Hive get mimimum of two values for where clause












0















I am trying to write a hive query such that i need to use a date based where clause to filter on records.



WHERE date_key 
BETWEEN date_sub(current_date, 4)
AND MINIMUM(date_sub(current_date, 1), to_date("2018-10-14"))


Can we do something like MINIMUM of two values?










share|improve this question



























    0















    I am trying to write a hive query such that i need to use a date based where clause to filter on records.



    WHERE date_key 
    BETWEEN date_sub(current_date, 4)
    AND MINIMUM(date_sub(current_date, 1), to_date("2018-10-14"))


    Can we do something like MINIMUM of two values?










    share|improve this question

























      0












      0








      0








      I am trying to write a hive query such that i need to use a date based where clause to filter on records.



      WHERE date_key 
      BETWEEN date_sub(current_date, 4)
      AND MINIMUM(date_sub(current_date, 1), to_date("2018-10-14"))


      Can we do something like MINIMUM of two values?










      share|improve this question














      I am trying to write a hive query such that i need to use a date based where clause to filter on records.



      WHERE date_key 
      BETWEEN date_sub(current_date, 4)
      AND MINIMUM(date_sub(current_date, 1), to_date("2018-10-14"))


      Can we do something like MINIMUM of two values?







      sql hive






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 13 '18 at 23:47









      Pratik KhadloyaPratik Khadloya

      7,68145876




      7,68145876
























          2 Answers
          2






          active

          oldest

          votes


















          2














          if you are using oracle then there is a keyword called "least" which will output the lesser of values.
          Eg:



          WHERE date_key 
          BETWEEN date_sub(current_date, 4)
          AND LEAST(date_sub(current_date, 1), to_date("2018-10-14"))


          Otherwise you can handcraft the query to compare the two values as follows



          WHERE date_key 
          BETWEEN date_sub(current_date, 4)
          AND (CASE WHEN date_sub(current_date, 1)< to_date("2018-10-14") THEN
          date_sub(current_date, 1)
          ELSE to_date("2018-10-14")
          END)





          share|improve this answer
























          • the first approach is better. i would suggest not using case expressions in where. btw..least works with Hive too.

            – Vamsi Prabhala
            Nov 14 '18 at 1:52



















          1














          Don't bother. Just write:



          WHERE date_key >= date_sub(current_date, 4) AND
          date_key <= date_sub(current_date, 1) AND
          date_key <= to_date('2018-10-14')


          If something is less than the minimum of two values, then it is less than each of the values.






          share|improve this answer























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2














            if you are using oracle then there is a keyword called "least" which will output the lesser of values.
            Eg:



            WHERE date_key 
            BETWEEN date_sub(current_date, 4)
            AND LEAST(date_sub(current_date, 1), to_date("2018-10-14"))


            Otherwise you can handcraft the query to compare the two values as follows



            WHERE date_key 
            BETWEEN date_sub(current_date, 4)
            AND (CASE WHEN date_sub(current_date, 1)< to_date("2018-10-14") THEN
            date_sub(current_date, 1)
            ELSE to_date("2018-10-14")
            END)





            share|improve this answer
























            • the first approach is better. i would suggest not using case expressions in where. btw..least works with Hive too.

              – Vamsi Prabhala
              Nov 14 '18 at 1:52
















            2














            if you are using oracle then there is a keyword called "least" which will output the lesser of values.
            Eg:



            WHERE date_key 
            BETWEEN date_sub(current_date, 4)
            AND LEAST(date_sub(current_date, 1), to_date("2018-10-14"))


            Otherwise you can handcraft the query to compare the two values as follows



            WHERE date_key 
            BETWEEN date_sub(current_date, 4)
            AND (CASE WHEN date_sub(current_date, 1)< to_date("2018-10-14") THEN
            date_sub(current_date, 1)
            ELSE to_date("2018-10-14")
            END)





            share|improve this answer
























            • the first approach is better. i would suggest not using case expressions in where. btw..least works with Hive too.

              – Vamsi Prabhala
              Nov 14 '18 at 1:52














            2












            2








            2







            if you are using oracle then there is a keyword called "least" which will output the lesser of values.
            Eg:



            WHERE date_key 
            BETWEEN date_sub(current_date, 4)
            AND LEAST(date_sub(current_date, 1), to_date("2018-10-14"))


            Otherwise you can handcraft the query to compare the two values as follows



            WHERE date_key 
            BETWEEN date_sub(current_date, 4)
            AND (CASE WHEN date_sub(current_date, 1)< to_date("2018-10-14") THEN
            date_sub(current_date, 1)
            ELSE to_date("2018-10-14")
            END)





            share|improve this answer













            if you are using oracle then there is a keyword called "least" which will output the lesser of values.
            Eg:



            WHERE date_key 
            BETWEEN date_sub(current_date, 4)
            AND LEAST(date_sub(current_date, 1), to_date("2018-10-14"))


            Otherwise you can handcraft the query to compare the two values as follows



            WHERE date_key 
            BETWEEN date_sub(current_date, 4)
            AND (CASE WHEN date_sub(current_date, 1)< to_date("2018-10-14") THEN
            date_sub(current_date, 1)
            ELSE to_date("2018-10-14")
            END)






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 14 '18 at 1:28









            George JosephGeorge Joseph

            1,44249




            1,44249













            • the first approach is better. i would suggest not using case expressions in where. btw..least works with Hive too.

              – Vamsi Prabhala
              Nov 14 '18 at 1:52



















            • the first approach is better. i would suggest not using case expressions in where. btw..least works with Hive too.

              – Vamsi Prabhala
              Nov 14 '18 at 1:52

















            the first approach is better. i would suggest not using case expressions in where. btw..least works with Hive too.

            – Vamsi Prabhala
            Nov 14 '18 at 1:52





            the first approach is better. i would suggest not using case expressions in where. btw..least works with Hive too.

            – Vamsi Prabhala
            Nov 14 '18 at 1:52













            1














            Don't bother. Just write:



            WHERE date_key >= date_sub(current_date, 4) AND
            date_key <= date_sub(current_date, 1) AND
            date_key <= to_date('2018-10-14')


            If something is less than the minimum of two values, then it is less than each of the values.






            share|improve this answer




























              1














              Don't bother. Just write:



              WHERE date_key >= date_sub(current_date, 4) AND
              date_key <= date_sub(current_date, 1) AND
              date_key <= to_date('2018-10-14')


              If something is less than the minimum of two values, then it is less than each of the values.






              share|improve this answer


























                1












                1








                1







                Don't bother. Just write:



                WHERE date_key >= date_sub(current_date, 4) AND
                date_key <= date_sub(current_date, 1) AND
                date_key <= to_date('2018-10-14')


                If something is less than the minimum of two values, then it is less than each of the values.






                share|improve this answer













                Don't bother. Just write:



                WHERE date_key >= date_sub(current_date, 4) AND
                date_key <= date_sub(current_date, 1) AND
                date_key <= to_date('2018-10-14')


                If something is less than the minimum of two values, then it is less than each of the values.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 14 '18 at 4:24









                Gordon LinoffGordon Linoff

                764k35296400




                764k35296400






























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