How to list duplicate values in a dictionary that represents flights?
I have a dictionary that had another dictionary and some lists inside that.
flightsD={"Delta":{1102:[["IND",1850],["MDW",1955]],
1096:[["PHX",900],["MDW",1255]],
1445:[["ATL",1135],["LAX",1810]],
1776:[["PHL",1350],["RAP",1610]],
1226:[["PHX",950],["MDW",1345]],
1885:[["ATL",1305],["LAX",2000]],
1009:[["MDW",1850],["IND",1955]],
9001:[["MDW",2145],["IND",2255]]},
"Southwestern":{1111:[["SAT",430],["MDW",825]],
2121:[["MDW",430],["SAT",825]],
4335:[["PHX",450],["MDW",745]],
1102:[["MDW",1100],["PHX",1450]]},
"American":{7765:[["IND",1850],["CHA",2105]],
2133:[["BNA",900],["IND",1115]],
3321:[["HOU",1335],["ATL",1615]],
2100:[["BNA",900],["IND",1115]],
4311:[["HOU",905],["ATL",1255]],
5577:[["ATL",1100],["HOU",1350]],
1102:[["BNA",1100],["HOU",1450]]} }
As you can see, Delta, Southwestern and American all have a flights 1102. I would like to list all duplicate flights as a list inside a dictionary.
Expected output:
{1102: ['American', 'Southwestern', 'Delta']}
I have tried to access these values by iterating through the dictionary like so:
for airline in flightsD:
for flights in flightsD[airline]:
I am thinking about making a list to store all of these values but I'm not entirely sure how to go about it
python list dictionary
add a comment |
I have a dictionary that had another dictionary and some lists inside that.
flightsD={"Delta":{1102:[["IND",1850],["MDW",1955]],
1096:[["PHX",900],["MDW",1255]],
1445:[["ATL",1135],["LAX",1810]],
1776:[["PHL",1350],["RAP",1610]],
1226:[["PHX",950],["MDW",1345]],
1885:[["ATL",1305],["LAX",2000]],
1009:[["MDW",1850],["IND",1955]],
9001:[["MDW",2145],["IND",2255]]},
"Southwestern":{1111:[["SAT",430],["MDW",825]],
2121:[["MDW",430],["SAT",825]],
4335:[["PHX",450],["MDW",745]],
1102:[["MDW",1100],["PHX",1450]]},
"American":{7765:[["IND",1850],["CHA",2105]],
2133:[["BNA",900],["IND",1115]],
3321:[["HOU",1335],["ATL",1615]],
2100:[["BNA",900],["IND",1115]],
4311:[["HOU",905],["ATL",1255]],
5577:[["ATL",1100],["HOU",1350]],
1102:[["BNA",1100],["HOU",1450]]} }
As you can see, Delta, Southwestern and American all have a flights 1102. I would like to list all duplicate flights as a list inside a dictionary.
Expected output:
{1102: ['American', 'Southwestern', 'Delta']}
I have tried to access these values by iterating through the dictionary like so:
for airline in flightsD:
for flights in flightsD[airline]:
I am thinking about making a list to store all of these values but I'm not entirely sure how to go about it
python list dictionary
add a comment |
I have a dictionary that had another dictionary and some lists inside that.
flightsD={"Delta":{1102:[["IND",1850],["MDW",1955]],
1096:[["PHX",900],["MDW",1255]],
1445:[["ATL",1135],["LAX",1810]],
1776:[["PHL",1350],["RAP",1610]],
1226:[["PHX",950],["MDW",1345]],
1885:[["ATL",1305],["LAX",2000]],
1009:[["MDW",1850],["IND",1955]],
9001:[["MDW",2145],["IND",2255]]},
"Southwestern":{1111:[["SAT",430],["MDW",825]],
2121:[["MDW",430],["SAT",825]],
4335:[["PHX",450],["MDW",745]],
1102:[["MDW",1100],["PHX",1450]]},
"American":{7765:[["IND",1850],["CHA",2105]],
2133:[["BNA",900],["IND",1115]],
3321:[["HOU",1335],["ATL",1615]],
2100:[["BNA",900],["IND",1115]],
4311:[["HOU",905],["ATL",1255]],
5577:[["ATL",1100],["HOU",1350]],
1102:[["BNA",1100],["HOU",1450]]} }
As you can see, Delta, Southwestern and American all have a flights 1102. I would like to list all duplicate flights as a list inside a dictionary.
