How to access an object outside when it is present in a named function
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
How to access an object outside of the function when it is present in a named function.
function a(){
var someobj = { b: "abc"}
console.log(someobj)
}
I tried to set a variable and then access it but I get an error.
var bla = function a() {
var someobj = {
b: "abc"
}
console.log(someobj)
}
console.log(bla().someobj)javascript
edited Nov 25 '18 at 1:33
Ele
25.7k52252
asked Nov 25 '18 at 1:32
DekeDeke
1,49611226
add a comment |
How to access an object outside of the function when it is present in a named function.
function a(){
var someobj = { b: "abc"}
console.log(someobj)
}
I tried to set a variable and then access it but I get an error.
var bla = function a() {
var someobj = {
b: "abc"
}
console.log(someobj)
}
console.log(bla().someobj)javascript
edited Nov 25 '18 at 1:33
Ele
25.7k52252
asked Nov 25 '18 at 1:32
DekeDeke
1,49611226
Functions acts as objects . Here is another similar case: stackoverflow.com/questions/27887281/…
– Deke
Nov 25 '18 at 1:41
add a comment |
How to access an object outside of the function when it is present in a named function.
function a(){
var someobj = { b: "abc"}
console.log(someobj)
}
I tried to set a variable and then access it but I get an error.
var bla = function a() {
var someobj = {
b: "abc"
}
console.log(someobj)
}
console.log(bla().someobj)javascript
edited Nov 25 '18 at 1:33
Ele
25.7k52252
asked Nov 25 '18 at 1:32
DekeDeke
1,49611226
How to access an object outside of the function when it is present in a named function.
function a(){
var someobj = { b: "abc"}
console.log(someobj)
}
I tried to set a variable and then access it but I get an error.
var bla = function a() {
var someobj = {
b: "abc"
}
console.log(someobj)
}
console.log(bla().someobj)var bla = function a() {
var someobj = {
b: "abc"
}
console.log(someobj)
}
console.log(bla().someobj)var bla = function a() {
var someobj = {
b: "abc"
}
console.log(someobj)
}
console.log(bla().someobj)javascript
javascript
edited Nov 25 '18 at 1:33
Ele
25.7k52252
asked Nov 25 '18 at 1:32
DekeDeke
1,49611226
edited Nov 25 '18 at 1:33
Ele
25.7k52252
asked Nov 25 '18 at 1:32
DekeDeke
1,49611226
edited Nov 25 '18 at 1:33
Ele
25.7k52252
edited Nov 25 '18 at 1:33
Ele
25.7k52252
edited Nov 25 '18 at 1:33
Ele
25.7k52252
25.7k52252
asked Nov 25 '18 at 1:32
DekeDeke
1,49611226
asked Nov 25 '18 at 1:32
DekeDeke
1,49611226
asked Nov 25 '18 at 1:32
DekeDeke
1,49611226
1,49611226
Functions acts as objects . Here is another similar case: stackoverflow.com/questions/27887281/…
– Deke
Nov 25 '18 at 1:41
add a comment |
Functions acts as objects . Here is another similar case: stackoverflow.com/questions/27887281/…
– Deke
Nov 25 '18 at 1:41
Functions acts as objects . Here is another similar case: stackoverflow.com/questions/27887281/…
– Deke
Nov 25 '18 at 1:41
Functions acts as objects . Here is another similar case: stackoverflow.com/questions/27887281/…
– Deke
Nov 25 '18 at 1:41
add a comment |
2 Answers
2
active
oldest
votes
That's a local variable and its scope is inside of that function.
Probably, your confusion is on how a function is called as a constructor.
new bla()
So, you can access properties from instantiated objects through a function called as a constructor. Further, to set properties you need to use the context this.
var bla = function a() {
this.someobj = {b: "abc"};
//^^^^
// console.log(someobj)
}
console.log(new bla().someobj)
// ^^^^^^^^^answered Nov 25 '18 at 1:37
EleEle
25.7k52252
I learnt something new from both the answers.
– Deke
Nov 25 '18 at 5:09
add a comment |
You need to return the object in your function.
Adding the "." after bla() without returning something is the same thing as undefined.someobj
var bla = function a() {
return {someobj:{
b: "abc"
}}
}
console.log(bla().someobj)answered Nov 25 '18 at 1:46
kemicofakemicofa
10.8k44185
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53463942%2fhow-to-access-an-object-outside-when-it-is-present-in-a-named-function%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
That's a local variable and its scope is inside of that function.
