How to create new button in Xamarin
I'm really new in coding but I know a few things in C#
.
I'm learning by myself just for the sake of it, for fun.
I've made some little programs in console and now I'm learning Xamarin
.
For now, I've followed the xamarin tutorials (those with the "phoneword" app).
I'm now working on another app for android and I would like to know how to create a new button in code.
Example:
On the main page, the user presses a button that creates a new page where he can fill a form. After he finished, a new button appear on the main page that leads to the form previously filled.
So when the user open the app, he has to choose whether he opens a new form or accesses to the old form (because now there is a new button).
All I want to know is: how do I create this new button ?
I've look everywhere and can't find any working solution. I don't know if that matters, but all I can see is explanations for Xamarin.Forms and that's not what I'm using. I'm using Xamarin Native.
For example, I've tried :
Button b = new Button();
b.Content = "Test";
b.Click += OnClick;
But it's not working. VS returns various errors.
I understand that "Button()" needs parameters, but I don't know what to do.
Someone can give a little help, please ?
PS: I'm not a native speaker, so please don't mind some mistakes with English grammar.
c# xamarin button xamarin.android
|
show 1 more comment
I'm really new in coding but I know a few things in C#
.
I'm learning by myself just for the sake of it, for fun.
I've made some little programs in console and now I'm learning Xamarin
.
For now, I've followed the xamarin tutorials (those with the "phoneword" app).
I'm now working on another app for android and I would like to know how to create a new button in code.
Example:
On the main page, the user presses a button that creates a new page where he can fill a form. After he finished, a new button appear on the main page that leads to the form previously filled.
So when the user open the app, he has to choose whether he opens a new form or accesses to the old form (because now there is a new button).
All I want to know is: how do I create this new button ?
I've look everywhere and can't find any working solution. I don't know if that matters, but all I can see is explanations for Xamarin.Forms and that's not what I'm using. I'm using Xamarin Native.
For example, I've tried :
Button b = new Button();
b.Content = "Test";
b.Click += OnClick;
But it's not working. VS returns various errors.
I understand that "Button()" needs parameters, but I don't know what to do.
Someone can give a little help, please ?
PS: I'm not a native speaker, so please don't mind some mistakes with English grammar.
c# xamarin button xamarin.android
"VS returns various errors" - it would be really helpful if you tell us what these errors are.
– Jason
Nov 21 '18 at 14:00
1
Xamarin Native can mean Xamarin.iOS, Xamarin.Android, Xamarin.Mac, maybe even some other flavors so you first need to say what you actually do.
– Ivan Ičin
Nov 21 '18 at 14:02
1
@DiegoRafaelSouza : didn't do it on purpose. Sorry.
– Jojojojo
Nov 21 '18 at 14:54
1
@IvanIčin as I wrote, it's for Android.
– Jojojojo
Nov 21 '18 at 14:55
@Jason Below you can check screens I uploaded. Thanks for helping !
– Jojojojo
Nov 21 '18 at 15:50
|
show 1 more comment
I'm really new in coding but I know a few things in C#
.
I'm learning by myself just for the sake of it, for fun.
I've made some little programs in console and now I'm learning Xamarin
.
For now, I've followed the xamarin tutorials (those with the "phoneword" app).
I'm now working on another app for android and I would like to know how to create a new button in code.
Example:
On the main page, the user presses a button that creates a new page where he can fill a form. After he finished, a new button appear on the main page that leads to the form previously filled.
So when the user open the app, he has to choose whether he opens a new form or accesses to the old form (because now there is a new button).
All I want to know is: how do I create this new button ?
I've look everywhere and can't find any working solution. I don't know if that matters, but all I can see is explanations for Xamarin.Forms and that's not what I'm using. I'm using Xamarin Native.
For example, I've tried :
Button b = new Button();
b.Content = "Test";
b.Click += OnClick;
But it's not working. VS returns various errors.
I understand that "Button()" needs parameters, but I don't know what to do.
Someone can give a little help, please ?
PS: I'm not a native speaker, so please don't mind some mistakes with English grammar.
c# xamarin button xamarin.android
I'm really new in coding but I know a few things in C#
.
