how to find xml element by attribute value using ElementTree [duplicate]
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This question already has an answer here:
Parse xml from file using etree works when reading string, but not a file
2 answers
Attempting to parse an XML with namespaces and attributes. I wish to retrieve an element by a given attribute (id).
Documentation specifies but
[@attrib] Selects all elements that have the given attribute.
[@attrib='value'] Selects all elements for which the given attribute has the given value. The value cannot contain quotes.
neither solutions below returns an element when given an attribute name & value or when given an attribute name only
from lxml import etree
tree = etree.parse("es.xml")
root = tree.getroot()
print root.findall('file/body/trans-unit', root.nsmap)
# Unable to fetch all with attribute == id
print root.findall('file/body/trans-unit[@id]', root.nsmap)
# Unable to fetch element with id = 111
print root.find('file/body/trans-unit[@id="111"]', root.nsmap)
XML
<?xml version="1.0" encoding="UTF-8"?>
<xliff xmlns="urn:oasis:names:tc:xliff:document:1.2">
<file original="PDDDD" source-language="en" datatype="plaintext" target-language="es">
<header>
<tool tool-id="com.apple.dt.xcode" tool-name="Xcode" tool-version="10.1" build-num="10B61"/>
</header>
<body>
<trans-unit id="111">
<source>Welcome!</source>
<target>Welcome!</target>
<note>Class = "UILabel"; text = "Welcome!"; ObjectID = "7oz-Od-KDt";</note>
</trans-unit>
</body>
</file>
</xliff>
python xml xliff
asked Nov 24 '18 at 3:24
kyekye
98521833
marked as duplicate by Michael Kay xml
Users with the xml badge can single-handedly close xml questions as duplicates and reopen them as needed.
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Nov 24 '18 at 9:46
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
Parse xml from file using etree works when reading string, but not a file
2 answers
Attempting to parse an XML with namespaces and attributes. I wish to retrieve an element by a given attribute (id).
Documentation specifies but
[@attrib] Selects all elements that have the given attribute.
[@attrib='value'] Selects all elements for which the given attribute has the given value. The value cannot contain quotes.
neither solutions below returns an element when given an attribute name & value or when given an attribute name only
from lxml import etree
tree = etree.parse("es.xml")
root = tree.getroot()
print root.findall('file/body/trans-unit', root.nsmap)
# Unable to fetch all with attribute == id
print root.findall('file/body/trans-unit[@id]', root.nsmap)
# Unable to fetch element with id = 111
print root.find('file/body/trans-unit[@id="111"]', root.nsmap)
XML
<?xml version="1.0" encoding="UTF-8"?>
<xliff xmlns="urn:oasis:names:tc:xliff:document:1.2">
<file original="PDDDD" source-language="en" datatype="plaintext" target-language="es">
<header>
<tool tool-id="com.apple.dt.xcode" tool-name="Xcode" tool-version="10.1" build-num="10B61"/>
</header>
<body>
<trans-unit id="111">
<source>Welcome!</source>
<target>Welcome!</target>
<note>Class = "UILabel"; text = "Welcome!"; ObjectID = "7oz-Od-KDt";</note>
</trans-unit>
</body>
</file>
</xliff>
python xml xliff
asked Nov 24 '18 at 3:24
kyekye
98521833
marked as duplicate by Michael Kay xml
Users with the xml badge can single-handedly close xml questions as duplicates and reopen them as needed.
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Nov 24 '18 at 9:46
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
Parse xml from file using etree works when reading string, but not a file
2 answers
Attempting to parse an XML with namespaces and attributes. I wish to retrieve an element by a given attribute (id).
Documentation specifies but
[@attrib] Selects all elements that have the given attribute.
[@attrib='value'] Selects all elements for which the given attribute has the given value. The value cannot contain quotes.
neither solutions below returns an element when given an attribute name & value or when given an attribute name only
from lxml import etree
tree = etree.parse("es.xml")
root = tree.getroot()
print root.findall('file/body/trans-unit', root.nsmap)
# Unable to fetch all with attribute == id
print root.findall('file/body/trans-unit[@id]', root.nsmap)
# Unable to fetch element with id = 111
print root.find('file/body/trans-unit[@id="111"]', root.nsmap)
XML
<?xml version="1.0" encoding="UTF-8"?>
<xliff xmlns="urn:oasis:names:tc:xliff:document:1.2">
<file original="PDDDD" source-language="en" datatype="plaintext" target-language="es">
<header>
<tool tool-id="com.apple.dt.xcode" tool-name="Xcode" tool-version="10.1" build-num="10B61"/>
</header>
<body>
<trans-unit id="111">
<source>Welcome!</source>
<target>Welcome!</target>
<note>Class = "UILabel"; text = "Welcome!"; ObjectID = "7oz-Od-KDt";</note>
</trans-unit>
</body>
</file>
</xliff>
python xml xliff
asked Nov 24 '18 at 3:24
kyekye
98521833
This question already has an answer here:
Parse xml from file using etree works when reading string, but not a file
2 answers
Attempting to parse an XML with namespaces and attributes. I wish to retrieve an element by a given attribute (id).
