Accessing certain elements of tuples
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I have to solve a problem for university studies. So what I want basically is that I want to access certain elements two 2-tuples. I already defined a function:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
as you can see the function takes two 2-tuples containing integers and returns a integer.
And now I have to add the first elements of both tuples and 2nd of both. And I don't now how to access these values which were put in by a user before.
Thank you for your help.
haskell tuples element
asked Nov 7 at 16:58
Mathmeeeeen
111
add a comment |
up vote
0
down vote
favorite
I have to solve a problem for university studies. So what I want basically is that I want to access certain elements two 2-tuples. I already defined a function:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
as you can see the function takes two 2-tuples containing integers and returns a integer.
And now I have to add the first elements of both tuples and 2nd of both. And I don't now how to access these values which were put in by a user before.
Thank you for your help.
haskell tuples element
asked Nov 7 at 16:58
Mathmeeeeen
111
if you're adding the first and second elements you're probably doing the computations wrong.
– karakfa
Nov 7 at 17:24
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have to solve a problem for university studies. So what I want basically is that I want to access certain elements two 2-tuples. I already defined a function:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
as you can see the function takes two 2-tuples containing integers and returns a integer.
And now I have to add the first elements of both tuples and 2nd of both. And I don't now how to access these values which were put in by a user before.
Thank you for your help.
haskell tuples element
asked Nov 7 at 16:58
Mathmeeeeen
111
I have to solve a problem for university studies. So what I want basically is that I want to access certain elements two 2-tuples. I already defined a function:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
as you can see the function takes two 2-tuples containing integers and returns a integer.
And now I have to add the first elements of both tuples and 2nd of both. And I don't now how to access these values which were put in by a user before.
Thank you for your help.
haskell tuples element
haskell tuples element
asked Nov 7 at 16:58
Mathmeeeeen
111
asked Nov 7 at 16:58
Mathmeeeeen
111
asked Nov 7 at 16:58
Mathmeeeeen
111
asked Nov 7 at 16:58
Mathmeeeeen
111
asked Nov 7 at 16:58
Mathmeeeeen
111
111
if you're adding the first and second elements you're probably doing the computations wrong.
– karakfa
Nov 7 at 17:24
add a comment |
if you're adding the first and second elements you're probably doing the computations wrong.
– karakfa
Nov 7 at 17:24
if you're adding the first and second elements you're probably doing the computations wrong.
– karakfa
Nov 7 at 17:24
if you're adding the first and second elements you're probably doing the computations wrong.
– karakfa
Nov 7 at 17:24
add a comment |
2 Answers
2
active
oldest
votes
up vote
4
down vote
you can use the functions fst + snd like this:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
taxiDistance x y = fst x + fst y
or alternatively you can deconstruct the tuples in the declaration like:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
taxiDistance (a,b) (c,d) = a + b + c + d
answered Nov 7 at 17:07
cmdv
8841919
damn I ruthless just came out with the answer!! sorry :S
– cmdv
Nov 7 at 17:20
I think this is fine, I don't see how it's pedagogically helpful not to reveal the syntax of what they're trying to do. There's nothing to "think through" here.
– luqui
Nov 7 at 19:58
This is fine as it is. You didn't solve the full task of the OP: the OP also needs to compute the taxi distance, and that will involve a (slightly) more complex formula. Revealing "how to access the pair components" is perfectly OK, since you can find it on books anyway. What is usually frowned upon (IMO) is to answer a much more broad question dumping the full solution, without a careful explanation. Doing that would only allow the OP to copy&paste their homework, with no chance of actually learning anything. But you didn't do that :)
– chi
Nov 7 at 21:52
add a comment |
up vote
1
down vote
Since this is university studies I won't give the entire answer right away but will point you to read up on pattern matching and tuple constructor.
answered Nov 7 at 17:06
tejasbubane
51637
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
you can use the functions fst + snd like this:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
taxiDistance x y = fst x + fst y
or alternatively you can deconstruct the tuples in the declaration like:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
taxiDistance (a,b) (c,d) = a + b + c + d
answered Nov 7 at 17:07
cmdv
8841919
damn I ruthless just came out with the answer!! sorry :S
– cmdv
Nov 7 at 17:20
I think this is fine, I don't see how it's pedagogically helpful not to reveal the syntax of what they're trying to do. There's nothing to "think through" here.
– luqui
Nov 7 at 19:58
This is fine as it is. You didn't solve the full task of the OP: the OP also needs to compute the taxi distance, and that will involve a (slightly) more complex formula. Revealing "how to access the pair components" is perfectly OK, since you can find it on books anyway. What is usually frowned upon (IMO) is to answer a much more broad question dumping the full solution, without a careful explanation. Doing that would only allow the OP to copy&paste their homework, with no chance of actually learning anything. But you didn't do that :)
– chi
Nov 7 at 21:52
add a comment |
up vote
4
down vote
you can use the functions fst + snd like this:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
taxiDistance x y = fst x + fst y
or alternatively you can deconstruct the tuples in the declaration like:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
taxiDistance (a,b) (c,d) = a + b + c + d
answered Nov 7 at 17:07
cmdv
8841919
damn I ruthless just came out with the answer!! sorry :S
– cmdv
Nov 7 at 17:20
I think this is fine, I don't see how it's pedagogically helpful not to reveal the syntax of what they're trying to do. There's nothing to "think through" here.