Probably, your confusion is on how a function is called as a constructor.
new bla()
So, you can access properties from instantiated objects through a function called as a constructor. Further, to set properties you need to use the context this.
var bla = function a() {
this.someobj = {b: "abc"};
//^^^^
// console.log(someobj)
}
console.log(new bla().someobj)
// ^^^^^^^^^answered Nov 25 '18 at 1:37
EleEle
25.7k52252
I learnt something new from both the answers.
– Deke
Nov 25 '18 at 5:09
add a comment |
That's a local variable and its scope is inside of that function.
Probably, your confusion is on how a function is called as a constructor.
new bla()
So, you can access properties from instantiated objects through a function called as a constructor. Further, to set properties you need to use the context this.
var bla = function a() {
this.someobj = {b: "abc"};
//^^^^
// console.log(someobj)
}
console.log(new bla().someobj)
// ^^^^^^^^^answered Nov 25 '18 at 1:37
EleEle
25.7k52252
I learnt something new from both the answers.
– Deke
Nov 25 '18 at 5:09
add a comment |
That's a local variable and its scope is inside of that function.
Probably, your confusion is on how a function is called as a constructor.
new bla()
So, you can access properties from instantiated objects through a function called as a constructor. Further, to set properties you need to use the context this.
var bla = function a() {
this.someobj = {b: "abc"};
//^^^^
// console.log(someobj)
}
console.log(new bla().someobj)
// ^^^^^^^^^answered Nov 25 '18 at 1:37
EleEle
25.7k52252
That's a local variable and its scope is inside of that function.
Probably, your confusion is on how a function is called as a constructor.
new bla()
So, you can access properties from instantiated objects through a function called as a constructor. Further, to set properties you need to use the context this.
var bla = function a() {
this.someobj = {b: "abc"};
//^^^^
// console.log(someobj)
}
console.log(new bla().someobj)
// ^^^^^^^^^var bla = function a() {
this.someobj = {b: "abc"};
//^^^^
// console.log(someobj)
}
console.log(new bla().someobj)
// ^^^^^^^^^var bla = function a() {
this.someobj = {b: "abc"};
//^^^^
// console.log(someobj)
}
console.log(new bla().someobj)
// ^^^^^^^^^answered Nov 25 '18 at 1:37
EleEle
25.7k52252
answered Nov 25 '18 at 1:37
EleEle
25.7k52252
answered Nov 25 '18 at 1:37
EleEle
25.7k52252
answered Nov 25 '18 at 1:37
EleEle
25.7k52252
25.7k52252
I learnt something new from both the answers.
– Deke
Nov 25 '18 at 5:09
add a comment |
I learnt something new from both the answers.
– Deke
Nov 25 '18 at 5:09
I learnt something new from both the answers.
– Deke
Nov 25 '18 at 5:09
I learnt something new from both the answers.
– Deke
Nov 25 '18 at 5:09
add a comment |
You need to return the object in your function.
Adding the "." after bla() without returning something is the same thing as undefined.someobj
var bla = function a() {
return {someobj:{
b: "abc"
}}
}
console.log(bla().someobj)answered Nov 25 '18 at 1:46
kemicofakemicofa
10.8k44185
add a comment |
You need to return the object in your function.
Adding the "." after bla() without returning something is the same thing as undefined.someobj
var bla = function a() {
return {someobj:{
b: "abc"
}}
}
console.log(bla().someobj)answered Nov 25 '18 at 1:46
kemicofakemicofa
10.8k44185
add a comment |
You need to return the object in your function.
Adding the "." after bla() without returning something is the same thing as undefined.someobj
var bla = function a() {
return {someobj:{
b: "abc"
}}
}
console.log(bla().someobj)answered Nov 25 '18 at 1:46
kemicofakemicofa
10.8k44185
You need to return the object in your function.
Adding the "." after bla() without returning something is the same thing as undefined.someobj
var bla = function a() {
return {someobj:{
b: "abc"
}}
}
console.log(bla().someobj)var bla = function a() {
return {someobj:{
b: "abc"
}}
}
console.log(bla().someobj)var bla = function a() {
return {someobj:{
b: "abc"
}}
}
console.log(bla().someobj)answered Nov 25 '18 at 1:46
kemicofakemicofa
10.8k44185
answered Nov 25 '18 at 1:46
kemicofakemicofa
10.8k44185
answered Nov 25 '18 at 1:46
kemicofakemicofa
10.8k44185
answered Nov 25 '18 at 1:46
kemicofakemicofa
10.8k44185
10.8k44185
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53463942%2fhow-to-access-an-object-outside-when-it-is-present-in-a-named-function%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Functions acts as objects . Here is another similar case: stackoverflow.com/questions/27887281/…
– Deke
Nov 25 '18 at 1:41