Image generation












0















I need to generate for each record image (combined from some images). I do it with canvas.



       html2canvas($("#target"), {
onrendered: function(canvas) {
var imgsrc = canvas.toDataURL("image/png");
$("#img-data").val(canvas.toDataURL("image/png"));
var extra_canvas = document.createElement("canvas");
extra_canvas.setAttribute("width",240);
extra_canvas.setAttribute("height",400);
var ctx = extra_canvas.getContext("2d");
ctx.drawImage(canvas,0,0,canvas.width,
canvas.height,0,0,240,400);
var dataURL = extra_canvas.toDataURL();


Something like this.
So in my action I can get content



$content = $this->renderPartial('renderingstest', ['model' => MyData::findOne($myData['data_id'])]);


but I will get the correct record after some time, so it's impossible to get data with using DOMDocument, or generating some html file for converting an image.



I need to find some way for getting generated image src...



Image generated by this code



  <?php for ( $i = 1; $i <= 6; $i++ ) { 
if ( $i == 1 ) { ?>
<div class="panel">
<?php } ?>
<div class="dd1<?= $i; ?> <?php echo $previewPanelSize ?>">
<?php

if (($model->{'tem_p' . $i . '_type'} == '2') and ($model->{'tem_p' . $i . '_content'} > 1500027946)) { // condition for projects that need the refnumber to display image, remove in case this changes

$im = Images::findOne(['ima_refnum' => $model->{'tem_p' . $i . '_content'}]);
if ($im) {
print '<center id="' . $im->ima_refnum . '">' . Html::img('data:' . $im->ima_type . ';base64,' . $im->ima_image, ) . '</center>';
}
} else {
print '<center>' . $model->{'tem_p' . $i . '_content'} . '</center>';
}
?>
</div>
<?php if ($i == 3 ) { ?>
</div>
<div class="panel">
<?php } ?>
<?php if ($i == 6 ) { ?>
</div>
<?php } ?>
<?php } ?>


Any good idea?










share|improve this question

























  • I use PHP GD to generate images

    – MadeInDreams
    Nov 16 '18 at 21:41











  • I cann't use imagecopymerge because I'm not sure about coordinates where the next image will be located

    – Lola_Padilya
    Nov 16 '18 at 21:50
















0















I need to generate for each record image (combined from some images). I do it with canvas.



       html2canvas($("#target"), {
onrendered: function(canvas) {
var imgsrc = canvas.toDataURL("image/png");
$("#img-data").val(canvas.toDataURL("image/png"));
var extra_canvas = document.createElement("canvas");
extra_canvas.setAttribute("width",240);
extra_canvas.setAttribute("height",400);
var ctx = extra_canvas.getContext("2d");
ctx.drawImage(canvas,0,0,canvas.width,
canvas.height,0,0,240,400);
var dataURL = extra_canvas.toDataURL();


Something like this.
So in my action I can get content



$content = $this->renderPartial('renderingstest', ['model' => MyData::findOne($myData['data_id'])]);


but I will get the correct record after some time, so it's impossible to get data with using DOMDocument, or generating some html file for converting an image.



I need to find some way for getting generated image src...



Image generated by this code



  <?php for ( $i = 1; $i <= 6; $i++ ) { 
if ( $i == 1 ) { ?>
<div class="panel">
<?php } ?>
<div class="dd1<?= $i; ?> <?php echo $previewPanelSize ?>">
<?php

if (($model->{'tem_p' . $i . '_type'} == '2') and ($model->{'tem_p' . $i . '_content'} > 1500027946)) { // condition for projects that need the refnumber to display image, remove in case this changes

$im = Images::findOne(['ima_refnum' => $model->{'tem_p' . $i . '_content'}]);
if ($im) {
print '<center id="' . $im->ima_refnum . '">' . Html::img('data:' . $im->ima_type . ';base64,' . $im->ima_image, ) . '</center>';
}
} else {
print '<center>' . $model->{'tem_p' . $i . '_content'} . '</center>';
}
?>
</div>
<?php if ($i == 3 ) { ?>
</div>
<div class="panel">
<?php } ?>
<?php if ($i == 6 ) { ?>
</div>
<?php } ?>
<?php } ?>


Any good idea?










share|improve this question

























  • I use PHP GD to generate images

    – MadeInDreams
    Nov 16 '18 at 21:41











  • I cann't use imagecopymerge because I'm not sure about coordinates where the next image will be located

    – Lola_Padilya
    Nov 16 '18 at 21:50














0












0








0








I need to generate for each record image (combined from some images). I do it with canvas.



       html2canvas($("#target"), {
onrendered: function(canvas) {
var imgsrc = canvas.toDataURL("image/png");
$("#img-data").val(canvas.toDataURL("image/png"));
var extra_canvas = document.createElement("canvas");
extra_canvas.setAttribute("width",240);
extra_canvas.setAttribute("height",400);
var ctx = extra_canvas.getContext("2d");
ctx.drawImage(canvas,0,0,canvas.width,
canvas.height,0,0,240,400);
var dataURL = extra_canvas.toDataURL();


Something like this.
So in my action I can get content



$content = $this->renderPartial('renderingstest', ['model' => MyData::findOne($myData['data_id'])]);


but I will get the correct record after some time, so it's impossible to get data with using DOMDocument, or generating some html file for converting an image.



