How to copy/duplicate a custom collectionview cell in Swift?
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I want to copy a custom collectionview cell from a viewcontroller to another, the problem is the collectionview cell disappears once I tap on it because of - apparently - adding it in the 2nd viewcontroller's as a subview.
I tried most of the methods here Create a copy of a UIView in Swift
One about Archiving returns nil.
Other about prototypes and structs, it doesn't return a new address for the view.
func collectionView(_ collectionView: UICollectionView, didSelectItemAt indexPath: IndexPath)
{
struct ObjectToCopied {
var objToBeRetrieved: UIView? = nil
init(objToSaved : UIView?) {
objToBeRetrieved = objToSaved
}
}
let pickedView : UIView? = collectionView.cellForItem(at: indexPath)
let tempObj = ObjectToCopied(objToSaved: pickedView)
let copiedObj = tempObj
let copiedView = copiedObj.objToBeRetrieved as? UIView
// here the copiedview's address is THE SAME as tempObj's ObjToBeRetrieved.
}
Custom CollectionView cell image example:
ios swift uiview uicollectionview uicollectionviewcell
asked Nov 23 '18 at 21:04
NewsonicNewsonic
636
add a comment |
I want to copy a custom collectionview cell from a viewcontroller to another, the problem is the collectionview cell disappears once I tap on it because of - apparently - adding it in the 2nd viewcontroller's as a subview.
I tried most of the methods here Create a copy of a UIView in Swift
One about Archiving returns nil.
Other about prototypes and structs, it doesn't return a new address for the view.
func collectionView(_ collectionView: UICollectionView, didSelectItemAt indexPath: IndexPath)
{
struct ObjectToCopied {
var objToBeRetrieved: UIView? = nil
init(objToSaved : UIView?) {
objToBeRetrieved = objToSaved
}
}
let pickedView : UIView? = collectionView.cellForItem(at: indexPath)
let tempObj = ObjectToCopied(objToSaved: pickedView)
let copiedObj = tempObj
let copiedView = copiedObj.objToBeRetrieved as? UIView
// here the copiedview's address is THE SAME as tempObj's ObjToBeRetrieved.
}
Custom CollectionView cell image example:
ios swift uiview uicollectionview uicollectionviewcell
asked Nov 23 '18 at 21:04
NewsonicNewsonic
636
add a comment |
I want to copy a custom collectionview cell from a viewcontroller to another, the problem is the collectionview cell disappears once I tap on it because of - apparently - adding it in the 2nd viewcontroller's as a subview.
I tried most of the methods here Create a copy of a UIView in Swift
One about Archiving returns nil.
Other about prototypes and structs, it doesn't return a new address for the view.
func collectionView(_ collectionView: UICollectionView, didSelectItemAt indexPath: IndexPath)
{
struct ObjectToCopied {
var objToBeRetrieved: UIView? = nil
init(objToSaved : UIView?) {
objToBeRetrieved = objToSaved
}
}
let pickedView : UIView? = collectionView.cellForItem(at: indexPath)
let tempObj = ObjectToCopied(objToSaved: pickedView)
let copiedObj = tempObj
let copiedView = copiedObj.objToBeRetrieved as? UIView
// here the copiedview's address is THE SAME as tempObj's ObjToBeRetrieved.
}
Custom CollectionView cell image example:
ios swift uiview uicollectionview uicollectionviewcell
asked Nov 23 '18 at 21:04
NewsonicNewsonic
636
I want to copy a custom collectionview cell from a viewcontroller to another, the problem is the collectionview cell disappears once I tap on it because of - apparently - adding it in the 2nd viewcontroller's as a subview.
I tried most of the methods here Create a copy of a UIView in Swift
One about Archiving returns nil.
Other about prototypes and structs, it doesn't return a new address for the view.
func collectionView(_ collectionView: UICollectionView, didSelectItemAt indexPath: IndexPath)
{
struct ObjectToCopied {
var objToBeRetrieved: UIView? = nil
init(objToSaved : UIView?) {
objToBeRetrieved = objToSaved
}
}
let pickedView : UIView? = collectionView.cellForItem(at: indexPath)
let tempObj = ObjectToCopied(objToSaved: pickedView)
let copiedObj = tempObj
let copiedView = copiedObj.objToBeRetrieved as? UIView
// here the copiedview's address is THE SAME as tempObj's ObjToBeRetrieved.