I'm learning by myself just for the sake of it, for fun.
I've made some little programs in console and now I'm learning Xamarin
.
For now, I've followed the xamarin tutorials (those with the "phoneword" app).
I'm now working on another app for android and I would like to know how to create a new button in code.
Example:
On the main page, the user presses a button that creates a new page where he can fill a form. After he finished, a new button appear on the main page that leads to the form previously filled.
So when the user open the app, he has to choose whether he opens a new form or accesses to the old form (because now there is a new button).
All I want to know is: how do I create this new button ?
I've look everywhere and can't find any working solution. I don't know if that matters, but all I can see is explanations for Xamarin.Forms and that's not what I'm using. I'm using Xamarin Native.
For example, I've tried :
Button b = new Button();
b.Content = "Test";
b.Click += OnClick;
But it's not working. VS returns various errors.
I understand that "Button()" needs parameters, but I don't know what to do.
Someone can give a little help, please ?
PS: I'm not a native speaker, so please don't mind some mistakes with English grammar.
c# xamarin button xamarin.android
c# xamarin button xamarin.android
edited Nov 21 '18 at 15:09
Diego Rafael Souza
3,33131242
3,33131242
asked Nov 21 '18 at 13:52
JojojojoJojojojo
31
31
"VS returns various errors" - it would be really helpful if you tell us what these errors are.
– Jason
Nov 21 '18 at 14:00
1
Xamarin Native can mean Xamarin.iOS, Xamarin.Android, Xamarin.Mac, maybe even some other flavors so you first need to say what you actually do.
– Ivan Ičin
Nov 21 '18 at 14:02
1
@DiegoRafaelSouza : didn't do it on purpose. Sorry.
– Jojojojo
Nov 21 '18 at 14:54
1
@IvanIčin as I wrote, it's for Android.
– Jojojojo
Nov 21 '18 at 14:55
@Jason Below you can check screens I uploaded. Thanks for helping !
– Jojojojo
Nov 21 '18 at 15:50
|
show 1 more comment
"VS returns various errors" - it would be really helpful if you tell us what these errors are.
– Jason
Nov 21 '18 at 14:00
1
Xamarin Native can mean Xamarin.iOS, Xamarin.Android, Xamarin.Mac, maybe even some other flavors so you first need to say what you actually do.
– Ivan Ičin
Nov 21 '18 at 14:02
1
@DiegoRafaelSouza : didn't do it on purpose. Sorry.
– Jojojojo
Nov 21 '18 at 14:54
1
@IvanIčin as I wrote, it's for Android.
– Jojojojo
Nov 21 '18 at 14:55
@Jason Below you can check screens I uploaded. Thanks for helping !
– Jojojojo
Nov 21 '18 at 15:50
"VS returns various errors" - it would be really helpful if you tell us what these errors are.
– Jason
Nov 21 '18 at 14:00
"VS returns various errors" - it would be really helpful if you tell us what these errors are.
– Jason
Nov 21 '18 at 14:00
1
1
Xamarin Native can mean Xamarin.iOS, Xamarin.Android, Xamarin.Mac, maybe even some other flavors so you first need to say what you actually do.
– Ivan Ičin
Nov 21 '18 at 14:02
Xamarin Native can mean Xamarin.iOS, Xamarin.Android, Xamarin.Mac, maybe even some other flavors so you first need to say what you actually do.
– Ivan Ičin
Nov 21 '18 at 14:02
1
1
@DiegoRafaelSouza : didn't do it on purpose. Sorry.
– Jojojojo
Nov 21 '18 at 14:54
@DiegoRafaelSouza : didn't do it on purpose. Sorry.
– Jojojojo
Nov 21 '18 at 14:54
1
1
@IvanIčin as I wrote, it's for Android.
– Jojojojo
Nov 21 '18 at 14:55
@IvanIčin as I wrote, it's for Android.
– Jojojojo
Nov 21 '18 at 14:55
@Jason Below you can check screens I uploaded. Thanks for helping !
– Jojojojo
Nov 21 '18 at 15:50
@Jason Below you can check screens I uploaded. Thanks for helping !
