AES-128 encryption in Java
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I have tried to encrypt some plaintext, which is in bytes, with a key, which is in bytes. However, the output I am getting is not what I am expecting.
public class AES {
public static byte encrypt(byte plainText, byte key) {
try {
Cipher cipher = Cipher.getInstance("AES");
SecretKeySpec secretKey = new SecretKeySpec(key, "AES");
cipher.init(Cipher.ENCRYPT_MODE, secretKey);
byte cipherText = cipher.doFinal(plainText);
return cipherText;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
public static String byteToHex(byte hash) {
StringBuilder sb = new StringBuilder(hash.length * 2);
for (byte b : hash) {
sb.append(String.format("%02x", b));
}
return sb.toString();
}
public static void main(String args) {
byte plaintext = {0x00,0x11,0x22,0x33,0x44,0x55,0x66,0x77,0x58,0x63,(byte)0xaa,(byte)0xbb,(byte)0xcc,(byte)0xdd,(byte)0xee,(byte)0xff};
byte key = {0x00,0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f};
byte encrypted = encrypt(plaintext, key);
System.out.println("Encrypted String : " + byteToHex(encrypted));
}
}
The output I am getting is: 814064943fe05668da1f3d2269a4ee22954f64f2e4e86e9eee82d20216684899 while I am expecting 69c4e0d86a7b0430d8cdb78070b4c55a. I am using the plaintext and key from here
java encryption aes
asked Nov 9 at 22:31
Bab
12910
|
show 1 more comment
up vote
1
down vote
favorite
I have tried to encrypt some plaintext, which is in bytes, with a key, which is in bytes. However, the output I am getting is not what I am expecting.
public class AES {
public static byte encrypt(byte plainText, byte key) {
try {
Cipher cipher = Cipher.getInstance("AES");
SecretKeySpec secretKey = new SecretKeySpec(key, "AES");
cipher.init(Cipher.ENCRYPT_MODE, secretKey);
byte cipherText = cipher.doFinal(plainText);
return cipherText;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
public static String byteToHex(byte hash) {
StringBuilder sb = new StringBuilder(hash.length * 2);
for (byte b : hash) {
sb.append(String.format("%02x", b));
}
return sb.toString();
}
public static void main(String args) {
byte plaintext = {0x00,0x11,0x22,0x33,0x44,0x55,0x66,0x77,0x58,0x63,(byte)0xaa,(byte)0xbb,(byte)0xcc,(byte)0xdd,(byte)0xee,(byte)0xff};
byte key = {0x00,0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f};
byte encrypted = encrypt(plaintext, key);
System.out.println("Encrypted String : " + byteToHex(encrypted));
}
}
The output I am getting is: 814064943fe05668da1f3d2269a4ee22954f64f2e4e86e9eee82d20216684899 while I am expecting 69c4e0d86a7b0430d8cdb78070b4c55a. I am using the plaintext and key from here
java encryption aes
asked Nov 9 at 22:31
Bab
12910
Do you understand what PKCS5 padding does? A hint: I will always make the result longer. So an input of 16 bytes can never result in an output of 16 bytes.
– Codo
Nov 9 at 22:44
No, I have removed it, and use the default. However, I would like to know why I am getting the incorrect output
– Bab
Nov 9 at 22:46
I have also tried to print the encrypted byte array withArray.toString(encrypted )
– Bab
Nov 9 at 22:51
The default padding mode of your AES provider is most likely "PKCS5". So you haven't changed anything... Read about it and you have a good idea why your result is different.
– Codo
Nov 9 at 22:53
Have read about it, and I found out that I had to use NoPadding, which has given me the proper format. However, I am still getting the incorrect output.
– Bab
Nov 9 at 23:00
|
show 1 more comment
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have tried to encrypt some plaintext, which is in bytes, with a key, which is in bytes. However, the output I am getting is not what I am expecting.
public class AES {
public static byte encrypt(byte plainText, byte key) {
try {
Cipher cipher = Cipher.getInstance("AES");
SecretKeySpec secretKey = new SecretKeySpec(key, "AES");
cipher.init(Cipher.ENCRYPT_MODE, secretKey);
byte cipherText = cipher.doFinal(plainText);
return cipherText;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
public static String byteToHex(byte hash) {
StringBuilder sb = new StringBuilder(hash.length * 2);
for (byte b : hash) {
sb.append(String.format("%02x", b));
}
return sb.toString();
}
public static void main(String args) {
byte plaintext = {0x00,0x11,0x22,0x33,0x44,0x55,0x66,0x77,0x58,0x63,(byte)0xaa,(byte)0xbb,(byte)0xcc,(byte)0xdd,(byte)0xee,(byte)0xff};
byte key = {0x00,0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f};
byte encrypted = encrypt(plaintext, key);
System.out.println("Encrypted String : " + byteToHex(encrypted));
}
}
The output I am getting is: 814064943fe05668da1f3d2269a4ee22954f64f2e4e86e9eee82d20216684899 while I am expecting 69c4e0d86a7b0430d8cdb78070b4c55a. I am using the plaintext and key from here
java encryption aes
asked Nov 9 at 22:31
Bab
12910
I have tried to encrypt some plaintext, which is in bytes, with a key, which is in bytes. However, the output I am getting is not what I am expecting.