– luqui
Nov 7 at 19:58
This is fine as it is. You didn't solve the full task of the OP: the OP also needs to compute the taxi distance, and that will involve a (slightly) more complex formula. Revealing "how to access the pair components" is perfectly OK, since you can find it on books anyway. What is usually frowned upon (IMO) is to answer a much more broad question dumping the full solution, without a careful explanation. Doing that would only allow the OP to copy&paste their homework, with no chance of actually learning anything. But you didn't do that :)
– chi
Nov 7 at 21:52
add a comment |
up vote
4
down vote
up vote
4
down vote
you can use the functions fst + snd like this:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
taxiDistance x y = fst x + fst y
or alternatively you can deconstruct the tuples in the declaration like:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
taxiDistance (a,b) (c,d) = a + b + c + d
answered Nov 7 at 17:07
cmdv
8841919
you can use the functions fst + snd like this:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
taxiDistance x y = fst x + fst y
or alternatively you can deconstruct the tuples in the declaration like:
taxiDistance :: (Integer, Integer) -> (Integer, Integer) -> Integer
taxiDistance (a,b) (c,d) = a + b + c + d
answered Nov 7 at 17:07
cmdv
8841919
answered Nov 7 at 17:07
cmdv
8841919
answered Nov 7 at 17:07
cmdv
8841919
answered Nov 7 at 17:07
cmdv
8841919
8841919
damn I ruthless just came out with the answer!! sorry :S
– cmdv
Nov 7 at 17:20
I think this is fine, I don't see how it's pedagogically helpful not to reveal the syntax of what they're trying to do. There's nothing to "think through" here.
– luqui
Nov 7 at 19:58
This is fine as it is. You didn't solve the full task of the OP: the OP also needs to compute the taxi distance, and that will involve a (slightly) more complex formula. Revealing "how to access the pair components" is perfectly OK, since you can find it on books anyway. What is usually frowned upon (IMO) is to answer a much more broad question dumping the full solution, without a careful explanation. Doing that would only allow the OP to copy&paste their homework, with no chance of actually learning anything. But you didn't do that :)
– chi
Nov 7 at 21:52
add a comment |
damn I ruthless just came out with the answer!! sorry :S
– cmdv
Nov 7 at 17:20
I think this is fine, I don't see how it's pedagogically helpful not to reveal the syntax of what they're trying to do. There's nothing to "think through" here.
– luqui
Nov 7 at 19:58
This is fine as it is. You didn't solve the full task of the OP: the OP also needs to compute the taxi distance, and that will involve a (slightly) more complex formula. Revealing "how to access the pair components" is perfectly OK, since you can find it on books anyway. What is usually frowned upon (IMO) is to answer a much more broad question dumping the full solution, without a careful explanation. Doing that would only allow the OP to copy&paste their homework, with no chance of actually learning anything. But you didn't do that :)
– chi
Nov 7 at 21:52
damn I ruthless just came out with the answer!! sorry :S
– cmdv
Nov 7 at 17:20
damn I ruthless just came out with the answer!! sorry :S
– cmdv
Nov 7 at 17:20
I think this is fine, I don't see how it's pedagogically helpful not to reveal the syntax of what they're trying to do. There's nothing to "think through" here.
– luqui
Nov 7 at 19:58
I think this is fine, I don't see how it's pedagogically helpful not to reveal the syntax of what they're trying to do. There's nothing to "think through" here.
– luqui
Nov 7 at 19:58
This is fine as it is. You didn't solve the full task of the OP: the OP also needs to compute the taxi distance, and that will involve a (slightly) more complex formula. Revealing "how to access the pair components" is perfectly OK, since you can find it on books anyway. What is usually frowned upon (IMO) is to answer a much more broad question dumping the full solution, without a careful explanation. Doing that would only allow the OP to copy&paste their homework, with no chance of actually learning anything. But you didn't do that :)
– chi
Nov 7 at 21:52
This is fine as it is. You didn't solve the full task of the OP: the OP also needs to compute the taxi distance, and that will involve a (slightly) more complex formula. Revealing "how to access the pair components" is perfectly OK, since you can find it on books anyway. What is usually frowned upon (IMO) is to answer a much more broad question dumping the full solution, without a careful explanation. Doing that would only allow the OP to copy&paste their homework, with no chance of actually learning anything. But you didn't do that :)
– chi
Nov 7 at 21:52
add a comment |
up vote
1
down vote
Since this is university studies I won't give the entire answer right away but will point you to read up on pattern matching and tuple constructor.
answered Nov 7 at 17:06
tejasbubane
51637
add a comment |
up vote
1
down vote
Since this is university studies I won't give the entire answer right away but will point you to read up on pattern matching and tuple constructor.
answered Nov 7 at 17:06
tejasbubane
51637
add a comment |
up vote
1
down vote
up vote
1
down vote
Since this is university studies I won't give the entire answer right away but will point you to read up on pattern matching and tuple constructor.
answered Nov 7 at 17:06
tejasbubane
51637
Since this is university studies I won't give the entire answer right away but will point you to read up on pattern matching and tuple constructor.
answered Nov 7 at 17:06
tejasbubane
51637
answered Nov 7 at 17:06
tejasbubane
51637
answered Nov 7 at 17:06
tejasbubane
51637
answered Nov 7 at 17:06
tejasbubane
51637
51637
add a comment |
add a comment |
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if you're adding the first and second elements you're probably doing the computations wrong.
– karakfa
Nov 7 at 17:24