Rearrangement of lists of strings












5












$begingroup$


I have a list:



lis = {{"abc","def","ghi"},{"jkl","mno"}}


and wish to get:



res = {"abc def ghi","jkl mno"}


This:



Table[StringJoin[lis[[i]]], {i, Length[lis]}]


doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!






string-manipulation







share|improve this question











$endgroup$

















    5












    $begingroup$


    I have a list:



    lis = {{"abc","def","ghi"},{"jkl","mno"}}


    and wish to get:



    res = {"abc def ghi","jkl mno"}


    This:



    Table[StringJoin[lis[[i]]], {i, Length[lis]}]


    doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!






    string-manipulation







    share|improve this question











    $endgroup$















      5












      5








      5





      $begingroup$


      I have a list:



      lis = {{"abc","def","ghi"},{"jkl","mno"}}


      and wish to get:



      res = {"abc def ghi","jkl mno"}


      This:



      Table[StringJoin[lis[[i]]], {i, Length[lis]}]


      doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!






      string-manipulation







      share|improve this question











      $endgroup$




      I have a list:



      lis = {{"abc","def","ghi"},{"jkl","mno"}}


      and wish to get:



      res = {"abc def ghi","jkl mno"}


      This:



      Table[StringJoin[lis[[i]]], {i, Length[lis]}]


      doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!






      string-manipulation




      string-manipulation






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 25 '18 at 9:27









      kglr

      190k10209426




      190k10209426










      asked Nov 25 '18 at 2:43









      Suite401Suite401

      1,098312




      1,098312






















          2 Answers
          2






          active

          oldest

          votes


















          14












          $begingroup$

          You can use StringRiffle:



          StringRiffle /@ lis



          {"abc def ghi", "jkl mno"}







          share|improve this answer









          $endgroup$





















            6












            $begingroup$

            Use Riffle 



            lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
            

            
StringJoin[Riffle[#, " "]] & /@ lis
            

            
(* {"abc def ghi", "jkl mno"} *)





            share|improve this answer









            $endgroup$














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              2 Answers
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              active

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              2 Answers
              2






              active

              oldest

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              active

              oldest

              votes






              active

              oldest

              votes









              14












              $begingroup$

              You can use StringRiffle:



              StringRiffle /@ lis



              {"abc def ghi", "jkl mno"}







              share|improve this answer









              $endgroup$


















                14












                $begingroup$

                You can use StringRiffle:



                StringRiffle /@ lis



                {"abc def ghi", "jkl mno"}







                share|improve this answer









                $endgroup$
















                  14












                  14








                  14





                  $begingroup$

                  You can use StringRiffle:



                  StringRiffle /@ lis



                  {"abc def ghi", "jkl mno"}







                  share|improve this answer









                  $endgroup$



                  You can use StringRiffle:



                  StringRiffle /@ lis



                  {"abc def ghi", "jkl mno"}








                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 25 '18 at 2:56









                  kglrkglr

                  190k10209426




                  190k10209426























                      6












                      $begingroup$

                      Use Riffle 



                      lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
                      

                      
StringJoin[Riffle[#, " "]] & /@ lis
                      

                      
(* {"abc def ghi", "jkl mno"} *)





                      share|improve this answer









                      $endgroup$


















                        6












                        $begingroup$

                        Use Riffle 



                        lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
                        

                        
StringJoin[Riffle[#, " "]] & /@ lis
                        

                        
(* {"abc def ghi", "jkl mno"} *)





                        share|improve this answer









                        $endgroup$
















                          6












                          6








                          6





                          $begingroup$

                          Use Riffle 



                          lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
                          

                          
StringJoin[Riffle[#, " "]] & /@ lis
                          

                          
(* {"abc def ghi", "jkl mno"} *)





                          share|improve this answer









                          $endgroup$



                          Use Riffle 



                          lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
                          

                          
StringJoin[Riffle[#, " "]] & /@ lis
                          

                          
(* {"abc def ghi", "jkl mno"} *)






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 25 '18 at 2:52









                          Bob HanlonBob Hanlon

                          61.8k33598




                          61.8k33598






























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