– Jojojojo
Nov 21 '18 at 15:50
|
show 1 more comment
3 Answers
3
active
oldest
votes
First you need to create parameters
of layout & than add those params to button like this
var params = new LinearLayout.LayoutParams(ViewGroup.LayoutParams.FillParent, ViewGroup.LayoutParams.WrapContent);
Button b = new Button(this);
b.SetText("Test",TextView.BufferType.Normal);
b.Click=OnClick;
b.LayoutParameters = params;
Or add layout in your in axml like this
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@id/linear_layout"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
Than in your activity get you Layout
using Id
& add button to it.
LinearLayout l_layout = (LinearLayout)FindViewById(Resource.Id.linear_layout);
l_layout.Orientation = Orientation.Horizontal;
Button b = new Button(this);
b.Click=OnClick;
b.SetText("Test",TextView.BufferType.Normal);
l_layout.AddView(b);
Thanks for responding, I have some issues with both ways. Here you can check what VS returns : link and link . Thanks for helping !
– Jojojojo
Nov 21 '18 at 15:48
@Jojojojo The screenshots are hard to read (for instance I can't see your OnClick method), which it is why it is bad practise to use them. It is best to copy and paste your code and format it here according to the guidelines.
– uprightbassfan78
Nov 21 '18 at 15:59
@jojojo - For first part, do that inside 'OnCreate' method of your activity & your are not passing 'this' in button at right side as I provided code. Create 'OnClick' method too or you can comment that line.
– CGPA6.4
Nov 21 '18 at 17:00
@CGPA6.4 as a matter of fact, I noticed that I didn't and try it again, but I uploaded the wrong screen. Thanks
– Jojojojo
Nov 21 '18 at 20:09
So, I did what you said (comment the OnClick line) plus I rewrote the ID line (android:id="@+id/linear_layout"), and now it's working. Thanks a lot !
– Jojojojo
Nov 21 '18 at 21:13
add a comment |
With this You can create the button You only need to add the size of the button and add it to some layout.
Xamarin.Forms
Button button = new Button();
button.Text = "Title";
Xamarin.Android
Button button = new Button(this); //if your using a fragment you have to use this.Activity
button.Text = "Title";
Xamarin.iOS
UIButton button = new UIButton();
button.SetTitle("Title", UIControlState.Normal);
Thanks for responding. I tried but I don't know how to add a layout. So I tried @CGPA6.4 's way but got errors as you can see below.
– Jojojojo
Nov 21 '18 at 15:45
which platform are you using ?
– Ricardo Romo
Nov 21 '18 at 15:46
add a comment |
Xamarin forms button example
var Tittlebutton= new Button
{
Text = "Title"
};
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
First you need to create parameters
of layout & than add those params to button like this
var params = new LinearLayout.LayoutParams(ViewGroup.LayoutParams.FillParent, ViewGroup.LayoutParams.WrapContent);
Button b = new Button(this);
b.SetText("Test",TextView.BufferType.Normal);
b.Click=OnClick;
b.LayoutParameters = params;
Or add layout in your in axml like this
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@id/linear_layout"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
Than in your activity get you Layout
using Id
& add button to it.
LinearLayout l_layout = (LinearLayout)FindViewById(Resource.Id.linear_layout);
l_layout.Orientation = Orientation.Horizontal;
Button b = new Button(this);
b.Click=OnClick;
b.SetText("Test",TextView.BufferType.Normal);
l_layout.AddView(b);
Thanks for responding, I have some issues with both ways. Here you can check what VS returns : link and link . Thanks for helping !
– Jojojojo
Nov 21 '18 at 15:48
@Jojojojo The screenshots are hard to read (for instance I can't see your OnClick method), which it is why it is bad practise to use them. It is best to copy and paste your code and format it here according to the guidelines.
– uprightbassfan78
Nov 21 '18 at 15:59
@jojojo - For first part, do that inside 'OnCreate' method of your activity & your are not passing 'this' in button at right side as I provided code. Create 'OnClick' method too or you can comment that line.
