What R object can hold variables so I can iterate over the object?
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This seems simple, but I'm spinning my wheels.
I have 80 character variables. I want to 1) view the unique values in each variable, 2) view the number of unique values, and 3) convert some or all variables to factors.
I can do this one-by-one by explicitly naming the columns:
df$var1 # "val2" "val2" "val1" "val2" ...
unique(df$var1) # "val1" "val2" "val3"
length(unique(df$var1)) # 3
df$var1 = as.factor(df$var1)
... although this produces an error:
levels(df@var1)
# Error in levels(df@var1) :
# trying to get slot "var1" from an object (class "tbl_df")
# that is not an S4 object
But when I create a list of the character variables and try the same as above it doesn't work.
# create list of char vars
char_vars_names <- names(df[, sapply(df, class) == 'character'])
char_vars_names
#[1] "var1" "var2" "var3" ...
df$char_vars_names[1] # NULL
# Warning message: Unknown or uninitialised column: 'char_vars_names'.
unique(df$char_vars_names[1]) # NULL
length(unique(df$char_vars_names[1])) # 0
Once I get the above working I figure I can iterate over the list with a for loop:
for (i in range(length(char_vars_names))) {
# code
}
What is it about the char_vars_names object or elsewhere in my code that makes this not work?
In case it's helpful, here's my imports and data ingestion prior to the above code:
library(car)
library(lattice)
library(tidyverse)
library(ISLR)
library(Lahman)
library(mdsr)
file = "file.csv"
df <- read_csv(
file=file,
col_names = TRUE,
skip = 3,
na = c("", "NA"))
r for-loop variables
asked Nov 23 '18 at 20:54
Karl BakerKarl Baker
366115
add a comment |
This seems simple, but I'm spinning my wheels.
I have 80 character variables. I want to 1) view the unique values in each variable, 2) view the number of unique values, and 3) convert some or all variables to factors.
I can do this one-by-one by explicitly naming the columns:
df$var1 # "val2" "val2" "val1" "val2" ...
unique(df$var1) # "val1" "val2" "val3"
length(unique(df$var1)) # 3
df$var1 = as.factor(df$var1)
... although this produces an error:
levels(df@var1)
# Error in levels(df@var1) :
# trying to get slot "var1" from an object (class "tbl_df")
# that is not an S4 object
But when I create a list of the character variables and try the same as above it doesn't work.
# create list of char vars
char_vars_names <- names(df[, sapply(df, class) == 'character'])
char_vars_names
#[1] "var1" "var2" "var3" ...
df$char_vars_names[1] # NULL
# Warning message: Unknown or uninitialised column: 'char_vars_names'.
unique(df$char_vars_names[1]) # NULL
length(unique(df$char_vars_names[1])) # 0
Once I get the above working I figure I can iterate over the list with a for loop:
for (i in range(length(char_vars_names))) {
# code
}
What is it about the char_vars_names object or elsewhere in my code that makes this not work?
In case it's helpful, here's my imports and data ingestion prior to the above code:
library(car)
library(lattice)
library(tidyverse)
library(ISLR)
library(Lahman)
library(mdsr)
file = "file.csv"
df <- read_csv(
file=file,
col_names = TRUE,
skip = 3,
na = c("", "NA"))
r for-loop variables
asked Nov 23 '18 at 20:54
Karl BakerKarl Baker
366115
3
Trydf[[char_vars_names]][1]. The$notation can't take advantage of variable substitution, but the double brackets can.
– jdobres
Nov 23 '18 at 21:06
3
Also your use ofrangewill not work (I'm guessing you're coming from Python).for (i in char_vars_names)might be what you're after.
– jdobres
Nov 23 '18 at 21:07
I get an error when I use the double bracket below, but maybe I didn't follow your suggestion correctly:char_vars_names # [1] "var1" "var2" ...char_vars_names[1] # "var1"# Works/works/doesn't work:df$var1 # "val2" "val2" "val1" ...df[char_vars_names][1] # "val2" "val2" "val1" ...df[[char_vars_names]][1] # Error in .subset2(x, i) : recursive indexing failed at level 2
– Karl Baker
Nov 24 '18 at 0:01
Thanks for the tip on the for loop. That is exactly what I'll need as soon as I can get the rest of the code to work!
