SolverStudio how to reference 1 column in a 2D list in a for loop(PuLP)












1















I have 2 data sets x1 and x2. I want to be able to get a total sum of all the products of x1 and x2 only in the rows where the From column has Auckland in it.
see here



The final answer should be (5*1) + (2*1) + (3*1) + (4*1) or 14. The PuLP code that I wrote to do this is given below



# Import PuLP modeller functions
from pulp import *

varFinal = sum([x1[a] * x2[a] for a in Arcs if a == Nodes[0]])

print Nodes[0]
print Arcs[0]

Final = varFinal


The output that gets printed to the console is




Auckland

('Auckland', 'Albany')




I realise that my final value is zero because Arcs[some number] does not equal Nodes[some number]. Is there anyway to change the code so my final value is 14?



Any help is appreciated.










share|improve this question





























    1















    I have 2 data sets x1 and x2. I want to be able to get a total sum of all the products of x1 and x2 only in the rows where the From column has Auckland in it.
    see here



    The final answer should be (5*1) + (2*1) + (3*1) + (4*1) or 14. The PuLP code that I wrote to do this is given below



    # Import PuLP modeller functions
    from pulp import *

    varFinal = sum([x1[a] * x2[a] for a in Arcs if a == Nodes[0]])

    print Nodes[0]
    print Arcs[0]

    Final = varFinal


    The output that gets printed to the console is




    Auckland

    ('Auckland', 'Albany')




    I realise that my final value is zero because Arcs[some number] does not equal Nodes[some number]. Is there anyway to change the code so my final value is 14?



    Any help is appreciated.










    share|improve this question



























      1












      1








      1








      I have 2 data sets x1 and x2. I want to be able to get a total sum of all the products of x1 and x2 only in the rows where the From column has Auckland in it.
      see here



      The final answer should be (5*1) + (2*1) + (3*1) + (4*1) or 14. The PuLP code that I wrote to do this is given below



      # Import PuLP modeller functions
      from pulp import *

      varFinal = sum([x1[a] * x2[a] for a in Arcs if a == Nodes[0]])

      print Nodes[0]
      print Arcs[0]

      Final = varFinal


      The output that gets printed to the console is




      Auckland

      ('Auckland', 'Albany')




      I realise that my final value is zero because Arcs[some number] does not equal Nodes[some number]. Is there anyway to change the code so my final value is 14?



      Any help is appreciated.










      share|improve this question
















      I have 2 data sets x1 and x2. I want to be able to get a total sum of all the products of x1 and x2 only in the rows where the From column has Auckland in it.
      see here



      The final answer should be (5*1) + (2*1) + (3*1) + (4*1) or 14. The PuLP code that I wrote to do this is given below



      # Import PuLP modeller functions
      from pulp import *

      varFinal = sum([x1[a] * x2[a] for a in Arcs if a == Nodes[0]])

      print Nodes[0]
      print Arcs[0]

      Final = varFinal


      The output that gets printed to the console is




      Auckland

      ('Auckland', 'Albany')




      I realise that my final value is zero because Arcs[some number] does not equal Nodes[some number]. Is there anyway to change the code so my final value is 14?



      Any help is appreciated.







      excel solver pulp






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 20 '18 at 1:30







      Filip Jovanovic

















      asked Nov 20 '18 at 1:17









      Filip JovanovicFilip Jovanovic

      84




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          1 Answer
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          0














          Welcome to stack overflow! Cause you've only posted part of your code, I have to guess at what data-types you're using. From the output, I'm guessing your Nodes are strings, and your Arcs are tuples of strings.



          Your attempt is very close, you want the from column to have Auckland in it. You can index into a tuple the same way you would into an array, so you want to do: a[0] == Nodes[0].



