Typescript interface with private members
Why typescript not supporting private members in interfaces?
How to handle the following scenario?
interface IFoo
{
private member: {};
}
class Foo implements IFoo
{
private member = {};
}
typescript
asked Nov 21 '18 at 22:46
Ahmed M.KamalAhmed M.Kamal
529517
add a comment |
Why typescript not supporting private members in interfaces?
How to handle the following scenario?
interface IFoo
{
private member: {};
}
class Foo implements IFoo
{
private member = {};
}
typescript
asked Nov 21 '18 at 22:46
Ahmed M.KamalAhmed M.Kamal
529517
add a comment |
Why typescript not supporting private members in interfaces?
How to handle the following scenario?
interface IFoo
{
private member: {};
}
class Foo implements IFoo
{
private member = {};
}
typescript
asked Nov 21 '18 at 22:46
Ahmed M.KamalAhmed M.Kamal
529517
Why typescript not supporting private members in interfaces?
How to handle the following scenario?
interface IFoo
{
private member: {};
}
class Foo implements IFoo
{
private member = {};
}
typescript
typescript
asked Nov 21 '18 at 22:46
Ahmed M.KamalAhmed M.Kamal
529517
asked Nov 21 '18 at 22:46
Ahmed M.KamalAhmed M.Kamal
529517
asked Nov 21 '18 at 22:46
Ahmed M.KamalAhmed M.Kamal
529517
asked Nov 21 '18 at 22:46
Ahmed M.KamalAhmed M.Kamal
529517
asked Nov 21 '18 at 22:46
Ahmed M.KamalAhmed M.Kamal
529517
529517
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Interfaces define "public contracts", it describes the public side of the class and as such it doesn't make sense to have private access modifier.
From Typescript interface documentation:
This prohibits you from using them to check that a class also has
particular types for the private side of the class instance.
But an interface can extend classes with private memmbers.
From Understanding TypeScript:
In TypeScript, interfaces can also extend classes, but only in a way
that involves inheritance. When an interface extends a class, the
interface includes all class members (public and private), but without
the class’ implementations.
class Customer
{
private id: number;
get Id(): number
{
return this.id
}
set Id( value: number )
{
this.id = value;
}
}
interface ICustomer extends Customer
{
MiddleName: string;
}
answered Nov 21 '18 at 23:11
MaartiMaarti
1,8643823
Thanks for explanation, but isn't this considered a weakness of the language?
– Ahmed M.Kamal
Nov 21 '18 at 23:20
1
@AhmedM.Kamal in what way? It makes very little sense to check if the instance itself implements something, you can see it yourself right in your editor already.
– zerkms
Nov 21 '18 at 23:21
@zerkms it makes sense for me now, thanks.
– Ahmed M.Kamal
Nov 21 '18 at 23:34
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Interfaces define "public contracts", it describes the public side of the class and as such it doesn't make sense to have private access modifier.
From Typescript interface documentation:
This prohibits you from using them to check that a class also has
particular types for the private side of the class instance.
But an interface can extend classes with private memmbers.
From Understanding TypeScript:
In TypeScript, interfaces can also extend classes, but only in a way
that involves inheritance. When an interface extends a class, the
interface includes all class members (public and private), but without
the class’ implementations.
class Customer
{
private id: number;
get Id(): number
{
return this.id
}
set Id( value: number )
{
this.id = value;
}
}
interface ICustomer extends Customer
{
MiddleName: string;
}
answered Nov 21 '18 at 23:11
MaartiMaarti
1,8643823
Thanks for explanation, but isn't this considered a weakness of the language?
– Ahmed M.Kamal
Nov 21 '18 at 23:20
1
@AhmedM.Kamal in what way? It makes very little sense to check if the instance itself implements something, you can see it yourself right in your editor already.
– zerkms
Nov 21 '18 at 23:21
@zerkms it makes sense for me now, thanks.
– Ahmed M.Kamal
Nov 21 '18 at 23:34
add a comment |
Interfaces define "public contracts", it describes the public side of the class and as such it doesn't make sense to have private access modifier.
From Typescript interface documentation:
This prohibits you from using them to check that a class also has
particular types for the private side of the class instance.
But an interface can extend classes with private memmbers.