public class AES {
public static byte encrypt(byte plainText, byte key) {
try {
Cipher cipher = Cipher.getInstance("AES");
SecretKeySpec secretKey = new SecretKeySpec(key, "AES");
cipher.init(Cipher.ENCRYPT_MODE, secretKey);
byte cipherText = cipher.doFinal(plainText);
return cipherText;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
public static String byteToHex(byte hash) {
StringBuilder sb = new StringBuilder(hash.length * 2);
for (byte b : hash) {
sb.append(String.format("%02x", b));
}
return sb.toString();
}
public static void main(String args) {
byte plaintext = {0x00,0x11,0x22,0x33,0x44,0x55,0x66,0x77,0x58,0x63,(byte)0xaa,(byte)0xbb,(byte)0xcc,(byte)0xdd,(byte)0xee,(byte)0xff};
byte key = {0x00,0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f};
byte encrypted = encrypt(plaintext, key);
System.out.println("Encrypted String : " + byteToHex(encrypted));
}
}
The output I am getting is: 814064943fe05668da1f3d2269a4ee22954f64f2e4e86e9eee82d20216684899 while I am expecting 69c4e0d86a7b0430d8cdb78070b4c55a. I am using the plaintext and key from here
java encryption aes
java encryption aes
asked Nov 9 at 22:31
Bab
12910
asked Nov 9 at 22:31
Bab
12910
edited Nov 9 at 22:44
asked Nov 9 at 22:31
Bab
12910
asked Nov 9 at 22:31
Bab
12910
asked Nov 9 at 22:31
Bab
12910
12910
Do you understand what PKCS5 padding does? A hint: I will always make the result longer. So an input of 16 bytes can never result in an output of 16 bytes.
– Codo
Nov 9 at 22:44
No, I have removed it, and use the default. However, I would like to know why I am getting the incorrect output
– Bab
Nov 9 at 22:46
I have also tried to print the encrypted byte array withArray.toString(encrypted )
– Bab
Nov 9 at 22:51
The default padding mode of your AES provider is most likely "PKCS5". So you haven't changed anything... Read about it and you have a good idea why your result is different.
– Codo
Nov 9 at 22:53
Have read about it, and I found out that I had to use NoPadding, which has given me the proper format. However, I am still getting the incorrect output.
– Bab
Nov 9 at 23:00
|
show 1 more comment
Do you understand what PKCS5 padding does? A hint: I will always make the result longer. So an input of 16 bytes can never result in an output of 16 bytes.
– Codo
Nov 9 at 22:44
No, I have removed it, and use the default. However, I would like to know why I am getting the incorrect output
– Bab
Nov 9 at 22:46
I have also tried to print the encrypted byte array withArray.toString(encrypted )
– Bab
Nov 9 at 22:51
The default padding mode of your AES provider is most likely "PKCS5". So you haven't changed anything... Read about it and you have a good idea why your result is different.
– Codo
Nov 9 at 22:53
Have read about it, and I found out that I had to use NoPadding, which has given me the proper format. However, I am still getting the incorrect output.
– Bab
Nov 9 at 23:00
Do you understand what PKCS5 padding does? A hint: I will always make the result longer. So an input of 16 bytes can never result in an output of 16 bytes.
– Codo
Nov 9 at 22:44
Do you understand what PKCS5 padding does? A hint: I will always make the result longer. So an input of 16 bytes can never result in an output of 16 bytes.
– Codo
Nov 9 at 22:44
No, I have removed it, and use the default. However, I would like to know why I am getting the incorrect output
– Bab
Nov 9 at 22:46
No, I have removed it, and use the default. However, I would like to know why I am getting the incorrect output
– Bab
Nov 9 at 22:46
I have also tried to print the encrypted byte array with
Array.toString(encrypted )– Bab
Nov 9 at 22:51
I have also tried to print the encrypted byte array with
Array.toString(encrypted )– Bab
Nov 9 at 22:51
The default padding mode of your AES provider is most likely "PKCS5". So you haven't changed anything... Read about it and you have a good idea why your result is different.
