Add rows to table with jQuery .each and .append
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I'm trying to add rows to a table. GetLogEntries returns an IEnumererable of an anonymous type. How to I refer to the members? When I append the constant string, the correct number of rows is written, but when I try to refer to an element in the anonymous type, nothing it written. How to I refer to the members of the anonymous type?
$.getJSON('@Url.Action("GetLogEntries")', { FacilityID: selectedFacility }, function (entries) {
if (entries != null && !jQuery.isEmptyObject(entries)) {
var logEntries = $('#logEntries');
$.each(entries, function (index, entry) {
//logEntries.append($("<tr><td>1</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>"));
logEntries.append($("<tr><td>",entry.InventoryID,"</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>"));
});
};
});
jquery
asked Nov 9 at 20:21
Barry Sweezey
11
|
show 2 more comments
up vote
0
down vote
favorite
I'm trying to add rows to a table. GetLogEntries returns an IEnumererable of an anonymous type. How to I refer to the members? When I append the constant string, the correct number of rows is written, but when I try to refer to an element in the anonymous type, nothing it written. How to I refer to the members of the anonymous type?
$.getJSON('@Url.Action("GetLogEntries")', { FacilityID: selectedFacility }, function (entries) {
if (entries != null && !jQuery.isEmptyObject(entries)) {
var logEntries = $('#logEntries');
$.each(entries, function (index, entry) {
//logEntries.append($("<tr><td>1</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>"));
logEntries.append($("<tr><td>",entry.InventoryID,"</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>"));
});
};
});
jquery
asked Nov 9 at 20:21
Barry Sweezey
11
1
Your append is weird. You are giving it the result of a$()with three arguments, not one single string. Did you typo a comma in place of a+concatenator?
– Taplar
Nov 9 at 20:23
1
$("<tr><td>",entry.InventoryID,"</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>")doesn't make sense.
– Kevin B
Nov 9 at 20:24
@Taplar.append()takes an infinite amount of elements, however the$( ... )certainly doesn't make sense.
– Tyler Roper
Nov 9 at 20:24
1
.append in this case only gets one argument, i think taplar mispoke
– Kevin B
Nov 9 at 20:24
@Taplar & Kevin B - Yup, think we're all on the same page here. Clarified my comment.
– Tyler Roper
Nov 9 at 20:24
|
show 2 more comments
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm trying to add rows to a table. GetLogEntries returns an IEnumererable of an anonymous type. How to I refer to the members? When I append the constant string, the correct number of rows is written, but when I try to refer to an element in the anonymous type, nothing it written. How to I refer to the members of the anonymous type?
$.getJSON('@Url.Action("GetLogEntries")', { FacilityID: selectedFacility }, function (entries) {
if (entries != null && !jQuery.isEmptyObject(entries)) {
var logEntries = $('#logEntries');
$.each(entries, function (index, entry) {
//logEntries.append($("<tr><td>1</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>"));
logEntries.append($("<tr><td>",entry.InventoryID,"</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>"));
});
};
});
jquery
asked Nov 9 at 20:21
Barry Sweezey
11
I'm trying to add rows to a table. GetLogEntries returns an IEnumererable of an anonymous type. How to I refer to the members? When I append the constant string, the correct number of rows is written, but when I try to refer to an element in the anonymous type, nothing it written. How to I refer to the members of the anonymous type?
$.getJSON('@Url.Action("GetLogEntries")', { FacilityID: selectedFacility }, function (entries) {
if (entries != null && !jQuery.isEmptyObject(entries)) {
var logEntries = $('#logEntries');
$.each(entries, function (index, entry) {
//logEntries.append($("<tr><td>1</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>"));
logEntries.append($("<tr><td>",entry.InventoryID,"</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>"));
});
};
});
jquery
jquery
asked Nov 9 at 20:21
Barry Sweezey
11
asked Nov 9 at 20:21
Barry Sweezey
11
asked Nov 9 at 20:21
Barry Sweezey
11
asked Nov 9 at 20:21
Barry Sweezey
11
asked Nov 9 at 20:21
Barry Sweezey
11
11
1
Your append is weird. You are giving it the result of a$()with three arguments, not one single string. Did you typo a comma in place of a+concatenator?
– Taplar
Nov 9 at 20:23
1
$("<tr><td>",entry.InventoryID,"</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>")doesn't make sense.
– Kevin B
Nov 9 at 20:24
@Taplar.append()takes an infinite amount of elements, however the$( ... )certainly doesn't make sense.
– Tyler Roper
Nov 9 at 20:24
1
.append in this case only gets one argument, i think taplar mispoke
– Kevin B
Nov 9 at 20:24
@Taplar & Kevin B - Yup, think we're all on the same page here. Clarified my comment.
– Tyler Roper
Nov 9 at 20:24
|
show 2 more comments
1
Your append is weird. You are giving it the result of a$()with three arguments, not one single string. Did you typo a comma in place of a+concatenator?
– Taplar
Nov 9 at 20:23
1
$("<tr><td>",entry.InventoryID,"</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>")doesn't make sense.
– Kevin B
Nov 9 at 20:24
@Taplar.append()takes an infinite amount of elements, however the$( ... )certainly doesn't make sense.
– Tyler Roper
Nov 9 at 20:24
1
.append in this case only gets one argument, i think taplar mispoke
– Kevin B
Nov 9 at 20:24
@Taplar & Kevin B - Yup, think we're all on the same page here. Clarified my comment.
– Tyler Roper
Nov 9 at 20:24
1
1
Your append is weird. You are giving it the result of a
$() with three arguments, not one single string. Did you typo a comma in place of a + concatenator?– Taplar
Nov 9 at 20:23
Your append is weird. You are giving it the result of a
$() with three arguments, not one single string. Did you typo a comma in place of a + concatenator?– Taplar
Nov 9 at 20:23
1
1
$("<tr><td>",entry.InventoryID,"</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>") doesn't make sense.– Kevin B
Nov 9 at 20:24
$("<tr><td>",entry.InventoryID,"</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>") doesn't make sense.– Kevin B
Nov 9 at 20:24
@Taplar
.append() takes an infinite amount of elements, however the $( ... ) certainly doesn't make sense.– Tyler Roper
Nov 9 at 20:24
@Taplar
.append() takes an infinite amount of elements, however the $( ... ) certainly doesn't make sense.– Tyler Roper
Nov 9 at 20:24
1
1
.append in this case only gets one argument, i think taplar mispoke
– Kevin B
Nov 9 at 20:24
.append in this case only gets one argument, i think taplar mispoke
– Kevin B
Nov 9 at 20:24
@Taplar & Kevin B - Yup, think we're all on the same page here. Clarified my comment.
– Tyler Roper
Nov 9 at 20:24
@Taplar & Kevin B - Yup, think we're all on the same page here. Clarified my comment.
– Tyler Roper
Nov 9 at 20:24
|
show 2 more comments
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1
Your append is weird. You are giving it the result of a
$()with three arguments, not one single string. Did you typo a comma in place of a+concatenator?– Taplar
Nov 9 at 20:23
1
$("<tr><td>",entry.InventoryID,"</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td></tr>")doesn't make sense.– Kevin B
Nov 9 at 20:24
@Taplar
.append()takes an infinite amount of elements, however the$( ... )certainly doesn't make sense.– Tyler Roper
Nov 9 at 20:24
1
.append in this case only gets one argument, i think taplar mispoke
– Kevin B
Nov 9 at 20:24
@Taplar & Kevin B - Yup, think we're all on the same page here. Clarified my comment.
– Tyler Roper
Nov 9 at 20:24