SQL Server Match Closest Record With Another Table
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I have two tables, one with the time a customer spoke with a colleague and another where they have made a purchase however I can't figure out how to tie the closest purchase to a particular colleague
For example
Table 1 - Colleague Interactions
[ColleagueID] [DateOfInteraction] [CustomerID]
------------------------------------------------
A 2018-11-22 12:00 123
B 2018-11-22 12:02 123
Table 2 - List of Purchases
[PurchaseID] [DateOfPurchase] [PurchaseOutcome] [CustomerID]
----------------------------------------------------------------
1 2018-11-22 12:01 FAIL 123
2 2018-11-22 12:03 SUCCESS 123
What I want to do with the above is to tie these two records together, initially I do this on the CustomerID but this obviously create duplication as the customerID appears twice in Table 2 and Table 1. I then try to narrow to say where DateOfInteraction < DateOfPurchase which will eliminate the first record however I am unsure on how to match the second?
The results should look like
[ColleagueID] [DateOfInteraction] [CustomerID] [PurchaseID] [DateOfPurchase] [PurchaseOutcome]
---------------------------------------------------------------------------------------------------
A 2018-11-22 12:00 123 1 2018-11-22 12:01 FAIL
B 2018-11-22 12:02 123 2 2018-11-22 12:03 SUCCESS
sql-server tsql edited Feb 24 at 13:30
Cœur
19.4k10116155
asked Nov 24 '18 at 14:50
ChrisChris
1,18211632
add a comment |
I have two tables, one with the time a customer spoke with a colleague and another where they have made a purchase however I can't figure out how to tie the closest purchase to a particular colleague
For example
Table 1 - Colleague Interactions
[ColleagueID] [DateOfInteraction] [CustomerID]
------------------------------------------------
A 2018-11-22 12:00 123
B 2018-11-22 12:02 123
Table 2 - List of Purchases
[PurchaseID] [DateOfPurchase] [PurchaseOutcome] [CustomerID]
----------------------------------------------------------------
1 2018-11-22 12:01 FAIL 123
2 2018-11-22 12:03 SUCCESS 123
What I want to do with the above is to tie these two records together, initially I do this on the CustomerID but this obviously create duplication as the customerID appears twice in Table 2 and Table 1. I then try to narrow to say where DateOfInteraction < DateOfPurchase which will eliminate the first record however I am unsure on how to match the second?
The results should look like
[ColleagueID] [DateOfInteraction] [CustomerID] [PurchaseID] [DateOfPurchase] [PurchaseOutcome]
---------------------------------------------------------------------------------------------------
A 2018-11-22 12:00 123 1 2018-11-22 12:01 FAIL
B 2018-11-22 12:02 123 2 2018-11-22 12:03 SUCCESS
edited Feb 24 at 13:30
Cœur
19.4k10116155
asked Nov 24 '18 at 14:50
ChrisChris
1,18211632
add a comment |
I have two tables, one with the time a customer spoke with a colleague and another where they have made a purchase however I can't figure out how to tie the closest purchase to a particular colleague
For example
Table 1 - Colleague Interactions
[ColleagueID] [DateOfInteraction] [CustomerID]
------------------------------------------------
A 2018-11-22 12:00 123
B 2018-11-22 12:02 123
Table 2 - List of Purchases
[PurchaseID] [DateOfPurchase] [PurchaseOutcome] [CustomerID]
----------------------------------------------------------------
1 2018-11-22 12:01 FAIL 123
2 2018-11-22 12:03 SUCCESS 123
What I want to do with the above is to tie these two records together, initially I do this on the CustomerID but this obviously create duplication as the customerID appears twice in Table 2 and Table 1. I then try to narrow to say where DateOfInteraction < DateOfPurchase which will eliminate the first record however I am unsure on how to match the second?
The results should look like
[ColleagueID] [DateOfInteraction] [CustomerID] [PurchaseID] [DateOfPurchase] [PurchaseOutcome]
---------------------------------------------------------------------------------------------------
A 2018-11-22 12:00 123 1 2018-11-22 12:01 FAIL
B 2018-11-22 12:02 123 2 2018-11-22 12:03 SUCCESS
edited Feb 24 at 13:30
Cœur
19.4k10116155
asked Nov 24 '18 at 14:50
ChrisChris
1,18211632
I have two tables, one with the time a customer spoke with a colleague and another where they have made a purchase however I can't figure out how to tie the closest purchase to a particular colleague
For example
Table 1 - Colleague Interactions
[ColleagueID] [DateOfInteraction] [CustomerID]
------------------------------------------------
A 2018-11-22 12:00 123
B 2018-11-22 12:02 123
Table 2 - List of Purchases
[PurchaseID] [DateOfPurchase] [PurchaseOutcome] [CustomerID]
----------------------------------------------------------------
1 2018-11-22 12:01 FAIL 123
2 2018-11-22 12:03 SUCCESS 123
What I want to do with the above is to tie these two records together, initially I do this on the CustomerID but this obviously create duplication as the customerID appears twice in Table 2 and Table 1. I then try to narrow to say where DateOfInteraction < DateOfPurchase which will eliminate the first record however I am unsure on how to match the second?