– Codo
Nov 9 at 22:53
The default padding mode of your AES provider is most likely "PKCS5". So you haven't changed anything... Read about it and you have a good idea why your result is different.
– Codo
Nov 9 at 22:53
Have read about it, and I found out that I had to use NoPadding, which has given me the proper format. However, I am still getting the incorrect output.
– Bab
Nov 9 at 23:00
Have read about it, and I found out that I had to use NoPadding, which has given me the proper format. However, I am still getting the incorrect output.
– Bab
Nov 9 at 23:00
|
show 1 more comment
1 Answer
1
active
oldest
votes
up vote
2
down vote
accepted
There are two things incorrect in your code.
You use PKCS5 padding while the original example doesn't use any padding.
You incorrectly copied the plain text.
So:
Cipher cipher = Cipher.getInstance("AES/ECB/NoPadding");
...
byte plaintext = { 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, (byte) 0x88,
(byte) 0x99, (byte) 0xaa, (byte) 0xbb, (byte) 0xcc, (byte) 0xdd, (byte) 0xee, (byte) 0xff };
Result:
Encrypted String : 69c4e0d86a7b0430d8cdb78070b4c55a
answered Nov 9 at 23:11
Codo
50.2k11110147
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
There are two things incorrect in your code.
You use PKCS5 padding while the original example doesn't use any padding.
You incorrectly copied the plain text.
So:
Cipher cipher = Cipher.getInstance("AES/ECB/NoPadding");
...
byte plaintext = { 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, (byte) 0x88,
(byte) 0x99, (byte) 0xaa, (byte) 0xbb, (byte) 0xcc, (byte) 0xdd, (byte) 0xee, (byte) 0xff };
Result:
Encrypted String : 69c4e0d86a7b0430d8cdb78070b4c55a
answered Nov 9 at 23:11
Codo
50.2k11110147
add a comment |
up vote
2
down vote
accepted
There are two things incorrect in your code.
You use PKCS5 padding while the original example doesn't use any padding.
You incorrectly copied the plain text.
So:
Cipher cipher = Cipher.getInstance("AES/ECB/NoPadding");
...
byte plaintext = { 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, (byte) 0x88,
(byte) 0x99, (byte) 0xaa, (byte) 0xbb, (byte) 0xcc, (byte) 0xdd, (byte) 0xee, (byte) 0xff };
Result:
Encrypted String : 69c4e0d86a7b0430d8cdb78070b4c55a
answered Nov 9 at 23:11
Codo
50.2k11110147
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
There are two things incorrect in your code.
You use PKCS5 padding while the original example doesn't use any padding.
You incorrectly copied the plain text.
So:
Cipher cipher = Cipher.getInstance("AES/ECB/NoPadding");
...
byte plaintext = { 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, (byte) 0x88,
(byte) 0x99, (byte) 0xaa, (byte) 0xbb, (byte) 0xcc, (byte) 0xdd, (byte) 0xee, (byte) 0xff };
Result:
Encrypted String : 69c4e0d86a7b0430d8cdb78070b4c55a
answered Nov 9 at 23:11
Codo
50.2k11110147
There are two things incorrect in your code.
You use PKCS5 padding while the original example doesn't use any padding.
You incorrectly copied the plain text.
So:
Cipher cipher = Cipher.getInstance("AES/ECB/NoPadding");
...
byte plaintext = { 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, (byte) 0x88,
(byte) 0x99, (byte) 0xaa, (byte) 0xbb, (byte) 0xcc, (byte) 0xdd, (byte) 0xee, (byte) 0xff };
Result:
Encrypted String : 69c4e0d86a7b0430d8cdb78070b4c55a
answered Nov 9 at 23:11
Codo
50.2k11110147
answered Nov 9 at 23:11
Codo
50.2k11110147
answered Nov 9 at 23:11
Codo
50.2k11110147
answered Nov 9 at 23:11
Codo
50.2k11110147
50.2k11110147
add a comment |
add a comment |
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Do you understand what PKCS5 padding does? A hint: I will always make the result longer. So an input of 16 bytes can never result in an output of 16 bytes.
– Codo
Nov 9 at 22:44
No, I have removed it, and use the default. However, I would like to know why I am getting the incorrect output
– Bab
Nov 9 at 22:46
I have also tried to print the encrypted byte array with
Array.toString(encrypted )– Bab
Nov 9 at 22:51
The default padding mode of your AES provider is most likely "PKCS5". So you haven't changed anything... Read about it and you have a good idea why your result is different.
– Codo
Nov 9 at 22:53
Have read about it, and I found out that I had to use NoPadding, which has given me the proper format. However, I am still getting the incorrect output.
– Bab
Nov 9 at 23:00