          Below is a self-contained example with the first bit of your data in which outputs the following (note that I've changed to python 3.x print statements (with parentheses)):



          Output:



          Auckland
          ('Auckland', 'Albany')
          14


          Code:



          # Import PuLP modeller functions
          from pulp import *

          # Data
          Nodes = ['Auckland',
          'Wellington',
          'Hamilton',
          'Kansas City',
          'Christchuch',
          'Albany',
          'Whangarei',
          'Rotorua',
          'New Plymouth']

          Arcs = [('Auckland','Albany'),
          ('Auckland','Hamilton'),
          ('Auckland','Kansas City'),
          ('Auckland','Christchuch'),
          ('Wellington','Hamilton'),
          ('Hamilton','Albany'),
          ('Kansas City','Whangarei'),
          ('Christchuch','Rotorua')]

          x1_vals = [1, 2, 3, 4, 5, 9, 11, 13]
          x2_vals = [5, 1, 1, 1, 1, 1, 1, 1]

          x1 = dict((Arcs[i], x1_vals[i]) for i in range(len(Arcs)))
          x2 = dict((Arcs[i], x2_vals[i]) for i in range(len(Arcs)))

          varFinal = sum([x1[a] * x2[a] for a in Arcs if a[0] == Nodes[0]])

          print(Nodes[0])
          print(Arcs[0])
          print(varFinal)


          For future reference, answers are most likely to be forthcoming if you include code which others can try to run (without external data dependencies), that way people can try to run it, fix it, and re-post it.






          share|improve this answer
























          • Hi kabdulla, thanks a lot for your help. I was wondering if x1 and x2 was to now have an index range equal to Arcs set by the Data Items Editor, How would you alter the above code to make it work? See below i.imgur.com/3pRHm4X.png i.imgur.com/6imfPDm.png

            – Filip Jovanovic
            Nov 20 '18 at 23:11













          • I've never used solver studio and don't know what data items editor is. Also those images are very pixelated. Perhaps you could edit your question with an embedded image and someone might be able to help.

            – kabdulla
            Nov 21 '18 at 8:09











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          1 Answer
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          1 Answer
          1






          active

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          active

          oldest

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          active

          oldest

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          0














          Welcome to stack overflow! Cause you've only posted part of your code, I have to guess at what data-types you're using. From the output, I'm guessing your Nodes are strings, and your Arcs are tuples of strings.



          Your attempt is very close, you want the from column to have Auckland in it. You can index into a tuple the same way you would into an array, so you want to do: a[0] == Nodes[0].



          Below is a self-contained example with the first bit of your data in which outputs the following (note that I've changed to python 3.x print statements (with parentheses)):



          Output:



          Auckland
          ('Auckland', 'Albany')
          14


          Code:



          # Import PuLP modeller functions
          from pulp import *

          # Data
          Nodes = ['Auckland',
          'Wellington',
          'Hamilton',
          'Kansas City',
          'Christchuch',
          'Albany',
          'Whangarei',
          'Rotorua',
          'New Plymouth']

          Arcs = [('Auckland','Albany'),
          ('Auckland','Hamilton'),
          ('Auckland','Kansas City'),
          ('Auckland','Christchuch'),
          ('Wellington','Hamilton'),
          ('Hamilton','Albany'),
          ('Kansas City','Whangarei'),
          ('Christchuch','Rotorua')]

          x1_vals = [1, 2, 3, 4, 5, 9, 11, 13]
          x2_vals = [5, 1, 1, 1, 1, 1, 1, 1]

          x1 = dict((Arcs[i], x1_vals[i]) for i in range(len(Arcs)))
          x2 = dict((Arcs[i], x2_vals[i]) for i in range(len(Arcs)))

          varFinal = sum([x1[a] * x2[a] for a in Arcs if a[0] == Nodes[0]])

          print(Nodes[0])
          print(Arcs[0])
          print(varFinal)


          For future reference, answers are most likely to be forthcoming if you include code which others can try to run (without external data dependencies), that way people can try to run it, fix it, and re-post it.






          share|improve this answer
























          • Hi kabdulla, thanks a lot for your help. I was wondering if x1 and x2 was to now have an index range equal to Arcs set by the Data Items Editor, How would you alter the above code to make it work? See below i.imgur.com/3pRHm4X.png i.imgur.com/6imfPDm.png

            – Filip Jovanovic
            Nov 20 '18 at 23:11













          • I've never used solver studio and don't know what data items editor is. Also those images are very pixelated. Perhaps you could edit your question with an embedded image and someone might be able to help.