}
Custom CollectionView cell image example:
ios swift uiview uicollectionview uicollectionviewcell
ios swift uiview uicollectionview uicollectionviewcell
asked Nov 23 '18 at 21:04
NewsonicNewsonic
636
asked Nov 23 '18 at 21:04
NewsonicNewsonic
636
edited Nov 23 '18 at 21:41
Newsonic
asked Nov 23 '18 at 21:04
NewsonicNewsonic
636
asked Nov 23 '18 at 21:04
NewsonicNewsonic
636
asked Nov 23 '18 at 21:04
NewsonicNewsonic
636
636
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Don't copy UIView object!
Your model isn't good.
You have to store the data – information somewhere outside the cell directly.
You have to call your 'database' using indexPath to retrieve the information. No more!
About your question.
This object doesn't copy your object.
struct ObjectToCopied {
var objToBeRetrieved: UIView? = nil
init(objToSaved : UIView?) {
objToBeRetrieved = objToSaved
}
}
ObjectToCopied is a value type. But UIView is a reference type. So, objToBeRetrieved contains the same address as pickedView. Solution? Use objToBeRetrieved = objToSaved.copy(). But, please, really don't do it. That's really bad. Futhermore, I think this will corrupt something. Use better application model – the first suggestion.
answered Nov 23 '18 at 21:51
VyacheslavVyacheslav
15.1k964127
add a comment |
Why do you need to copy the collectionView cell? You can simply pass your data to next viewController and create new view or cell (whatever you need) and display data on it.
Any specific reason to copy collectionView cell?
answered Nov 24 '18 at 6:08
iDev750iDev750
6251417
Nope, just wanted to copy it in few lines of code instead of the hassle of creating it again
– Newsonic
Nov 24 '18 at 15:15
It's not a good way to copy UI object.
– iDev750
Nov 24 '18 at 17:19
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Don't copy UIView object!
Your model isn't good.
You have to store the data – information somewhere outside the cell directly.
You have to call your 'database' using indexPath to retrieve the information. No more!
About your question.
This object doesn't copy your object.
struct ObjectToCopied {
var objToBeRetrieved: UIView? = nil
init(objToSaved : UIView?) {
objToBeRetrieved = objToSaved
}
}
ObjectToCopied is a value type. But UIView is a reference type. So, objToBeRetrieved contains the same address as pickedView. Solution? Use objToBeRetrieved = objToSaved.copy(). But, please, really don't do it. That's really bad. Futhermore, I think this will corrupt something. Use better application model – the first suggestion.
answered Nov 23 '18 at 21:51
VyacheslavVyacheslav
15.1k964127
add a comment |
Don't copy UIView object!
Your model isn't good.
You have to store the data – information somewhere outside the cell directly.
You have to call your 'database' using indexPath to retrieve the information. No more!
About your question.
This object doesn't copy your object.
struct ObjectToCopied {
var objToBeRetrieved: UIView? = nil
init(objToSaved : UIView?) {
objToBeRetrieved = objToSaved
}
}
ObjectToCopied is a value type. But UIView is a reference type. So, objToBeRetrieved contains the same address as pickedView. Solution? Use objToBeRetrieved = objToSaved.copy(). But, please, really don't do it. That's really bad. Futhermore, I think this will corrupt something. Use better application model – the first suggestion.
answered Nov 23 '18 at 21:51
VyacheslavVyacheslav
15.1k964127
add a comment |
Don't copy UIView object!
Your model isn't good.
You have to store the data – information somewhere outside the cell directly.
You have to call your 'database' using indexPath to retrieve the information. No more!
About your question.