– Karl Baker
Nov 24 '18 at 0:10
add a comment |
This seems simple, but I'm spinning my wheels.
I have 80 character variables. I want to 1) view the unique values in each variable, 2) view the number of unique values, and 3) convert some or all variables to factors.
I can do this one-by-one by explicitly naming the columns:
df$var1 # "val2" "val2" "val1" "val2" ...
unique(df$var1) # "val1" "val2" "val3"
length(unique(df$var1)) # 3
df$var1 = as.factor(df$var1)
... although this produces an error:
levels(df@var1)
# Error in levels(df@var1) :
# trying to get slot "var1" from an object (class "tbl_df")
# that is not an S4 object
But when I create a list of the character variables and try the same as above it doesn't work.
# create list of char vars
char_vars_names <- names(df[, sapply(df, class) == 'character'])
char_vars_names
#[1] "var1" "var2" "var3" ...
df$char_vars_names[1] # NULL
# Warning message: Unknown or uninitialised column: 'char_vars_names'.
unique(df$char_vars_names[1]) # NULL
length(unique(df$char_vars_names[1])) # 0
Once I get the above working I figure I can iterate over the list with a for loop:
for (i in range(length(char_vars_names))) {
# code
}
What is it about the char_vars_names object or elsewhere in my code that makes this not work?
In case it's helpful, here's my imports and data ingestion prior to the above code:
library(car)
library(lattice)
library(tidyverse)
library(ISLR)
library(Lahman)
library(mdsr)
file = "file.csv"
df <- read_csv(
file=file,
col_names = TRUE,
skip = 3,
na = c("", "NA"))
r for-loop variables
asked Nov 23 '18 at 20:54
Karl BakerKarl Baker
366115
This seems simple, but I'm spinning my wheels.
I have 80 character variables. I want to 1) view the unique values in each variable, 2) view the number of unique values, and 3) convert some or all variables to factors.
I can do this one-by-one by explicitly naming the columns:
df$var1 # "val2" "val2" "val1" "val2" ...
unique(df$var1) # "val1" "val2" "val3"
length(unique(df$var1)) # 3
df$var1 = as.factor(df$var1)
... although this produces an error:
levels(df@var1)
# Error in levels(df@var1) :
# trying to get slot "var1" from an object (class "tbl_df")
# that is not an S4 object
But when I create a list of the character variables and try the same as above it doesn't work.
# create list of char vars
char_vars_names <- names(df[, sapply(df, class) == 'character'])
char_vars_names
#[1] "var1" "var2" "var3" ...
df$char_vars_names[1] # NULL
# Warning message: Unknown or uninitialised column: 'char_vars_names'.
unique(df$char_vars_names[1]) # NULL
length(unique(df$char_vars_names[1])) # 0
Once I get the above working I figure I can iterate over the list with a for loop:
for (i in range(length(char_vars_names))) {
# code
}
What is it about the char_vars_names object or elsewhere in my code that makes this not work?
In case it's helpful, here's my imports and data ingestion prior to the above code:
library(car)
library(lattice)
library(tidyverse)
library(ISLR)
library(Lahman)
library(mdsr)
file = "file.csv"
df <- read_csv(
file=file,
col_names = TRUE,
skip = 3,
na = c("", "NA"))
r for-loop variables
r for-loop variables
asked Nov 23 '18 at 20:54
Karl BakerKarl Baker
366115
asked Nov 23 '18 at 20:54
Karl BakerKarl Baker
366115
asked Nov 23 '18 at 20:54
Karl BakerKarl Baker
366115
asked Nov 23 '18 at 20:54
Karl BakerKarl Baker
366115
asked Nov 23 '18 at 20:54
Karl BakerKarl Baker
366115
366115
3
Trydf[[char_vars_names]][1]. The$notation can't take advantage of variable substitution, but the double brackets can.
– jdobres
Nov 23 '18 at 21:06
3
Also your use ofrangewill not work (I'm guessing you're coming from Python).for (i in char_vars_names)might be what you're after.
