Powershell function returning an array instead of string











up vote
2
down vote

favorite












i'm importing a csv and i would like to add a column to it (with the result based off of the previous columns)



my data looks like this



host address,host prefix,site
10.1.1.0,24,400-01


i would like to add a column called "sub site"



so I wrote this module but the problem is, the actual ending object is an array instead of string



function site {
Param($s)
$s -match '(ddd)'
return $Matches[0]
}

$csv = import-csv $file | select-object *,@{Name='Sub Site';expression= {site $_.site}}


if I run the command



PS C:>$csv[0]

Host Address :10.1.1.0
host prefix :24
site :400-01
sub site : {True,400}


when it should look like



PS C:>$csv[0]

Host Address :10.1.1.0
host prefix :24
site :400-01
sub site : 400


EDIT: I found the solution but the question is now WHY.



If I change my function to $s -match "ddd" |out-null I get back the expected 400










share|improve this question




















  • 2




    The $s -match '(ddd)' outputs True. That gets passed to the pipeline if you do not suppress it.
    – Lieven Keersmaekers
    Nov 7 at 7:47






  • 2




    and fwiw - if you subsite is always 3 characters like your regex shows, following woud do without the need of an extra function *,@{Name='Sub Site';expression= {$_.site.SubString(0,3)}}
    – Lieven Keersmaekers
    Nov 7 at 7:50










  • thanks, great idea. However my case is a bit more complicated then I actually posted so it isn't always at the front!
    – genx1mx6
    Nov 8 at 8:22















up vote
2
down vote

favorite












i'm importing a csv and i would like to add a column to it (with the result based off of the previous columns)



my data looks like this



host address,host prefix,site
10.1.1.0,24,400-01


i would like to add a column called "sub site"



so I wrote this module but the problem is, the actual ending object is an array instead of string



function site {
Param($s)
$s -match '(ddd)'
return $Matches[0]
}

$csv = import-csv $file | select-object *,@{Name='Sub Site';expression= {site $_.site}}


if I run the command



PS C:>$csv[0]

Host Address :10.1.1.0
host prefix :24
site :400-01
sub site : {True,400}


when it should look like



PS C:>$csv[0]

Host Address :10.1.1.0
host prefix :24
site :400-01
sub site : 400


EDIT: I found the solution but the question is now WHY.



If I change my function to $s -match "ddd" |out-null I get back the expected 400










share|improve this question




















  • 2




    The $s -match '(ddd)' outputs True. That gets passed to the pipeline if you do not suppress it.
    – Lieven Keersmaekers
    Nov 7 at 7:47






  • 2




    and fwiw - if you subsite is always 3 characters like your regex shows, following woud do without the need of an extra function *,@{Name='Sub Site';expression= {$_.site.SubString(0,3)}}
    – Lieven Keersmaekers
    Nov 7 at 7:50










  • thanks, great idea. However my case is a bit more complicated then I actually posted so it isn't always at the front!
    – genx1mx6
    Nov 8 at 8:22













up vote
2
down vote

favorite









up vote
2
down vote

favorite











i'm importing a csv and i would like to add a column to it (with the result based off of the previous columns)



my data looks like this



host address,host prefix,site
10.1.1.0,24,400-01


i would like to add a column called "sub site"



so I wrote this module but the problem is, the actual ending object is an array instead of string



function site {
Param($s)
$s -match '(ddd)'
return $Matches[0]
}

$csv = import-csv $file | select-object *,@{Name='Sub Site';expression= {site $_.site}}


if I run the command



PS C:>$csv[0]

Host Address :10.1.1.0
host prefix :24
site :400-01
sub site : {True,400}


when it should look like



PS C:>$csv[0]

Host Address :10.1.1.0
host prefix :24
site :400-01
sub site : 400


EDIT: I found the solution but the question is now WHY.



If I change my function to $s -match "ddd" |out-null I get back the expected 400










share|improve this question















i'm importing a csv and i would like to add a column to it (with the result based off of the previous columns)



my data looks like this



host address,host prefix,site
10.1.1.0,24,400-01


i would like to add a column called "sub site"



so I wrote this module but the problem is, the actual ending object is an array instead of string



function site {
Param($s)
$s -match '(ddd)'
return $Matches[0]
}

$csv = import-csv $file | select-object *,@{Name='Sub Site';expression= {site $_.site}}


if I run the command



PS C:>$csv[0]

Host Address :10.1.1.0
host prefix :24
site :400-01
sub site : {True,400}


when it should look like



PS C:>$csv[0]

Host Address :10.1.1.0
host prefix :24
site :400-01
sub site : 400


EDIT: I found the solution but the question is now WHY.