– CGPA6.4
Nov 21 '18 at 17:00
@CGPA6.4 as a matter of fact, I noticed that I didn't and try it again, but I uploaded the wrong screen. Thanks
– Jojojojo
Nov 21 '18 at 20:09
So, I did what you said (comment the OnClick line) plus I rewrote the ID line (android:id="@+id/linear_layout"), and now it's working. Thanks a lot !
– Jojojojo
Nov 21 '18 at 21:13
add a comment |
First you need to create parameters
of layout & than add those params to button like this
var params = new LinearLayout.LayoutParams(ViewGroup.LayoutParams.FillParent, ViewGroup.LayoutParams.WrapContent);
Button b = new Button(this);
b.SetText("Test",TextView.BufferType.Normal);
b.Click=OnClick;
b.LayoutParameters = params;
Or add layout in your in axml like this
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@id/linear_layout"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
Than in your activity get you Layout
using Id
& add button to it.
LinearLayout l_layout = (LinearLayout)FindViewById(Resource.Id.linear_layout);
l_layout.Orientation = Orientation.Horizontal;
Button b = new Button(this);
b.Click=OnClick;
b.SetText("Test",TextView.BufferType.Normal);
l_layout.AddView(b);
Thanks for responding, I have some issues with both ways. Here you can check what VS returns : link and link . Thanks for helping !
– Jojojojo
Nov 21 '18 at 15:48
@Jojojojo The screenshots are hard to read (for instance I can't see your OnClick method), which it is why it is bad practise to use them. It is best to copy and paste your code and format it here according to the guidelines.
– uprightbassfan78
Nov 21 '18 at 15:59
@jojojo - For first part, do that inside 'OnCreate' method of your activity & your are not passing 'this' in button at right side as I provided code. Create 'OnClick' method too or you can comment that line.
– CGPA6.4
Nov 21 '18 at 17:00
@CGPA6.4 as a matter of fact, I noticed that I didn't and try it again, but I uploaded the wrong screen. Thanks
– Jojojojo
Nov 21 '18 at 20:09
So, I did what you said (comment the OnClick line) plus I rewrote the ID line (android:id="@+id/linear_layout"), and now it's working. Thanks a lot !
– Jojojojo
Nov 21 '18 at 21:13
add a comment |
First you need to create parameters
of layout & than add those params to button like this
var params = new LinearLayout.LayoutParams(ViewGroup.LayoutParams.FillParent, ViewGroup.LayoutParams.WrapContent);
Button b = new Button(this);
b.SetText("Test",TextView.BufferType.Normal);
b.Click=OnClick;
b.LayoutParameters = params;
Or add layout in your in axml like this
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@id/linear_layout"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
Than in your activity get you Layout
using Id
& add button to it.
LinearLayout l_layout = (LinearLayout)FindViewById(Resource.Id.linear_layout);
l_layout.Orientation = Orientation.Horizontal;
Button b = new Button(this);
b.Click=OnClick;
b.SetText("Test",TextView.BufferType.Normal);
l_layout.AddView(b);
First you need to create parameters
of layout & than add those params to button like this
var params = new LinearLayout.LayoutParams(ViewGroup.LayoutParams.FillParent, ViewGroup.LayoutParams.WrapContent);
Button b = new Button(this);
b.SetText("Test",TextView.BufferType.Normal);
b.Click=OnClick;
b.LayoutParameters = params;
Or add layout in your in axml like this
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@id/linear_layout"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
Than in your activity get you Layout
using Id
& add button to it.
LinearLayout l_layout = (LinearLayout)FindViewById(Resource.Id.linear_layout);
l_layout.Orientation = Orientation.Horizontal;
Button b = new Button(this);
b.Click=OnClick;
b.SetText("Test",TextView.BufferType.Normal);
l_layout.AddView(b);
answered Nov 21 '18 at 14:28
CGPA6.4CGPA6.4
2,88831031
2,88831031
Thanks for responding, I have some issues with both ways. Here you can check what VS returns : link and link . Thanks for helping !
– Jojojojo
Nov 21 '18 at 15:48
@Jojojojo The screenshots are hard to read (for instance I can't see your OnClick method), which it is why it is bad practise to use them. It is best to copy and paste your code and format it here according to the guidelines.
