My program in Julia sees syntax error where there is none
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I have a problem with this bit of code. Every time I try to run it it says that I have "Unexpected" end. For me everything is on point and I cant figure it out can someone help me find solution? Full error code and program code below.
Program:
function mbisekcji(f, a::Float64, b::Float64, delta::Float64, epsilon::Float64)
e = b-a
u = f(a)
v = f(b)
err = 0
iterator = 0
if sign(u) == sign(v)
err = 1
return err
end
while true
e = e/2
c = a+e
w = f(c)
if (norm(e) < delta) || (norm(w) < epsilon)
return w, f(w), iterator, err
end
if sign(w) == sign(u)
b = c
v = w
else
a = c
u = w
end
iterator++
end
end
Error:
LoadError: [91msyntax: unexpected "end"[39m
while loading C:UsersusernameDesktopStudyzad1.jl, in expression starting on line 60
include_string(::String, ::String) at loading.jl:522
include_string(::Module, ::String, ::String) at Compat.jl:84
(::Atom.##112#116{String,String})() at eval.jl:109
withpath(::Atom.##112#116{String,String}, ::String) at utils.jl:30
withpath(::Function, ::String) at eval.jl:38
hideprompt(::Atom.##111#115{String,String}) at repl.jl:67
macro expansion at eval.jl:106 [inlined]
(::Atom.##110#114{Dict{String,Any}})() at task.jl:80
Also, just to make thing easier, line 60 is second end from the back. The one closing while loop.
syntax-error julia
asked Nov 23 '18 at 20:47
EmarthEmarth
276
add a comment |
I have a problem with this bit of code. Every time I try to run it it says that I have "Unexpected" end. For me everything is on point and I cant figure it out can someone help me find solution? Full error code and program code below.
Program:
function mbisekcji(f, a::Float64, b::Float64, delta::Float64, epsilon::Float64)
e = b-a
u = f(a)
v = f(b)
err = 0
iterator = 0
if sign(u) == sign(v)
err = 1
return err
end
while true
e = e/2
c = a+e
w = f(c)
if (norm(e) < delta) || (norm(w) < epsilon)
return w, f(w), iterator, err
end
if sign(w) == sign(u)
b = c
v = w
else
a = c
u = w
end
iterator++
end
end
Error:
LoadError: [91msyntax: unexpected "end"[39m
while loading C:UsersusernameDesktopStudyzad1.jl, in expression starting on line 60
include_string(::String, ::String) at loading.jl:522
include_string(::Module, ::String, ::String) at Compat.jl:84
(::Atom.##112#116{String,String})() at eval.jl:109
withpath(::Atom.##112#116{String,String}, ::String) at utils.jl:30
withpath(::Function, ::String) at eval.jl:38
hideprompt(::Atom.##111#115{String,String}) at repl.jl:67
macro expansion at eval.jl:106 [inlined]
(::Atom.##110#114{Dict{String,Any}})() at task.jl:80
Also, just to make thing easier, line 60 is second end from the back. The one closing while loop.
syntax-error julia
asked Nov 23 '18 at 20:47
EmarthEmarth
276
add a comment |
I have a problem with this bit of code. Every time I try to run it it says that I have "Unexpected" end. For me everything is on point and I cant figure it out can someone help me find solution? Full error code and program code below.
Program:
function mbisekcji(f, a::Float64, b::Float64, delta::Float64, epsilon::Float64)
e = b-a
u = f(a)
v = f(b)
err = 0
iterator = 0
if sign(u) == sign(v)
err = 1
return err
end
while true
e = e/2
c = a+e
w = f(c)
if (norm(e) < delta) || (norm(w) < epsilon)
return w, f(w), iterator, err
end
if sign(w) == sign(u)
b = c
v = w
else
a = c
u = w
end
iterator++
end
end
Error:
LoadError: [91msyntax: unexpected "end"[39m
while loading C:UsersusernameDesktopStudyzad1.jl, in expression starting on line 60
include_string(::String, ::String) at loading.jl:522
include_string(::Module, ::String, ::String) at Compat.jl:84
(::Atom.##112#116{String,String})() at eval.jl:109
withpath(::Atom.##112#116{String,String}, ::String) at utils.jl:30
withpath(::Function, ::String) at eval.jl:38
hideprompt(::Atom.##111#115{String,String}) at repl.jl:67
macro expansion at eval.jl:106 [inlined]
(::Atom.##110#114{Dict{String,Any}})() at task.jl:80
Also, just to make thing easier, line 60 is second end from the back. The one closing while loop.
syntax-error julia
asked Nov 23 '18 at 20:47
EmarthEmarth
276
I have a problem with this bit of code. Every time I try to run it it says that I have "Unexpected" end. For me everything is on point and I cant figure it out can someone help me find solution? Full error code and program code below.
