() %>%
          setNames(., nm = names(df))
          # A B
          #1 1 6
          #2 2 7
          #3 3 8
          #4 4 9
          #5 5 10


          Or use purrr's equivalent set_names



          mtrx %>% 
          data.frame() %>%
          purrr::set_names(., nm = names(df))




          A third option is "names<-"



          mtrx %>% 
          data.frame() %>%
          "names<-"(names(df))





          share|improve this answer

























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            We can use rename_all from tidyverse



            library(tidyverse)
            mtrx %>%
            as.data.frame %>%
            rename_all(~ names(df))
            # A B
            # 1 1 6
            # 2 2 7
            # 3 3 8
            # 4 4 9
            # 5 5 10





            share|improve this answer



















            • 1





              That's what I was looking for! Thanks

              – iod
              Nov 18 '18 at 21:15
















            1














            We can use rename_all from tidyverse



            library(tidyverse)
            mtrx %>%
            as.data.frame %>%
            rename_all(~ names(df))
            # A B
            # 1 1 6
            # 2 2 7
            # 3 3 8
            # 4 4 9
            # 5 5 10





            share|improve this answer



















            • 1





              That's what I was looking for! Thanks

              – iod
              Nov 18 '18 at 21:15














            1












            1








            1







            We can use rename_all from tidyverse



            library(tidyverse)
            mtrx %>%
            as.data.frame %>%
            rename_all(~ names(df))
            # A B
            # 1 1 6
            # 2 2 7
            # 3 3 8
            # 4 4 9
            # 5 5 10





            share|improve this answer













            We can use rename_all from tidyverse



            library(tidyverse)
            mtrx %>%
            as.data.frame %>%
            rename_all(~ names(df))
            # A B
            # 1 1 6
            # 2 2 7
            # 3 3 8
            # 4 4 9
            # 5 5 10






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 18 '18 at 20:55









            akrunakrun

            406k13196270




            406k13196270








            • 1





              That's what I was looking for! Thanks

              – iod
              Nov 18 '18 at 21:15














            • 1





              That's what I was looking for! Thanks

              – iod
              Nov 18 '18 at 21:15








            1




            1





            That's what I was looking for! Thanks

            – iod
            Nov 18 '18 at 21:15





            That's what I was looking for! Thanks

            – iod
            Nov 18 '18 at 21:15













            2














            You can use setNames



            mtrx %>% 
            data.frame() %>%
            setNames(., nm = names(df))
            # A B
            #1 1 6
            #2 2 7
            #3 3 8
            #4 4 9
            #5 5 10


            Or use purrr's equivalent set_names



            mtrx %>% 
            data.frame() %>%
            purrr::set_names(., nm = names(df))




            A third option is "names<-"



            mtrx %>% 
            data.frame() %>%
            "names<-"(names(df))





            share|improve this answer






























              2














              You can use setNames



              mtrx %>% 
              data.frame() %>%
              setNames(., nm = names(df))
              # A B
              #1 1 6
              #2 2 7
              #3 3 8
              #4 4 9
              #5 5 10


              Or use purrr's equivalent set_names



              mtrx %>% 
              data.frame() %>%
              purrr::set_names(., nm = names(df))




              A third option is "names<-"



              mtrx %>% 
              data.frame() %>%
              "names<-"(names(df))





              share|improve this answer




























                2












                2








                2







                You can use setNames



                mtrx %>% 
                data.frame() %>%
                setNames(., nm = names(df))
                # A B
                #1 1 6
                #2 2 7
                #3 3 8
                #4 4 9
                #5 5 10


                Or use purrr's equivalent set_names



                mtrx %>% 
                data.frame() %>%
                purrr::set_names(., nm = names(df))




                A third option is "names<-"



                mtrx %>% 
                data.frame() %>%
                "names<-"(names(df))





                share|improve this answer















                You can use setNames



                mtrx %>% 
                data.frame() %>%
                setNames(., nm = names(df))
                # A B
                #1 1 6
                #2 2 7
                #3 3 8
                #4 4 9
                #5 5 10


                Or use purrr's equivalent set_names



                mtrx %>% 
                data.frame() %>%
                purrr::set_names(., nm = names(df))




                A third option is "names<-"



                mtrx %>% 
                data.frame() %>%
                "names<-"(names(df))






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 18 '18 at 7:44

























                answered Nov 18 '18 at 7:37









                markusmarkus

                11.9k1234




                11.9k1234






























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