Expected output:
{1102: ['American', 'Southwestern', 'Delta']}
I have tried to access these values by iterating through the dictionary like so:
for airline in flightsD:
for flights in flightsD[airline]:
I am thinking about making a list to store all of these values but I'm not entirely sure how to go about it
python list dictionary
I have a dictionary that had another dictionary and some lists inside that.
flightsD={"Delta":{1102:[["IND",1850],["MDW",1955]],
1096:[["PHX",900],["MDW",1255]],
1445:[["ATL",1135],["LAX",1810]],
1776:[["PHL",1350],["RAP",1610]],
1226:[["PHX",950],["MDW",1345]],
1885:[["ATL",1305],["LAX",2000]],
1009:[["MDW",1850],["IND",1955]],
9001:[["MDW",2145],["IND",2255]]},
"Southwestern":{1111:[["SAT",430],["MDW",825]],
2121:[["MDW",430],["SAT",825]],
4335:[["PHX",450],["MDW",745]],
1102:[["MDW",1100],["PHX",1450]]},
"American":{7765:[["IND",1850],["CHA",2105]],
2133:[["BNA",900],["IND",1115]],
3321:[["HOU",1335],["ATL",1615]],
2100:[["BNA",900],["IND",1115]],
4311:[["HOU",905],["ATL",1255]],
5577:[["ATL",1100],["HOU",1350]],
1102:[["BNA",1100],["HOU",1450]]} }
As you can see, Delta, Southwestern and American all have a flights 1102. I would like to list all duplicate flights as a list inside a dictionary.
Expected output:
{1102: ['American', 'Southwestern', 'Delta']}
I have tried to access these values by iterating through the dictionary like so:
for airline in flightsD:
for flights in flightsD[airline]:
I am thinking about making a list to store all of these values but I'm not entirely sure how to go about it
python list dictionary
python list dictionary
asked Nov 16 '18 at 21:22
Caleb CollierCaleb Collier
83
83
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
You can iterate over the dict items, use dict.setdefault to initialize the output dict with a list to append airlines to, and use a dict comprehension to output items with sublists with more than 1 item:
d = {}
for airline, flights in flightsD.items():
for flight in flights:
d.setdefault(flight, ).append(airline)
print({k: v for k, v in d.items() if len(v) > 1})
This outputs:
{1102: ['Delta', 'Southwestern', 'American']}
add a comment |
You can use defaultdict as follows:
from collections import defaultdict
airlines, schedules = flightsD.keys(), flightsD.values()
flight_nums = [s.keys() for s in schedules]
duplicates = defaultdict(list)
for i, item1 in enumerate(flight_nums):
for j, item2 in enumerate(flight_nums):
for k in item1:
if i != j and k in item2 and airlines[i] not in duplicates[k]:
duplicates[k].append(airlines[i])
print(duplicates)
>>> {1102: ['American', 'Southwestern', 'Delta']}
add a comment |
If you want a dictionary with just those values, you can use the code below (based on the code above):
list =
for flights in flightsD.values():
list.extend(flights.keys())
d = {}
for airline, flights in flightsD.items():
for flight in flights:
if list.count(flight) > 1:
d.setdefault(flight, ).append(airline)
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can iterate over the dict items, use dict.setdefault to initialize the output dict with a list to append airlines to, and use a dict comprehension to output items with sublists with more than 1 item:
d = {}
for airline, flights in flightsD.items():
for flight in flights:
d.setdefault(flight, ).append(airline)
print({k: v for k, v in d.items() if len(v) > 1})
This outputs:
{1102: ['Delta', 'Southwestern', 'American']}
add a comment |
You can iterate over the dict items, use dict.setdefault to initialize the output dict with a list to append airlines to, and use a dict comprehension to output items with sublists with more than 1 item:
d = {}
for airline, flights in flightsD.items():
for flight in flights:
d.setdefault(flight, ).append(airline)
print({k: v for k, v in d.items() if len(v) > 1})
This outputs:
{1102: ['Delta', 'Southwestern', 'American']}
add a comment |
You can iterate over the dict items, use dict.setdefault to initialize the output dict with a list to append airlines to, and use a dict comprehension to output items with sublists with more than 1 item:
d = {}
for airline, flights in flightsD.items():