This object doesn't copy your object.
struct ObjectToCopied {
var objToBeRetrieved: UIView? = nil
init(objToSaved : UIView?) {
objToBeRetrieved = objToSaved
}
}
ObjectToCopied is a value type. But UIView is a reference type. So, objToBeRetrieved contains the same address as pickedView. Solution? Use objToBeRetrieved = objToSaved.copy(). But, please, really don't do it. That's really bad. Futhermore, I think this will corrupt something. Use better application model – the first suggestion.
answered Nov 23 '18 at 21:51
VyacheslavVyacheslav
15.1k964127
Don't copy UIView object!
Your model isn't good.
You have to store the data – information somewhere outside the cell directly.
You have to call your 'database' using indexPath to retrieve the information. No more!
About your question.
This object doesn't copy your object.
struct ObjectToCopied {
var objToBeRetrieved: UIView? = nil
init(objToSaved : UIView?) {
objToBeRetrieved = objToSaved
}
}
ObjectToCopied is a value type. But UIView is a reference type. So, objToBeRetrieved contains the same address as pickedView. Solution? Use objToBeRetrieved = objToSaved.copy(). But, please, really don't do it. That's really bad. Futhermore, I think this will corrupt something. Use better application model – the first suggestion.
answered Nov 23 '18 at 21:51
VyacheslavVyacheslav
15.1k964127
answered Nov 23 '18 at 21:51
VyacheslavVyacheslav
15.1k964127
answered Nov 23 '18 at 21:51
VyacheslavVyacheslav
15.1k964127
answered Nov 23 '18 at 21:51
VyacheslavVyacheslav
15.1k964127
15.1k964127
add a comment |
add a comment |
Why do you need to copy the collectionView cell? You can simply pass your data to next viewController and create new view or cell (whatever you need) and display data on it.
Any specific reason to copy collectionView cell?
answered Nov 24 '18 at 6:08
iDev750iDev750
6251417
Nope, just wanted to copy it in few lines of code instead of the hassle of creating it again
– Newsonic
Nov 24 '18 at 15:15
It's not a good way to copy UI object.
– iDev750
Nov 24 '18 at 17:19
add a comment |
Why do you need to copy the collectionView cell? You can simply pass your data to next viewController and create new view or cell (whatever you need) and display data on it.
Any specific reason to copy collectionView cell?
answered Nov 24 '18 at 6:08
iDev750iDev750
6251417
Nope, just wanted to copy it in few lines of code instead of the hassle of creating it again
– Newsonic
Nov 24 '18 at 15:15
It's not a good way to copy UI object.
– iDev750
Nov 24 '18 at 17:19
add a comment |
Why do you need to copy the collectionView cell? You can simply pass your data to next viewController and create new view or cell (whatever you need) and display data on it.
Any specific reason to copy collectionView cell?
answered Nov 24 '18 at 6:08
iDev750iDev750
6251417
Why do you need to copy the collectionView cell? You can simply pass your data to next viewController and create new view or cell (whatever you need) and display data on it.
Any specific reason to copy collectionView cell?
answered Nov 24 '18 at 6:08
iDev750iDev750
6251417
answered Nov 24 '18 at 6:08
iDev750iDev750
6251417
answered Nov 24 '18 at 6:08
iDev750iDev750
6251417
answered Nov 24 '18 at 6:08
iDev750iDev750
6251417
6251417
Nope, just wanted to copy it in few lines of code instead of the hassle of creating it again
– Newsonic
Nov 24 '18 at 15:15
It's not a good way to copy UI object.
– iDev750
Nov 24 '18 at 17:19
add a comment |
Nope, just wanted to copy it in few lines of code instead of the hassle of creating it again
– Newsonic
Nov 24 '18 at 15:15
It's not a good way to copy UI object.
– iDev750
Nov 24 '18 at 17:19
Nope, just wanted to copy it in few lines of code instead of the hassle of creating it again
– Newsonic
Nov 24 '18 at 15:15
Nope, just wanted to copy it in few lines of code instead of the hassle of creating it again
– Newsonic
Nov 24 '18 at 15:15
It's not a good way to copy UI object.
– iDev750
Nov 24 '18 at 17:19
It's not a good way to copy UI object.
– iDev750
Nov 24 '18 at 17:19
add a comment |
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