Program:
function mbisekcji(f, a::Float64, b::Float64, delta::Float64, epsilon::Float64)
e = b-a
u = f(a)
v = f(b)
err = 0
iterator = 0
if sign(u) == sign(v)
err = 1
return err
end
while true
e = e/2
c = a+e
w = f(c)
if (norm(e) < delta) || (norm(w) < epsilon)
return w, f(w), iterator, err
end
if sign(w) == sign(u)
b = c
v = w
else
a = c
u = w
end
iterator++
end
end
Error:
LoadError: [91msyntax: unexpected "end"[39m
while loading C:UsersusernameDesktopStudyzad1.jl, in expression starting on line 60
include_string(::String, ::String) at loading.jl:522
include_string(::Module, ::String, ::String) at Compat.jl:84
(::Atom.##112#116{String,String})() at eval.jl:109
withpath(::Atom.##112#116{String,String}, ::String) at utils.jl:30
withpath(::Function, ::String) at eval.jl:38
hideprompt(::Atom.##111#115{String,String}) at repl.jl:67
macro expansion at eval.jl:106 [inlined]
(::Atom.##110#114{Dict{String,Any}})() at task.jl:80
Also, just to make thing easier, line 60 is second end from the back. The one closing while loop.
syntax-error julia
syntax-error julia
asked Nov 23 '18 at 20:47
EmarthEmarth
276
asked Nov 23 '18 at 20:47
EmarthEmarth
276
asked Nov 23 '18 at 20:47
EmarthEmarth
276
asked Nov 23 '18 at 20:47
EmarthEmarth
276
asked Nov 23 '18 at 20:47
EmarthEmarth
276
276
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
In order to increment a variable by 1 in Julia you have to write
iterator += 1
Julia does not support ++ to increment a variable.
But, for example, you could define a macro to do almost what you want:
julia> macro ++(x)
esc(:($x += 1))
end
@++ (macro with 1 method)
julia> x = 1
1
julia> @++x
2
julia> x
2
answered Nov 23 '18 at 20:55
Bogumił KamińskiBogumił Kamiński
15.2k21422
That was it. Thank you. So simple yet so frustrating. I guess that's how programming has always been :D
– Emarth
Nov 23 '18 at 21:02
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
In order to increment a variable by 1 in Julia you have to write
iterator += 1
Julia does not support ++ to increment a variable.
But, for example, you could define a macro to do almost what you want:
julia> macro ++(x)
esc(:($x += 1))
end
@++ (macro with 1 method)
julia> x = 1
1
julia> @++x
2
julia> x
2
answered Nov 23 '18 at 20:55
Bogumił KamińskiBogumił Kamiński
15.2k21422
That was it. Thank you. So simple yet so frustrating. I guess that's how programming has always been :D
– Emarth
Nov 23 '18 at 21:02
add a comment |
In order to increment a variable by 1 in Julia you have to write
iterator += 1
Julia does not support ++ to increment a variable.
But, for example, you could define a macro to do almost what you want:
julia> macro ++(x)
esc(:($x += 1))
end
@++ (macro with 1 method)
julia> x = 1
1
julia> @++x
2
julia> x
2
answered Nov 23 '18 at 20:55
Bogumił KamińskiBogumił Kamiński
15.2k21422
That was it. Thank you. So simple yet so frustrating. I guess that's how programming has always been :D
– Emarth
Nov 23 '18 at 21:02
add a comment |
In order to increment a variable by 1 in Julia you have to write
iterator += 1
Julia does not support ++ to increment a variable.
But, for example, you could define a macro to do almost what you want:
julia> macro ++(x)
esc(:($x += 1))
end
@++ (macro with 1 method)
julia> x = 1
1
julia> @++x
2
julia> x
2
answered Nov 23 '18 at 20:55
Bogumił KamińskiBogumił Kamiński
15.2k21422
In order to increment a variable by 1 in Julia you have to write
iterator += 1
Julia does not support ++ to increment a variable.
But, for example, you could define a macro to do almost what you want:
julia> macro ++(x)
esc(:($x += 1))
end
@++ (macro with 1 method)
julia> x = 1
1
julia> @++x
2
julia> x
2
answered Nov 23 '18 at 20:55
Bogumił KamińskiBogumił Kamiński
15.2k21422
answered Nov 23 '18 at 20:55
Bogumił KamińskiBogumił Kamiński
15.2k21422
answered Nov 23 '18 at 20:55
Bogumił KamińskiBogumił Kamiński
15.2k21422
answered Nov 23 '18 at 20:55
Bogumił KamińskiBogumił Kamiński
15.2k21422
15.2k21422
That was it. Thank you. So simple yet so frustrating. I guess that's how programming has always been :D
– Emarth
Nov 23 '18 at 21:02
add a comment |
That was it. Thank you. So simple yet so frustrating. I guess that's how programming has always been :D
– Emarth
Nov 23 '18 at 21:02
That was it. Thank you. So simple yet so frustrating. I guess that's how programming has always been :D
– Emarth
Nov 23 '18 at 21:02
That was it. Thank you. So simple yet so frustrating. I guess that's how programming has always been :D
– Emarth
Nov 23 '18 at 21:02
add a comment |
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