Sequelize.js: get association of many-to-many junction model
I have some application. There is an Character, which can belong to many group. A group can have many characters and also many ranks. Each Character have specified rank. Ranks differs across the groups.
Character model:
module.exports = (sequelize, DataTypes) => {
let Character = sequelize.define('Character', {
/* attributes */
}, {});
Character.associate = (models) => {
Character.hasMany(models.outfit, { foreignKey: 'owner' });
Character.belongsToMany(models.group, { through: models.groupmember });
};
return Character;
};
Group model:
module.exports = (sequelize, DataTypes) => {
let Group = sequelize.define('Group', {
/* attributes */
}, {});
Group.associate = function (models) {
Group.belongsToMany(models.character, { through: models.groupmember, as: 'members' });
Group.hasMany(models.grouprank);
};
return Group;
};
GroupMember (junction table) model:
module.exports = (sequelize, DataTypes) => {
let GroupMember = sequelize.define('GroupMember', {
/* groupId, characterId are generated by sequelize */
rankId: DataTypes.INTEGER
}, {});
GroupMember.associate = function (models) {
GroupMember.belongsTo(models.grouprank, { foreignKey: 'rankId', targetKey: 'id' });
};
return GroupMember;
};
Group rank model: (doesn't matter much in my question)
module.exports = (sequelize, DataTypes) => {
let GroupRank = sequelize.define('GroupRank', {
// atributes
}, {});
GroupRank.associate = function (models) {
GroupRank.belongsTo(models.group);
GroupRank.hasMany(models.groupmember, { foreignKey: 'rankId' });
};
return GroupRank;
};
I have added rankId
column to junction table and I have problem to retrieve Character with all its groups included and also the rank which it have.
My current code, which returns the Character, the groups to which he belongst to, and also ranks, but the ALL ranks which belongs to the group. And I want just the rank with ID which is specified by rankId
.
database.character.findById(characterId, {
include: [{
model: database.group,
through: database.groupmember,
include: {
model: database.grouprank,
/* where: { id: '$GroupMember.rankId$' } */
}
}]
}).then(result => {
});
Yep. I know it looks weird little, it lacks CamelCase but however my problem is about something else. I tried to query with where
attribute, but Sequelize is parsing the string, so I can't put there column name. I hope the question is understable enough. Thank you for your time!
javascript orm sequelize.js
add a comment |
I have some application. There is an Character, which can belong to many group. A group can have many characters and also many ranks. Each Character have specified rank. Ranks differs across the groups.
Character model:
module.exports = (sequelize, DataTypes) => {
let Character = sequelize.define('Character', {
/* attributes */
}, {});
Character.associate = (models) => {
Character.hasMany(models.outfit, { foreignKey: 'owner' });
Character.belongsToMany(models.group, { through: models.groupmember });
};
return Character;
};
Group model:
module.exports = (sequelize, DataTypes) => {
let Group = sequelize.define('Group', {
/* attributes */
}, {});
Group.associate = function (models) {
Group.belongsToMany(models.character, { through: models.groupmember, as: 'members' });
Group.hasMany(models.grouprank);
};
return Group;
};
GroupMember (junction table) model:
module.exports = (sequelize, DataTypes) => {
let GroupMember = sequelize.define('GroupMember', {
/* groupId, characterId are generated by sequelize */
rankId: DataTypes.INTEGER
}, {});
GroupMember.associate = function (models) {
GroupMember.belongsTo(models.grouprank, { foreignKey: 'rankId', targetKey: 'id' });
};
return GroupMember;
};
Group rank model: (doesn't matter much in my question)
module.exports = (sequelize, DataTypes) => {
let GroupRank = sequelize.define('GroupRank', {
// atributes
}, {});
GroupRank.associate = function (models) {
GroupRank.belongsTo(models.group);
GroupRank.hasMany(models.groupmember, { foreignKey: 'rankId' });
};
return GroupRank;
};
I have added rankId
column to junction table and I have problem to retrieve Character with all its groups included and also the rank which it have.
