Python regex, matching pattern over multiple lines.. why isn't this working?












13















I know that for parsing I should ideally remove all spaces and linebreaks but I was just doing this as a quick fix for something I was trying and I can't figure out why its not working.. I have wrapped different areas of text in my document with the wrappers like "####1" and am trying to parse based on this but its just not working no matter what I try, I think I am using multiline correctly.. any advice is appreciated



This returns no results at all:



string='

####1

ttteest

####1

ttttteeeestt



####2   



ttest

####2'



import re

pattern = '.*?####(.*?)####'

returnmatch = re.compile(pattern, re.MULTILINE).findall(string)

return returnmatch





python regex parsing







share|improve this question


















  • 1





    It won't run period because you're not using multi-line string symbols ''' or """

    – Nick T
    Aug 20 '10 at 20:13











  • ok, I missed this concept completely then, i will dig through the re documentation to find where it mentions this.. thanks

    – Rick
    Aug 20 '10 at 20:15






  • 3





    Your assignment to string is a syntax error. Did you mean to use '''?

    – msw
    Aug 20 '10 at 20:15











  • no I'm new to python so I didn't know about the mutline string delimiter

    – Rick
    Aug 20 '10 at 20:20
















13















I know that for parsing I should ideally remove all spaces and linebreaks but I was just doing this as a quick fix for something I was trying and I can't figure out why its not working.. I have wrapped different areas of text in my document with the wrappers like "####1" and am trying to parse based on this but its just not working no matter what I try, I think I am using multiline correctly.. any advice is appreciated



This returns no results at all:



string='

####1

ttteest

####1

ttttteeeestt



####2   



ttest

####2'



import re

pattern = '.*?####(.*?)####'

returnmatch = re.compile(pattern, re.MULTILINE).findall(string)

return returnmatch





python regex parsing







share|improve this question


















  • 1





    It won't run period because you're not using multi-line string symbols ''' or """

    – Nick T
    Aug 20 '10 at 20:13











  • ok, I missed this concept completely then, i will dig through the re documentation to find where it mentions this.. thanks

    – Rick
    Aug 20 '10 at 20:15






  • 3





    Your assignment to string is a syntax error. Did you mean to use '''?

    – msw
    Aug 20 '10 at 20:15











  • no I'm new to python so I didn't know about the mutline string delimiter

    – Rick
    Aug 20 '10 at 20:20














13












13








13


1






I know that for parsing I should ideally remove all spaces and linebreaks but I was just doing this as a quick fix for something I was trying and I can't figure out why its not working.. I have wrapped different areas of text in my document with the wrappers like "####1" and am trying to parse based on this but its just not working no matter what I try, I think I am using multiline correctly.. any advice is appreciated



This returns no results at all:



string='

####1

ttteest

####1

ttttteeeestt



####2   



ttest

####2'



import re

pattern = '.*?####(.*?)####'

returnmatch = re.compile(pattern, re.MULTILINE).findall(string)

return returnmatch





python regex parsing







share|improve this question














I know that for parsing I should ideally remove all spaces and linebreaks but I was just doing this as a quick fix for something I was trying and I can't figure out why its not working.. I have wrapped different areas of text in my document with the wrappers like "####1" and am trying to parse based on this but its just not working no matter what I try, I think I am using multiline correctly.. any advice is appreciated



This returns no results at all:



string='

####1

ttteest

####1

ttttteeeestt



####2   



ttest

####2'



import re

pattern = '.*?####(.*?)####'

returnmatch = re.compile(pattern, re.MULTILINE).findall(string)

return returnmatch





python regex parsing




python regex parsing






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Aug 20 '10 at 20:09









RickRick

7,1233298159




7,1233298159








  • 1





    It won't run period because you're not using multi-line string symbols ''' or """

    – Nick T
    Aug 20 '10 at 20:13











  • ok, I missed this concept completely then, i will dig through the re documentation to find where it mentions this.. thanks

    – Rick
    Aug 20 '10 at 20:15






  • 3





    Your assignment to string is a syntax error. Did you mean to use '''?

    – msw
    Aug 20 '10 at 20:15











  • no I'm new to python so I didn't know about the mutline string delimiter

    – Rick
    Aug 20 '10 at 20:20














  • 1





    It won't run period because you're not using multi-line string symbols ''' or """

    – Nick T
    Aug 20 '10 at 20:13











  • ok, I missed this concept completely then, i will dig through the re documentation to find where it mentions this.. thanks

    – Rick
    Aug 20 '10 at 20:15






  • 3





    Your assignment to string is a syntax error. Did you mean to use '''?

    – msw
    Aug 20 '10 at 20:15











  • no I'm new to python so I didn't know about the mutline string delimiter

    – Rick
    Aug 20 '10 at 20:20








1




1





It won't run period because you're not using multi-line string symbols ''' or """

– Nick T
Aug 20 '10 at 20:13





It won't run period because you're not using multi-line string symbols ''' or """

– Nick T
Aug 20 '10 at 20:13













ok, I missed this concept completely then, i will dig through the re documentation to find where it mentions this.. thanks

– Rick
Aug 20 '10 at 20:15





ok, I missed this concept completely then, i will dig through the re documentation to find where it mentions this.. thanks

– Rick
Aug 20 '10 at 20:15




3




3





Your assignment to string is a syntax error. Did you mean to use '''?

– msw
Aug 20 '10 at 20:15





Your assignment to string is a syntax error. Did you mean to use '''?

