Can I create HashOperations on demand?












0















With given instance of RedisTemplate<String, Object>,
can I create instances of HashOperation<String, HK, HV> on demand?



My team's codes look like this.



@Repository
class RedisRepository {

final RedisTemplate<String, Object> redisTemplate;
}


Due to some historical and technical reasons, I can't inject the redisTemplate directly into my service class.



So I want to know is it safe to invoke opsForHash on every request scoped operations?



@Serivce
class SomeSerivce {

// safe? no leak? what about performance?
public void doSomething() {
HashOperations<String, String, List<Some>> hashOperations =
redisRepository.getRedisTemplate().opsForHash();
}

@Autowired
RedisRepository redisRepository;
}


Is there any possible problem with approach?
Thanks in advance.










share|improve this question





























    0















    With given instance of RedisTemplate<String, Object>,
    can I create instances of HashOperation<String, HK, HV> on demand?



    My team's codes look like this.



    @Repository
    class RedisRepository {

    final RedisTemplate<String, Object> redisTemplate;
    }


    Due to some historical and technical reasons, I can't inject the redisTemplate directly into my service class.



    So I want to know is it safe to invoke opsForHash on every request scoped operations?



    @Serivce
    class SomeSerivce {

    // safe? no leak? what about performance?
    public void doSomething() {
    HashOperations<String, String, List<Some>> hashOperations =
    redisRepository.getRedisTemplate().opsForHash();
    }

    @Autowired
    RedisRepository redisRepository;
    }


    Is there any possible problem with approach?
    Thanks in advance.










    share|improve this question



























      0












      0








      0








      With given instance of RedisTemplate<String, Object>,
      can I create instances of HashOperation<String, HK, HV> on demand?



      My team's codes look like this.



      @Repository
      class RedisRepository {

      final RedisTemplate<String, Object> redisTemplate;
      }


      Due to some historical and technical reasons, I can't inject the redisTemplate directly into my service class.



      So I want to know is it safe to invoke opsForHash on every request scoped operations?



      @Serivce
      class SomeSerivce {

      // safe? no leak? what about performance?
      public void doSomething() {
      HashOperations<String, String, List<Some>> hashOperations =
      redisRepository.getRedisTemplate().opsForHash();
      }

      @Autowired
      RedisRepository redisRepository;
      }


      Is there any possible problem with approach?
      Thanks in advance.










      share|improve this question
















      With given instance of RedisTemplate<String, Object>,
      can I create instances of HashOperation<String, HK, HV> on demand?



      My team's codes look like this.



      @Repository
      class RedisRepository {

      final RedisTemplate<String, Object> redisTemplate;
      }


      Due to some historical and technical reasons, I can't inject the redisTemplate directly into my service class.



      So I want to know is it safe to invoke opsForHash on every request scoped operations?



      @Serivce
      class SomeSerivce {

      // safe? no leak? what about performance?
      public void doSomething() {
      HashOperations<String, String, List<Some>> hashOperations =
      redisRepository.getRedisTemplate().opsForHash();
      }

      @Autowired
      RedisRepository redisRepository;
      }


      Is there any possible problem with approach?
      Thanks in advance.







      spring redis spring-data spring-data-redis






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 21 '18 at 13:15







      Jin Kwon

















      asked Nov 21 '18 at 12:51









      Jin KwonJin Kwon

      10.3k667107




      10.3k667107
























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