            – kabdulla
            Nov 21 '18 at 8:09
















          0














          Welcome to stack overflow! Cause you've only posted part of your code, I have to guess at what data-types you're using. From the output, I'm guessing your Nodes are strings, and your Arcs are tuples of strings.



          Your attempt is very close, you want the from column to have Auckland in it. You can index into a tuple the same way you would into an array, so you want to do: a[0] == Nodes[0].



          Below is a self-contained example with the first bit of your data in which outputs the following (note that I've changed to python 3.x print statements (with parentheses)):



          Output:



          Auckland
          ('Auckland', 'Albany')
          14


          Code:



          # Import PuLP modeller functions
          from pulp import *

          # Data
          Nodes = ['Auckland',
          'Wellington',
          'Hamilton',
          'Kansas City',
          'Christchuch',
          'Albany',
          'Whangarei',
          'Rotorua',
          'New Plymouth']

          Arcs = [('Auckland','Albany'),
          ('Auckland','Hamilton'),
          ('Auckland','Kansas City'),
          ('Auckland','Christchuch'),
          ('Wellington','Hamilton'),
          ('Hamilton','Albany'),
          ('Kansas City','Whangarei'),
          ('Christchuch','Rotorua')]

          x1_vals = [1, 2, 3, 4, 5, 9, 11, 13]
          x2_vals = [5, 1, 1, 1, 1, 1, 1, 1]

          x1 = dict((Arcs[i], x1_vals[i]) for i in range(len(Arcs)))
          x2 = dict((Arcs[i], x2_vals[i]) for i in range(len(Arcs)))

          varFinal = sum([x1[a] * x2[a] for a in Arcs if a[0] == Nodes[0]])

          print(Nodes[0])
          print(Arcs[0])
          print(varFinal)


          For future reference, answers are most likely to be forthcoming if you include code which others can try to run (without external data dependencies), that way people can try to run it, fix it, and re-post it.






          share|improve this answer
























          • Hi kabdulla, thanks a lot for your help. I was wondering if x1 and x2 was to now have an index range equal to Arcs set by the Data Items Editor, How would you alter the above code to make it work? See below i.imgur.com/3pRHm4X.png i.imgur.com/6imfPDm.png

            – Filip Jovanovic
            Nov 20 '18 at 23:11













          • I've never used solver studio and don't know what data items editor is. Also those images are very pixelated. Perhaps you could edit your question with an embedded image and someone might be able to help.

            – kabdulla
            Nov 21 '18 at 8:09














          0












          0








          0







          Welcome to stack overflow! Cause you've only posted part of your code, I have to guess at what data-types you're using. From the output, I'm guessing your Nodes are strings, and your Arcs are tuples of strings.



          Your attempt is very close, you want the from column to have Auckland in it. You can index into a tuple the same way you would into an array, so you want to do: a[0] == Nodes[0].



          Below is a self-contained example with the first bit of your data in which outputs the following (note that I've changed to python 3.x print statements (with parentheses)):



          Output:



          Auckland
          ('Auckland', 'Albany')
          14


          Code:



          # Import PuLP modeller functions
          from pulp import *

          # Data
          Nodes = ['Auckland',
          'Wellington',
          'Hamilton',
          'Kansas City',
          'Christchuch',
          'Albany',
          'Whangarei',
          'Rotorua',
          'New Plymouth']

          Arcs = [('Auckland','Albany'),
          ('Auckland','Hamilton'),
          ('Auckland','Kansas City'),
          ('Auckland','Christchuch'),
          ('Wellington','Hamilton'),
          ('Hamilton','Albany'),
          ('Kansas City','Whangarei'),
          ('Christchuch','Rotorua')]

          x1_vals = [1, 2, 3, 4, 5, 9, 11, 13]
          x2_vals = [5, 1, 1, 1, 1, 1, 1, 1]

          x1 = dict((Arcs[i], x1_vals[i]) for i in range(len(Arcs)))
          x2 = dict((Arcs[i], x2_vals[i]) for i in range(len(Arcs)))

          varFinal = sum([x1[a] * x2[a] for a in Arcs if a[0] == Nodes[0]])

          print(Nodes[0])
          print(Arcs[0])
          print(varFinal)


          For future reference, answers are most likely to be forthcoming if you include code which others can try to run (without external data dependencies), that way people can try to run it, fix it, and re-post it.






          share|improve this answer













          Welcome to stack overflow! Cause you've only posted part of your code, I have to guess at what data-types you're using. From the output, I'm guessing your Nodes are strings, and your Arcs are tuples of strings.



