if (condition || condition) vs if (condition) if (condition)





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-1















I just started the project Euler and I already have some problems.
why do these methods produce different results?



int sum=0;

for (int i=0;i<n;i++)

{

if(i%3==0 || i%5==0)

    sum+=i;

}


vs



int sum=0;

for (int i=0;i<n;i++)

{

if(i%3==0)

   sum+=i;

if (i%5==0)

   sum+=i;

}





java if-statement







share|improve this question


















  • 5





    What if i is divisible by both 3 and 5? What does your second code do?

    – tkausl
    Nov 25 '18 at 1:23






  • 2





    What happens when i is 15?

    – Cup of Java
    Nov 25 '18 at 1:25






  • 4





    Might be a good time to learn to debug ericlippert.com/2014/03/05/how-to-debug-small-programs

    – cricket_007
    Nov 25 '18 at 1:25


















-1















I just started the project Euler and I already have some problems.
why do these methods produce different results?



int sum=0;

for (int i=0;i<n;i++)

{

if(i%3==0 || i%5==0)

    sum+=i;

}


vs



int sum=0;

for (int i=0;i<n;i++)

{

if(i%3==0)

   sum+=i;

if (i%5==0)

   sum+=i;

}





java if-statement







share|improve this question


















  • 5





    What if i is divisible by both 3 and 5? What does your second code do?

    – tkausl
    Nov 25 '18 at 1:23






  • 2





    What happens when i is 15?

    – Cup of Java
    Nov 25 '18 at 1:25






  • 4





    Might be a good time to learn to debug ericlippert.com/2014/03/05/how-to-debug-small-programs

    – cricket_007
    Nov 25 '18 at 1:25














-1












-1








-1








I just started the project Euler and I already have some problems.
why do these methods produce different results?



int sum=0;

for (int i=0;i<n;i++)

{

if(i%3==0 || i%5==0)

    sum+=i;

}


vs



int sum=0;

for (int i=0;i<n;i++)

{

if(i%3==0)

   sum+=i;

if (i%5==0)

   sum+=i;

}





java if-statement







share|improve this question














I just started the project Euler and I already have some problems.
why do these methods produce different results?



int sum=0;

for (int i=0;i<n;i++)

{

if(i%3==0 || i%5==0)

    sum+=i;

}


vs



int sum=0;

for (int i=0;i<n;i++)

{

if(i%3==0)

   sum+=i;

if (i%5==0)

   sum+=i;

}





java if-statement




java if-statement






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 25 '18 at 1:21









R.PodarR.Podar

337




337








  • 5





    What if i is divisible by both 3 and 5? What does your second code do?

    – tkausl
    Nov 25 '18 at 1:23






  • 2





    What happens when i is 15?

    – Cup of Java
    Nov 25 '18 at 1:25






  • 4





    Might be a good time to learn to debug ericlippert.com/2014/03/05/how-to-debug-small-programs

    – cricket_007
    Nov 25 '18 at 1:25














  • 5





    What if i is divisible by both 3 and 5? What does your second code do?

    – tkausl
    Nov 25 '18 at 1:23






  • 2





    What happens when i is 15?

    – Cup of Java
    Nov 25 '18 at 1:25






  • 4





    Might be a good time to learn to debug ericlippert.com/2014/03/05/how-to-debug-small-programs

    – cricket_007
    Nov 25 '18 at 1:25








5




5





What if i is divisible by both 3 and 5? What does your second code do?

– tkausl
Nov 25 '18 at 1:23





What if i is divisible by both 3 and 5? What does your second code do?

– tkausl
Nov 25 '18 at 1:23




2




2





What happens when i is 15?

– Cup of Java
Nov 25 '18 at 1:25





What happens when i is 15?