Documentation specifies but
[@attrib] Selects all elements that have the given attribute.
[@attrib='value'] Selects all elements for which the given attribute has the given value. The value cannot contain quotes.
neither solutions below returns an element when given an attribute name & value or when given an attribute name only
from lxml import etree
tree = etree.parse("es.xml")
root = tree.getroot()
print root.findall('file/body/trans-unit', root.nsmap)
# Unable to fetch all with attribute == id
print root.findall('file/body/trans-unit[@id]', root.nsmap)
# Unable to fetch element with id = 111
print root.find('file/body/trans-unit[@id="111"]', root.nsmap)
XML
<?xml version="1.0" encoding="UTF-8"?>
<xliff xmlns="urn:oasis:names:tc:xliff:document:1.2">
<file original="PDDDD" source-language="en" datatype="plaintext" target-language="es">
<header>
<tool tool-id="com.apple.dt.xcode" tool-name="Xcode" tool-version="10.1" build-num="10B61"/>
</header>
<body>
<trans-unit id="111">
<source>Welcome!</source>
<target>Welcome!</target>
<note>Class = "UILabel"; text = "Welcome!"; ObjectID = "7oz-Od-KDt";</note>
</trans-unit>
</body>
</file>
</xliff>
This question already has an answer here:
Parse xml from file using etree works when reading string, but not a file
2 answers
python xml xliff
python xml xliff
asked Nov 24 '18 at 3:24
kyekye
98521833
asked Nov 24 '18 at 3:24
kyekye
98521833
asked Nov 24 '18 at 3:24
kyekye
98521833
asked Nov 24 '18 at 3:24
kyekye
98521833
asked Nov 24 '18 at 3:24
kyekye
98521833
98521833
marked as duplicate by Michael Kay xml
Users with the xml badge can single-handedly close xml questions as duplicates and reopen them as needed.
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Nov 24 '18 at 9:46
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Michael Kay xml
Users with the xml badge can single-handedly close xml questions as duplicates and reopen them as needed.
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Nov 24 '18 at 9:46
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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1 Answer
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I don't know how to do it with the {None: "urn:oasis:names:tc:xliff:document:1.2"} namespace of root.nsmap...
However, if you redefine a namespace map like
ns = {"n": "urn:oasis:names:tc:xliff:document:1.2"}
then this works
root.find('.//n:trans-unit[@id="111"]', ns)
answered Nov 24 '18 at 9:17
SilmathoronSilmathoron
1,0861921
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
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active
oldest
votes
I don't know how to do it with the {None: "urn:oasis:names:tc:xliff:document:1.2"} namespace of root.nsmap...
However, if you redefine a namespace map like
ns = {"n": "urn:oasis:names:tc:xliff:document:1.2"}
then this works
root.find('.//n:trans-unit[@id="111"]', ns)
answered Nov 24 '18 at 9:17
SilmathoronSilmathoron
1,0861921
add a comment |
I don't know how to do it with the {None: "urn:oasis:names:tc:xliff:document:1.2"} namespace of root.nsmap...
However, if you redefine a namespace map like
ns = {"n": "urn:oasis:names:tc:xliff:document:1.2"}
then this works
root.find('.//n:trans-unit[@id="111"]', ns)
answered Nov 24 '18 at 9:17
SilmathoronSilmathoron
1,0861921
add a comment |
I don't know how to do it with the {None: "urn:oasis:names:tc:xliff:document:1.2"} namespace of root.nsmap...
However, if you redefine a namespace map like
ns = {"n": "urn:oasis:names:tc:xliff:document:1.2"}
then this works
root.find('.//n:trans-unit[@id="111"]', ns)
answered Nov 24 '18 at 9:17
SilmathoronSilmathoron
1,0861921
I don't know how to do it with the {None: "urn:oasis:names:tc:xliff:document:1.2"} namespace of root.nsmap...
However, if you redefine a namespace map like
ns = {"n": "urn:oasis:names:tc:xliff:document:1.2"}
then this works
root.find('.//n:trans-unit[@id="111"]', ns)
answered Nov 24 '18 at 9:17
SilmathoronSilmathoron
1,0861921
answered Nov 24 '18 at 9:17
SilmathoronSilmathoron
1,0861921
answered Nov 24 '18 at 9:17
SilmathoronSilmathoron
1,0861921
answered Nov 24 '18 at 9:17
SilmathoronSilmathoron
1,0861921
1,0861921
add a comment |
add a comment |
