Show entire row for duplicates












0















I can find the duplicates in rawHR table, but now need to show all of the remaining columns of those duplicates. Here's what I've tried, but it gives me all employees, not just the duplicate ones.



select *
from rawHR
where exists
(
select distinct firstname, lastname
from rawHR
group by firstname, lastname
having count(*)> 1
)










share|improve this question























  • I'm new to this site, so i don't know how to format.

    – jciszek
    Nov 21 '18 at 18:51











  • Just for learning sake...I can do it with a JOIN...but shouldn't it work with EXISTS?

    – jciszek
    Nov 21 '18 at 19:03
















0















I can find the duplicates in rawHR table, but now need to show all of the remaining columns of those duplicates. Here's what I've tried, but it gives me all employees, not just the duplicate ones.



select *
from rawHR
where exists
(
select distinct firstname, lastname
from rawHR
group by firstname, lastname
having count(*)> 1
)










share|improve this question























  • I'm new to this site, so i don't know how to format.

    – jciszek
    Nov 21 '18 at 18:51











  • Just for learning sake...I can do it with a JOIN...but shouldn't it work with EXISTS?

    – jciszek
    Nov 21 '18 at 19:03














0












0








0








I can find the duplicates in rawHR table, but now need to show all of the remaining columns of those duplicates. Here's what I've tried, but it gives me all employees, not just the duplicate ones.



select *
from rawHR
where exists
(
select distinct firstname, lastname
from rawHR
group by firstname, lastname
having count(*)> 1
)










share|improve this question














I can find the duplicates in rawHR table, but now need to show all of the remaining columns of those duplicates. Here's what I've tried, but it gives me all employees, not just the duplicate ones.



select *
from rawHR
where exists
(
select distinct firstname, lastname
from rawHR
group by firstname, lastname
having count(*)> 1
)







duplicates






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 21 '18 at 18:50









jciszekjciszek

11




11













  • I'm new to this site, so i don't know how to format.

    – jciszek
    Nov 21 '18 at 18:51











  • Just for learning sake...I can do it with a JOIN...but shouldn't it work with EXISTS?

    – jciszek
    Nov 21 '18 at 19:03



















  • I'm new to this site, so i don't know how to format.

    – jciszek
    Nov 21 '18 at 18:51











  • Just for learning sake...I can do it with a JOIN...but shouldn't it work with EXISTS?

    – jciszek
    Nov 21 '18 at 19:03

















I'm new to this site, so i don't know how to format.

– jciszek
Nov 21 '18 at 18:51





I'm new to this site, so i don't know how to format.

– jciszek
Nov 21 '18 at 18:51













Just for learning sake...I can do it with a JOIN...but shouldn't it work with EXISTS?

– jciszek
Nov 21 '18 at 19:03





Just for learning sake...I can do it with a JOIN...but shouldn't it work with EXISTS?

– jciszek
Nov 21 '18 at 19:03












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