Passing array unsigned in a function recursion in C
How do I use array as argument in recursion?
The procedure
void divide(int arr, int i, int j, int max, int min){
//Deklarasi
int min1, min2, max1, max2, k;//Algoritma
//1 Elemen
if(i == j){
min = arr[i];
max = arr[i];
}
else{
//2 Elemen
if(i == j-1){
if (arr[i] > arr[j]){
max = arr[i];
min = arr[j];
}
else{
max = arr[j];
min = arr[i];
}
}
//>2 Elemen
else{
k = (i+j)/2;
divide(arr[j],i,k,max1,min1);
divide(arr[j],k+1,j,max2,min2);
min = (min1>min2) ? (min2) : (min1);
max = (max1>max2) ? (max1) : (max2);
}
}
}
The main
int main(){
int i,j,min,max,x;
i = 1;
scanf("%d",&j);
//Input the array
int arr[j];
for(x=0;x<j;x++){
scanf("%d",&arr[x]);
}
divide(arr[j],i,j,max,min);
printf("%d %d", min, max);
}
when I execute the code, I can input the size and the array, but the program can't run(error)
Please help me, how do I pass array in a function?
c
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How do I use array as argument in recursion?
The procedure
void divide(int arr, int i, int j, int max, int min){
//Deklarasi
int min1, min2, max1, max2, k;//Algoritma
//1 Elemen
if(i == j){
min = arr[i];
max = arr[i];
}
else{
//2 Elemen
if(i == j-1){
if (arr[i] > arr[j]){
max = arr[i];
min = arr[j];
}
else{
max = arr[j];
min = arr[i];
}
}
//>2 Elemen
else{
k = (i+j)/2;
divide(arr[j],i,k,max1,min1);
divide(arr[j],k+1,j,max2,min2);
min = (min1>min2) ? (min2) : (min1);
max = (max1>max2) ? (max1) : (max2);
}
}
}
The main
int main(){
int i,j,min,max,x;
i = 1;
scanf("%d",&j);
//Input the array
int arr[j];
for(x=0;x<j;x++){
scanf("%d",&arr[x]);
}
divide(arr[j],i,j,max,min);
printf("%d %d", min, max);
}
when I execute the code, I can input the size and the array, but the program can't run(error)
Please help me, how do I pass array in a function?
c
add a comment |
How do I use array as argument in recursion?
The procedure
void divide(int arr, int i, int j, int max, int min){
//Deklarasi
int min1, min2, max1, max2, k;//Algoritma
//1 Elemen
if(i == j){
min = arr[i];
max = arr[i];
}
else{
//2 Elemen
if(i == j-1){
if (arr[i] > arr[j]){
max = arr[i];
min = arr[j];
}
else{
max = arr[j];
min = arr[i];
}
}
//>2 Elemen
else{
k = (i+j)/2;
divide(arr[j],i,k,max1,min1);
divide(arr[j],k+1,j,max2,min2);
min = (min1>min2) ? (min2) : (min1);
max = (max1>max2) ? (max1) : (max2);
}
}
}
The main
int main(){
int i,j,min,max,x;
i = 1;
scanf("%d",&j);
//Input the array
int arr[j];
for(x=0;x<j;x++){
scanf("%d",&arr[x]);
}
divide(arr[j],i,j,max,min);
printf("%d %d", min, max);
}
when I execute the code, I can input the size and the array, but the program can't run(error)
Please help me, how do I pass array in a function?
c
How do I use array as argument in recursion?
The procedure
void divide(int arr, int i, int j, int max, int min){
//Deklarasi
int min1, min2, max1, max2, k;//Algoritma
//1 Elemen
if(i == j){
min = arr[i];
max = arr[i];
}
else{
//2 Elemen
if(i == j-1){
if (arr[i] > arr[j]){
max = arr[i];
min = arr[j];
}
else{
max = arr[j];
min = arr[i];
}
}
//>2 Elemen
else{
k = (i+j)/2;
divide(arr[j],i,k,max1,min1);
divide(arr[j],k+1,j,max2,min2);
min = (min1>min2) ? (min2) : (min1);
max = (max1>max2) ? (max1) : (max2);
}
}
}
The main
int main(){
int i,j,min,max,x;
i = 1;
scanf("%d",&j);
//Input the array
int arr[j];
for(x=0;x<j;x++){
scanf("%d",&arr[x]);
}
divide(arr[j],i,j,max,min);
printf("%d %d", min, max);
}
when I execute the code, I can input the size and the array, but the program can't run(error)
Please help me, how do I pass array in a function?
c
c
edited Nov 20 '18 at 2:01
asked Nov 20 '18 at 1:29
user7945914
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
When you call divide, you need to pass arr, not arr[j]. arr[j] is just a single element of the array. Also you may want to pass in your min and max as pointers so that you actually get the new values in your main function.
answered Nov 20 '18 at 1:37
ahotaahota
37138
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
When you call divide, you need to pass arr, not arr[j]. arr[j] is just a single element of the array. Also you may want to pass in your min and max as pointers so that you actually get the new values in your main function.
answered Nov 20 '18 at 1:37
ahotaahota
37138
add a comment |
When you call divide, you need to pass arr, not arr[j]. arr[j] is just a single element of the array. Also you may want to pass in your min and max as pointers so that you actually get the new values in your main function.
answered Nov 20 '18 at 1:37
ahotaahota
37138
add a comment |
When you call divide, you need to pass arr, not arr[j]. arr[j] is just a single element of the array. Also you may want to pass in your min and max as pointers so that you actually get the new values in your main function.
answered Nov 20 '18 at 1:37
ahotaahota
37138
When you call divide, you need to pass arr, not arr[j]. arr[j] is just a single element of the array. Also you may want to pass in your min and max as pointers so that you actually get the new values in your main function.
answered Nov 20 '18 at 1:37
ahotaahota
37138
answered Nov 20 '18 at 1:37
ahotaahota
37138
answered Nov 20 '18 at 1:37
ahotaahota
37138
answered Nov 20 '18 at 1:37
ahotaahota
37138
37138
add a comment |
add a comment |
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