– msw
Aug 20 '10 at 20:15













no I'm new to python so I didn't know about the mutline string delimiter

– Rick
Aug 20 '10 at 20:20





no I'm new to python so I didn't know about the mutline string delimiter

– Rick
Aug 20 '10 at 20:20












2 Answers
2






active

oldest

votes


















14














Try re.findall(r"####(.*?)s(.*?)s####", string, re.DOTALL) (works with re.compile too, of course).



This regexp will return tuples containing the number of the section and the section content.



For your example, this will return [('1', 'ttteest'), ('2', ' nnttest')].



(BTW: your example won't run, for multiline strings, use ''' or """)






share|improve this answer
























  • thanks, this works

    – Rick
    Aug 20 '10 at 20:21



















22














Multiline doesn't mean . will match line return, it means that ^ and $ are limited to lines only




re.M
re.MULTILINE



When specified, the pattern character '^' matches at the beginning of the string and at the >beginning of each line (immediately following each newline); and the pattern character '$' >matches at the end of the string and at the end of each line (immediately preceding each >newline). By default, '^' matches only at the beginning of the string, and '$' only at the >end of the string and immediately before the newline (if any) at the end of the string.




re.S or re.DOTALL makes . match even new lines.



Source



http://docs.python.org/






share|improve this answer























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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    14














    Try re.findall(r"####(.*?)s(.*?)s####", string, re.DOTALL) (works with re.compile too, of course).



    This regexp will return tuples containing the number of the section and the section content.



    For your example, this will return [('1', 'ttteest'), ('2', ' nnttest')].



    (BTW: your example won't run, for multiline strings, use ''' or """)






    share|improve this answer
























    • thanks, this works

      – Rick
      Aug 20 '10 at 20:21
















    14














    Try re.findall(r"####(.*?)s(.*?)s####", string, re.DOTALL) (works with re.compile too, of course).



    This regexp will return tuples containing the number of the section and the section content.



    For your example, this will return [('1', 'ttteest'), ('2', ' nnttest')].



    (BTW: your example won't run, for multiline strings, use ''' or """)






    share|improve this answer
























    • thanks, this works

      – Rick
      Aug 20 '10 at 20:21














    14












    14








    14







    Try re.findall(r"####(.*?)s(.*?)s####", string, re.DOTALL) (works with re.compile too, of course).



    This regexp will return tuples containing the number of the section and the section content.



    For your example, this will return [('1', 'ttteest'), ('2', ' nnttest')].



    (BTW: your example won't run, for multiline strings, use ''' or """)






    share|improve this answer













    Try re.findall(r"####(.*?)s(.*?)s####", string, re.DOTALL) (works with re.compile too, of course).



    This regexp will return tuples containing the number of the section and the section content.



    For your example, this will return [('1', 'ttteest'), ('2', ' nnttest')].



    (BTW: your example won't run, for multiline strings, use ''' or """)







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Aug 20 '10 at 20:16









    leolukleoluk

    9,10643546




    9,10643546













    • thanks, this works

      – Rick
      Aug 20 '10 at 20:21



















    • thanks, this works

      – Rick
      Aug 20 '10 at 20:21

















    thanks, this works

    – Rick
    Aug 20 '10 at 20:21





    thanks, this works

    – Rick
    Aug 20 '10 at 20:21













    22














    Multiline doesn't mean . will match line return, it means that ^ and $ are limited to lines only




    re.M
    re.MULTILINE



    When specified, the pattern character '^' matches at the beginning of the string and at the >beginning of each line (immediately following each newline); and the pattern character '$' >matches at the end of the string and at the end of each line (immediately preceding each >newline). By default, '^' matches only at the beginning of the string, and '$' only at the >end of the string and immediately before the newline (if any) at the end of the string.




    re.S or re.DOTALL makes . match even new lines.



    Source



    http://docs.python.org/






    share|improve this answer




























      22














      Multiline doesn't mean . will match line return, it means that ^ and $ are limited to lines only




      re.M
      re.MULTILINE



      When specified, the pattern character '^' matches at the beginning of the string and at the >beginning of each line (immediately following each newline); and the pattern character '$' >matches at the end of the string and at the end of each line (immediately preceding each >newline). By default, '^' matches only at the beginning of the string, and '$' only at the >end of the string and immediately before the newline (if any) at the end of the string.




      re.S or re.DOTALL makes . match even new lines.



      Source



      http://docs.python.org/






      share|improve this answer


























        22












        22








        22







        Multiline doesn't mean . will match line return, it means that ^ and $ are limited to lines only




        re.M
        re.MULTILINE



        When specified, the pattern character '^' matches at the beginning of the string and at the >beginning of each line (immediately following each newline); and the pattern character '$' >matches at the end of the string and at the end of each line (immediately preceding each >newline). By default, '^' matches only at the beginning of the string, and '$' only at the >end of the string and immediately before the newline (if any) at the end of the string.




        re.S or re.DOTALL makes . match even new lines.



        Source



        http://docs.python.org/






        share|improve this answer













        Multiline doesn't mean . will match line return, it means that ^ and $ are limited to lines only




        re.M
        re.MULTILINE



        When specified, the pattern character '^' matches at the beginning of the string and at the >beginning of each line (immediately following each newline); and the pattern character '$' >matches at the end of the string and at the end of each line (immediately preceding each >newline). By default, '^' matches only at the beginning of the string, and '$' only at the >end of the string and immediately before the newline (if any) at the end of the string.




        re.S or re.DOTALL makes . match even new lines.



        Source



        http://docs.python.org/







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Aug 20 '10 at 20:16









        Colin HebertColin Hebert

        75.9k12137137




        75.9k12137137






























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