Is there a way to avoid amp; prepending to request parameter name in GrailsParameterMap











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0
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My request URL is



http://localhost:8080/application/controller/action?param1=value1&param2=value2


I obtain request params in controller through grails-core/WebAttributes.groovy



/**

* Obtains the Grails parameter map

*

* @return The GrailsParameterMap instance

*/

GrailsParameterMap getParams() {

    currentRequestAttributes().getParams()

}


The 2nd param in the map is of structure 



{LinkedHashMap$Entry@00000} "amp;param2" -> "value2"


How or is it possible to eliminate "amp;"?






grails httprequest







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    up vote
    0
    down vote

    favorite












    My request URL is



    http://localhost:8080/application/controller/action?param1=value1&param2=value2


    I obtain request params in controller through grails-core/WebAttributes.groovy



    /**
    
* Obtains the Grails parameter map
    
*
    
* @return The GrailsParameterMap instance
    
*/
    
GrailsParameterMap getParams() {
    
    currentRequestAttributes().getParams()
    
}


    The 2nd param in the map is of structure 



    {LinkedHashMap$Entry@00000} "amp;param2" -> "value2"


    How or is it possible to eliminate "amp;"?






    grails httprequest







    share|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      My request URL is



      http://localhost:8080/application/controller/action?param1=value1&param2=value2


      I obtain request params in controller through grails-core/WebAttributes.groovy



      /**
      
* Obtains the Grails parameter map
      
*
      
* @return The GrailsParameterMap instance
      
*/
      
GrailsParameterMap getParams() {
      
    currentRequestAttributes().getParams()
      
}


      The 2nd param in the map is of structure 



      {LinkedHashMap$Entry@00000} "amp;param2" -> "value2"


      How or is it possible to eliminate "amp;"?






      grails httprequest







      share|improve this question













      My request URL is



      http://localhost:8080/application/controller/action?param1=value1&param2=value2


      I obtain request params in controller through grails-core/WebAttributes.groovy



      /**
      
* Obtains the Grails parameter map
      
*
      
* @return The GrailsParameterMap instance
      
*/
      
GrailsParameterMap getParams() {
      
    currentRequestAttributes().getParams()
      
}


      The 2nd param in the map is of structure 



      {LinkedHashMap$Entry@00000} "amp;param2" -> "value2"


      How or is it possible to eliminate "amp;"?






      grails httprequest




      grails httprequest






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 5 at 3:52









      Pradeep Kumaresan

      598




      598
























          1 Answer
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          Your request URL (https://en.wikipedia.org/wiki/Query_string) includes parameters named amp;param2 and similar; parameters are separated by ampersands, not HTML-encoded ampersands. This is not a problem with Grails, but instead with however you are generating your URL.



          How are you generating the request URL that you reference here?






          share|improve this answer





















          • You are right. The URL is generated like this url?.encodeAsHTML()
            – Pradeep Kumaresan
            yesterday













          Your Answer






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          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          0
          down vote



          accepted










          Your request URL (https://en.wikipedia.org/wiki/Query_string) includes parameters named amp;param2 and similar; parameters are separated by ampersands, not HTML-encoded ampersands. This is not a problem with Grails, but instead with however you are generating your URL.



          How are you generating the request URL that you reference here?






          share|improve this answer





















          • You are right. The URL is generated like this url?.encodeAsHTML()
            – Pradeep Kumaresan
            yesterday

















          up vote
          0
          down vote



          accepted










          Your request URL (https://en.wikipedia.org/wiki/Query_string) includes parameters named amp;param2 and similar; parameters are separated by ampersands, not HTML-encoded ampersands. This is not a problem with Grails, but instead with however you are generating your URL.



          How are you generating the request URL that you reference here?






          share|improve this answer





















          • You are right. The URL is generated like this url?.encodeAsHTML()
            – Pradeep Kumaresan
            yesterday















          up vote
          0
          down vote



          accepted







          up vote
          0
          down vote



          accepted






          Your request URL (https://en.wikipedia.org/wiki/Query_string) includes parameters named amp;param2 and similar; parameters are separated by ampersands, not HTML-encoded ampersands. This is not a problem with Grails, but instead with however you are generating your URL.



          How are you generating the request URL that you reference here?






          share|improve this answer












          Your request URL (https://en.wikipedia.org/wiki/Query_string) includes parameters named amp;param2 and similar; parameters are separated by ampersands, not HTML-encoded ampersands. This is not a problem with Grails, but instead with however you are generating your URL.



          How are you generating the request URL that you reference here?







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 6 at 0:22









          Daniel

          1,4961319




          1,4961319












          • You are right. The URL is generated like this url?.encodeAsHTML()
            – Pradeep Kumaresan
            yesterday




















          • You are right. The URL is generated like this url?.encodeAsHTML()
            – Pradeep Kumaresan
            yesterday


















          You are right. The URL is generated like this url?.encodeAsHTML()
          – Pradeep Kumaresan
          yesterday






          You are right. The URL is generated like this url?.encodeAsHTML()
          – Pradeep Kumaresan
          yesterday




















           

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