I need to find some way for getting generated image src...



Image generated by this code



  <?php for ( $i = 1; $i <= 6; $i++ ) { 
if ( $i == 1 ) { ?>
<div class="panel">
<?php } ?>
<div class="dd1<?= $i; ?> <?php echo $previewPanelSize ?>">
<?php

if (($model->{'tem_p' . $i . '_type'} == '2') and ($model->{'tem_p' . $i . '_content'} > 1500027946)) { // condition for projects that need the refnumber to display image, remove in case this changes

$im = Images::findOne(['ima_refnum' => $model->{'tem_p' . $i . '_content'}]);
if ($im) {
print '<center id="' . $im->ima_refnum . '">' . Html::img('data:' . $im->ima_type . ';base64,' . $im->ima_image, ) . '</center>';
}
} else {
print '<center>' . $model->{'tem_p' . $i . '_content'} . '</center>';
}
?>
</div>
<?php if ($i == 3 ) { ?>
</div>
<div class="panel">
<?php } ?>
<?php if ($i == 6 ) { ?>
</div>
<?php } ?>
<?php } ?>


Any good idea?










share|improve this question
















I need to generate for each record image (combined from some images). I do it with canvas.



       html2canvas($("#target"), {
onrendered: function(canvas) {
var imgsrc = canvas.toDataURL("image/png");
$("#img-data").val(canvas.toDataURL("image/png"));
var extra_canvas = document.createElement("canvas");
extra_canvas.setAttribute("width",240);
extra_canvas.setAttribute("height",400);
var ctx = extra_canvas.getContext("2d");
ctx.drawImage(canvas,0,0,canvas.width,
canvas.height,0,0,240,400);
var dataURL = extra_canvas.toDataURL();


Something like this.
So in my action I can get content



$content = $this->renderPartial('renderingstest', ['model' => MyData::findOne($myData['data_id'])]);


but I will get the correct record after some time, so it's impossible to get data with using DOMDocument, or generating some html file for converting an image.



I need to find some way for getting generated image src...



Image generated by this code



  <?php for ( $i = 1; $i <= 6; $i++ ) { 
if ( $i == 1 ) { ?>
<div class="panel">
<?php } ?>
<div class="dd1<?= $i; ?> <?php echo $previewPanelSize ?>">
<?php

if (($model->{'tem_p' . $i . '_type'} == '2') and ($model->{'tem_p' . $i . '_content'} > 1500027946)) { // condition for projects that need the refnumber to display image, remove in case this changes

$im = Images::findOne(['ima_refnum' => $model->{'tem_p' . $i . '_content'}]);
if ($im) {
print '<center id="' . $im->ima_refnum . '">' . Html::img('data:' . $im->ima_type . ';base64,' . $im->ima_image, ) . '</center>';
}
} else {
print '<center>' . $model->{'tem_p' . $i . '_content'} . '</center>';
}
?>
</div>
<?php if ($i == 3 ) { ?>
</div>
<div class="panel">
<?php } ?>
<?php if ($i == 6 ) { ?>
</div>
<?php } ?>
<?php } ?>


Any good idea?







php jquery yii2 render image-generation






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 16 '18 at 21:49







Lola_Padilya

















asked Nov 16 '18 at 21:24









Lola_PadilyaLola_Padilya

326




326













  • I use PHP GD to generate images

    – MadeInDreams
    Nov 16 '18 at 21:41











  • I cann't use imagecopymerge because I'm not sure about coordinates where the next image will be located

    – Lola_Padilya
    Nov 16 '18 at 21:50



















  • I use PHP GD to generate images

    – MadeInDreams
    Nov 16 '18 at 21:41











  • I cann't use imagecopymerge because I'm not sure about coordinates where the next image will be located

    – Lola_Padilya
    Nov 16 '18 at 21:50

















I use PHP GD to generate images

– MadeInDreams
Nov 16 '18 at 21:41





I use PHP GD to generate images

– MadeInDreams
Nov 16 '18 at 21:41













I cann't use imagecopymerge because I'm not sure about coordinates where the next image will be located

– Lola_Padilya
Nov 16 '18 at 21:50





I cann't use imagecopymerge because I'm not sure about coordinates where the next image will be located

– Lola_Padilya
Nov 16 '18 at 21:50












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