How to make the response object that another ViewController's post request returns append to a...












1















I am a Swift beginner so apologies. With Siesta, I want to make a post request in a ViewController and then have the Entry object the request returns added to the TableViewController. In my ViewController:



EntryAPI.sharedInstance.addEntry()


The API code:



 func addEntry()  -> Request {
return newEntry().request(.post, json:["foo": "bar"])
}

func newEntry() -> Resource {
return service
.resource("/entry")
}


After the post request the ViewController does an unwind segue to the TableViewController, of course before the post request completes. I am not sure where in the code I would take the response and call a function in the TableViewController that appends the new Entry object to the entry list.



I am not sure if I should pass the new Entry object from the addEntry() function to the TableViewController with onSuccess() or if the TableViewController can have the newEntry() resource and know when the post request completes. I am not sure if I am going about this in the right way either. Thanks in advance.










share|improve this question

























  • Add an observer for your request (bustoutsolutions.github.io/siesta/guide/observers) and when it completes update the data in your tableview.

    – Alex Bailey
    Nov 14 '18 at 2:21











  • Thanks. So to clarify, am I adding the TableViewController to be an observer or the ViewController? If the ViewController, how can I send the new Entry object to the TableViewController if the segue happens before it completes?

    – Mickey Barcia
    Nov 14 '18 at 2:33











  • observer to your post request in Siesta to some external API.

    – Alex Bailey
    Nov 14 '18 at 2:52
















1















I am a Swift beginner so apologies. With Siesta, I want to make a post request in a ViewController and then have the Entry object the request returns added to the TableViewController. In my ViewController:



EntryAPI.sharedInstance.addEntry()


The API code:



 func addEntry()  -> Request {
return newEntry().request(.post, json:["foo": "bar"])
}

func newEntry() -> Resource {
return service
.resource("/entry")
}


After the post request the ViewController does an unwind segue to the TableViewController, of course before the post request completes. I am not sure where in the code I would take the response and call a function in the TableViewController that appends the new Entry object to the entry list.



I am not sure if I should pass the new Entry object from the addEntry() function to the TableViewController with onSuccess() or if the TableViewController can have the newEntry() resource and know when the post request completes. I am not sure if I am going about this in the right way either. Thanks in advance.










share|improve this question

























  • Add an observer for your request (bustoutsolutions.github.io/siesta/guide/observers) and when it completes update the data in your tableview.

    – Alex Bailey
    Nov 14 '18 at 2:21











  • Thanks. So to clarify, am I adding the TableViewController to be an observer or the ViewController? If the ViewController, how can I send the new Entry object to the TableViewController if the segue happens before it completes?

    – Mickey Barcia
    Nov 14 '18 at 2:33











  • observer to your post request in Siesta to some external API.

    – Alex Bailey
    Nov 14 '18 at 2:52














1












1








1


1






I am a Swift beginner so apologies. With Siesta, I want to make a post request in a ViewController and then have the Entry object the request returns added to the TableViewController. In my ViewController:



EntryAPI.sharedInstance.addEntry()


The API code:



 func addEntry()  -> Request {
return newEntry().request(.post, json:["foo": "bar"])
}

func newEntry() -> Resource {
return service
.resource("/entry")
}


After the post request the ViewController does an unwind segue to the TableViewController, of course before the post request completes. I am not sure where in the code I would take the response and call a function in the TableViewController that appends the new Entry object to the entry list.



I am not sure if I should pass the new Entry object from the addEntry() function to the TableViewController with onSuccess() or if the TableViewController can have the newEntry() resource and know when the post request completes. I am not sure if I am going about this in the right way either. Thanks in advance.










share|improve this question
















I am a Swift beginner so apologies. With Siesta, I want to make a post request in a ViewController and then have the Entry object the request returns added to the TableViewController. In my ViewController:



EntryAPI.sharedInstance.addEntry()


The API code:



 func addEntry()  -> Request {
return newEntry().request(.post, json:["foo": "bar"])
}

func newEntry() -> Resource {
return service
.resource("/entry")
}


After the post request the ViewController does an unwind segue to the TableViewController, of course before the post request completes. I am not sure where in the code I would take the response and call a function in the TableViewController that appends the new Entry object to the entry list.



