Python crypt.crypt not using sha512 despite $6$












0















For some reason using the crypt module uses the 13 char hash rather than sha-512 no matter what I try. I have seen countless questions about problems, but none of them match mine. Is there simply no way to change the crypt method?



>>> import crypt
>>> print(crypt.crypt("password", salt="$6$saltsalt"))
$6FMi11BJFsAc
>>> print(crypt.crypt("password", crypt.METHOD_SHA512))
$6FMi11BJFsAc
>>>


Not sure exactly what is going on. If this is a case-specific thing, are there alternatives to crypt that have the same crypt(3) functionality?



Thanks in advance!










share|improve this question























  • What version of Python are you using? You need at least Python 3.3 to get an implementation that understands the $6$... format to select different hashing algorithms.

    – ottomeister
    Sep 30 '18 at 1:31











  • I am using python 3.6.5 on mac.

    – UnsignedByte
    Sep 30 '18 at 3:29
















0















For some reason using the crypt module uses the 13 char hash rather than sha-512 no matter what I try. I have seen countless questions about problems, but none of them match mine. Is there simply no way to change the crypt method?



>>> import crypt
>>> print(crypt.crypt("password", salt="$6$saltsalt"))
$6FMi11BJFsAc
>>> print(crypt.crypt("password", crypt.METHOD_SHA512))
$6FMi11BJFsAc
>>>


Not sure exactly what is going on. If this is a case-specific thing, are there alternatives to crypt that have the same crypt(3) functionality?



Thanks in advance!










share|improve this question























  • What version of Python are you using? You need at least Python 3.3 to get an implementation that understands the $6$... format to select different hashing algorithms.

    – ottomeister
    Sep 30 '18 at 1:31











  • I am using python 3.6.5 on mac.

    – UnsignedByte
    Sep 30 '18 at 3:29














0












0








0








For some reason using the crypt module uses the 13 char hash rather than sha-512 no matter what I try. I have seen countless questions about problems, but none of them match mine. Is there simply no way to change the crypt method?



>>> import crypt
>>> print(crypt.crypt("password", salt="$6$saltsalt"))
$6FMi11BJFsAc
>>> print(crypt.crypt("password", crypt.METHOD_SHA512))
$6FMi11BJFsAc
>>>


Not sure exactly what is going on. If this is a case-specific thing, are there alternatives to crypt that have the same crypt(3) functionality?



Thanks in advance!










share|improve this question














For some reason using the crypt module uses the 13 char hash rather than sha-512 no matter what I try. I have seen countless questions about problems, but none of them match mine. Is there simply no way to change the crypt method?



>>> import crypt
>>> print(crypt.crypt("password", salt="$6$saltsalt"))
$6FMi11BJFsAc
>>> print(crypt.crypt("password", crypt.METHOD_SHA512))
$6FMi11BJFsAc
>>>


Not sure exactly what is going on. If this is a case-specific thing, are there alternatives to crypt that have the same crypt(3) functionality?



Thanks in advance!







python python-3.x crypt sha512






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share|improve this question










asked Sep 29 '18 at 3:07









UnsignedByteUnsignedByte

538421




538421













  • What version of Python are you using? You need at least Python 3.3 to get an implementation that understands the $6$... format to select different hashing algorithms.

    – ottomeister
    Sep 30 '18 at 1:31











  • I am using python 3.6.5 on mac.

    – UnsignedByte
    Sep 30 '18 at 3:29



















  • What version of Python are you using? You need at least Python 3.3 to get an implementation that understands the $6$... format to select different hashing algorithms.

    – ottomeister
    Sep 30 '18 at 1:31











  • I am using python 3.6.5 on mac.

    – UnsignedByte
    Sep 30 '18 at 3:29

















What version of Python are you using? You need at least Python 3.3 to get an implementation that understands the $6$... format to select different hashing algorithms.

– ottomeister
Sep 30 '18 at 1:31





What version of Python are you using? You need at least Python 3.3 to get an implementation that understands the $6$... format to select different hashing algorithms.

– ottomeister
Sep 30 '18 at 1:31













I am using python 3.6.5 on mac.

– UnsignedByte
Sep 30 '18 at 3:29





I am using python 3.6.5 on mac.

– UnsignedByte
Sep 30 '18 at 3:29












1 Answer
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This is, unfortunately, an issue with the crypt(3) implementation on Macs. There is a cross-platform crypt library, passlib, but it doesn't seem to have received any updates in over a year; still, it's one Ansible recommends in it's FAQ, for example.






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    1 Answer
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    active

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    active

    oldest

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    This is, unfortunately, an issue with the crypt(3) implementation on Macs. There is a cross-platform crypt library, passlib, but it doesn't seem to have received any updates in over a year; still, it's one Ansible recommends in it's FAQ, for example.






    share|improve this answer




























      0














      This is, unfortunately, an issue with the crypt(3) implementation on Macs. There is a cross-platform crypt library, passlib, but it doesn't seem to have received any updates in over a year; still, it's one Ansible recommends in it's FAQ, for example.






      share|improve this answer


























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        0







        This is, unfortunately, an issue with the crypt(3) implementation on Macs. There is a cross-platform crypt library, passlib, but it doesn't seem to have received any updates in over a year; still, it's one Ansible recommends in it's FAQ, for example.






        share|improve this answer













        This is, unfortunately, an issue with the crypt(3) implementation on Macs. There is a cross-platform crypt library, passlib, but it doesn't seem to have received any updates in over a year; still, it's one Ansible recommends in it's FAQ, for example.







        share|improve this answer












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        share|improve this answer










        answered Nov 19 '18 at 17:07









        ModZeroModZero

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