for flight in flights:
d.setdefault(flight, ).append(airline)
print({k: v for k, v in d.items() if len(v) > 1})
This outputs:
{1102: ['Delta', 'Southwestern', 'American']}
You can iterate over the dict items, use dict.setdefault to initialize the output dict with a list to append airlines to, and use a dict comprehension to output items with sublists with more than 1 item:
d = {}
for airline, flights in flightsD.items():
for flight in flights:
d.setdefault(flight, ).append(airline)
print({k: v for k, v in d.items() if len(v) > 1})
This outputs:
{1102: ['Delta', 'Southwestern', 'American']}
edited Nov 16 '18 at 21:38
answered Nov 16 '18 at 21:30
blhsingblhsing
30.5k41336
30.5k41336
add a comment |
add a comment |
You can use defaultdict as follows:
from collections import defaultdict
airlines, schedules = flightsD.keys(), flightsD.values()
flight_nums = [s.keys() for s in schedules]
duplicates = defaultdict(list)
for i, item1 in enumerate(flight_nums):
for j, item2 in enumerate(flight_nums):
for k in item1:
if i != j and k in item2 and airlines[i] not in duplicates[k]:
duplicates[k].append(airlines[i])
print(duplicates)
>>> {1102: ['American', 'Southwestern', 'Delta']}
add a comment |
You can use defaultdict as follows:
from collections import defaultdict
airlines, schedules = flightsD.keys(), flightsD.values()
flight_nums = [s.keys() for s in schedules]
duplicates = defaultdict(list)
for i, item1 in enumerate(flight_nums):
for j, item2 in enumerate(flight_nums):
for k in item1:
if i != j and k in item2 and airlines[i] not in duplicates[k]:
duplicates[k].append(airlines[i])
print(duplicates)
>>> {1102: ['American', 'Southwestern', 'Delta']}
add a comment |
You can use defaultdict as follows:
from collections import defaultdict
airlines, schedules = flightsD.keys(), flightsD.values()
flight_nums = [s.keys() for s in schedules]
duplicates = defaultdict(list)
for i, item1 in enumerate(flight_nums):
for j, item2 in enumerate(flight_nums):
for k in item1:
if i != j and k in item2 and airlines[i] not in duplicates[k]:
duplicates[k].append(airlines[i])
print(duplicates)
>>> {1102: ['American', 'Southwestern', 'Delta']}
You can use defaultdict as follows:
from collections import defaultdict
airlines, schedules = flightsD.keys(), flightsD.values()
flight_nums = [s.keys() for s in schedules]
duplicates = defaultdict(list)
for i, item1 in enumerate(flight_nums):
for j, item2 in enumerate(flight_nums):
for k in item1:
if i != j and k in item2 and airlines[i] not in duplicates[k]:
duplicates[k].append(airlines[i])
print(duplicates)
>>> {1102: ['American', 'Southwestern', 'Delta']}
answered Nov 16 '18 at 21:52
berkelemberkelem
8682720
8682720
add a comment |
add a comment |
If you want a dictionary with just those values, you can use the code below (based on the code above):
list =
for flights in flightsD.values():
list.extend(flights.keys())
d = {}
for airline, flights in flightsD.items():
for flight in flights:
if list.count(flight) > 1:
d.setdefault(flight, ).append(airline)
add a comment |
If you want a dictionary with just those values, you can use the code below (based on the code above):
list =
for flights in flightsD.values():
list.extend(flights.keys())
d = {}
for airline, flights in flightsD.items():
for flight in flights:
if list.count(flight) > 1:
d.setdefault(flight, ).append(airline)
add a comment |
If you want a dictionary with just those values, you can use the code below (based on the code above):
list =
for flights in flightsD.values():
list.extend(flights.keys())
d = {}
for airline, flights in flightsD.items():
for flight in flights:
if list.count(flight) > 1:
d.setdefault(flight, ).append(airline)
If you want a dictionary with just those values, you can use the code below (based on the code above):
list =
for flights in flightsD.values():
list.extend(flights.keys())
d = {}
for airline, flights in flightsD.items():
for flight in flights:
if list.count(flight) > 1:
d.setdefault(flight, ).append(airline)
answered Nov 16 '18 at 21:50
Ellie HannaEllie Hanna
585
585
add a comment |
add a comment |
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