          Your attempt is very close, you want the from column to have Auckland in it. You can index into a tuple the same way you would into an array, so you want to do: a[0] == Nodes[0].



          Below is a self-contained example with the first bit of your data in which outputs the following (note that I've changed to python 3.x print statements (with parentheses)):



          Output:



          Auckland
          ('Auckland', 'Albany')
          14


          Code:



          # Import PuLP modeller functions
          from pulp import *

          # Data
          Nodes = ['Auckland',
          'Wellington',
          'Hamilton',
          'Kansas City',
          'Christchuch',
          'Albany',
          'Whangarei',
          'Rotorua',
          'New Plymouth']

          Arcs = [('Auckland','Albany'),
          ('Auckland','Hamilton'),
          ('Auckland','Kansas City'),
          ('Auckland','Christchuch'),
          ('Wellington','Hamilton'),
          ('Hamilton','Albany'),
          ('Kansas City','Whangarei'),
          ('Christchuch','Rotorua')]

          x1_vals = [1, 2, 3, 4, 5, 9, 11, 13]
          x2_vals = [5, 1, 1, 1, 1, 1, 1, 1]

          x1 = dict((Arcs[i], x1_vals[i]) for i in range(len(Arcs)))
          x2 = dict((Arcs[i], x2_vals[i]) for i in range(len(Arcs)))

          varFinal = sum([x1[a] * x2[a] for a in Arcs if a[0] == Nodes[0]])

          print(Nodes[0])
          print(Arcs[0])
          print(varFinal)


          For future reference, answers are most likely to be forthcoming if you include code which others can try to run (without external data dependencies), that way people can try to run it, fix it, and re-post it.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 20 '18 at 22:19









          kabdullakabdulla

          2,2021724




          2,2021724













          • Hi kabdulla, thanks a lot for your help. I was wondering if x1 and x2 was to now have an index range equal to Arcs set by the Data Items Editor, How would you alter the above code to make it work? See below i.imgur.com/3pRHm4X.png i.imgur.com/6imfPDm.png

            – Filip Jovanovic
            Nov 20 '18 at 23:11













          • I've never used solver studio and don't know what data items editor is. Also those images are very pixelated. Perhaps you could edit your question with an embedded image and someone might be able to help.

            – kabdulla
            Nov 21 '18 at 8:09



















          • Hi kabdulla, thanks a lot for your help. I was wondering if x1 and x2 was to now have an index range equal to Arcs set by the Data Items Editor, How would you alter the above code to make it work? See below i.imgur.com/3pRHm4X.png i.imgur.com/6imfPDm.png

            – Filip Jovanovic
            Nov 20 '18 at 23:11













          • I've never used solver studio and don't know what data items editor is. Also those images are very pixelated. Perhaps you could edit your question with an embedded image and someone might be able to help.

            – kabdulla
            Nov 21 '18 at 8:09

















          Hi kabdulla, thanks a lot for your help. I was wondering if x1 and x2 was to now have an index range equal to Arcs set by the Data Items Editor, How would you alter the above code to make it work? See below i.imgur.com/3pRHm4X.png i.imgur.com/6imfPDm.png

          – Filip Jovanovic
          Nov 20 '18 at 23:11







          Hi kabdulla, thanks a lot for your help. I was wondering if x1 and x2 was to now have an index range equal to Arcs set by the Data Items Editor, How would you alter the above code to make it work? See below i.imgur.com/3pRHm4X.png i.imgur.com/6imfPDm.png

          – Filip Jovanovic
          Nov 20 '18 at 23:11















          I've never used solver studio and don't know what data items editor is. Also those images are very pixelated. Perhaps you could edit your question with an embedded image and someone might be able to help.

          – kabdulla
          Nov 21 '18 at 8:09





          I've never used solver studio and don't know what data items editor is. Also those images are very pixelated. Perhaps you could edit your question with an embedded image and someone might be able to help.

          – kabdulla
          Nov 21 '18 at 8:09




















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