My current code, which returns the Character, the groups to which he belongst to, and also ranks, but the ALL ranks which belongs to the group. And I want just the rank with ID which is specified by rankId
.
database.character.findById(characterId, {
include: [{
model: database.group,
through: database.groupmember,
include: {
model: database.grouprank,
/* where: { id: '$GroupMember.rankId$' } */
}
}]
}).then(result => {
});
Yep. I know it looks weird little, it lacks CamelCase but however my problem is about something else. I tried to query with where
attribute, but Sequelize is parsing the string, so I can't put there column name. I hope the question is understable enough. Thank you for your time!
javascript orm sequelize.js
add a comment |
I have some application. There is an Character, which can belong to many group. A group can have many characters and also many ranks. Each Character have specified rank. Ranks differs across the groups.
Character model:
module.exports = (sequelize, DataTypes) => {
let Character = sequelize.define('Character', {
/* attributes */
}, {});
Character.associate = (models) => {
Character.hasMany(models.outfit, { foreignKey: 'owner' });
Character.belongsToMany(models.group, { through: models.groupmember });
};
return Character;
};
Group model:
module.exports = (sequelize, DataTypes) => {
let Group = sequelize.define('Group', {
/* attributes */
}, {});
Group.associate = function (models) {
Group.belongsToMany(models.character, { through: models.groupmember, as: 'members' });
Group.hasMany(models.grouprank);
};
return Group;
};
GroupMember (junction table) model:
module.exports = (sequelize, DataTypes) => {
let GroupMember = sequelize.define('GroupMember', {
/* groupId, characterId are generated by sequelize */
rankId: DataTypes.INTEGER
}, {});
GroupMember.associate = function (models) {
GroupMember.belongsTo(models.grouprank, { foreignKey: 'rankId', targetKey: 'id' });
};
return GroupMember;
};
Group rank model: (doesn't matter much in my question)
module.exports = (sequelize, DataTypes) => {
let GroupRank = sequelize.define('GroupRank', {
// atributes
}, {});
GroupRank.associate = function (models) {
GroupRank.belongsTo(models.group);
GroupRank.hasMany(models.groupmember, { foreignKey: 'rankId' });
};
return GroupRank;
};
I have added rankId
column to junction table and I have problem to retrieve Character with all its groups included and also the rank which it have.
My current code, which returns the Character, the groups to which he belongst to, and also ranks, but the ALL ranks which belongs to the group. And I want just the rank with ID which is specified by rankId
.
database.character.findById(characterId, {
include: [{
model: database.group,
through: database.groupmember,
include: {
model: database.grouprank,
/* where: { id: '$GroupMember.rankId$' } */
}
}]
}).then(result => {
});
Yep. I know it looks weird little, it lacks CamelCase but however my problem is about something else. I tried to query with where
attribute, but Sequelize is parsing the string, so I can't put there column name. I hope the question is understable enough. Thank you for your time!
javascript orm sequelize.js
I have some application. There is an Character, which can belong to many group. A group can have many characters and also many ranks. Each Character have specified rank. Ranks differs across the groups.
Character model:
module.exports = (sequelize, DataTypes) => {
let Character = sequelize.define('Character', {
/* attributes */
}, {});
Character.associate = (models) => {
Character.hasMany(models.outfit, { foreignKey: 'owner' });
Character.belongsToMany(models.group, { through: models.groupmember });
};
return Character;
};
Group model:
module.exports = (sequelize, DataTypes) => {
let Group = sequelize.define('Group', {
/* attributes */
}, {});
Group.associate = function (models) {
Group.belongsToMany(models.character, { through: models.groupmember, as: 'members' });
Group.hasMany(models.grouprank);
};
return Group;
};
GroupMember (junction table) model:
module.exports = (sequelize, DataTypes) => {
let GroupMember = sequelize.define('GroupMember', {
/* groupId, characterId are generated by sequelize */
rankId: DataTypes.INTEGER
}, {});
GroupMember.associate = function (models) {
GroupMember.belongsTo(models.grouprank, { foreignKey: 'rankId', targetKey: 'id' });
};
return GroupMember;
};
Group rank model: (doesn't matter much in my question)
module.exports = (sequelize, DataTypes) => {
let GroupRank = sequelize.define('GroupRank', {
// atributes
}, {});
GroupRank.associate = function (models) {
GroupRank.belongsTo(models.group);
GroupRank.hasMany(models.groupmember, { foreignKey: 'rankId' });
};
return GroupRank;
};
I have added rankId
column to junction table and I have problem to retrieve Character with all its groups included and also the rank which it have.
