Creating a submodule that relies on a properties file
up vote
0
down vote
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I have the following structure
main.py
module/
properties.yaml
file.py
file.py relevant code:
def read_properties():
with open('properties.yaml') as file:
properties = yaml.load(file)
main.py relevant code:
from module import file
file.read_properties()
When read_properties() is called within main.py, I get the following error: FileNotFoundError: [Errno 2] No such file or directory: 'properties.yaml'
What is the recommended way of allowing my module to access the properties file even when imported?
python import python-import python-3.7
asked Nov 9 at 19:45
Dominic Roy-Stang
13
add a comment |
up vote
0
down vote
favorite
I have the following structure
main.py
module/
properties.yaml
file.py
file.py relevant code:
def read_properties():
with open('properties.yaml') as file:
properties = yaml.load(file)
main.py relevant code:
from module import file
file.read_properties()
When read_properties() is called within main.py, I get the following error: FileNotFoundError: [Errno 2] No such file or directory: 'properties.yaml'
What is the recommended way of allowing my module to access the properties file even when imported?
python import python-import python-3.7
asked Nov 9 at 19:45
Dominic Roy-Stang
13
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have the following structure
main.py
module/
properties.yaml
file.py
file.py relevant code:
def read_properties():
with open('properties.yaml') as file:
properties = yaml.load(file)
main.py relevant code:
from module import file
file.read_properties()
When read_properties() is called within main.py, I get the following error: FileNotFoundError: [Errno 2] No such file or directory: 'properties.yaml'
What is the recommended way of allowing my module to access the properties file even when imported?
python import python-import python-3.7
asked Nov 9 at 19:45
Dominic Roy-Stang
13
I have the following structure
main.py
module/
properties.yaml
file.py
file.py relevant code:
def read_properties():
with open('properties.yaml') as file:
properties = yaml.load(file)
main.py relevant code:
from module import file
file.read_properties()
When read_properties() is called within main.py, I get the following error: FileNotFoundError: [Errno 2] No such file or directory: 'properties.yaml'
What is the recommended way of allowing my module to access the properties file even when imported?
python import python-import python-3.7
python import python-import python-3.7
asked Nov 9 at 19:45
Dominic Roy-Stang
13
asked Nov 9 at 19:45
Dominic Roy-Stang
13
asked Nov 9 at 19:45
Dominic Roy-Stang
13
asked Nov 9 at 19:45
Dominic Roy-Stang
13
asked Nov 9 at 19:45
Dominic Roy-Stang
13
13
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
up vote
0
down vote
Provide the absolute path to properties.yaml:
with open('/Users/You/Some/Path/properties.yaml') as file:
answered Nov 9 at 19:54
JacobIRR
3,09521027
add a comment |
up vote
0
down vote
As JacobIRR said in his answer, it is best to use the absolute path to the file. I use the os module to construct the absolute path based on the current working directory. So for your code it would be something like:
import os
working_directory = os.path.dirname(__file__)
properties_file = os.path.join(working_directory, 'module', 'properties.yaml')
answered Nov 9 at 20:00
BigGerman
20518
add a comment |
up vote
0
down vote
accepted
Based on answers from @JacobIRR and @BigGerman
I ended up using pathlib instead of os, but the logic is the same.