The results should look like
[ColleagueID] [DateOfInteraction] [CustomerID] [PurchaseID] [DateOfPurchase] [PurchaseOutcome]
---------------------------------------------------------------------------------------------------
A 2018-11-22 12:00 123 1 2018-11-22 12:01 FAIL
B 2018-11-22 12:02 123 2 2018-11-22 12:03 SUCCESS
edited Feb 24 at 13:30
Cœur
19.4k10116155
asked Nov 24 '18 at 14:50
ChrisChris
1,18211632
edited Feb 24 at 13:30
Cœur
19.4k10116155
asked Nov 24 '18 at 14:50
ChrisChris
1,18211632
edited Feb 24 at 13:30
Cœur
19.4k10116155
edited Feb 24 at 13:30
Cœur
19.4k10116155
edited Feb 24 at 13:30
Cœur
19.4k10116155
19.4k10116155
asked Nov 24 '18 at 14:50
ChrisChris
1,18211632
asked Nov 24 '18 at 14:50
ChrisChris
1,18211632
asked Nov 24 '18 at 14:50
ChrisChris
1,18211632
1,18211632
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I think apply does what you want:
select p.*, i.*
from purchases p outer apply
(select top (1) i.*
from interactions i
where i.customer_id = p.customer_id and
i.DateOfInteraction < p.DateOfPurhase
order by i.DateOfInteraction desc
) i;
answered Nov 24 '18 at 14:54
Gordon LinoffGordon Linoff
799k37321426
hey, sorry thought this was the answer, issue is that Top (1) bit doesn't work as that sub query is still returning 3 rows, 2 for the first colleague(because both interactions are less than the purchase date) so I end up with the same colleague for both purchases?
– Chris
Nov 24 '18 at 15:37
missed the order by desc, working now :) thanks
– Chris
Nov 24 '18 at 15:40
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think apply does what you want:
select p.*, i.*
from purchases p outer apply
(select top (1) i.*
from interactions i
where i.customer_id = p.customer_id and
i.DateOfInteraction < p.DateOfPurhase
order by i.DateOfInteraction desc
) i;
answered Nov 24 '18 at 14:54
Gordon LinoffGordon Linoff
799k37321426
hey, sorry thought this was the answer, issue is that Top (1) bit doesn't work as that sub query is still returning 3 rows, 2 for the first colleague(because both interactions are less than the purchase date) so I end up with the same colleague for both purchases?
– Chris
Nov 24 '18 at 15:37
missed the order by desc, working now :) thanks
– Chris
Nov 24 '18 at 15:40
add a comment |
I think apply does what you want:
select p.*, i.*
from purchases p outer apply
(select top (1) i.*
from interactions i
where i.customer_id = p.customer_id and
i.DateOfInteraction < p.DateOfPurhase
order by i.DateOfInteraction desc
) i;
answered Nov 24 '18 at 14:54
Gordon LinoffGordon Linoff
799k37321426
hey, sorry thought this was the answer, issue is that Top (1) bit doesn't work as that sub query is still returning 3 rows, 2 for the first colleague(because both interactions are less than the purchase date) so I end up with the same colleague for both purchases?
– Chris
Nov 24 '18 at 15:37
missed the order by desc, working now :) thanks
– Chris
Nov 24 '18 at 15:40
add a comment |
I think apply does what you want:
select p.*, i.*
from purchases p outer apply
(select top (1) i.*
from interactions i
where i.customer_id = p.customer_id and
i.DateOfInteraction < p.DateOfPurhase
order by i.DateOfInteraction desc
) i;
answered Nov 24 '18 at 14:54
Gordon LinoffGordon Linoff
799k37321426
I think apply does what you want:
select p.*, i.*
from purchases p outer apply
(select top (1) i.*
from interactions i
where i.customer_id = p.customer_id and
i.DateOfInteraction < p.DateOfPurhase
order by i.DateOfInteraction desc
) i;
answered Nov 24 '18 at 14:54
Gordon LinoffGordon Linoff
799k37321426
answered Nov 24 '18 at 14:54
Gordon LinoffGordon Linoff
799k37321426
answered Nov 24 '18 at 14:54
Gordon LinoffGordon Linoff
799k37321426
answered Nov 24 '18 at 14:54
Gordon LinoffGordon Linoff
799k37321426
799k37321426
hey, sorry thought this was the answer, issue is that Top (1) bit doesn't work as that sub query is still returning 3 rows, 2 for the first colleague(because both interactions are less than the purchase date) so I end up with the same colleague for both purchases?
– Chris
Nov 24 '18 at 15:37
missed the order by desc, working now :) thanks
– Chris
Nov 24 '18 at 15:40
add a comment |
hey, sorry thought this was the answer, issue is that Top (1) bit doesn't work as that sub query is still returning 3 rows, 2 for the first colleague(because both interactions are less than the purchase date) so I end up with the same colleague for both purchases?
– Chris
Nov 24 '18 at 15:37
missed the order by desc, working now :) thanks
– Chris
Nov 24 '18 at 15:40
hey, sorry thought this was the answer, issue is that Top (1) bit doesn't work as that sub query is still returning 3 rows, 2 for the first colleague(because both interactions are less than the purchase date) so I end up with the same colleague for both purchases?
– Chris
Nov 24 '18 at 15:37
hey, sorry thought this was the answer, issue is that Top (1) bit doesn't work as that sub query is still returning 3 rows, 2 for the first colleague(because both interactions are less than the purchase date) so I end up with the same colleague for both purchases?
– Chris
Nov 24 '18 at 15:37
missed the order by desc, working now :) thanks
– Chris
Nov 24 '18 at 15:40
missed the order by desc, working now :) thanks
– Chris
Nov 24 '18 at 15:40
add a comment |
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