My current code, which returns the Character, the groups to which he belongst to, and also ranks, but the ALL ranks which belongs to the group. And I want just the rank with ID which is specified by rankId
.
database.character.findById(characterId, {
include: [{
model: database.group,
through: database.groupmember,
include: {
model: database.grouprank,
/* where: { id: '$GroupMember.rankId$' } */
}
}]
}).then(result => {
});
Yep. I know it looks weird little, it lacks CamelCase but however my problem is about something else. I tried to query with where
attribute, but Sequelize is parsing the string, so I can't put there column name. I hope the question is understable enough. Thank you for your time!
javascript orm sequelize.js
javascript orm sequelize.js
edited Nov 18 '18 at 17:48
Jakub
asked Nov 18 '18 at 17:31
JakubJakub
1624
1624
add a comment |
add a comment |
1 Answer
1
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votes
I think below code finally worked for me. http://docs.sequelizejs.com/class/lib/sequelize.js~Sequelize.html#static-method-literal
database.character.findById(characterId, {
include: [{
model: database.group,
through: database.groupmember,
include: {
model: database.grouprank,
where: database.Sequelize.literal('`Groups->GroupRanks`.`id` = `Groups->GroupMember`.`rankId`')
}
}]
})
edit: Finally I decided to rewrite models as stated here -> FindAll with includes involving a complicated many-to-(many-to-many) relationship (sequelizejs)
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think below code finally worked for me. http://docs.sequelizejs.com/class/lib/sequelize.js~Sequelize.html#static-method-literal
database.character.findById(characterId, {
include: [{
model: database.group,
through: database.groupmember,
include: {
model: database.grouprank,
where: database.Sequelize.literal('`Groups->GroupRanks`.`id` = `Groups->GroupMember`.`rankId`')
}
}]
})
edit: Finally I decided to rewrite models as stated here -> FindAll with includes involving a complicated many-to-(many-to-many) relationship (sequelizejs)
add a comment |
I think below code finally worked for me. http://docs.sequelizejs.com/class/lib/sequelize.js~Sequelize.html#static-method-literal
database.character.findById(characterId, {
include: [{
model: database.group,
through: database.groupmember,
include: {
model: database.grouprank,
where: database.Sequelize.literal('`Groups->GroupRanks`.`id` = `Groups->GroupMember`.`rankId`')
}
}]
})
edit: Finally I decided to rewrite models as stated here -> FindAll with includes involving a complicated many-to-(many-to-many) relationship (sequelizejs)
add a comment |
I think below code finally worked for me. http://docs.sequelizejs.com/class/lib/sequelize.js~Sequelize.html#static-method-literal
database.character.findById(characterId, {
include: [{
model: database.group,
through: database.groupmember,
include: {
model: database.grouprank,
where: database.Sequelize.literal('`Groups->GroupRanks`.`id` = `Groups->GroupMember`.`rankId`')
}
}]
})
edit: Finally I decided to rewrite models as stated here -> FindAll with includes involving a complicated many-to-(many-to-many) relationship (sequelizejs)
I think below code finally worked for me. http://docs.sequelizejs.com/class/lib/sequelize.js~Sequelize.html#static-method-literal
database.character.findById(characterId, {
include: [{
model: database.group,
through: database.groupmember,
include: {
model: database.grouprank,
where: database.Sequelize.literal('`Groups->GroupRanks`.`id` = `Groups->GroupMember`.`rankId`')
}
}]
})
edit: Finally I decided to rewrite models as stated here -> FindAll with includes involving a complicated many-to-(many-to-many) relationship (sequelizejs)
edited Dec 18 '18 at 18:15
answered Nov 18 '18 at 21:17
JakubJakub
1624
1624
add a comment |
add a comment |
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