Here is the syntax with pathlib for those interested:
in file.py:
from pathlib import Path
properties_file = Path(__file__).resolve().parent/"properties.yaml"
with open(properties_file) as file:
properties = yaml.load(file)
answered Nov 9 at 20:17
Dominic Roy-Stang
13
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Provide the absolute path to properties.yaml:
with open('/Users/You/Some/Path/properties.yaml') as file:
answered Nov 9 at 19:54
JacobIRR
3,09521027
add a comment |
up vote
0
down vote
Provide the absolute path to properties.yaml:
with open('/Users/You/Some/Path/properties.yaml') as file:
answered Nov 9 at 19:54
JacobIRR
3,09521027
add a comment |
up vote
0
down vote
up vote
0
down vote
Provide the absolute path to properties.yaml:
with open('/Users/You/Some/Path/properties.yaml') as file:
answered Nov 9 at 19:54
JacobIRR
3,09521027
Provide the absolute path to properties.yaml:
with open('/Users/You/Some/Path/properties.yaml') as file:
answered Nov 9 at 19:54
JacobIRR
3,09521027
answered Nov 9 at 19:54
JacobIRR
3,09521027
answered Nov 9 at 19:54
JacobIRR
3,09521027
answered Nov 9 at 19:54
JacobIRR
3,09521027
3,09521027
add a comment |
add a comment |
up vote
0
down vote
As JacobIRR said in his answer, it is best to use the absolute path to the file. I use the os module to construct the absolute path based on the current working directory. So for your code it would be something like:
import os
working_directory = os.path.dirname(__file__)
properties_file = os.path.join(working_directory, 'module', 'properties.yaml')
answered Nov 9 at 20:00
BigGerman
20518
add a comment |
up vote
0
down vote
As JacobIRR said in his answer, it is best to use the absolute path to the file. I use the os module to construct the absolute path based on the current working directory. So for your code it would be something like:
import os
working_directory = os.path.dirname(__file__)
properties_file = os.path.join(working_directory, 'module', 'properties.yaml')
answered Nov 9 at 20:00
BigGerman
20518
add a comment |
up vote
0
down vote
up vote
0
down vote
As JacobIRR said in his answer, it is best to use the absolute path to the file. I use the os module to construct the absolute path based on the current working directory. So for your code it would be something like:
import os
working_directory = os.path.dirname(__file__)
properties_file = os.path.join(working_directory, 'module', 'properties.yaml')
answered Nov 9 at 20:00
BigGerman
20518
As JacobIRR said in his answer, it is best to use the absolute path to the file. I use the os module to construct the absolute path based on the current working directory. So for your code it would be something like:
import os
working_directory = os.path.dirname(__file__)
properties_file = os.path.join(working_directory, 'module', 'properties.yaml')
answered Nov 9 at 20:00
BigGerman
20518
answered Nov 9 at 20:00
BigGerman
20518
answered Nov 9 at 20:00
BigGerman
20518
answered Nov 9 at 20:00
BigGerman
20518
20518
add a comment |
add a comment |
up vote
0
down vote
accepted
Based on answers from @JacobIRR and @BigGerman
I ended up using pathlib instead of os, but the logic is the same.
Here is the syntax with pathlib for those interested:
in file.py:
from pathlib import Path
properties_file = Path(__file__).resolve().parent/"properties.yaml"
with open(properties_file) as file:
properties = yaml.load(file)
answered Nov 9 at 20:17
Dominic Roy-Stang
13
add a comment |
up vote
0
down vote
accepted
Based on answers from @JacobIRR and @BigGerman
I ended up using pathlib instead of os, but the logic is the same.
Here is the syntax with pathlib for those interested:
in file.py:
from pathlib import Path
properties_file = Path(__file__).resolve().parent/"properties.yaml"
with open(properties_file) as file:
properties = yaml.load(file)
answered Nov 9 at 20:17
Dominic Roy-Stang
13
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Based on answers from @JacobIRR and @BigGerman
I ended up using pathlib instead of os, but the logic is the same.
Here is the syntax with pathlib for those interested:
in file.py:
from pathlib import Path
properties_file = Path(__file__).resolve().parent/"properties.yaml"
with open(properties_file) as file:
properties = yaml.load(file)
answered Nov 9 at 20:17
Dominic Roy-Stang
13
Based on answers from @JacobIRR and @BigGerman
I ended up using pathlib instead of os, but the logic is the same.
Here is the syntax with pathlib for those interested:
in file.py:
from pathlib import Path
properties_file = Path(__file__).resolve().parent/"properties.yaml"
with open(properties_file) as file:
properties = yaml.load(file)
answered Nov 9 at 20:17
Dominic Roy-Stang
13
edited Nov 9 at 20:26
answered Nov 9 at 20:17
Dominic Roy-Stang
13
answered Nov 9 at 20:17
Dominic Roy-Stang
13
answered Nov 9 at 20:17
Dominic Roy-Stang
13
13
add a comment |
add a comment |
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