I am not sure if I should pass the new Entry object from the addEntry() function to the TableViewController with onSuccess() or if the TableViewController can have the newEntry() resource and know when the post request completes. I am not sure if I am going about this in the right way either. Thanks in advance.







swift siesta-swift






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edited Nov 14 '18 at 0:42







Mickey Barcia

















asked Nov 14 '18 at 0:36









Mickey BarciaMickey Barcia

62




62













  • Add an observer for your request (bustoutsolutions.github.io/siesta/guide/observers) and when it completes update the data in your tableview.

    – Alex Bailey
    Nov 14 '18 at 2:21











  • Thanks. So to clarify, am I adding the TableViewController to be an observer or the ViewController? If the ViewController, how can I send the new Entry object to the TableViewController if the segue happens before it completes?

    – Mickey Barcia
    Nov 14 '18 at 2:33











  • observer to your post request in Siesta to some external API.

    – Alex Bailey
    Nov 14 '18 at 2:52



















  • Add an observer for your request (bustoutsolutions.github.io/siesta/guide/observers) and when it completes update the data in your tableview.

    – Alex Bailey
    Nov 14 '18 at 2:21











  • Thanks. So to clarify, am I adding the TableViewController to be an observer or the ViewController? If the ViewController, how can I send the new Entry object to the TableViewController if the segue happens before it completes?

    – Mickey Barcia
    Nov 14 '18 at 2:33











  • observer to your post request in Siesta to some external API.

    – Alex Bailey
    Nov 14 '18 at 2:52

















Add an observer for your request (bustoutsolutions.github.io/siesta/guide/observers) and when it completes update the data in your tableview.

– Alex Bailey
Nov 14 '18 at 2:21





Add an observer for your request (bustoutsolutions.github.io/siesta/guide/observers) and when it completes update the data in your tableview.

– Alex Bailey
Nov 14 '18 at 2:21













Thanks. So to clarify, am I adding the TableViewController to be an observer or the ViewController? If the ViewController, how can I send the new Entry object to the TableViewController if the segue happens before it completes?

– Mickey Barcia
Nov 14 '18 at 2:33





Thanks. So to clarify, am I adding the TableViewController to be an observer or the ViewController? If the ViewController, how can I send the new Entry object to the TableViewController if the segue happens before it completes?

– Mickey Barcia
Nov 14 '18 at 2:33













observer to your post request in Siesta to some external API.

– Alex Bailey
Nov 14 '18 at 2:52





observer to your post request in Siesta to some external API.

– Alex Bailey
Nov 14 '18 at 2:52












1 Answer
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oldest

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I am able to add the newEntry() resource to the TableViewController and change the API method:



func addEntry()  -> Request {
let resource = newEntry()
return resource.load(using: resource.request(.post, json:
["foo": "bar"]).onSuccess {_ in})
}


Now resourceChanged function will be called where I can handle the response object. Answer was in the documentation.






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    I am able to add the newEntry() resource to the TableViewController and change the API method:



    func addEntry()  -> Request {
    let resource = newEntry()
    return resource.load(using: resource.request(.post, json:
    ["foo": "bar"]).onSuccess {_ in})
    }


    Now resourceChanged function will be called where I can handle the response object. Answer was in the documentation.






    share|improve this answer




























      0














      I am able to add the newEntry() resource to the TableViewController and change the API method:



      func addEntry()  -> Request {
      let resource = newEntry()
      return resource.load(using: resource.request(.post, json:
      ["foo": "bar"]).onSuccess {_ in})
      }


      Now resourceChanged function will be called where I can handle the response object. Answer was in the documentation.






      share|improve this answer


























        0












        0








        0







        I am able to add the newEntry() resource to the TableViewController and change the API method:



        func addEntry()  -> Request {
        let resource = newEntry()
        return resource.load(using: resource.request(.post, json:
        ["foo": "bar"]).onSuccess {_ in})
        }


        Now resourceChanged function will be called where I can handle the response object. Answer was in the documentation.






        share|improve this answer













        I am able to add the newEntry() resource to the TableViewController and change the API method:



        func addEntry()  -> Request {
        let resource = newEntry()
        return resource.load(using: resource.request(.post, json:
        ["foo": "bar"]).onSuccess {_ in})
        }


        Now resourceChanged function will be called where I can handle the response object. Answer was in the documentation.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 14 '18 at 3:29









        Mickey BarciaMickey Barcia

        62




        62






























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