If I change my function to $s -match "ddd" |out-null I get back the expected 400







powershell






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 7 at 7:45

























asked Nov 7 at 7:36









genx1mx6

14528




14528








  • 2




    The $s -match '(ddd)' outputs True. That gets passed to the pipeline if you do not suppress it.
    – Lieven Keersmaekers
    Nov 7 at 7:47






  • 2




    and fwiw - if you subsite is always 3 characters like your regex shows, following woud do without the need of an extra function *,@{Name='Sub Site';expression= {$_.site.SubString(0,3)}}
    – Lieven Keersmaekers
    Nov 7 at 7:50










  • thanks, great idea. However my case is a bit more complicated then I actually posted so it isn't always at the front!
    – genx1mx6
    Nov 8 at 8:22














  • 2




    The $s -match '(ddd)' outputs True. That gets passed to the pipeline if you do not suppress it.
    – Lieven Keersmaekers
    Nov 7 at 7:47






  • 2




    and fwiw - if you subsite is always 3 characters like your regex shows, following woud do without the need of an extra function *,@{Name='Sub Site';expression= {$_.site.SubString(0,3)}}
    – Lieven Keersmaekers
    Nov 7 at 7:50










  • thanks, great idea. However my case is a bit more complicated then I actually posted so it isn't always at the front!
    – genx1mx6
    Nov 8 at 8:22








2




2




The $s -match '(ddd)' outputs True. That gets passed to the pipeline if you do not suppress it.
– Lieven Keersmaekers
Nov 7 at 7:47




The $s -match '(ddd)' outputs True. That gets passed to the pipeline if you do not suppress it.
– Lieven Keersmaekers
Nov 7 at 7:47




2




2




and fwiw - if you subsite is always 3 characters like your regex shows, following woud do without the need of an extra function *,@{Name='Sub Site';expression= {$_.site.SubString(0,3)}}
– Lieven Keersmaekers
Nov 7 at 7:50




and fwiw - if you subsite is always 3 characters like your regex shows, following woud do without the need of an extra function *,@{Name='Sub Site';expression= {$_.site.SubString(0,3)}}
– Lieven Keersmaekers
Nov 7 at 7:50












thanks, great idea. However my case is a bit more complicated then I actually posted so it isn't always at the front!
– genx1mx6
Nov 8 at 8:22




thanks, great idea. However my case is a bit more complicated then I actually posted so it isn't always at the front!
– genx1mx6
Nov 8 at 8:22












1 Answer
1






active

oldest

votes

















up vote
1
down vote



accepted










Good you found the answer. I was typing this up as you found it. The reason is because the -match returns a value and it is added to the pipeline, which is all "returned" from the function.



For example, run this one line and see what is does:



"Hello" -match 'h'


It prints True.



Since I had this typed up, here is another way to phrase your question with the fix...



function site {
Param($s)
$null = $s -match '(ddd)'
$ret = $Matches[0]

return $ret
}

$csv = @"
host address,host prefix,site
10.1.1.1,24,400-01
10.1.1.2,24,500-02
10.1.1.3,24,600-03
"@

$data = $csv | ConvertFrom-Csv

'1 =============='
$data | ft -AutoSize

$data2 = $data | select-object *,@{Name='Sub Site';expression= {site $_.site}}

'2 =============='
$data2 | ft -AutoSize





share|improve this answer





















  • Thanks, I also thought of another way and that's to take the last index of the array that gets returned so site $($_.site)[-1] However I think I like your solution more since you aren't guaranteed to get an array back from every function.
    – genx1mx6
    Nov 8 at 8:21











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










Good you found the answer. I was typing this up as you found it. The reason is because the -match returns a value and it is added to the pipeline, which is all "returned" from the function.



For example, run this one line and see what is does:



"Hello" -match 'h'


It prints True.