– uprightbassfan78
Nov 21 '18 at 15:59
@jojojo - For first part, do that inside 'OnCreate' method of your activity & your are not passing 'this' in button at right side as I provided code. Create 'OnClick' method too or you can comment that line.
– CGPA6.4
Nov 21 '18 at 17:00
@CGPA6.4 as a matter of fact, I noticed that I didn't and try it again, but I uploaded the wrong screen. Thanks
– Jojojojo
Nov 21 '18 at 20:09
So, I did what you said (comment the OnClick line) plus I rewrote the ID line (android:id="@+id/linear_layout"), and now it's working. Thanks a lot !
– Jojojojo
Nov 21 '18 at 21:13
add a comment |
Thanks for responding, I have some issues with both ways. Here you can check what VS returns : link and link . Thanks for helping !
– Jojojojo
Nov 21 '18 at 15:48
@Jojojojo The screenshots are hard to read (for instance I can't see your OnClick method), which it is why it is bad practise to use them. It is best to copy and paste your code and format it here according to the guidelines.
– uprightbassfan78
Nov 21 '18 at 15:59
@jojojo - For first part, do that inside 'OnCreate' method of your activity & your are not passing 'this' in button at right side as I provided code. Create 'OnClick' method too or you can comment that line.
– CGPA6.4
Nov 21 '18 at 17:00
@CGPA6.4 as a matter of fact, I noticed that I didn't and try it again, but I uploaded the wrong screen. Thanks
– Jojojojo
Nov 21 '18 at 20:09
So, I did what you said (comment the OnClick line) plus I rewrote the ID line (android:id="@+id/linear_layout"), and now it's working. Thanks a lot !
– Jojojojo
Nov 21 '18 at 21:13
Thanks for responding, I have some issues with both ways. Here you can check what VS returns : link and link . Thanks for helping !
– Jojojojo
Nov 21 '18 at 15:48
Thanks for responding, I have some issues with both ways. Here you can check what VS returns : link and link . Thanks for helping !
– Jojojojo
Nov 21 '18 at 15:48
@Jojojojo The screenshots are hard to read (for instance I can't see your OnClick method), which it is why it is bad practise to use them. It is best to copy and paste your code and format it here according to the guidelines.
– uprightbassfan78
Nov 21 '18 at 15:59
@Jojojojo The screenshots are hard to read (for instance I can't see your OnClick method), which it is why it is bad practise to use them. It is best to copy and paste your code and format it here according to the guidelines.
– uprightbassfan78
Nov 21 '18 at 15:59
@jojojo - For first part, do that inside 'OnCreate' method of your activity & your are not passing 'this' in button at right side as I provided code. Create 'OnClick' method too or you can comment that line.
– CGPA6.4
Nov 21 '18 at 17:00
@jojojo - For first part, do that inside 'OnCreate' method of your activity & your are not passing 'this' in button at right side as I provided code. Create 'OnClick' method too or you can comment that line.
– CGPA6.4
Nov 21 '18 at 17:00
@CGPA6.4 as a matter of fact, I noticed that I didn't and try it again, but I uploaded the wrong screen. Thanks
– Jojojojo
Nov 21 '18 at 20:09
@CGPA6.4 as a matter of fact, I noticed that I didn't and try it again, but I uploaded the wrong screen. Thanks
– Jojojojo
Nov 21 '18 at 20:09
So, I did what you said (comment the OnClick line) plus I rewrote the ID line (android:id="@+id/linear_layout"), and now it's working. Thanks a lot !
– Jojojojo
Nov 21 '18 at 21:13
So, I did what you said (comment the OnClick line) plus I rewrote the ID line (android:id="@+id/linear_layout"), and now it's working. Thanks a lot !
– Jojojojo
Nov 21 '18 at 21:13
add a comment |
With this You can create the button You only need to add the size of the button and add it to some layout.
Xamarin.Forms
Button button = new Button();
button.Text = "Title";
Xamarin.Android
Button button = new Button(this); //if your using a fragment you have to use this.Activity
button.Text = "Title";
Xamarin.iOS
UIButton button = new UIButton();
button.SetTitle("Title", UIControlState.Normal);
Thanks for responding. I tried but I don't know how to add a layout. So I tried @CGPA6.4 's way but got errors as you can see below.