– Cup of Java
Nov 25 '18 at 1:25




4




4





Might be a good time to learn to debug ericlippert.com/2014/03/05/how-to-debug-small-programs

– cricket_007
Nov 25 '18 at 1:25





Might be a good time to learn to debug ericlippert.com/2014/03/05/how-to-debug-small-programs

– cricket_007
Nov 25 '18 at 1:25












2 Answers
2






active

oldest

votes


















2














The first one will look if it is either i%3 or i%5.
Even if both are true, it only executes it once.



The seconde one, will execute sum+=i twice, if both are true:



30%3 = 0 and 30%5 = 0


So both of these will be executed:



if(i%3==0)

   sum+=i;

if (i%5==0)





share|improve this answer































    1














    In the first, it is sufficient that any of the comparisons be true to execute the sentence. If the first comparison is true, the second comparison will no longer be made. This is because True or [boolean] is always true. That is, it is enough that in the sequence of comparisons joined by or there is a true one, then the result will always be true.



    In the second, the two conditions are always evaluated. And depending on those evaluations the sentences will be executed or not.






    share|improve this answer
























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2














      The first one will look if it is either i%3 or i%5.
      Even if both are true, it only executes it once.



      The seconde one, will execute sum+=i twice, if both are true:



      30%3 = 0 and 30%5 = 0


      So both of these will be executed:



      if(i%3==0)
      
   sum+=i;
      
if (i%5==0)





      share|improve this answer




























        2














        The first one will look if it is either i%3 or i%5.
        Even if both are true, it only executes it once.



        The seconde one, will execute sum+=i twice, if both are true:



        30%3 = 0 and 30%5 = 0


        So both of these will be executed:



        if(i%3==0)
        
   sum+=i;
        
if (i%5==0)





        share|improve this answer


























          2












          2








          2







          The first one will look if it is either i%3 or i%5.
          Even if both are true, it only executes it once.



          The seconde one, will execute sum+=i twice, if both are true:



          30%3 = 0 and 30%5 = 0


          So both of these will be executed:



          if(i%3==0)
          
   sum+=i;
          
if (i%5==0)





          share|improve this answer













          The first one will look if it is either i%3 or i%5.
          Even if both are true, it only executes it once.



          The seconde one, will execute sum+=i twice, if both are true:



          30%3 = 0 and 30%5 = 0


          So both of these will be executed:



          if(i%3==0)
          
   sum+=i;
          
if (i%5==0)






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 25 '18 at 1:24









          Timothy Lukas H.Timothy Lukas H.

          286313




          286313

























              1














              In the first, it is sufficient that any of the comparisons be true to execute the sentence. If the first comparison is true, the second comparison will no longer be made. This is because True or [boolean] is always true. That is, it is enough that in the sequence of comparisons joined by or there is a true one, then the result will always be true.



              In the second, the two conditions are always evaluated. And depending on those evaluations the sentences will be executed or not.






              share|improve this answer




























                1














                In the first, it is sufficient that any of the comparisons be true to execute the sentence. If the first comparison is true, the second comparison will no longer be made. This is because True or [boolean] is always true. That is, it is enough that in the sequence of comparisons joined by or there is a true one, then the result will always be true.



                In the second, the two conditions are always evaluated. And depending on those evaluations the sentences will be executed or not.






                share|improve this answer


























                  1












                  1








                  1







                  In the first, it is sufficient that any of the comparisons be true to execute the sentence. If the first comparison is true, the second comparison will no longer be made. This is because True or [boolean] is always true. That is, it is enough that in the sequence of comparisons joined by or there is a true one, then the result will always be true.



                  In the second, the two conditions are always evaluated. And depending on those evaluations the sentences will be executed or not.






                  share|improve this answer













                  In the first, it is sufficient that any of the comparisons be true to execute the sentence. If the first comparison is true, the second comparison will no longer be made. This is because True or [boolean] is always true. That is, it is enough that in the sequence of comparisons joined by or there is a true one, then the result will always be true.



                  In the second, the two conditions are always evaluated. And depending on those evaluations the sentences will be executed or not.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 25 '18 at 2:37









                  Luis Ivan Mera DávilaLuis Ivan Mera Dávila

                  1816




                  1816






























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