– jdobres
Nov 23 '18 at 21:07
I get an error when I use the double bracket below, but maybe I didn't follow your suggestion correctly:char_vars_names # [1] "var1" "var2" ...char_vars_names[1] # "var1"# Works/works/doesn't work:df$var1 # "val2" "val2" "val1" ...df[char_vars_names][1] # "val2" "val2" "val1" ...df[[char_vars_names]][1] # Error in .subset2(x, i) : recursive indexing failed at level 2
– Karl Baker
Nov 24 '18 at 0:01
Thanks for the tip on the for loop. That is exactly what I'll need as soon as I can get the rest of the code to work!
– Karl Baker
Nov 24 '18 at 0:10
add a comment |
3
Trydf[[char_vars_names]][1]. The$notation can't take advantage of variable substitution, but the double brackets can.
– jdobres
Nov 23 '18 at 21:06
3
Also your use ofrangewill not work (I'm guessing you're coming from Python).for (i in char_vars_names)might be what you're after.
– jdobres
Nov 23 '18 at 21:07
I get an error when I use the double bracket below, but maybe I didn't follow your suggestion correctly:char_vars_names # [1] "var1" "var2" ...char_vars_names[1] # "var1"# Works/works/doesn't work:df$var1 # "val2" "val2" "val1" ...df[char_vars_names][1] # "val2" "val2" "val1" ...df[[char_vars_names]][1] # Error in .subset2(x, i) : recursive indexing failed at level 2
– Karl Baker
Nov 24 '18 at 0:01
Thanks for the tip on the for loop. That is exactly what I'll need as soon as I can get the rest of the code to work!
– Karl Baker
Nov 24 '18 at 0:10
3
3
Try
df[[char_vars_names]][1]. The $ notation can't take advantage of variable substitution, but the double brackets can.– jdobres
Nov 23 '18 at 21:06
Try
df[[char_vars_names]][1]. The $ notation can't take advantage of variable substitution, but the double brackets can.– jdobres
Nov 23 '18 at 21:06
3
3
Also your use of
range will not work (I'm guessing you're coming from Python). for (i in char_vars_names) might be what you're after.– jdobres
Nov 23 '18 at 21:07
Also your use of
range will not work (I'm guessing you're coming from Python). for (i in char_vars_names) might be what you're after.– jdobres
Nov 23 '18 at 21:07
I get an error when I use the double bracket below, but maybe I didn't follow your suggestion correctly:
char_vars_names # [1] "var1" "var2" ... char_vars_names[1] # "var1" # Works/works/doesn't work: df$var1 # "val2" "val2" "val1" ... df[char_vars_names][1] # "val2" "val2" "val1" ... df[[char_vars_names]][1] # Error in .subset2(x, i) : recursive indexing failed at level 2– Karl Baker
Nov 24 '18 at 0:01
I get an error when I use the double bracket below, but maybe I didn't follow your suggestion correctly:
char_vars_names # [1] "var1" "var2" ... char_vars_names[1] # "var1" # Works/works/doesn't work: df$var1 # "val2" "val2" "val1" ... df[char_vars_names][1] # "val2" "val2" "val1" ... df[[char_vars_names]][1] # Error in .subset2(x, i) : recursive indexing failed at level 2– Karl Baker
Nov 24 '18 at 0:01
Thanks for the tip on the for loop. That is exactly what I'll need as soon as I can get the rest of the code to work!
– Karl Baker
Nov 24 '18 at 0:10
Thanks for the tip on the for loop. That is exactly what I'll need as soon as I can get the rest of the code to work!
– Karl Baker
Nov 24 '18 at 0:10
add a comment |
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3
Try
df[[char_vars_names]][1]. The$notation can't take advantage of variable substitution, but the double brackets can.– jdobres
Nov 23 '18 at 21:06
3
Also your use of
rangewill not work (I'm guessing you're coming from Python).for (i in char_vars_names)might be what you're after.– jdobres
Nov 23 '18 at 21:07
I get an error when I use the double bracket below, but maybe I didn't follow your suggestion correctly:
char_vars_names # [1] "var1" "var2" ...char_vars_names[1] # "var1"# Works/works/doesn't work:df$var1 # "val2" "val2" "val1" ...df[char_vars_names][1] # "val2" "val2" "val1" ...df[[char_vars_names]][1] # Error in .subset2(x, i) : recursive indexing failed at level 2– Karl Baker
Nov 24 '18 at 0:01
Thanks for the tip on the for loop. That is exactly what I'll need as soon as I can get the rest of the code to work!
– Karl Baker
Nov 24 '18 at 0:10