– Jojojojo
Nov 21 '18 at 15:45
which platform are you using ?
– Ricardo Romo
Nov 21 '18 at 15:46
add a comment |
With this You can create the button You only need to add the size of the button and add it to some layout.
Xamarin.Forms
Button button = new Button();
button.Text = "Title";
Xamarin.Android
Button button = new Button(this); //if your using a fragment you have to use this.Activity
button.Text = "Title";
Xamarin.iOS
UIButton button = new UIButton();
button.SetTitle("Title", UIControlState.Normal);
Thanks for responding. I tried but I don't know how to add a layout. So I tried @CGPA6.4 's way but got errors as you can see below.
– Jojojojo
Nov 21 '18 at 15:45
which platform are you using ?
– Ricardo Romo
Nov 21 '18 at 15:46
add a comment |
With this You can create the button You only need to add the size of the button and add it to some layout.
Xamarin.Forms
Button button = new Button();
button.Text = "Title";
Xamarin.Android
Button button = new Button(this); //if your using a fragment you have to use this.Activity
button.Text = "Title";
Xamarin.iOS
UIButton button = new UIButton();
button.SetTitle("Title", UIControlState.Normal);
With this You can create the button You only need to add the size of the button and add it to some layout.
Xamarin.Forms
Button button = new Button();
button.Text = "Title";
Xamarin.Android
Button button = new Button(this); //if your using a fragment you have to use this.Activity
button.Text = "Title";
Xamarin.iOS
UIButton button = new UIButton();
button.SetTitle("Title", UIControlState.Normal);
answered Nov 21 '18 at 14:18
Ricardo RomoRicardo Romo
809820
809820
Thanks for responding. I tried but I don't know how to add a layout. So I tried @CGPA6.4 's way but got errors as you can see below.
– Jojojojo
Nov 21 '18 at 15:45
which platform are you using ?
– Ricardo Romo
Nov 21 '18 at 15:46
add a comment |
Thanks for responding. I tried but I don't know how to add a layout. So I tried @CGPA6.4 's way but got errors as you can see below.
– Jojojojo
Nov 21 '18 at 15:45
which platform are you using ?
– Ricardo Romo
Nov 21 '18 at 15:46
Thanks for responding. I tried but I don't know how to add a layout. So I tried @CGPA6.4 's way but got errors as you can see below.
– Jojojojo
Nov 21 '18 at 15:45
Thanks for responding. I tried but I don't know how to add a layout. So I tried @CGPA6.4 's way but got errors as you can see below.
– Jojojojo
Nov 21 '18 at 15:45
which platform are you using ?
– Ricardo Romo
Nov 21 '18 at 15:46
which platform are you using ?
– Ricardo Romo
Nov 21 '18 at 15:46
add a comment |
Xamarin forms button example
var Tittlebutton= new Button
{
Text = "Title"
};
add a comment |
Xamarin forms button example
var Tittlebutton= new Button
{
Text = "Title"
};
add a comment |
Xamarin forms button example
var Tittlebutton= new Button
{
Text = "Title"
};
Xamarin forms button example
var Tittlebutton= new Button
{
Text = "Title"
};
answered Dec 3 '18 at 9:40
Chetan RawatChetan Rawat
83
83
add a comment |
add a comment |
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"VS returns various errors" - it would be really helpful if you tell us what these errors are.
– Jason
Nov 21 '18 at 14:00
1
Xamarin Native can mean Xamarin.iOS, Xamarin.Android, Xamarin.Mac, maybe even some other flavors so you first need to say what you actually do.
– Ivan Ičin
Nov 21 '18 at 14:02
1
@DiegoRafaelSouza : didn't do it on purpose. Sorry.
– Jojojojo
Nov 21 '18 at 14:54
1
@IvanIčin as I wrote, it's for Android.
– Jojojojo
Nov 21 '18 at 14:55
@Jason Below you can check screens I uploaded. Thanks for helping !
– Jojojojo
Nov 21 '18 at 15:50