From Understanding TypeScript:
In TypeScript, interfaces can also extend classes, but only in a way
that involves inheritance. When an interface extends a class, the
interface includes all class members (public and private), but without
the class’ implementations.
class Customer
{
private id: number;
get Id(): number
{
return this.id
}
set Id( value: number )
{
this.id = value;
}
}
interface ICustomer extends Customer
{
MiddleName: string;
}
answered Nov 21 '18 at 23:11
MaartiMaarti
1,8643823
Thanks for explanation, but isn't this considered a weakness of the language?
– Ahmed M.Kamal
Nov 21 '18 at 23:20
1
@AhmedM.Kamal in what way? It makes very little sense to check if the instance itself implements something, you can see it yourself right in your editor already.
– zerkms
Nov 21 '18 at 23:21
@zerkms it makes sense for me now, thanks.
– Ahmed M.Kamal
Nov 21 '18 at 23:34
add a comment |
Interfaces define "public contracts", it describes the public side of the class and as such it doesn't make sense to have private access modifier.
From Typescript interface documentation:
This prohibits you from using them to check that a class also has
particular types for the private side of the class instance.
But an interface can extend classes with private memmbers.
From Understanding TypeScript:
In TypeScript, interfaces can also extend classes, but only in a way
that involves inheritance. When an interface extends a class, the
interface includes all class members (public and private), but without
the class’ implementations.
class Customer
{
private id: number;
get Id(): number
{
return this.id
}
set Id( value: number )
{
this.id = value;
}
}
interface ICustomer extends Customer
{
MiddleName: string;
}
answered Nov 21 '18 at 23:11
MaartiMaarti
1,8643823
Interfaces define "public contracts", it describes the public side of the class and as such it doesn't make sense to have private access modifier.
From Typescript interface documentation:
This prohibits you from using them to check that a class also has
particular types for the private side of the class instance.
But an interface can extend classes with private memmbers.
From Understanding TypeScript:
In TypeScript, interfaces can also extend classes, but only in a way
that involves inheritance. When an interface extends a class, the
interface includes all class members (public and private), but without
the class’ implementations.
class Customer
{
private id: number;
get Id(): number
{
return this.id
}
set Id( value: number )
{
this.id = value;
}
}
interface ICustomer extends Customer
{
MiddleName: string;
}
answered Nov 21 '18 at 23:11
MaartiMaarti
1,8643823
edited Nov 21 '18 at 23:23
answered Nov 21 '18 at 23:11
MaartiMaarti
1,8643823
answered Nov 21 '18 at 23:11
MaartiMaarti
1,8643823
answered Nov 21 '18 at 23:11
MaartiMaarti
1,8643823
1,8643823
Thanks for explanation, but isn't this considered a weakness of the language?
– Ahmed M.Kamal
Nov 21 '18 at 23:20
1
@AhmedM.Kamal in what way? It makes very little sense to check if the instance itself implements something, you can see it yourself right in your editor already.
– zerkms
Nov 21 '18 at 23:21
@zerkms it makes sense for me now, thanks.
– Ahmed M.Kamal
Nov 21 '18 at 23:34
add a comment |
Thanks for explanation, but isn't this considered a weakness of the language?
– Ahmed M.Kamal
Nov 21 '18 at 23:20
1
@AhmedM.Kamal in what way? It makes very little sense to check if the instance itself implements something, you can see it yourself right in your editor already.
– zerkms
Nov 21 '18 at 23:21
@zerkms it makes sense for me now, thanks.
– Ahmed M.Kamal
Nov 21 '18 at 23:34
Thanks for explanation, but isn't this considered a weakness of the language?
– Ahmed M.Kamal
Nov 21 '18 at 23:20
Thanks for explanation, but isn't this considered a weakness of the language?
– Ahmed M.Kamal
Nov 21 '18 at 23:20
1
1
@AhmedM.Kamal in what way? It makes very little sense to check if the instance itself implements something, you can see it yourself right in your editor already.
– zerkms
Nov 21 '18 at 23:21
@AhmedM.Kamal in what way? It makes very little sense to check if the instance itself implements something, you can see it yourself right in your editor already.
– zerkms
Nov 21 '18 at 23:21
@zerkms it makes sense for me now, thanks.
– Ahmed M.Kamal
Nov 21 '18 at 23:34
@zerkms it makes sense for me now, thanks.
– Ahmed M.Kamal
Nov 21 '18 at 23:34
add a comment |
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