Funny behavior with numba - guvectorized functions using argmax()





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1















Consider the following script:



from numba import guvectorize, u1, i8
import numpy as np

@guvectorize([(u1[:],i8)], '(n)->()')
def f(x, res):
res = x.argmax()

x = np.array([1,2,3],dtype=np.uint8)
print(f(x))
print(x.argmax())
print(f(x))


When running it, I get the following:



4382569440205035030
2
2


Why is this happening? Is there a way to get it right?










share|improve this question





























    1















    Consider the following script:



    from numba import guvectorize, u1, i8
    import numpy as np

    @guvectorize([(u1[:],i8)], '(n)->()')
    def f(x, res):
    res = x.argmax()

    x = np.array([1,2,3],dtype=np.uint8)
    print(f(x))
    print(x.argmax())
    print(f(x))


    When running it, I get the following:



    4382569440205035030
    2
    2


    Why is this happening? Is there a way to get it right?










    share|improve this question

























      1












      1








      1








      Consider the following script:



      from numba import guvectorize, u1, i8
      import numpy as np

      @guvectorize([(u1[:],i8)], '(n)->()')
      def f(x, res):
      res = x.argmax()

      x = np.array([1,2,3],dtype=np.uint8)
      print(f(x))
      print(x.argmax())
      print(f(x))


      When running it, I get the following:



      4382569440205035030
      2
      2


      Why is this happening? Is there a way to get it right?










      share|improve this question














      Consider the following script:



      from numba import guvectorize, u1, i8
      import numpy as np

      @guvectorize([(u1[:],i8)], '(n)->()')
      def f(x, res):
      res = x.argmax()

      x = np.array([1,2,3],dtype=np.uint8)
      print(f(x))
      print(x.argmax())
      print(f(x))


      When running it, I get the following:



      4382569440205035030
      2
      2


      Why is this happening? Is there a way to get it right?







      vectorization numba argmax






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 23 '18 at 20:50









      Rodrigo VargasRodrigo Vargas

      82




      82
























          1 Answer
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          Python doesn't have references, so res = ... is not actually assigning to the output parameter, but instead rebinding the name res. I believe res is pointing to uninitialized memory, which is why your first run gives a seemingly random value.



          Numba works around this using the slice syntax ([:]) which does mutate res- you also need to declare the type as an array. A working function is:



          @guvectorize([(u1[:], i8[:])], '(n)->()')
          def f(x, res):
          res[:] = x.argmax()





          share|improve this answer
























          • I had somehow managed to convince myself that the weird behavior had to do with numba in combination with argmax, but indeed something like res = x[0] has the same problem.

            – Rodrigo Vargas
            Nov 28 '18 at 18:27












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          1 Answer
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          active

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          active

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          0














          Python doesn't have references, so res = ... is not actually assigning to the output parameter, but instead rebinding the name res. I believe res is pointing to uninitialized memory, which is why your first run gives a seemingly random value.



          Numba works around this using the slice syntax ([:]) which does mutate res- you also need to declare the type as an array. A working function is:



          @guvectorize([(u1[:], i8[:])], '(n)->()')
          def f(x, res):
          res[:] = x.argmax()





          share|improve this answer
























          • I had somehow managed to convince myself that the weird behavior had to do with numba in combination with argmax, but indeed something like res = x[0] has the same problem.

            – Rodrigo Vargas
            Nov 28 '18 at 18:27
















          0














          Python doesn't have references, so res = ... is not actually assigning to the output parameter, but instead rebinding the name res. I believe res is pointing to uninitialized memory, which is why your first run gives a seemingly random value.



          Numba works around this using the slice syntax ([:]) which does mutate res- you also need to declare the type as an array. A working function is:



          @guvectorize([(u1[:], i8[:])], '(n)->()')
          def f(x, res):
          res[:] = x.argmax()





          share|improve this answer
























          • I had somehow managed to convince myself that the weird behavior had to do with numba in combination with argmax, but indeed something like res = x[0] has the same problem.

            – Rodrigo Vargas
            Nov 28 '18 at 18:27














          0












          0








          0







          Python doesn't have references, so res = ... is not actually assigning to the output parameter, but instead rebinding the name res. I believe res is pointing to uninitialized memory, which is why your first run gives a seemingly random value.



          Numba works around this using the slice syntax ([:]) which does mutate res- you also need to declare the type as an array. A working function is:



          @guvectorize([(u1[:], i8[:])], '(n)->()')
          def f(x, res):
          res[:] = x.argmax()





          share|improve this answer













          Python doesn't have references, so res = ... is not actually assigning to the output parameter, but instead rebinding the name res. I believe res is pointing to uninitialized memory, which is why your first run gives a seemingly random value.



          Numba works around this using the slice syntax ([:]) which does mutate res- you also need to declare the type as an array. A working function is:



          @guvectorize([(u1[:], i8[:])], '(n)->()')
          def f(x, res):
          res[:] = x.argmax()






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 27 '18 at 14:43









          chrisbchrisb

          25.2k73840




          25.2k73840













          • I had somehow managed to convince myself that the weird behavior had to do with numba in combination with argmax, but indeed something like res = x[0] has the same problem.

            – Rodrigo Vargas
            Nov 28 '18 at 18:27



















          • I had somehow managed to convince myself that the weird behavior had to do with numba in combination with argmax, but indeed something like res = x[0] has the same problem.

            – Rodrigo Vargas
            Nov 28 '18 at 18:27

















          I had somehow managed to convince myself that the weird behavior had to do with numba in combination with argmax, but indeed something like res = x[0] has the same problem.

          – Rodrigo Vargas
          Nov 28 '18 at 18:27





          I had somehow managed to convince myself that the weird behavior had to do with numba in combination with argmax, but indeed something like res = x[0] has the same problem.

          – Rodrigo Vargas
          Nov 28 '18 at 18:27




















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