Since I had this typed up, here is another way to phrase your question with the fix...



function site {
Param($s)
$null = $s -match '(ddd)'
$ret = $Matches[0]

return $ret
}

$csv = @"
host address,host prefix,site
10.1.1.1,24,400-01
10.1.1.2,24,500-02
10.1.1.3,24,600-03
"@

$data = $csv | ConvertFrom-Csv

'1 =============='
$data | ft -AutoSize

$data2 = $data | select-object *,@{Name='Sub Site';expression= {site $_.site}}

'2 =============='
$data2 | ft -AutoSize





share|improve this answer





















  • Thanks, I also thought of another way and that's to take the last index of the array that gets returned so site $($_.site)[-1] However I think I like your solution more since you aren't guaranteed to get an array back from every function.
    – genx1mx6
    Nov 8 at 8:21















up vote
1
down vote



accepted










Good you found the answer. I was typing this up as you found it. The reason is because the -match returns a value and it is added to the pipeline, which is all "returned" from the function.



For example, run this one line and see what is does:



"Hello" -match 'h'


It prints True.



Since I had this typed up, here is another way to phrase your question with the fix...



function site {
Param($s)
$null = $s -match '(ddd)'
$ret = $Matches[0]

return $ret
}

$csv = @"
host address,host prefix,site
10.1.1.1,24,400-01
10.1.1.2,24,500-02
10.1.1.3,24,600-03
"@

$data = $csv | ConvertFrom-Csv

'1 =============='
$data | ft -AutoSize

$data2 = $data | select-object *,@{Name='Sub Site';expression= {site $_.site}}

'2 =============='
$data2 | ft -AutoSize





share|improve this answer





















  • Thanks, I also thought of another way and that's to take the last index of the array that gets returned so site $($_.site)[-1] However I think I like your solution more since you aren't guaranteed to get an array back from every function.
    – genx1mx6
    Nov 8 at 8:21













up vote
1
down vote



accepted







up vote
1
down vote



accepted






Good you found the answer. I was typing this up as you found it. The reason is because the -match returns a value and it is added to the pipeline, which is all "returned" from the function.



For example, run this one line and see what is does:



"Hello" -match 'h'


It prints True.



Since I had this typed up, here is another way to phrase your question with the fix...



function site {
Param($s)
$null = $s -match '(ddd)'
$ret = $Matches[0]

return $ret
}

$csv = @"
host address,host prefix,site
10.1.1.1,24,400-01
10.1.1.2,24,500-02
10.1.1.3,24,600-03
"@

$data = $csv | ConvertFrom-Csv

'1 =============='
$data | ft -AutoSize

$data2 = $data | select-object *,@{Name='Sub Site';expression= {site $_.site}}

'2 =============='
$data2 | ft -AutoSize





share|improve this answer












Good you found the answer. I was typing this up as you found it. The reason is because the -match returns a value and it is added to the pipeline, which is all "returned" from the function.



For example, run this one line and see what is does:



"Hello" -match 'h'


It prints True.



Since I had this typed up, here is another way to phrase your question with the fix...



function site {
Param($s)
$null = $s -match '(ddd)'
$ret = $Matches[0]

return $ret
}

$csv = @"
host address,host prefix,site
10.1.1.1,24,400-01
10.1.1.2,24,500-02
10.1.1.3,24,600-03
"@

$data = $csv | ConvertFrom-Csv

'1 =============='
$data | ft -AutoSize

$data2 = $data | select-object *,@{Name='Sub Site';expression= {site $_.site}}

'2 =============='
$data2 | ft -AutoSize






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 7 at 7:51









Kory Gill

4,8711824




4,8711824












  • Thanks, I also thought of another way and that's to take the last index of the array that gets returned so site $($_.site)[-1] However I think I like your solution more since you aren't guaranteed to get an array back from every function.
    – genx1mx6
    Nov 8 at 8:21


















  • Thanks, I also thought of another way and that's to take the last index of the array that gets returned so site $($_.site)[-1] However I think I like your solution more since you aren't guaranteed to get an array back from every function.
    – genx1mx6
    Nov 8 at 8:21
















Thanks, I also thought of another way and that's to take the last index of the array that gets returned so site $($_.site)[-1] However I think I like your solution more since you aren't guaranteed to get an array back from every function.
– genx1mx6
Nov 8 at 8:21




Thanks, I also thought of another way and that's to take the last index of the array that gets returned so site $($_.site)[-1] However I think I like your solution more since you aren't guaranteed to get an array back from every function.
– genx1mx6
Nov 8 at 8:21


















 

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